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Mathematics

Complex Numbers — JEE Main PYQs

46 previous year questions

Q1JEE Main 2026 Apr 2 Shift 2Medium

Let the circles C1:∣z∣=rC_1 : |z| = r and C2:∣zāˆ’3āˆ’4i∣=5C_2 : |z - 3 - 4i| = 5, z∈Cz \in \mathbb{C}, be such that C2C_2 lies within C1C_1. If z1z_1 moves on C1C_1, z2z_2 moves on C2C_2 and min⁔∣z1āˆ’z2∣=2\min |z_1 - z_2| = 2, then max⁔∣z1āˆ’z2∣\max |z_1 - z_2| is equal to :

  1. A

    1212

  2. B

    1717

  3. C

    2222

  4. D

    2424

Show answer

Correct option: C

Q2JEE Main 2026 Apr 4 Shift 1Medium

Let zz be a complex number such that ∣z+2∣=∣zāˆ’2∣|z+2| = |z-2| and arg⁔(z+3zāˆ’i)=Ļ€4\arg\left(\frac{z+3}{z-i}\right) = \frac{\pi}{4}. Then ∣z∣2|z|^2 is equal to:

  1. A

    99

  2. B

    44

  3. C

    55

  4. D

    11

Show answer

Correct option: A

Q3JEE Main 2026 Apr 4 Shift 2Medium

Let S={z∈C:z2+4z+16=0}S = \{z \in \mathbb{C} : z^2 + 4z + 16 = 0\}. Then āˆ‘z∈S∣z+3 i∣2\displaystyle\sum_{z \in S} |z + \sqrt{3}\,i|^2 is equal to:

  1. A

    42

  2. B

    23

  3. C

    27

  4. D

    38

Show answer

Correct option: D

Q4JEE Main 2026 Apr 5 Shift 1Medium

Let a,b∈Ca, b \in \mathbb{C}. Let α,β\alpha, \beta be the roots of the equation x2+ax+b=0x^2 + ax + b = 0. If Ī²āˆ’Ī±=11\beta - \alpha = \sqrt{11} and β2āˆ’Ī±2=3i11\beta^2 - \alpha^2 = 3i\sqrt{11}, then (β3āˆ’Ī±3)2(\beta^3 - \alpha^3)^2 is equal to:

  1. A

    160

  2. B

    176

  3. C

    194

  4. D

    187

Show answer

Correct option: B

Q5JEE Main 2026 Apr 5 Shift 2Medium

Let z1,z2∈Cz_1, z_2 \in \mathbf{C} be the distinct solutions of the equation z2+4zāˆ’(1+12i)=0z^2 + 4z - (1 + 12i) = 0. Then ∣z1∣2+∣z2∣2|z_1|^2 + |z_2|^2 is equal to :

  1. A

    18

  2. B

    22

  3. C

    29

  4. D

    34

Show answer

Correct option: D

Q6JEE Main 2026 Apr 6 Shift 1Hard

Let the set of all values of k∈Rk \in \mathbb{R} such that the equation z(zˉ+2+i)+k(2+3i)=0z\left(\bar{z}+2+i\right)+k\left(2+3i\right)=0, z∈Cz \in \mathbb{C}, has at least one solution, be the interval [α,β][\alpha, \beta]. Then 9(α+β)9(\alpha+\beta) is equal to:

  1. A

    āˆ’10-10

  2. B

    āˆ’8-8

  3. C

    101310\sqrt{13}

  4. D

    8138\sqrt{13}

Show answer

Correct option: A

Q7JEE Main 2026 Apr 6 Shift 2Medium

Let S={z∈C:z2+6 izāˆ’3=0}S = \left\{z \in \mathbb{C} : z^2 + \sqrt{6}\,iz - 3 = 0\right\}. Then āˆ‘z∈Sz8\sum_{z \in S} z^8 is equal to :

  1. A

    162162

  2. B

    184184

  3. C

    262262

  4. D

    324324

Show answer

Correct option: A

Q8JEE Main 2026 Apr 8 Shift 2Medium

The number of values of z∈Cz \in \mathbb{C}, satisfying the equations

∣zāˆ’(4+8i)∣=10Ā and ∣zāˆ’(3+5i)∣+∣zāˆ’(5+11i)∣=45,|z - (4 + 8i)| = \sqrt{10} \text{ and } |z - (3 + 5i)| + |z - (5 + 11i)| = 4\sqrt{5},

is :

