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Mathematics

Differential Equations — JEE Main PYQs

65 previous year questions

Q1JEE Main 2026 Apr 2 Shift 2Medium

Let x=x(y)x = x(y) be the solution of the differential equation 2y2dxdyāˆ’2xy+x2=02y^2\frac{dx}{dy} - 2xy + x^2 = 0, y>1y > 1, x(e)=ex(e) = e. Then x(e2)x(e^2) is equal to :

  1. A

    32e2\frac{3}{2}e^2

  2. B

    23e2\frac{2}{3}e^2

  3. C

    e2e^2

  4. D

    2e22e^2

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Correct option: B

Q2JEE Main 2026 Apr 4 Shift 1Medium

Let y=y(x)y = y(x) be the solution of the differential equation dydx=(1+x+x2)(1āˆ’y+y2)\frac{dy}{dx} = (1 + x + x^2)(1 - y + y^2), y(0)=12y(0) = \frac{1}{2}. Then (2y(1)āˆ’1)(2y(1) - 1) is equal to

  1. A

    3tan⁔(1136)\sqrt{3}\tan\left(\frac{11\sqrt{3}}{6}\right)

  2. B

    32tan⁔(11312)\frac{\sqrt{3}}{2}\tan\left(\frac{11\sqrt{3}}{12}\right)

  3. C

    3tan⁔(11312)\sqrt{3}\tan\left(\frac{11\sqrt{3}}{12}\right)

  4. D

    32tan⁔(1136)\frac{\sqrt{3}}{2}\tan\left(\frac{11\sqrt{3}}{6}\right)

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Correct option: C

Q3JEE Main 2026 Apr 4 Shift 2Hard

Let y=y(x)y = y(x) be the solution of the differential equation:

dydx+(6x2+(3x2+2x3+4)eāˆ’2x(x3+2)(2+eāˆ’2x))y=2+eāˆ’2x,\frac{dy}{dx} + \left(\frac{6x^2 + \left(3x^2 + 2x^3 + 4\right)e^{-2x}}{\left(x^3 + 2\right)\left(2 + e^{-2x}\right)}\right)y = 2 + e^{-2x},

x∈(āˆ’1,2)x \in (-1, 2), satisfying y(0)=32y(0) = \dfrac{3}{2}. If y(1)=α(2+eāˆ’2)y(1) = \alpha(2 + e^{-2}), α\alpha is equal to:

  1. A

    138\dfrac{13}{8}

  2. B

    613\dfrac{6}{13}

  3. C

    1213\dfrac{12}{13}

  4. D

    1312\dfrac{13}{12}

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Correct option: D

Q4JEE Main 2026 Apr 5 Shift 1HardNumerical

Let y=y(x)y = y(x) be the solution of the differential equation

xsin⁔(yx)dy=(ysin⁔(yx)āˆ’x)dx,y(1)=Ļ€2x \sin\left( \frac{y}{x} \right) dy = \left( y \sin\left( \frac{y}{x} \right) - x \right) dx, \quad y(1) = \frac{\pi}{2}

and let α=cos⁔(y(e12)e12)\alpha = \cos\left( \frac{y\left( e^{12} \right)}{e^{12}} \right). Then the number of integral values of pp, for which the equation x2+y2āˆ’2px+2py+α+2=0x^2 + y^2 - 2px + 2py + \alpha + 2 = 0 represents a circle of radius r≤6r \leq 6, is ________.

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Dropped — any non-negative integer accepted

Q5JEE Main 2026 Apr 5 Shift 2Hard

Let f:[1,āˆž)→Rf : [1, \infty) \to \mathbf{R} be a differentiable function defined as f(x)=∫1xf(t) dt+(1āˆ’x)(log⁔exāˆ’1)+ef(x) = \displaystyle\int_1^x f(t)\,dt + (1 - x)(\log_e x - 1) + e. Then the value of f(f(1))f(f(1)) is :

  1. A

    (1+ee)(1 + e^e)

  2. B

    (1+e)(1 + e)

  3. C

    (1+e+ee)(1 + e + e^e)

  4. D

    1+2e1 + 2e

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Correct option: A

Q6JEE Main 2026 Apr 5 Shift 2HardNumerical

Let y=y(x)y = y(x) be the solution of the differential equation

(tan⁔x)1/2 dy=(sec⁔3xāˆ’(tan⁔x)3/2 y)dx,ā€…ā€Š0<x<Ļ€2,ā€…ā€Šy(Ļ€4)=625.(\tan x)^{1/2}\,dy = \left(\sec^3 x - (\tan x)^{3/2}\,y\right)dx, \; 0 < x < \frac{\pi}{2}, \; y\left(\frac{\pi}{4}\right) = \frac{6\sqrt{2}}{5}.

If y(Ļ€3)=45 αy\left(\dfrac{\pi}{3}\right) = \dfrac{4}{5}\,\alpha, then α4\alpha^4 equals __________.

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Answer: 48

Q7JEE Main 2026 Apr 6 Shift 1HardNumerical

Let y=y(x)y=y(x) be the solution of the differential equation

(x2āˆ’xx2āˆ’1)dy+(y(xāˆ’x2āˆ’1)āˆ’x)dx=0,Ā x≄1.\left(x^2-x\sqrt{x^2-1}\right)dy+\left(y\left(x-\sqrt{x^2-1}\right)-x\right)dx=0,\ x \geq 1.

If y(1)=1y(1)=1, then the greatest integer less than y(5)y\left(\sqrt{5}\right) is ________.

