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Mathematics

Complex Numbers — JEE Main PYQs

46 previous year questions

Q1JEE Main 2026 Apr 2 Shift 2Medium

Let the circles C1:z=rC_1 : |z| = r and C2:z34i=5C_2 : |z - 3 - 4i| = 5, zCz \in \mathbb{C}, be such that C2C_2 lies within C1C_1. If z1z_1 moves on C1C_1, z2z_2 moves on C2C_2 and minz1z2=2\min |z_1 - z_2| = 2, then maxz1z2\max |z_1 - z_2| is equal to :

  1. A

    1212

  2. B

    1717

  3. C

    2222

  4. D

    2424

Show answer

Correct option: C

Q2JEE Main 2026 Apr 4 Shift 1Medium

Let zz be a complex number such that z+2=z2|z+2| = |z-2| and arg(z+3zi)=π4\arg\left(\frac{z+3}{z-i}\right) = \frac{\pi}{4}. Then z2|z|^2 is equal to:

  1. A

    99

  2. B

    44

  3. C

    55

  4. D

    11

Show answer

Correct option: A

Q3JEE Main 2026 Apr 4 Shift 2Medium

Let S={zC:z2+4z+16=0}S = \{z \in \mathbb{C} : z^2 + 4z + 16 = 0\}. Then zSz+3i2\displaystyle\sum_{z \in S} |z + \sqrt{3}\,i|^2 is equal to:

  1. A

    42

  2. B

    23

  3. C

    27

  4. D

    38

Show answer

Correct option: D

Q4JEE Main 2026 Apr 5 Shift 1Medium

Let a,bCa, b \in \mathbb{C}. Let α,β\alpha, \beta be the roots of the equation x2+ax+b=0x^2 + ax + b = 0. If βα=11\beta - \alpha = \sqrt{11} and β2α2=3i11\beta^2 - \alpha^2 = 3i\sqrt{11}, then (β3α3)2(\beta^3 - \alpha^3)^2 is equal to:

  1. A

    160

  2. B

    176

  3. C

    194

  4. D

    187

Show answer

Correct option: B

Q5JEE Main 2026 Apr 5 Shift 2Medium

Let z1,z2Cz_1, z_2 \in \mathbf{C} be the distinct solutions of the equation z2+4z(1+12i)=0z^2 + 4z - (1 + 12i) = 0. Then z12+z22|z_1|^2 + |z_2|^2 is equal to :

  1. A

    18

  2. B

    22

  3. C

    29

  4. D

    34

Show answer

Correct option: D

Q6JEE Main 2026 Apr 6 Shift 1Hard

Let the set of all values of kRk \in \mathbb{R} such that the equation z(zˉ+2+i)+k(2+3i)=0z\left(\bar{z}+2+i\right)+k\left(2+3i\right)=0, zCz \in \mathbb{C}, has at least one solution, be the interval [α,β][\alpha, \beta]. Then 9(α+β)9(\alpha+\beta) is equal to:

  1. A

    10-10

  2. B

    8-8

  3. C

    101310\sqrt{13}

  4. D

    8138\sqrt{13}

Show answer

Correct option: A

Q7JEE Main 2026 Apr 6 Shift 2Medium

Let S={zC:z2+6iz3=0}S = \left\{z \in \mathbb{C} : z^2 + \sqrt{6}\,iz - 3 = 0\right\}. Then zSz8\sum_{z \in S} z^8 is equal to :

  1. A

    162162

  2. B

    184184

  3. C

    262262

  4. D

    324324

Show answer

Correct option: A

Q8JEE Main 2026 Apr 8 Shift 2Medium

The number of values of zCz \in \mathbb{C}, satisfying the equations

z(4+8i)=10 and z(3+5i)+z(5+11i)=45,|z - (4 + 8i)| = \sqrt{10} \text{ and } |z - (3 + 5i)| + |z - (5 + 11i)| = 4\sqrt{5},

is :

  1. A

    00

  2. B

    22

  3. C

    11

  4. D

    44

Show answer

Correct option: B

Q9JEE Main 2025 Apr 2 Shift 1Medium

Let zz be a complex number such that z=1|z| = 1. If 2+k2zk+zˉ=kz\frac{2 + k^2 z}{k + \bar{z}} = kz, kRk \in \mathbf{R}, then the maximum distance of k+ik2k + ik^2 from the circle z(1+2i)=1|z - (1 + 2i)| = 1 is :