  1. A

    00

  2. B

    22

  3. C

    11

  4. D

    44

Show answer

Correct option: B

Q9JEE Main 2025 Apr 2 Shift 1Medium

Let zz be a complex number such that ∣z∣=1|z| = 1. If 2+k2zk+zˉ=kz\frac{2 + k^2 z}{k + \bar{z}} = kz, k∈Rk \in \mathbf{R}, then the maximum distance of k+ik2k + ik^2 from the circle ∣zāˆ’(1+2i)∣=1|z - (1 + 2i)| = 1 is :

  1. A

    3+1\sqrt{3} + 1

  2. B

    2

  3. C

    5+1\sqrt{5} + 1

  4. D

    3

Show answer

Correct option: C

Q10JEE Main 2025 Apr 3 Shift 1Medium

Let z∈Cz \in \mathbb{C} be such that z2+3izāˆ’2+i=2+3i\frac{z^2 + 3i}{z - 2 + i} = 2 + 3i. Then the sum of all possible values of z2z^2 is

  1. A

    19āˆ’2i19 - 2i

  2. B

    āˆ’19+2i-19 + 2i

  3. C

    19+2i19 + 2i

  4. D

    āˆ’19āˆ’2i-19 - 2i

Show answer

Correct option: D

Q11JEE Main 2025 Apr 3 Shift 2Medium

If z1,z2,z3∈Cz_1, z_2, z_3 \in \mathbb{C} are the vertices of an equilateral triangle, whose centroid is z0z_0, then āˆ‘k=13(zkāˆ’z0)2\displaystyle\sum_{k=1}^{3} (z_k - z_0)^2 is equal to

  1. A

    11

  2. B

    00

  3. C

    ii

  4. D

    āˆ’i-i

Show answer

Correct option: B

Q12JEE Main 2025 Apr 4 Shift 1MediumNumerical

Let A={z∈C:∣zāˆ’2āˆ’i∣=3}\mathrm{A} = \{z \in \mathbb{C} : |z - 2 - i| = 3\}, B={z∈C:Re(zāˆ’iz)=2}\mathrm{B} = \{z \in \mathbb{C} : \mathrm{Re}(z - iz) = 2\} and S=A∩B\mathrm{S} = \mathrm{A} \cap \mathrm{B}. Then āˆ‘z∈S∣z∣2\sum\limits_{z \in S} |z|^2 is equal to ________

Show answer

Answer: 22

Q13JEE Main 2025 Apr 4 Shift 2Medium

Let the product of ω1=(8+i)sin⁔θ+(7+4i)cos⁔θ\omega_1=(8+i)\sin\theta+(7+4i)\cos\theta and ω2=(1+8i)sin⁔θ+(4+7i)cos⁔θ\omega_2=(1+8i)\sin\theta+(4+7i)\cos\theta be α+iβ\alpha+i\beta, i=āˆ’1i=\sqrt{-1}. Let pp and qq be the maximum and the minimum values of α+β\alpha+\beta respectively. Then p+qp+q is equal to :

  1. A

    130130

  2. B

    140140

  3. C

    150150

  4. D

    160160

Show answer

Correct option: A

Q14JEE Main 2025 Apr 4 Shift 2MediumNumerical

If α\alpha is a root of the equation x2+x+1=0x^2+x+1=0 and āˆ‘k=1n(αk+1αk)2=20\displaystyle\sum_{\mathrm{k}=1}^{\mathrm{n}}\left(\alpha^{\mathrm{k}}+\dfrac{1}{\alpha^{\mathrm{k}}}\right)^2=20, then n\mathrm{n} is equal to __________.

Show answer

Answer: 11

Q15JEE Main 2025 Apr 7 Shift 1Medium

Among the statements

(S1) : The set { z∈Cāˆ’{āˆ’i}:∣z∣=1Ā andĀ zāˆ’iz+iĀ isĀ purelyĀ real }\{\, z \in \mathbb{C} - \{-i\} : |z| = 1 \text{ and } \frac{z-i}{z+i} \text{ is purely real} \,\} contains exactly two elements, and

(S2) : The set { z∈Cāˆ’{āˆ’1}:∣z∣=1Ā andĀ zāˆ’1z+1Ā isĀ purelyĀ imaginary }\{\, z \in \mathbb{C} - \{-1\} : |z| = 1 \text{ and } \frac{z-1}{z+1} \text{ is purely imaginary} \,\} contains infinitely many elements.