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Answer: 3

Q8JEE Main 2026 Apr 6 Shift 2Hard

Let f:R→Rf: \mathbb{R} \to \mathbb{R} be such that f(xy)=f(x)f(y)f(xy) = f(x)f(y), for all x,y∈Rx, y \in \mathbb{R} and f(0)≠0f(0) \neq 0. Let g:[1,āˆž)→Rg : [1, \infty) \to \mathbb{R} be a differentiable function such that x2g(x)=∫1x(t2f(t)āˆ’t g(t))dt.x^2 g(x) = \int_1^x \left(t^2 f(t) - t\,g(t)\right) dt. Then g(2)g(2) is equal to :

  1. A

    138\frac{13}{8}

  2. B

    1116\frac{11}{16}

  3. C

    1532\frac{15}{32}

  4. D

    1764\frac{17}{64}

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Correct option: C

Q9JEE Main 2026 Apr 8 Shift 2Hard

Let y=y(x)y = y(x) be the solution of the differential equation

x1āˆ’x2 dy+(y1āˆ’x2āˆ’xcosā”āˆ’1x)dx=0,ā€…ā€Šx∈(0,1),ā€…ā€Šlim⁔x→1āˆ’y(x)=1.x\sqrt{1 - x^2}\, dy + \left(y\sqrt{1 - x^2} - x\cos^{-1}x\right)dx = 0,\; x \in (0, 1),\; \lim_{x \to 1^-} y(x) = 1.

Then y(12)y\left(\frac{1}{2}\right) equals :

  1. A

    3āˆ’Ļ€33 - \frac{\pi}{\sqrt{3}}

  2. B

    4āˆ’3 π4 - \sqrt{3}\,\pi

  3. C

    4āˆ’2Ļ€34 - \frac{2\pi}{\sqrt{3}}

  4. D

    3āˆ’Ļ€233 - \frac{\pi}{2\sqrt{3}}

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Correct option: A

Q10JEE Main 2025 Apr 2 Shift 1MediumNumerical

Let f:R→Rf : \mathbf{R} \to \mathbf{R} be a thrice differentiable odd function satisfying f′(x)≄0f'(x) \geq 0, f′′(x)=f(x)f''(x) = f(x), f(0)=0f(0) = 0, f′(0)=3f'(0) = 3. Then 9f(log⁔e3)9f(\log_\mathrm{e} 3) is equal to __________.

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Answer: 36

Q11JEE Main 2025 Apr 2 Shift 2Medium

Let f:[1,āˆž)→[2,āˆž)f: [1, \infty) \to [2, \infty) be a differentiable function. If 10∫1xf(t) dt=5xf(x)āˆ’x5āˆ’910\displaystyle\int_1^x f(\mathrm{t})\,\mathrm{dt}=5xf(x)-x^5-9 for all x⩾1x \geqslant 1, then the value of f(3)f(3) is :

  1. A

    18

  2. B

    22

  3. C

    26

  4. D

    32

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Correct option: D

Q12JEE Main 2025 Apr 2 Shift 2MediumNumerical

Let y=y(x)y=y(x) be the solution of the differential equation dydx+2ysec⁔2x=2sec⁔2x+3tan⁔xā‹…sec⁔2x\frac{\mathrm{d}y}{\mathrm{d}x}+2y\sec^2 x=2\sec^2 x+3\tan x \cdot \sec^2 x such that y(0)=54y(0)=\frac{5}{4}. Then 12(y(Ļ€4)āˆ’eāˆ’2)12\left(y\left(\frac{\pi}{4}\right)-\mathrm{e}^{-2}\right) is equal to _________.

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Answer: 21

Q13JEE Main 2025 Apr 3 Shift 1Medium

Let gg be a differentiable function such that ∫0xg(t) dt=xāˆ’āˆ«0xt g(t) dt\int_0^x g(t)\, dt = x - \int_0^x t\, g(t)\, dt, x≄0x \ge 0 and let y=y(x)y = y(x) satisfy the differential equation dydxāˆ’ytan⁔x=2(x+1)sec⁔xĀ g(x)\frac{dy}{dx} - y\tan x = 2(x+1)\sec x \ g(x), x∈[0,Ļ€2)x \in \left[0, \frac{\pi}{2}\right). If y(0)=0y(0) = 0, then y(Ļ€3)y\left(\frac{\pi}{3}\right) is equal to

  1. A

    4Ļ€3\frac{4\pi}{3}

  2. B

    2Ļ€3\frac{2\pi}{3}

  3. C

    2Ļ€33\frac{2\pi}{3\sqrt{3}}

  4. D

    4Ļ€33\frac{4\pi}{3\sqrt{3}}

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Correct option: A

Q14JEE Main 2025 Apr 3 Shift 2Medium

Let y=y(x)y = y(x) be the solution of the differential equation dydx+3(tan⁔2x)y+3y=sec⁔2x\dfrac{dy}{dx} + 3\left(\tan^2 x\right)y + 3y = \sec^2 x, y(0)=13+e3y(0) = \dfrac{1}{3} + e^3. Then y(Ļ€4)y\left(\dfrac{\pi}{4}\right) is equal to

  1. A

    23+e3\dfrac{2}{3} + e^3

  2. B

    43+e3\dfrac{4}{3} + e^3

  3. C

    23\dfrac{2}{3}

  4. D

    43\dfrac{4}{3}

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Correct option: D

Q15JEE Main 2025 Apr 4 Shift 1Hard

Let f:[0,āˆž)→Rf : [0, \infty) \to \mathbb{R} be a differentiable function such that f(x)=1āˆ’2x+∫0xexāˆ’tf(t) dtf(x) = 1 - 2x + \int\limits_{0}^{x} e^{x-t} f(t)\, dt for all x∈[0,āˆž)x \in [0, \infty). Then the area of the region bounded by y=f(x)y = f(x) and the coordinate axes is