  1. A

    3+1\sqrt{3} + 1

  2. B

    2

  3. C

    5+1\sqrt{5} + 1

  4. D

    3

Show answer

Correct option: C

Q10JEE Main 2025 Apr 3 Shift 1Medium

Let zCz \in \mathbb{C} be such that z2+3iz2+i=2+3i\frac{z^2 + 3i}{z - 2 + i} = 2 + 3i. Then the sum of all possible values of z2z^2 is

  1. A

    192i19 - 2i

  2. B

    19+2i-19 + 2i

  3. C

    19+2i19 + 2i

  4. D

    192i-19 - 2i

Show answer

Correct option: D

Q11JEE Main 2025 Apr 3 Shift 2Medium

If z1,z2,z3Cz_1, z_2, z_3 \in \mathbb{C} are the vertices of an equilateral triangle, whose centroid is z0z_0, then k=13(zkz0)2\displaystyle\sum_{k=1}^{3} (z_k - z_0)^2 is equal to

  1. A

    11

  2. B

    00

  3. C

    ii

  4. D

    i-i

Show answer

Correct option: B

Q12JEE Main 2025 Apr 4 Shift 1MediumNumerical

Let A={zC:z2i=3}\mathrm{A} = \{z \in \mathbb{C} : |z - 2 - i| = 3\}, B={zC:Re(ziz)=2}\mathrm{B} = \{z \in \mathbb{C} : \mathrm{Re}(z - iz) = 2\} and S=AB\mathrm{S} = \mathrm{A} \cap \mathrm{B}. Then zSz2\sum\limits_{z \in S} |z|^2 is equal to ________

Show answer

Answer: 22

Q13JEE Main 2025 Apr 4 Shift 2Medium

Let the product of ω1=(8+i)sinθ+(7+4i)cosθ\omega_1=(8+i)\sin\theta+(7+4i)\cos\theta and ω2=(1+8i)sinθ+(4+7i)cosθ\omega_2=(1+8i)\sin\theta+(4+7i)\cos\theta be α+iβ\alpha+i\beta, i=1i=\sqrt{-1}. Let pp and qq be the maximum and the minimum values of α+β\alpha+\beta respectively. Then p+qp+q is equal to :

  1. A

    130130

  2. B

    140140

  3. C

    150150

  4. D

    160160

Show answer

Correct option: A

Q14JEE Main 2025 Apr 4 Shift 2MediumNumerical

If α\alpha is a root of the equation x2+x+1=0x^2+x+1=0 and k=1n(αk+1αk)2=20\displaystyle\sum_{\mathrm{k}=1}^{\mathrm{n}}\left(\alpha^{\mathrm{k}}+\dfrac{1}{\alpha^{\mathrm{k}}}\right)^2=20, then n\mathrm{n} is equal to __________.

Show answer

Answer: 11

Q15JEE Main 2025 Apr 7 Shift 1Medium

Among the statements

(S1) : The set {zC{i}:z=1 and ziz+i is purely real}\{\, z \in \mathbb{C} - \{-i\} : |z| = 1 \text{ and } \frac{z-i}{z+i} \text{ is purely real} \,\} contains exactly two elements, and

(S2) : The set {zC{1}:z=1 and z1z+1 is purely imaginary}\{\, z \in \mathbb{C} - \{-1\} : |z| = 1 \text{ and } \frac{z-1}{z+1} \text{ is purely imaginary} \,\} contains infinitely many elements.

  1. A

    both are correct

  2. B

    both are incorrect

  3. C

    only (S1) is correct

  4. D

    only (S2) is correct

Show answer

Correct option: D

Q16JEE Main 2025 Apr 7 Shift 2Medium

If the locus of zCz \in \mathbf{C}, such that Re(z12z+i)+Re(zˉ12zˉi)=2\mathrm{Re}\left(\dfrac{z - 1}{2z + i}\right) + \mathrm{Re}\left(\dfrac{\bar{z} - 1}{2\bar{z} - i}\right) = 2, is a circle of radius rr and center (a,b)(a, b), then 15abr2\dfrac{15ab}{r^2} is equal to :

  1. A

    1212

  2. B

    1616

  3. C

    1818

  4. D

    2424

Show answer

Correct option: C

Q17JEE Main 2025 Apr 8 Shift 2Medium

Let A={θ[0,2π]:1+10Re(2cosθ+isinθcosθ3isinθ)=0}A = \left\{\theta \in [0, 2\pi] : 1 + 10\,\mathrm{Re}\left(\frac{2\cos\theta + i\sin\theta}{\cos\theta - 3i\sin\theta}\right) = 0\right\}. Then θAθ2\sum_{\theta \in A} \theta^2 is equal to