  1. A

    both are correct

  2. B

    both are incorrect

  3. C

    only (S1) is correct

  4. D

    only (S2) is correct

Show answer

Correct option: D

Q16JEE Main 2025 Apr 7 Shift 2Medium

If the locus of z∈Cz \in \mathbf{C}, such that Re(zāˆ’12z+i)+Re(zĖ‰āˆ’12zĖ‰āˆ’i)=2\mathrm{Re}\left(\dfrac{z - 1}{2z + i}\right) + \mathrm{Re}\left(\dfrac{\bar{z} - 1}{2\bar{z} - i}\right) = 2, is a circle of radius rr and center (a,b)(a, b), then 15abr2\dfrac{15ab}{r^2} is equal to :

  1. A

    1212

  2. B

    1616

  3. C

    1818

  4. D

    2424

Show answer

Correct option: C

Q17JEE Main 2025 Apr 8 Shift 2Medium

Let A={θ∈[0,2Ļ€]:1+10 Re(2cos⁔θ+isin⁔θcosā”Īøāˆ’3isin⁔θ)=0}A = \left\{\theta \in [0, 2\pi] : 1 + 10\,\mathrm{Re}\left(\frac{2\cos\theta + i\sin\theta}{\cos\theta - 3i\sin\theta}\right) = 0\right\}. Then āˆ‘ĪøāˆˆAĪø2\sum_{\theta \in A} \theta^2 is equal to

  1. A

    8Ļ€28\pi^2

  2. B

    274Ļ€2\frac{27}{4}\pi^2

  3. C

    6Ļ€26\pi^2

  4. D

    214Ļ€2\frac{21}{4}\pi^2

Show answer

Correct option: D

Q18JEE Main 2025 Apr 8 Shift 2Medium

Let α\alpha be a solution of x2+x+1=0x^2 + x + 1 = 0, and for some aa and bb in R\mathbb{R}, [4ab][11613āˆ’1āˆ’12āˆ’2āˆ’14āˆ’8]=[000]\begin{bmatrix} 4 & a & b \end{bmatrix} \begin{bmatrix} 1 & 16 & 13 \\ -1 & -1 & 2 \\ -2 & -14 & -8 \end{bmatrix} = \begin{bmatrix} 0 & 0 & 0 \end{bmatrix}. If 4α4+mαa+nαb=3\frac{4}{\alpha^4} + \frac{m}{\alpha^a} + \frac{n}{\alpha^b} = 3, then m+nm + n is equal to ________

  1. A

    8

  2. B

    11

  3. C

    7

  4. D

    3

Show answer

Correct option: B

Q19JEE Main 2025 Jan 22 Shift 1Medium

Let z1,z2z_1, z_2 and z3z_3 be three complex numbers on the circle ∣z∣=1|z|=1 with arg⁔(z1)=āˆ’Ļ€4\arg(z_1)=\frac{-\pi}{4}, arg⁔(z2)=0\arg(z_2)=0 and arg⁔(z3)=Ļ€4\arg(z_3)=\frac{\pi}{4}. If ∣z1zˉ2+z2zˉ3+z3zˉ1∣2=α+β2\left|z_1\bar{z}_2+z_2\bar{z}_3+z_3\bar{z}_1\right|^2=\alpha+\beta\sqrt{2}, α,β∈Z\alpha, \beta \in \mathbb{Z}, then the value of α2+β2\alpha^2+\beta^2 is :

  1. A

    24

  2. B

    29

  3. C

    31

  4. D

    41

Show answer

Correct option: B

Q20JEE Main 2025 Jan 22 Shift 2Medium

Let the curve z(1+i)+zˉ(1āˆ’i)=4z(1 + i) + \bar{z}(1 - i) = 4, z∈Cz \in \mathbb{C}, divide the region ∣zāˆ’3āˆ£ā‰¤1|z - 3| \leq 1 into two parts of areas α\alpha and β\beta. Then āˆ£Ī±āˆ’Ī²āˆ£|\alpha - \beta| equals :