  1. A

    2

  2. B

    2\sqrt{2}

  3. C

    12\frac{1}{2}

  4. D

    5\sqrt{5}

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Correct option: C

Q16JEE Main 2025 Apr 4 Shift 2Medium

If a curve y=y(x)y=y(x) passes through the point (1,Ļ€2)\left(1,\dfrac{\pi}{2}\right) and satisfies the differential equation (7x4cot⁔yāˆ’excosec⁔y)dxdy=x5\left(7x^4\cot y-\mathrm{e}^x\operatorname{cosec} y\right)\dfrac{\mathrm{d}x}{\mathrm{d}y}=x^5, x≄1x\geq 1, then at x=2x=2, the value of cos⁔y\cos y is :

  1. A

    2e2āˆ’e64\dfrac{2\mathrm{e}^2-\mathrm{e}}{64}

  2. B

    2e2āˆ’e128\dfrac{2\mathrm{e}^2-\mathrm{e}}{128}

  3. C

    2e2+e64\dfrac{2\mathrm{e}^2+\mathrm{e}}{64}

  4. D

    2e2+e128\dfrac{2\mathrm{e}^2+\mathrm{e}}{128}

Show answer

Correct option: B

Q17JEE Main 2025 Apr 7 Shift 1Hard

Let y=y(x)y = y(x) be the solution curve of the differential equation x(x2+ex)dy+(ex(xāˆ’2) yāˆ’x3)dx=0x\left(x^2 + e^x\right) dy + \left(e^x (x - 2)\, y - x^3\right) dx = 0, x>0x > 0, passing through the point (1,0)(1, 0). Then y(2)y(2) is equal to

  1. A

    44āˆ’e2\frac{4}{4 - e^2}

  2. B

    22āˆ’e2\frac{2}{2 - e^2}

  3. C

    44+e2\frac{4}{4 + e^2}

  4. D

    22+e2\frac{2}{2 + e^2}

Show answer

Correct option: C

Q18JEE Main 2025 Apr 7 Shift 2Medium

Let y=y(x)y = y(x) be the solution of the differential equation (x2+1)yā€²āˆ’2xy=(x4+2x2+1)cos⁔x(x^2 + 1)y' - 2xy = (x^4 + 2x^2 + 1)\cos x, y(0)=1y(0) = 1. Then āˆ«āˆ’33y(x) dx\int\limits_{-3}^{3} y(x)\, \mathrm{d}x is :

  1. A

    1818

  2. B

    2424

  3. C

    3030

  4. D

    3636

Show answer

Correct option: B

Q19JEE Main 2025 Apr 8 Shift 2Medium

Let f(x)=xāˆ’1f(x) = x - 1 and g(x)=exg(x) = e^x for x∈Rx \in \mathbb{R}. If dydx=(eāˆ’2x g(f(f(x)))āˆ’yx)\frac{dy}{dx} = \left(e^{-2\sqrt{x}}\, g\left(f\left(f(x)\right)\right) - \frac{y}{\sqrt{x}}\right), y(0)=0y(0) = 0, then y(1)y(1) is

  1. A

    eāˆ’1e4\frac{e-1}{e^4}

  2. B

    2eāˆ’1e3\frac{2e-1}{e^3}

  3. C

    1āˆ’e2e4\frac{1-e^2}{e^4}

  4. D

    1āˆ’e3e4\frac{1-e^3}{e^4}

Show answer

Correct option: A

Q20JEE Main 2025 Jan 22 Shift 1Medium

Let x=x(y)x=x(y) be the solution of the differential equation y2dx+(xāˆ’1y)dy=0y^2 dx+\left(x-\frac{1}{y}\right)dy=0. If x(1)=1x(1)=1, then x(12)x\left(\frac{1}{2}\right) is :

  1. A

    12+e\frac{1}{2}+e

  2. B

    3āˆ’e3-e

  3. C

    32+e\frac{3}{2}+e

  4. D

    3+e3+e

Show answer

Correct option: B

Q21JEE Main 2025 Jan 22 Shift 2Medium

If x=f(y)x = f(y) is the solution of the differential equation

(1+y2)+(xāˆ’2etanā”āˆ’1y)dydx=0,ā€…ā€Šy∈(āˆ’Ļ€2,Ļ€2)\left(1 + y^2\right) + \left(x - 2e^{\tan^{-1} y}\right) \dfrac{dy}{dx} = 0, \; y \in \left(-\dfrac{\pi}{2}, \dfrac{\pi}{2}\right)

with f(0)=1f(0) = 1, then f(13)f\left(\dfrac{1}{\sqrt{3}}\right) is equal to :

  1. A

    eπ/6e^{\pi/6}

  2. B

    eπ/12e^{\pi/12}

  3. C

    eπ/3e^{\pi/3}

  4. D

    eπ/4e^{\pi/4}

Show answer

Correct option: A

Q22JEE Main 2025 Jan 22 Shift 2HardNumerical

Let y=f(x)y = f(x) be the solution of the differential equation dydx+xyx2āˆ’1=x6+4x1āˆ’x2\dfrac{dy}{dx} + \dfrac{xy}{x^2 - 1} = \dfrac{x^6 + 4x}{\sqrt{1 - x^2}}, āˆ’1<x<1-1 < x < 1 such that f(0)=0f(0) = 0. If 6āˆ«āˆ’1/21/2f(x) dx=2Ļ€āˆ’Ī±6\displaystyle\int_{-1/2}^{1/2} f(x)\,dx = 2\pi - \alpha then α2\alpha^2 is equal to ________.