  1. A

    8π28\pi^2

  2. B

    274π2\frac{27}{4}\pi^2

  3. C

    6π26\pi^2

  4. D

    214π2\frac{21}{4}\pi^2

Show answer

Correct option: D

Q18JEE Main 2025 Apr 8 Shift 2Medium

Let α\alpha be a solution of x2+x+1=0x^2 + x + 1 = 0, and for some aa and bb in R\mathbb{R}, [4ab][116131122148]=[000]\begin{bmatrix} 4 & a & b \end{bmatrix} \begin{bmatrix} 1 & 16 & 13 \\ -1 & -1 & 2 \\ -2 & -14 & -8 \end{bmatrix} = \begin{bmatrix} 0 & 0 & 0 \end{bmatrix}. If 4α4+mαa+nαb=3\frac{4}{\alpha^4} + \frac{m}{\alpha^a} + \frac{n}{\alpha^b} = 3, then m+nm + n is equal to ________

  1. A

    8

  2. B

    11

  3. C

    7

  4. D

    3

Show answer

Correct option: B

Q19JEE Main 2025 Jan 22 Shift 1Medium

Let z1,z2z_1, z_2 and z3z_3 be three complex numbers on the circle z=1|z|=1 with arg(z1)=π4\arg(z_1)=\frac{-\pi}{4}, arg(z2)=0\arg(z_2)=0 and arg(z3)=π4\arg(z_3)=\frac{\pi}{4}. If z1zˉ2+z2zˉ3+z3zˉ12=α+β2\left|z_1\bar{z}_2+z_2\bar{z}_3+z_3\bar{z}_1\right|^2=\alpha+\beta\sqrt{2}, α,βZ\alpha, \beta \in \mathbb{Z}, then the value of α2+β2\alpha^2+\beta^2 is :

  1. A

    24

  2. B

    29

  3. C

    31

  4. D

    41

Show answer

Correct option: B

Q20JEE Main 2025 Jan 22 Shift 2Medium

Let the curve z(1+i)+zˉ(1i)=4z(1 + i) + \bar{z}(1 - i) = 4, zCz \in \mathbb{C}, divide the region z31|z - 3| \leq 1 into two parts of areas α\alpha and β\beta. Then αβ|\alpha - \beta| equals :

  1. A

    1+π21 + \dfrac{\pi}{2}

  2. B

    1+π31 + \dfrac{\pi}{3}

  3. C

    1+π41 + \dfrac{\pi}{4}

  4. D

    1+π61 + \dfrac{\pi}{6}

Show answer

Correct option: A

Q21JEE Main 2025 Jan 23 Shift 1Medium

Let zˉi2zˉ+i=13\left|\frac{\bar{z} - i}{2\bar{z} + i}\right| = \frac{1}{3}, zCz \in \mathbb{C}, be the equation of a circle with center at CC. If the area of the triangle, whose vertices are at the points (0,0)(0, 0), CC and (α,0)(\alpha, 0) is 11 square units, then α2\alpha^2 equals:

  1. A

    5050

  2. B

    100100

  3. C

    8125\frac{81}{25}

  4. D

    12125\frac{121}{25}

Show answer

Correct option: B

Q22JEE Main 2025 Jan 23 Shift 2Medium

The number of complex numbers zz, satisfying z=1|z| = 1 and zzˉ+zˉz=1\left|\dfrac{z}{\bar{z}} + \dfrac{\bar{z}}{z}\right| = 1, is :

  1. A

    44

  2. B

    66

  3. C

    88

  4. D

    1010

Show answer

Correct option: C

Q23JEE Main 2025 Jan 24 Shift 1Hard

If α\alpha and β\beta are the roots of the equation 2z23z2i=02z^2-3z-2i=0, where i=1i=\sqrt{-1}, then 16Re(α19+β19+α11+β11α15+β15)Im(α19+β19+α11+β11α15+β15)16 \cdot \mathrm{Re}\left(\frac{\alpha^{19}+\beta^{19}+\alpha^{11}+\beta^{11}}{\alpha^{15}+\beta^{15}}\right) \cdot \mathrm{Im}\left(\frac{\alpha^{19}+\beta^{19}+\alpha^{11}+\beta^{11}}{\alpha^{15}+\beta^{15}}\right) is equal to