  1. A

    1+Ļ€21 + \dfrac{\pi}{2}

  2. B

    1+Ļ€31 + \dfrac{\pi}{3}

  3. C

    1+Ļ€41 + \dfrac{\pi}{4}

  4. D

    1+Ļ€61 + \dfrac{\pi}{6}

Show answer

Correct option: A

Q21JEE Main 2025 Jan 23 Shift 1Medium

Let ∣zĖ‰āˆ’i2zˉ+i∣=13\left|\frac{\bar{z} - i}{2\bar{z} + i}\right| = \frac{1}{3}, z∈Cz \in \mathbb{C}, be the equation of a circle with center at CC. If the area of the triangle, whose vertices are at the points (0,0)(0, 0), CC and (α,0)(\alpha, 0) is 11 square units, then α2\alpha^2 equals:

  1. A

    5050

  2. B

    100100

  3. C

    8125\frac{81}{25}

  4. D

    12125\frac{121}{25}

Show answer

Correct option: B

Q22JEE Main 2025 Jan 23 Shift 2Medium

The number of complex numbers zz, satisfying ∣z∣=1|z| = 1 and ∣zzˉ+zˉz∣=1\left|\dfrac{z}{\bar{z}} + \dfrac{\bar{z}}{z}\right| = 1, is :

  1. A

    44

  2. B

    66

  3. C

    88

  4. D

    1010

Show answer

Correct option: C

Q23JEE Main 2025 Jan 24 Shift 1Hard

If α\alpha and β\beta are the roots of the equation 2z2āˆ’3zāˆ’2i=02z^2-3z-2i=0, where i=āˆ’1i=\sqrt{-1}, then 16ā‹…Re(α19+β19+α11+β11α15+β15)ā‹…Im(α19+β19+α11+β11α15+β15)16 \cdot \mathrm{Re}\left(\frac{\alpha^{19}+\beta^{19}+\alpha^{11}+\beta^{11}}{\alpha^{15}+\beta^{15}}\right) \cdot \mathrm{Im}\left(\frac{\alpha^{19}+\beta^{19}+\alpha^{11}+\beta^{11}}{\alpha^{15}+\beta^{15}}\right) is equal to

  1. A

    312

  2. B

    398

  3. C

    409

  4. D

    441

Show answer

Correct option: D

Q24JEE Main 2025 Jan 28 Shift 1Medium

Let O be the origin, the point A be z1=3+22 iz_1 = \sqrt{3} + 2\sqrt{2}\,i, the point B(z2)(z_2) be such that 3ā€‰āˆ£z2∣=∣z1∣\sqrt{3}\,|z_2| = |z_1| and arg⁔(z2)=arg⁔(z1)+Ļ€6\arg(z_2) = \arg(z_1) + \frac{\pi}{6}. Then

  1. A

    ABO is an obtuse angled isosceles triangle

  2. B

    area of triangle ABO is 114\frac{11}{4}

  3. C

    area of triangle ABO is 113\frac{11}{\sqrt{3}}

  4. D

    ABO is a scalene triangle

Show answer

Correct option: A

Q25JEE Main 2025 Jan 28 Shift 2Medium

If α+iβ\alpha + i\beta and γ+iĪ“\gamma + i\delta are the roots of x2āˆ’(3āˆ’2i)xāˆ’(2iāˆ’2)=0x^2 - (3-2i)x - (2i-2) = 0, i=āˆ’1i = \sqrt{-1}, then αγ+βΓ\alpha\gamma + \beta\delta is equal to :

  1. A

    āˆ’2-2

  2. B

    22

  3. C

    66

  4. D

    āˆ’6-6

Show answer

Correct option: B

Q26JEE Main 2024 Apr 4 Shift 1Medium

Let α\alpha and β\beta be the sum and the product of all the non-zero solutions of the equation (zˉ)2+∣z∣=0(\bar{z})^{2}+|z|=0, z∈Cz \in \mathbf{C}. Then 4(α2+β2)4(\alpha^{2}+\beta^{2}) is equal to :

  1. A

    22

  2. B

    44

  3. C

    66

  4. D

    88

Show answer

Correct option: B

Q27JEE Main 2024 Apr 4 Shift 2Hard

The area (in sq. units) of the region S={z∈C:∣zāˆ’1āˆ£ā‰¤2;(z+zˉ)+i(zāˆ’zˉ)≤2,Im⁔(z)≄0}S = \{z \in \mathbb{C} : |z-1| \le 2; (z+\bar{z}) + i(z-\bar{z}) \le 2, \operatorname{Im}(z) \ge 0\} is