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Answer: 27

Q23JEE Main 2025 Jan 23 Shift 1Medium

Let a curve y=f(x)y = f(x) pass through the points (0,5)(0, 5) and (log⁔e2,k)(\log_e 2, k). If the curve satisfies the differential equation 2(3+y)e2xdxāˆ’(7+e2x)dy=02(3 + y)e^{2x}dx - (7 + e^{2x})dy = 0, then kk is equal to

  1. A

    44

  2. B

    88

  3. C

    1616

  4. D

    3232

Show answer

Correct option: B

Q24JEE Main 2025 Jan 23 Shift 2Hard

Let x=x(y)x = x(y) be the solution of the differential equation y=(xāˆ’ydxdy)sin⁔(xy)y = \left(x - y \dfrac{\mathrm{d}x}{\mathrm{d}y}\right) \sin\left(\dfrac{x}{y}\right), y>0y > 0 and x(1)=Ļ€2x(1) = \dfrac{\pi}{2}. Then cos⁔(x(2))\cos(x(2)) is equal to :

  1. A

    1āˆ’2(log⁔e2)21 - 2(\log_{\mathrm{e}} 2)^2

  2. B

    2(log⁔e2)2āˆ’12(\log_{\mathrm{e}} 2)^2 - 1

  3. C

    2(log⁔e2)āˆ’12(\log_{\mathrm{e}} 2) - 1

  4. D

    1āˆ’2(log⁔e2)1 - 2(\log_{\mathrm{e}} 2)

Show answer

Correct option: B

Q25JEE Main 2025 Jan 24 Shift 1Medium

Let y=y(x)y = y(x) be the solution of the differential equation (xyāˆ’5x21+x2)dx+(1+x2)dy=0\left(xy - 5x^2\sqrt{1+x^2}\right)dx + (1+x^2)dy = 0, y(0)=0y(0) = 0. Then y(3)y(\sqrt{3}) is equal to

  1. A

    532\frac{5\sqrt{3}}{2}

  2. B

    143\sqrt{\frac{14}{3}}

  3. C

    222\sqrt{2}

  4. D

    152\sqrt{\frac{15}{2}}

Show answer

Correct option: A

Q26JEE Main 2025 Jan 24 Shift 1MediumNumerical

Let f be a differentiable function such that 2(x+2)2f(x)āˆ’3(x+2)2=10∫0x(t+2)f(t) dt2(x+2)^2 f(x) - 3(x+2)^2 = 10\int_0^x (t+2)f(t)\,dt, x≄0x \geq 0. Then f(2)f(2) is equal to _____.

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Answer: 19

Q27JEE Main 2025 Jan 24 Shift 2Medium

Let f:(0,āˆž)→Rf : (0, \infty) \to \mathbf{R} be a function which is differentiable at all points of its domain and satisfies the condition x2f′(x)=2xf(x)+3x^2 f'(x) = 2xf(x) + 3, with f(1)=4f(1) = 4. Then 2f(2)2f(2) is equal to :

  1. A

    39

  2. B

    19

  3. C

    23

  4. D

    29

Show answer

Correct option: A

Q28JEE Main 2025 Jan 24 Shift 2MediumNumerical

Let y=y(x)y = y(x) be the solution of the differential equation 2cos⁔xdydx=sin⁔2xāˆ’4ysin⁔x2\cos x \dfrac{\mathrm{d}y}{\mathrm{d}x} = \sin 2x - 4y\sin x, x∈(0,Ļ€2)x \in \left(0, \dfrac{\pi}{2}\right). If y(Ļ€3)=0y\left(\dfrac{\pi}{3}\right) = 0, then y′(Ļ€4)+y(Ļ€4)y'\left(\dfrac{\pi}{4}\right) + y\left(\dfrac{\pi}{4}\right) is equal to __________.

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Answer: 1

Q29JEE Main 2025 Jan 28 Shift 1Medium

Let for some function y=f(x)y = f(x), ∫0xt f(t) dt=x2f(x)\int_0^x t\, f(t)\, dt = x^2 f(x), x>0x > 0 and f(2)=3f(2) = 3. Then f(6)f(6) is equal to

  1. A

    11

  2. B

    22

  3. C

    33

  4. D

    66

Show answer

Correct option: A

Q30JEE Main 2025 Jan 28 Shift 2MediumNumerical

If y=y(x)y = y(x) is the solution of the differential equation, 4āˆ’x2 dydx=((sinā”āˆ’1(x2))2āˆ’y)sinā”āˆ’1(x2)\sqrt{4 - x^2}\, \frac{\mathrm{d}y}{\mathrm{d}x} = \left(\left(\sin^{-1}\left(\frac{x}{2}\right)\right)^2 - y\right) \sin^{-1}\left(\frac{x}{2}\right), āˆ’2≤x≤2-2 \le x \le 2, y(2)=Ļ€2āˆ’84y(2) = \frac{\pi^2 - 8}{4}, then y2(0)y^2(0) is equal to __________.

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Answer: 4

Q31JEE Main 2024 Apr 4 Shift 1Medium

If the solution y=y(x)y=y(x) of the differential equation (x4+2x3+3x2+2x+2)dyāˆ’(2x2+2x+3)dx=0(x^{4}+2x^{3}+3x^{2}+2x+2)dy-(2x^{2}+2x+3)dx=0 satisfies y(āˆ’1)=āˆ’Ļ€4y(-1)=-\frac{\pi}{4}, then y(0)y(0) is equal to :

  1. A

    π4\frac{\pi}{4}

  2. B

    π2\frac{\pi}{2}

  3. C

    00

  4. D

    āˆ’Ļ€12-\frac{\pi}{12}

Show answer

Correct option: A

Q32JEE Main 2024 Apr 4 Shift 1MediumNumerical

Let the solution y=y(x)y=y(x) of the differential equation dydxāˆ’y=1+4sin⁔x\frac{dy}{dx}-y=1+4\sin x satisfy y(Ļ€)=1y(\pi)=1. Then y(Ļ€2)+10y\left(\frac{\pi}{2}\right)+10 is equal to ________.