  1. A

    312

  2. B

    398

  3. C

    409

  4. D

    441

Show answer

Correct option: D

Q24JEE Main 2025 Jan 28 Shift 1Medium

Let O be the origin, the point A be z1=3+22iz_1 = \sqrt{3} + 2\sqrt{2}\,i, the point B(z2)(z_2) be such that 3z2=z1\sqrt{3}\,|z_2| = |z_1| and arg(z2)=arg(z1)+π6\arg(z_2) = \arg(z_1) + \frac{\pi}{6}. Then

  1. A

    ABO is an obtuse angled isosceles triangle

  2. B

    area of triangle ABO is 114\frac{11}{4}

  3. C

    area of triangle ABO is 113\frac{11}{\sqrt{3}}

  4. D

    ABO is a scalene triangle

Show answer

Correct option: A

Q25JEE Main 2025 Jan 28 Shift 2Medium

If α+iβ\alpha + i\beta and γ+iδ\gamma + i\delta are the roots of x2(32i)x(2i2)=0x^2 - (3-2i)x - (2i-2) = 0, i=1i = \sqrt{-1}, then αγ+βδ\alpha\gamma + \beta\delta is equal to :

  1. A

    2-2

  2. B

    22

  3. C

    66

  4. D

    6-6

Show answer

Correct option: B

Q26JEE Main 2024 Apr 4 Shift 1Medium

Let α\alpha and β\beta be the sum and the product of all the non-zero solutions of the equation (zˉ)2+z=0(\bar{z})^{2}+|z|=0, zCz \in \mathbf{C}. Then 4(α2+β2)4(\alpha^{2}+\beta^{2}) is equal to :

  1. A

    22

  2. B

    44

  3. C

    66

  4. D

    88

Show answer

Correct option: B

Q27JEE Main 2024 Apr 4 Shift 2Hard

The area (in sq. units) of the region S={zC:z12;(z+zˉ)+i(zzˉ)2,Im(z)0}S = \{z \in \mathbb{C} : |z-1| \le 2; (z+\bar{z}) + i(z-\bar{z}) \le 2, \operatorname{Im}(z) \ge 0\} is

  1. A

    3π2\frac{3\pi}{2}

  2. B

    7π3\frac{7\pi}{3}

  3. C

    7π4\frac{7\pi}{4}

  4. D

    17π8\frac{17\pi}{8}

Show answer

Correct option: A

Q28JEE Main 2024 Apr 5 Shift 1Hard

Consider the following two statements :

Statement I : For any two non-zero complex numbers z1,z2z_1, z_2, (z1+z2)z1z1+z2z22(z1+z2),(|z_1| + |z_2|)\left|\frac{z_1}{|z_1|} + \frac{z_2}{|z_2|}\right| \le 2\,(|z_1| + |z_2|), and

Statement II : If x,y,zx, y, z are three distinct complex numbers and a,b,ca, b, c are three positive real numbers such that ayz=bzx=cxy\frac{a}{|y-z|} = \frac{b}{|z-x|} = \frac{c}{|x-y|}, then a2yz+b2zx+c2xy=1.\frac{a^2}{y-z} + \frac{b^2}{z-x} + \frac{c^2}{x-y} = 1.

Between the above two statements,

  1. A

    both Statement I and Statement II are correct.

  2. B

    both Statement I and Statement II are incorrect.

  3. C

    Statement I is correct but Statement II is incorrect.

  4. D

    Statement I is incorrect but Statement II is correct.

Show answer

Correct option: C

Q29JEE Main 2024 Apr 5 Shift 2Medium

Let S1={zC:z5}S_1 = \{z \in \mathbf{C} : |z| \leq 5\}, S2={zC:Im(z+13i13i)0}S_2 = \left\{z \in \mathbf{C} : \operatorname{Im}\left(\dfrac{z + 1 - \sqrt{3}\,i}{1 - \sqrt{3}\,i}\right) \geq 0\right\} and S3={zC:Re(z)0}S_3 = \{z \in \mathbf{C} : \operatorname{Re}(z) \geq 0\}. Then the area of the region S1S2S3S_1 \cap S_2 \cap S_3 is :

  1. A

    125π24\dfrac{125\,\pi}{24}

  2. B

    125π4\dfrac{125\,\pi}{4}

  3. C

    125π6\dfrac{125\,\pi}{6}

  4. D

    125π12\dfrac{125\,\pi}{12}

Show answer

Correct option: D

Q30JEE Main 2024 Apr 6 Shift 2Medium

If z1,z2z_1, z_2 are two distinct complex number such that z12z212z1zˉ2=2\left|\dfrac{z_1-2z_2}{\frac{1}{2}-z_1\bar{z}_2}\right|=2, then

  1. A

    both z1z_1 and z2z_2 lie on the same circle.