  1. A

    3Ļ€2\frac{3\pi}{2}

  2. B

    7Ļ€3\frac{7\pi}{3}

  3. C

    7Ļ€4\frac{7\pi}{4}

  4. D

    17Ļ€8\frac{17\pi}{8}

Show answer

Correct option: A

Q28JEE Main 2024 Apr 5 Shift 1Hard

Consider the following two statements :

Statement I : For any two non-zero complex numbers z1,z2z_1, z_2, (∣z1∣+∣z2∣)∣z1∣z1∣+z2∣z2āˆ£āˆ£ā‰¤2 (∣z1∣+∣z2∣),(|z_1| + |z_2|)\left|\frac{z_1}{|z_1|} + \frac{z_2}{|z_2|}\right| \le 2\,(|z_1| + |z_2|), and

Statement II : If x,y,zx, y, z are three distinct complex numbers and a,b,ca, b, c are three positive real numbers such that a∣yāˆ’z∣=b∣zāˆ’x∣=c∣xāˆ’y∣\frac{a}{|y-z|} = \frac{b}{|z-x|} = \frac{c}{|x-y|}, then a2yāˆ’z+b2zāˆ’x+c2xāˆ’y=1.\frac{a^2}{y-z} + \frac{b^2}{z-x} + \frac{c^2}{x-y} = 1.

Between the above two statements,

  1. A

    both Statement I and Statement II are correct.

  2. B

    both Statement I and Statement II are incorrect.

  3. C

    Statement I is correct but Statement II is incorrect.

  4. D

    Statement I is incorrect but Statement II is correct.

Show answer

Correct option: C

Q29JEE Main 2024 Apr 5 Shift 2Medium

Let S1={z∈C:∣zāˆ£ā‰¤5}S_1 = \{z \in \mathbf{C} : |z| \leq 5\}, S2={z∈C:Im⁔(z+1āˆ’3 i1āˆ’3 i)≄0}S_2 = \left\{z \in \mathbf{C} : \operatorname{Im}\left(\dfrac{z + 1 - \sqrt{3}\,i}{1 - \sqrt{3}\,i}\right) \geq 0\right\} and S3={z∈C:Re⁔(z)≄0}S_3 = \{z \in \mathbf{C} : \operatorname{Re}(z) \geq 0\}. Then the area of the region S1∩S2∩S3S_1 \cap S_2 \cap S_3 is :

  1. A

    125 π24\dfrac{125\,\pi}{24}

  2. B

    125 π4\dfrac{125\,\pi}{4}

  3. C

    125 π6\dfrac{125\,\pi}{6}

  4. D

    125 π12\dfrac{125\,\pi}{12}

Show answer

Correct option: D

Q30JEE Main 2024 Apr 6 Shift 2Medium

If z1,z2z_1, z_2 are two distinct complex number such that ∣z1āˆ’2z212āˆ’z1zˉ2∣=2\left|\dfrac{z_1-2z_2}{\frac{1}{2}-z_1\bar{z}_2}\right|=2, then

  1. A

    both z1z_1 and z2z_2 lie on the same circle.

  2. B

    z1z_1 lies on a circle of radius 12\frac{1}{2} and z2z_2 lies on a circle of radius 1.

  3. C

    either z1z_1 lies on a circle of radius 12\frac{1}{2} or z2z_2 lies on a circle of radius 1.

  4. D

    either z1z_1 lies on a circle of radius 1 or z2z_2 lies on a circle of radius 12\frac{1}{2}.