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Answer: 7

Q33JEE Main 2024 Apr 4 Shift 2Medium

Let y=y(x)y = y(x) be the solution of the differential equation (x2+4)2dy+(2x3y+8xyāˆ’2)dx=0(x^2 + 4)^2 dy + (2x^3y + 8xy - 2)dx = 0. If y(0)=0y(0) = 0, then y(2)y(2) is equal to

  1. A

    π32\frac{\pi}{32}

  2. B

    π16\frac{\pi}{16}

  3. C

    π8\frac{\pi}{8}

  4. D

    2Ļ€2\pi

Show answer

Correct option: A

Q34JEE Main 2024 Apr 4 Shift 2HardNumerical

Let y=y(x)y = y(x) be the solution of the differential equation (x+y+2)2dx=dy(x + y + 2)^2 dx = dy, y(0)=āˆ’2y(0) = -2. Let the maximum and minimum values of the function y=y(x)y = y(x) in [0,Ļ€3]\left[0, \dfrac{\pi}{3}\right] be α\alpha and β\beta, respectively. If (3α+Ļ€)2+β2=γ+Ī“3,γ,Γ∈Z(3\alpha + \pi)^2 + \beta^2 = \gamma + \delta\sqrt{3}, \gamma, \delta \in \mathbb{Z}, then γ+Ī“\gamma + \delta equals ________

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Answer: 31

Q35JEE Main 2024 Apr 5 Shift 1Medium

If y=y(x)y = y(x) is the solution of the differential equation dydx+2y=sin⁔(2x)\dfrac{\mathrm{d}y}{\mathrm{d}x} + 2y = \sin(2x), y(0)=34y(0) = \dfrac{3}{4}, then y ⁣(Ļ€8)y\!\left(\dfrac{\pi}{8}\right) is equal to :

  1. A

    eāˆ’Ļ€/4e^{-\pi/4}

  2. B

    eπ/4e^{\pi/4}

  3. C

    eπ/8e^{\pi/8}

  4. D

    eāˆ’Ļ€/8e^{-\pi/8}

Show answer

Correct option: A

Q36JEE Main 2024 Apr 5 Shift 1HardNumerical

Let ff be a differentiable function in the interval (0,āˆž)(0, \infty) such that f(1)=1f(1) = 1 and lim⁔t→xt2f(x)āˆ’x2f(t)tāˆ’x=1\displaystyle\lim_{t \to x} \frac{t^2 f(x) - x^2 f(t)}{t - x} = 1 for each x>0x > 0. Then 2f(2)+3f(3)2f(2) + 3f(3) is equal to ________.

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Answer: 24

Q37JEE Main 2024 Apr 5 Shift 2Medium

The differential equation of the family of circles passing through the origin and having centre at the line y=xy = x is :

  1. A

    (x2āˆ’y2+2xy) dx=(x2āˆ’y2āˆ’2xy) dy(x^2 - y^2 + 2xy)\,\mathrm{d}x = (x^2 - y^2 - 2xy)\,\mathrm{d}y

  2. B

    (x2+y2āˆ’2xy) dx=(x2+y2+2xy) dy(x^2 + y^2 - 2xy)\,\mathrm{d}x = (x^2 + y^2 + 2xy)\,\mathrm{d}y

  3. C

    (x2āˆ’y2+2xy) dx=(x2āˆ’y2+2xy) dy(x^2 - y^2 + 2xy)\,\mathrm{d}x = (x^2 - y^2 + 2xy)\,\mathrm{d}y

  4. D

    (x2+y2+2xy) dx=(x2+y2āˆ’2xy) dy(x^2 + y^2 + 2xy)\,\mathrm{d}x = (x^2 + y^2 - 2xy)\,\mathrm{d}y

Show answer

Correct option: A

Q38JEE Main 2024 Apr 5 Shift 2HardNumerical

Let y=y(x)y = y(x) be the solution of the differential equation

dydx+2x(1+x2)2 y=x e1(1+x2);Ā y(0)=0.\dfrac{\mathrm{d}y}{\mathrm{d}x} + \dfrac{2x}{(1 + x^2)^2}\,y = x\,\mathrm{e}^{\frac{1}{(1 + x^2)}};\ y(0) = 0.

Then the area enclosed by the curve f(x)=y(x) eāˆ’1(1+x2)f(x) = y(x)\,\mathrm{e}^{-\frac{1}{(1 + x^2)}} and the line yāˆ’x=4y - x = 4 is ________.

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Answer: 18

Q39JEE Main 2024 Apr 6 Shift 1Medium

Let y=y(x)y = y(x) be the solution of the differential equation (1+x2)dydx+y=etanā”āˆ’1x\left(1 + x^2\right) \dfrac{dy}{dx} + y = e^{\tan^{-1} x}, y(1)=0y(1) = 0. Then y(0)y(0) is

  1. A

    12(eĻ€/2āˆ’1)\dfrac{1}{2}\left(e^{\pi/2} - 1\right)

  2. B

    14(eĻ€/2āˆ’1)\dfrac{1}{4}\left(e^{\pi/2} - 1\right)

  3. C

    12(1āˆ’eĻ€/2)\dfrac{1}{2}\left(1 - e^{\pi/2}\right)

  4. D

    14(1āˆ’eĻ€/2)\dfrac{1}{4}\left(1 - e^{\pi/2}\right)

Show answer

Correct option: C

Q40JEE Main 2024 Apr 6 Shift 1Medium

Let y=y(x)y = y(x) be the solution of the differential equation (2xlog⁔ex)dydx+2y=3xlog⁔ex(2x \log_e x) \dfrac{dy}{dx} + 2y = \dfrac{3}{x} \log_e x, x>0x > 0 and y(eāˆ’1)=0y(e^{-1}) = 0. Then, y(e)y(e) is equal to