  2. B

    z1z_1 lies on a circle of radius 12\frac{1}{2} and z2z_2 lies on a circle of radius 1.

  3. C

    either z1z_1 lies on a circle of radius 12\frac{1}{2} or z2z_2 lies on a circle of radius 1.

  4. D

    either z1z_1 lies on a circle of radius 1 or z2z_2 lies on a circle of radius 12\frac{1}{2}.

Show answer

Correct option: D

Q31JEE Main 2024 Apr 8 Shift 1Medium

Let zz be a complex number such that z+2=1|z+2|=1 and Im(z+1z+2)=15\mathrm{Im}\left(\frac{z+1}{z+2}\right)=\frac{1}{5}. Then the value of Re(z+2)\left|\mathrm{Re}\left(\overline{z+2}\right)\right| is

  1. A

    265\frac{2\sqrt{6}}{5}

  2. B

    245\frac{24}{5}

  3. C

    65\frac{\sqrt{6}}{5}

  4. D

    1+65\frac{1+\sqrt{6}}{5}

Show answer

Correct option: A

Q32JEE Main 2024 Apr 8 Shift 1Medium

If the set R={(a,b):a+5b=42,a,bN}R=\{(a,b): a+5b=42, a,b\in\mathbb{N}\} has mm elements and n=1m(1in!)=x+iy\sum_{n=1}^{m}\left(1-i^{n!}\right)=x+iy, where i=1i=\sqrt{-1}, then the value of m+x+ym+x+y is

  1. A

    12

  2. B

    8

  3. C

    5

  4. D

    4

Show answer

Correct option: A

Q33JEE Main 2024 Apr 8 Shift 2Medium

The sum of all possible values of θ[π,2π]\theta \in [-\pi, 2\pi], for which 1+icosθ12icosθ\dfrac{1 + i\cos\theta}{1 - 2i\cos\theta} is purely imaginary, is equal to :

  1. A

    2π2\pi

  2. B

    3π3\pi

  3. C

    4π4\pi

  4. D

    5π5\pi

Show answer

Correct option: B

Q34JEE Main 2024 Apr 9 Shift 1MediumNumerical

The sum of the square of the modulus of the elements in the set {z=a+ib:a,bZ, zC, z11, z5z5i}\{z=\mathrm{a}+\mathrm{ib} : \mathrm{a}, \mathrm{b}\in\mathbf{Z},\ z\in\mathbf{C},\ |z-1|\le 1,\ |z-5|\le|z-5\mathrm{i}|\} is ________.

Show answer

Answer: 9

Q35JEE Main 2024 Apr 9 Shift 2Medium

Let zz be a complex number such that the real part of z2iz+2i\frac{z-2i}{z+2i} is zero. Then, the maximum value of z(6+8i)|z-(6+8i)| is equal to

  1. A

    88

  2. B

    1010

  3. C

    1212

  4. D

    \infty

Show answer

Correct option: C

Q36JEE Main 2024 Feb 1 Shift 1Hard

Let S={zC:z1=1 and (21)(z+zˉ)i(zzˉ)=22}S=\{z \in \mathbb{C} : |z-1|=1 \text{ and } (\sqrt{2}-1)(z+\bar{z}) - i(z-\bar{z}) = 2\sqrt{2}\}. Let z1,z2Sz_1, z_2 \in S be such that z1=maxzSz|z_1| = \max\limits_{z \in S} |z| and z2=minzSz|z_2| = \min\limits_{z \in S} |z|. Then 2z1z22\left|\sqrt{2}\, z_1 - z_2\right|^2 equals :

  1. A

    11

  2. B

    22

  3. C

    33

  4. D

    44

Show answer

Correct option: B

Q37JEE Main 2024 Feb 1 Shift 1HardNumerical

Let P={zC:z+23i1}P = \{z \in \mathbb{C} : |z + 2 - 3i| \le 1\} and Q={zC:z(1+i)+zˉ(1i)8}Q = \{z \in \mathbb{C} : z(1 + i) + \bar{z}(1 - i) \le -8\}. Let in PQP \cap Q, z3+2i|z - 3 + 2i| be maximum and minimum at z1z_1 and z2z_2 respectively. If z12+2z22=α+β2|z_1|^2 + 2|z_2|^2 = \alpha + \beta\sqrt{2}, where α,β\alpha, \beta are integers, then α+β\alpha + \beta equals ________.