Show answer

Correct option: D

Q31JEE Main 2024 Apr 8 Shift 1Medium

Let zz be a complex number such that ∣z+2∣=1|z+2|=1 and Im(z+1z+2)=15\mathrm{Im}\left(\frac{z+1}{z+2}\right)=\frac{1}{5}. Then the value of ∣Re(z+2‾)∣\left|\mathrm{Re}\left(\overline{z+2}\right)\right| is

  1. A

    265\frac{2\sqrt{6}}{5}

  2. B

    245\frac{24}{5}

  3. C

    65\frac{\sqrt{6}}{5}

  4. D

    1+65\frac{1+\sqrt{6}}{5}

Show answer

Correct option: A

Q32JEE Main 2024 Apr 8 Shift 1Medium

If the set R={(a,b):a+5b=42,a,b∈N}R=\{(a,b): a+5b=42, a,b\in\mathbb{N}\} has mm elements and āˆ‘n=1m(1āˆ’in!)=x+iy\sum_{n=1}^{m}\left(1-i^{n!}\right)=x+iy, where i=āˆ’1i=\sqrt{-1}, then the value of m+x+ym+x+y is

  1. A

    12

  2. B

    8

  3. C

    5

  4. D

    4

Show answer

Correct option: A

Q33JEE Main 2024 Apr 8 Shift 2Medium

The sum of all possible values of θ∈[āˆ’Ļ€,2Ļ€]\theta \in [-\pi, 2\pi], for which 1+icos⁔θ1āˆ’2icos⁔θ\dfrac{1 + i\cos\theta}{1 - 2i\cos\theta} is purely imaginary, is equal to :

  1. A

    2Ļ€2\pi

  2. B

    3Ļ€3\pi

  3. C

    4Ļ€4\pi

  4. D

    5Ļ€5\pi

Show answer

Correct option: B

Q34JEE Main 2024 Apr 9 Shift 1MediumNumerical

The sum of the square of the modulus of the elements in the set {z=a+ib:a,b∈Z,Ā z∈C, ∣zāˆ’1āˆ£ā‰¤1, ∣zāˆ’5āˆ£ā‰¤āˆ£zāˆ’5i∣}\{z=\mathrm{a}+\mathrm{ib} : \mathrm{a}, \mathrm{b}\in\mathbf{Z},\ z\in\mathbf{C},\ |z-1|\le 1,\ |z-5|\le|z-5\mathrm{i}|\} is ________.

Show answer

Answer: 9

Q35JEE Main 2024 Apr 9 Shift 2Medium

Let zz be a complex number such that the real part of zāˆ’2iz+2i\frac{z-2i}{z+2i} is zero. Then, the maximum value of ∣zāˆ’(6+8i)∣|z-(6+8i)| is equal to

  1. A

    88

  2. B

    1010

  3. C

    1212

  4. D

    āˆž\infty

Show answer

Correct option: C

Q36JEE Main 2024 Feb 1 Shift 1Hard

Let S={z∈C:∣zāˆ’1∣=1Ā andĀ (2āˆ’1)(z+zˉ)āˆ’i(zāˆ’zˉ)=22}S=\{z \in \mathbb{C} : |z-1|=1 \text{ and } (\sqrt{2}-1)(z+\bar{z}) - i(z-\bar{z}) = 2\sqrt{2}\}. Let z1,z2∈Sz_1, z_2 \in S be such that ∣z1∣=max⁔z∈S∣z∣|z_1| = \max\limits_{z \in S} |z| and ∣z2∣=min⁔z∈S∣z∣|z_2| = \min\limits_{z \in S} |z|. Then ∣2 z1āˆ’z2∣2\left|\sqrt{2}\, z_1 - z_2\right|^2 equals :

  1. A

    11

  2. B

    22

  3. C

    33

  4. D

    44

Show answer

Correct option: B

Q37JEE Main 2024 Feb 1 Shift 1HardNumerical

Let P={z∈C:∣z+2āˆ’3iāˆ£ā‰¤1}P = \{z \in \mathbb{C} : |z + 2 - 3i| \le 1\} and Q={z∈C:z(1+i)+zˉ(1āˆ’i)ā‰¤āˆ’8}Q = \{z \in \mathbb{C} : z(1 + i) + \bar{z}(1 - i) \le -8\}. Let in P∩QP \cap Q, ∣zāˆ’3+2i∣|z - 3 + 2i| be maximum and minimum at z1z_1 and z2z_2 respectively. If ∣z1∣2+2∣z2∣2=α+β2|z_1|^2 + 2|z_2|^2 = \alpha + \beta\sqrt{2}, where α,β\alpha, \beta are integers, then α+β\alpha + \beta equals ________.