  1. A

    āˆ’2e-\dfrac{2}{e}

  2. B

    āˆ’3e-\dfrac{3}{e}

  3. C

    āˆ’32e-\dfrac{3}{2e}

  4. D

    āˆ’23e-\dfrac{2}{3e}

Show answer

Correct option: B

Q41JEE Main 2024 Apr 6 Shift 2Hard

Suppose the solution of the differential equation dydx=(2+α)xāˆ’Ī²y+2βxāˆ’2αyāˆ’(Ī²Ī³āˆ’4α)\dfrac{\mathrm{d}y}{\mathrm{d}x} = \dfrac{(2+\alpha)x-\beta y+2}{\beta x-2\alpha y-(\beta\gamma-4\alpha)} represents a circle passing through origin. Then the radius of this circle is :

  1. A

    172\frac{\sqrt{17}}{2}

  2. B

    22

  3. C

    17\sqrt{17}

  4. D

    12\frac{1}{2}

Show answer

Correct option: A

Q42JEE Main 2024 Apr 6 Shift 2MediumNumerical

If the solution y(x)y(x) of the given differential equation (ey+1)cos⁔x dx+eysin⁔x dy=0(\mathrm{e}^y+1)\cos x\,\mathrm{d}x+\mathrm{e}^y \sin x\,\mathrm{d}y=0 passes through the point (Ļ€2,0)\left(\frac{\pi}{2}, 0\right), then the value of ey(Ļ€6)\mathrm{e}^{y\left(\frac{\pi}{6}\right)} is equal to ________.

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Answer: 3

Q43JEE Main 2024 Apr 8 Shift 1Medium

Let f(x)f(x) be a positive function such that the area bounded by y=f(x)y=f(x), y=0y=0 from x=0x=0 to x=a>0x=a>0 is eāˆ’a+4a2+aāˆ’1e^{-a}+4a^2+a-1. Then the differential equation, whose general solution is y=c1f(x)+c2y=c_1 f(x)+c_2, where c1c_1 and c2c_2 are arbitrary constants, is

  1. A

    (8exāˆ’1)d2ydx2āˆ’dydx=0\left(8e^{x}-1\right)\frac{d^2y}{dx^2}-\frac{dy}{dx}=0

  2. B

    (8exāˆ’1)d2ydx2+dydx=0\left(8e^{x}-1\right)\frac{d^2y}{dx^2}+\frac{dy}{dx}=0

  3. C

    (8ex+1)d2ydx2+dydx=0\left(8e^{x}+1\right)\frac{d^2y}{dx^2}+\frac{dy}{dx}=0

  4. D

    (8ex+1)d2ydx2āˆ’dydx=0\left(8e^{x}+1\right)\frac{d^2y}{dx^2}-\frac{dy}{dx}=0

Show answer

Correct option: C

Q44JEE Main 2024 Apr 8 Shift 1Medium

Let y=y(x)y=y(x) be the solution of the differential equation (1+y2)etan⁔x dx+cos⁔2x (1+e2tan⁔x) dy=0(1+y^2)e^{\tan x}\,dx+\cos^2 x\,(1+e^{2\tan x})\,dy=0, y(0)=1y(0)=1. Then y(Ļ€4)y\left(\frac{\pi}{4}\right) is equal to

  1. A

    1e2\frac{1}{e^2}

  2. B

    1e\frac{1}{e}

  3. C

    2e\frac{2}{e}

  4. D

    2e2\frac{2}{e^2}

Show answer

Correct option: B

Q45JEE Main 2024 Apr 8 Shift 2Medium

Let y=y(x)y = y(x) be the solution curve of the differential equation sec⁔ydydx+2xsin⁔y=x3cos⁔y\sec y \dfrac{\mathrm{d}y}{\mathrm{d}x} + 2x\sin y = x^3\cos y, y(1)=0y(1) = 0. Then y(3)y(\sqrt{3}) is equal to :

  1. A

    π12\dfrac{\pi}{12}

  2. B

    π6\dfrac{\pi}{6}

  3. C

    π4\dfrac{\pi}{4}

  4. D

    π3\dfrac{\pi}{3}

Show answer

Correct option: C

Q46JEE Main 2024 Apr 8 Shift 2HardNumerical

Let α∣x∣=∣y∣exyāˆ’Ī²\alpha|x| = |y|\mathrm{e}^{xy - \beta}, α,β∈N\alpha, \beta \in \mathbb{N} be the solution of the differential equation xdyāˆ’ydx+xy(xdy+ydx)=0x\mathrm{d}y - y\mathrm{d}x + xy(x\mathrm{d}y + y\mathrm{d}x) = 0, y(1)=2y(1) = 2. Then α+β\alpha + \beta is equal to ________

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Answer: 4

Q47JEE Main 2024 Apr 9 Shift 1Medium

The solution of the differential equation (x2+y2)dxāˆ’5xy dy=0(x^2+y^2)\mathrm{d}x-5xy\,\mathrm{d}y=0, y(1)=0y(1)=0, is :

  1. A

    ∣x2āˆ’2y2∣6=x\left|x^2-2y^2\right|^6=x

  2. B

    ∣x2āˆ’2y2∣5=x2\left|x^2-2y^2\right|^5=x^2

  3. C

    ∣x2āˆ’4y2∣6=x\left|x^2-4y^2\right|^6=x

  4. D

    ∣x2āˆ’4y2∣5=x2\left|x^2-4y^2\right|^5=x^2

Show answer

Correct option: D

Q48JEE Main 2024 Apr 9 Shift 1Medium

The solution curve, of the differential equation 2y dydx+3=5 dydx2y\,\frac{\mathrm{d}y}{\mathrm{d}x}+3=5\,\frac{\mathrm{d}y}{\mathrm{d}x}, passing through the point (0,1)(0, 1) is a conic, whose vertex lies on the line :