Show answer

Answer: 36

Q38JEE Main 2024 Feb 1 Shift 2Medium

If zz is a complex number such that z1|z| \geq 1, then the minimum value of z+12(3+4i)\left|z+\frac{1}{2}(3+4i)\right| is :

  1. A

    32\frac{3}{2}

  2. B

    22

  3. C

    52\frac{5}{2}

  4. D

    33

Q39JEE Main 2024 Jan 27 Shift 1Easy

If S={zC:zi=z+i=z1}S = \{z \in \mathbf{C} : |z - i| = |z + i| = |z - 1|\}, then, n(S)n(S) is :

  1. A

    00

  2. B

    11

  3. C

    22

  4. D

    33

Show answer

Correct option: B

Q40JEE Main 2024 Jan 27 Shift 1MediumNumerical

If α\alpha satisfies the equation x2+x+1=0x^2 + x + 1 = 0 and (1+α)7=A+Bα+Cα2(1 + \alpha)^7 = A + B\alpha + C\alpha^2, A,B,C0A, B, C \geq 0, then 5(3A2BC)5(3A - 2B - C) is equal to ________.

Show answer

Answer: 5

Q41JEE Main 2024 Jan 29 Shift 1Medium

If z=122iz=\dfrac{1}{2}-2i is such that z+1=αz+β(1+i)|z+1| = \alpha z + \beta(1+i), i=1i=\sqrt{-1} and α,βR\alpha, \beta \in \mathbb{R}, then α+β\alpha + \beta is equal to

  1. A

    1-1

  2. B

    22

  3. C

    33

  4. D

    4-4

Show answer

Correct option: C

Q42JEE Main 2024 Jan 29 Shift 1MediumNumerical

Let α,β\alpha, \beta be the roots of the equation x2x+2=0x^2 - x + 2 = 0 with Im(α)>Im(β)Im(\alpha) > Im(\beta).

Then α6+α4+β45α2\alpha^6 + \alpha^4 + \beta^4 - 5\alpha^2 is equal to __________.

Show answer

Answer: 13

Q43JEE Main 2024 Jan 30 Shift 1Medium

If z=x+iyz=x+\mathrm{i}y, xy0xy\neq 0, satisfies the equation z2+izˉ=0z^2+\mathrm{i}\bar{z}=0, then z2|z^2| is equal to :

  1. A

    14\frac{1}{4}

  2. B

    11

  3. C

    44

  4. D

    99

Show answer

Correct option: B

Q44JEE Main 2024 Jan 30 Shift 2Medium

If zz is a complex number, then the number of common roots of the equations z1985+z100+1=0z^{1985}+z^{100}+1=0 and z3+2z2+2z+1=0z^3+2z^2+2z+1=0, is equal to

  1. A

    0

  2. B

    1

  3. C

    2

  4. D

    3

Show answer

Correct option: C

Q45JEE Main 2024 Jan 31 Shift 1HardNumerical

If α\alpha denotes the number of solutions of 1ix=2x|1-i|^x=2^x and β=(zarg(z))\beta=\left(\frac{|z|}{\arg(z)}\right), where z=π4(1+i)4[1πiπ+i+πi1+πi]z=\frac{\pi}{4}(1+i)^4\left[\frac{1-\sqrt{\pi}\,i}{\sqrt{\pi}+i}+\frac{\sqrt{\pi}-i}{1+\sqrt{\pi}\,i}\right], i=1i=\sqrt{-1}, then the distance of the point (α,β)(\alpha, \beta) from the line 4x3y=74x-3y=7 is _____

Show answer

Answer: 3

Q46JEE Main 2024 Jan 31 Shift 2Medium

Let z1z_{1} and z2z_{2} be two complex numbers such that z1+z2=5z_{1}+z_{2}=5 and z13+z23=20+15iz_{1}^{3}+z_{2}^{3}=20+15 i. Then, z14+z24\left|z_{1}^{4}+z_{2}^{4}\right| equals -

  1. A

    30330 \sqrt{3}

  2. B

    151515 \sqrt{15}

  3. C

    25325 \sqrt{3}

  4. D

    75

Show answer

Correct option: D