Show answer

Answer: 36

Q38JEE Main 2024 Feb 1 Shift 2Medium

If zz is a complex number such that ∣zāˆ£ā‰„1|z| \geq 1, then the minimum value of ∣z+12(3+4i)∣\left|z+\frac{1}{2}(3+4i)\right| is :

  1. A

    32\frac{3}{2}

  2. B

    22

  3. C

    52\frac{5}{2}

  4. D

    33

Q39JEE Main 2024 Jan 27 Shift 1Easy

If S={z∈C:∣zāˆ’i∣=∣z+i∣=∣zāˆ’1∣}S = \{z \in \mathbf{C} : |z - i| = |z + i| = |z - 1|\}, then, n(S)n(S) is :

  1. A

    00

  2. B

    11

  3. C

    22

  4. D

    33

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Correct option: B

Q40JEE Main 2024 Jan 27 Shift 1MediumNumerical

If α\alpha satisfies the equation x2+x+1=0x^2 + x + 1 = 0 and (1+α)7=A+Bα+Cα2(1 + \alpha)^7 = A + B\alpha + C\alpha^2, A,B,C≄0A, B, C \geq 0, then 5(3Aāˆ’2Bāˆ’C)5(3A - 2B - C) is equal to ________.

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Answer: 5

Q41JEE Main 2024 Jan 29 Shift 1Medium

If z=12āˆ’2iz=\dfrac{1}{2}-2i is such that ∣z+1∣=αz+β(1+i)|z+1| = \alpha z + \beta(1+i), i=āˆ’1i=\sqrt{-1} and α,β∈R\alpha, \beta \in \mathbb{R}, then α+β\alpha + \beta is equal to

  1. A

    āˆ’1-1

  2. B

    22

  3. C

    33

  4. D

    āˆ’4-4

Show answer

Correct option: C

Q42JEE Main 2024 Jan 29 Shift 1MediumNumerical

Let α,β\alpha, \beta be the roots of the equation x2āˆ’x+2=0x^2 - x + 2 = 0 with Im(α)>Im(β)Im(\alpha) > Im(\beta).

Then α6+α4+β4āˆ’5α2\alpha^6 + \alpha^4 + \beta^4 - 5\alpha^2 is equal to __________.

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Answer: 13

Q43JEE Main 2024 Jan 30 Shift 1Medium

If z=x+iyz=x+\mathrm{i}y, xy≠0xy\neq 0, satisfies the equation z2+izˉ=0z^2+\mathrm{i}\bar{z}=0, then ∣z2∣|z^2| is equal to :

  1. A

    14\frac{1}{4}

  2. B

    11

  3. C

    44

  4. D

    99

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Correct option: B

Q44JEE Main 2024 Jan 30 Shift 2Medium

If zz is a complex number, then the number of common roots of the equations z1985+z100+1=0z^{1985}+z^{100}+1=0 and z3+2z2+2z+1=0z^3+2z^2+2z+1=0, is equal to

  1. A

    0

  2. B

    1

  3. C

    2

  4. D

    3

Show answer

Correct option: C

Q45JEE Main 2024 Jan 31 Shift 1HardNumerical

If α\alpha denotes the number of solutions of ∣1āˆ’i∣x=2x|1-i|^x=2^x and β=(∣z∣arg⁔(z))\beta=\left(\frac{|z|}{\arg(z)}\right), where z=Ļ€4(1+i)4[1āˆ’Ļ€ā€‰iĻ€+i+Ļ€āˆ’i1+π i]z=\frac{\pi}{4}(1+i)^4\left[\frac{1-\sqrt{\pi}\,i}{\sqrt{\pi}+i}+\frac{\sqrt{\pi}-i}{1+\sqrt{\pi}\,i}\right], i=āˆ’1i=\sqrt{-1}, then the distance of the point (α,β)(\alpha, \beta) from the line 4xāˆ’3y=74x-3y=7 is _____

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Answer: 3

Q46JEE Main 2024 Jan 31 Shift 2Medium

Let z1z_{1} and z2z_{2} be two complex numbers such that z1+z2=5z_{1}+z_{2}=5 and z13+z23=20+15iz_{1}^{3}+z_{2}^{3}=20+15 i. Then, ∣z14+z24∣\left|z_{1}^{4}+z_{2}^{4}\right| equals -

  1. A

    30330 \sqrt{3}

  2. B

    151515 \sqrt{15}

  3. C

    25325 \sqrt{3}

  4. D

    75

Show answer

Correct option: D