  1. A

    2x+3y=92x+3y=9

  2. B

    2x+3y=62x+3y=6

  3. C

    2x+3y=āˆ’62x+3y=-6

  4. D

    2x+3y=āˆ’92x+3y=-9

Show answer

Correct option: A

Q49JEE Main 2024 Apr 9 Shift 2Medium

Let ∫0x1āˆ’(y′(t))2 dt=∫0xy(t) dt\int_{0}^{x}\sqrt{1-\left(y'(t)\right)^2}\,dt=\int_{0}^{x} y(t)\,dt, 0≤x≤30 \le x \le 3, y≄0y \ge 0, y(0)=0y(0)=0. Then at x=2x=2, y′′+y+1y''+y+1 is equal to

  1. A

    11

  2. B

    1/21/2

  3. C

    2\sqrt{2}

  4. D

    22

Show answer

Correct option: A

Q50JEE Main 2024 Apr 9 Shift 2MediumNumerical

For a differentiable function f:R→Rf: \mathbb{R} \to \mathbb{R}, suppose f′(x)=3f(x)+αf'(x)=3f(x)+\alpha, where α∈R\alpha \in \mathbb{R}, f(0)=1f(0)=1 and lim⁔xā†’āˆ’āˆžf(x)=7\lim\limits_{x \to -\infty} f(x)=7. Then 9f(āˆ’log⁔e3)9f\left(-\log_e 3\right) is equal to ________.

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Answer: 61

Q51JEE Main 2024 Feb 1 Shift 1Hard

Let y=y(x)y = y(x) be the solution of the differential equation dydx=2x(x+y)3āˆ’x(x+y)āˆ’1\dfrac{dy}{dx} = 2x(x+y)^3 - x(x+y) - 1, y(0)=1y(0) = 1.

Then, (12+y(12))2\left(\dfrac{1}{\sqrt{2}} + y\left(\dfrac{1}{\sqrt{2}}\right)\right)^2 equals :

  1. A

    12āˆ’e\dfrac{1}{2 - \sqrt{e}}

  2. B

    21+e\dfrac{2}{1 + \sqrt{e}}

  3. C

    33āˆ’e\dfrac{3}{3 - \sqrt{e}}

  4. D

    44+e\dfrac{4}{4 + \sqrt{e}}

Show answer

Correct option: A

Q52JEE Main 2024 Feb 1 Shift 1MediumNumerical

If x=x(t)x = x(t) is the solution of the differential equation (t+1)dx=(2x+(t+1)4)dt(t + 1)dx = \left(2x + (t + 1)^4\right)dt, x(0)=2x(0) = 2, then, x(1)x(1) equals ________.

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Answer: 14

Q53JEE Main 2024 Feb 1 Shift 2Medium

Let α\alpha be a non-zero real number. Suppose f:R→Rf: \mathbf{R} \to \mathbf{R} is a differentiable function such that f(0)=2f(0)=2 and lim⁔xā†’āˆ’āˆžf(x)=1\lim_{x \to -\infty} f(x)=1. If f′(x)=αf(x)+3f'(x)=\alpha f(x)+3, for all x∈Rx \in \mathbf{R}, then f(āˆ’log⁔e2)f(-\log_e 2) is equal to ________.

  1. A

    33

  2. B

    55

  3. C

    77

  4. D

    99

Q54JEE Main 2024 Feb 1 Shift 2MediumNumerical

If dxdy=1+xāˆ’y2y\frac{\mathrm{d}x}{\mathrm{d}y}=\frac{1+x-y^2}{y}, x(1)=1x(1)=1, then 5x(2)5x(2) is equal to __________.

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Answer: 5

Q55JEE Main 2024 Jan 27 Shift 1Medium

Let x=x(t)x = x(t) and y=y(t)y = y(t) be solutions of the differential equations dxdt+ax=0\dfrac{dx}{dt} + ax = 0 and dydt+by=0\dfrac{dy}{dt} + by = 0 respectively, a,b∈Ra, b \in \mathbf{R}. Given that x(0)=2x(0) = 2; y(0)=1y(0) = 1 and 3y(1)=2x(1)3y(1) = 2x(1), the value of tt, for which x(t)=y(t)x(t) = y(t), is :

  1. A

    log⁔232\log_{\frac{2}{3}} 2

  2. B

    log⁔43\log_4 3

  3. C

    log⁔432\log_{\frac{4}{3}} 2

  4. D

    log⁔34\log_3 4

Show answer

Correct option: C

Q56JEE Main 2024 Jan 27 Shift 1MediumNumerical

If the solution of the differential equation (2x+3yāˆ’2) dx+(4x+6yāˆ’7) dy=0(2x + 3y - 2)\, dx + (4x + 6y - 7)\, dy = 0, y(0)=3y(0) = 3, is αx+βy+3log⁔e∣2x+3yāˆ’Ī³āˆ£=6\alpha x + \beta y + 3 \log_e |2x + 3y - \gamma| = 6, then α+2β+3γ\alpha + 2\beta + 3\gamma is equal to ________.

Show answer

Answer: 29

Q57JEE Main 2024 Jan 29 Shift 1Medium

A function y=f(x)y=f(x) satisfies f(x)sin⁔2x+sin⁔xāˆ’(1+cos⁔2x)f′(x)=0f(x)\sin 2x + \sin x - \left(1+\cos^2 x\right)f'(x) = 0 with condition f(0)=0f(0)=0. Then, f(Ļ€2)f\left(\dfrac{\pi}{2}\right) is equal to

  1. A

    00

  2. B

    11

  3. C

    āˆ’1-1

  4. D

    22

Show answer

Correct option: B

Q58JEE Main 2024 Jan 29 Shift 1HardNumerical

If the solution curve y=y(x)y=y(x) of the differential equation (1+y2)(1+log⁔ex) dx+x dy=0(1+y^2)(1+\log_e x)\,dx + x\,dy = 0, x>0x > 0 passes through the point (1,1)(1,1) and y(e)=Ī±āˆ’tan⁔(32)β+tan⁔(32)y(e) = \dfrac{\alpha - \tan\left(\dfrac{3}{2}\right)}{\beta + \tan\left(\dfrac{3}{2}\right)}, then α+2β\alpha + 2\beta is __________.

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Answer: 3

Q59JEE Main 2024 Jan 30 Shift 1Medium

Let y=y(x)y=y(x) be the solution of the differential equation sec⁔x dy+{2(1āˆ’x)tan⁔x+x(2āˆ’x)} dx=0\sec x\,\mathrm{d}y+\{2(1-x)\tan x+x(2-x)\}\,\mathrm{d}x=0 such that y(0)=2y(0)=2. Then y(2)y(2) is equal to :

  1. A

    11

  2. B

    22

  3. C

    2{sin⁔(2)+1}2\{\sin(2)+1\}

  4. D

    2{1āˆ’sin⁔(2)}2\{1-\sin(2)\}

Show answer

Correct option: B

Q60JEE Main 2024 Jan 30 Shift 1HardNumerical

Let y=y(x)y=y(x) be the solution of the differential equation (1āˆ’x2) dy=[xy+(x3+2)3(1āˆ’x2)]dx(1-x^2)\,\mathrm{d}y=\left[xy+(x^3+2)\sqrt{3(1-x^2)}\right]\mathrm{d}x, āˆ’1<x<1-1<x<1, y(0)=0y(0)=0. If y(12)=mny\left(\frac{1}{2}\right)=\frac{m}{n}, mm and nn are co-prime numbers, then m+nm+n is equal to ________.

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Answer: 97

Q61JEE Main 2024 Jan 30 Shift 2HardNumerical

Let Y=Y(X)Y=Y(X) be a curve lying in the first quadrant such that the area enclosed by the line Yāˆ’y=Y′(x)(Xāˆ’x)Y-y=Y'(x)(X-x) and the co-ordinate axes, where (x,y)(x, y) is any point on the curve, is always āˆ’y22Y′(x)+1,Ā Y′(x)≠0\frac{-y^2}{2Y'(x)}+1,\ Y'(x)\neq 0. If Y(1)=1Y(1)=1, then 12Y(2)12Y(2) equals _______.

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Answer: 20

Q62JEE Main 2024 Jan 31 Shift 1Medium

Let y=y(x)y=y(x) be the solution of the differential equation dydx=(tan⁔x)+ysin⁔x(sec⁔xāˆ’sin⁔xtan⁔x),x∈(0,Ļ€2)\frac{dy}{dx}=\frac{(\tan x)+y}{\sin x(\sec x-\sin x \tan x)}, x \in \left(0, \frac{\pi}{2}\right) satisfying the condition y(Ļ€4)=2y\left(\frac{\pi}{4}\right)=2. Then, y(Ļ€3)y\left(\frac{\pi}{3}\right) is

  1. A

    3(2+log⁔e3)\sqrt{3}(2+\log_e 3)

  2. B

    32(2+log⁔e3)\frac{\sqrt{3}}{2}(2+\log_e 3)

  3. C

    3(2+log⁔e3)\sqrt{3}(2+\log_e \sqrt{3})

  4. D

    3(1+2log⁔e3)\sqrt{3}(1+2\log_e 3)

Show answer

Correct option: C

Q63JEE Main 2024 Jan 31 Shift 1Medium

The solution curve of the differential equation ydxdy=x(log⁔exāˆ’log⁔ey+1),x>0,y>0y\frac{dx}{dy}=x(\log_e x-\log_e y+1), x>0, y>0 passing through the point (e,1)(e, 1) is

  1. A

    2∣log⁔exy∣=y+12\left|\log_e \frac{x}{y}\right|=y+1

  2. B

    ∣log⁔eyx∣=y2\left|\log_e \frac{y}{x}\right|=y^2

  3. C

    ∣log⁔eyx∣=x\left|\log_e \frac{y}{x}\right|=x

  4. D

    ∣log⁔exy∣=y\left|\log_e \frac{x}{y}\right|=y

Show answer

Correct option: D

Q64JEE Main 2024 Jan 31 Shift 2Medium

The temperature T(t)T(t) of a body at time t=0t=0 is 160∘F160^{\circ} \mathrm{F} and it decreases continuously as per the differential equation dTdt=āˆ’K(Tāˆ’80)\frac{d T}{d t}=-K(T-80), where KK is a positive constant. If T(15)=120∘FT(15)=120^{\circ} \mathrm{F}, then T(45)T(45) is equal to

  1. A

    80∘F80^{\circ} \mathrm{F}

  2. B

    85∘F85^{\circ} \mathrm{F}

  3. C

    90∘F90^{\circ} \mathrm{F}

  4. D

    95∘F95^{\circ} \mathrm{F}

Show answer

Correct option: C

Q65JEE Main 2024 Jan 31 Shift 2HardNumerical

Let y=y(x)y=y(x) be the solution of the differential equation sec⁔2xĀ dx+(e2ytan⁔2x+tan⁔x)dy=0\sec ^{2} x\ d x+\left(e^{2 y} \tan ^{2} x+\tan x\right) d y=0, 0<x<Ļ€20<x<\frac{\pi}{2}, y(Ļ€/4)=0y\left(\pi / 4\right)=0. If y(Ļ€/6)=αy\left(\pi / 6\right)=\alpha, then e8αe^{8 \alpha} is equal to _______.

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Answer: 9