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Differentiation and Applications of Derivatives — JEE Main PYQs

50 previous year questions

Q1JEE Main 2026 Apr 2 Shift 2Medium

Let f(x)f(x) be a polynomial of degree 5, and have extrema at x=1x = 1 and x=āˆ’1x = -1. If lim⁔x→0(f(x)x3)=āˆ’5\lim_{x \to 0}\left(\frac{f(x)}{x^3}\right) = -5, then f(2)āˆ’f(āˆ’2)f(2) - f(-2) is equal to :

  1. A

    00

  2. B

    5050

  3. C

    9292

  4. D

    112112

Show answer

Correct option: D

Q2JEE Main 2026 Apr 4 Shift 1Medium

If y=tanā”āˆ’1(3cos⁔xāˆ’4sin⁔x4cos⁔x+3sin⁔x)+2tanā”āˆ’1(x1+1āˆ’x2)y = \tan^{-1}\left(\frac{3\cos x - 4\sin x}{4\cos x + 3\sin x}\right) + 2\tan^{-1}\left(\frac{x}{1+\sqrt{1-x^2}}\right), then dydx\frac{dy}{dx} at x=32x = \frac{\sqrt{3}}{2} is equal to:

  1. A

    33

  2. B

    āˆ’1-1

  3. C

    11

  4. D

    22

Show answer

Correct option: C

Q3JEE Main 2026 Apr 4 Shift 1Medium

Let ff be a real polynomial of degree nn such that f(x)=f′(x) f′′(x)f(x) = f'(x)\, f''(x), for all x∈Rx \in \mathbb{R}. If f(0)=0f(0) = 0, then 36(f′(2)+f′′(2)+∫02f(x) dx)36\left(f'(2) + f''(2) + \int_0^2 f(x)\,dx\right) is equal to:

  1. A

    4242

  2. B

    4646

  3. C

    5656

  4. D

    6666

Show answer

Correct option: C

Q4JEE Main 2026 Apr 4 Shift 2Medium

max⁔0≤x≤π(16sin⁔(x2)cos⁔3(x2))\displaystyle\max_{0 \le x \le \pi}\left(16\sin\left(\frac{x}{2}\right)\cos^3\left(\frac{x}{2}\right)\right) is equal to:

  1. A

    332\dfrac{3\sqrt{3}}{2}

  2. B

    333\sqrt{3}

  3. C

    434\sqrt{3}

  4. D

    636\sqrt{3}

Show answer

Correct option: B

Q5JEE Main 2026 Apr 5 Shift 1Medium

Let f:R→Rf: \mathbb{R} \to \mathbb{R} be a differentiable function such that f(x+y3)=f(x)+f(y)3f\left( \frac{x+y}{3} \right) = \frac{f(x) + f(y)}{3} for all x,y∈Rx, y \in \mathbb{R}, and f′(0)=3f'(0) = 3. Then the minimum value of the function g(x)=3+exf(x)g(x) = 3 + e^x f(x), is:

  1. A

    3(e+1e)3\left( \frac{e+1}{e} \right)

  2. B

    3(eāˆ’1e)3\left( \frac{e-1}{e} \right)

  3. C

    3āˆ’ee\frac{3-e}{e}

  4. D

    3e3e

Show answer

Correct option: B

Q6JEE Main 2026 Apr 5 Shift 2Medium

Let f(x)f(x) and g(x)g(x) be twice differentiable functions satisfying f′′(x)=g′′(x)f''(x) = g''(x) for all x∈Rx \in \mathbf{R}, f′(1)=2g′(1)=4f'(1) = 2g'(1) = 4 and g(2)=3f(2)=9g(2) = 3f(2) = 9. Then f(25)āˆ’g(25)f(25) - g(25) is equal to :

  1. A

    20

  2. B

    40

  3. C

    āˆ’20-20

  4. D

    āˆ’40-40

Show answer

Correct option: B

Q7JEE Main 2025 Apr 2 Shift 1Medium

If the function f(x)=2x3āˆ’9ax2+12a2x+1f(x) = 2x^3 - 9ax^2 + 12a^2x + 1, where a>0a > 0, attains its local maximum and local minimum values at pp and qq, respectively, such that p2=qp^2 = q, then f(3)f(3) is equal to :

  1. A

    37

  2. B

    55

  3. C

    10

  4. D

    23

Show answer

Correct option: A

Q8JEE Main 2025 Apr 2 Shift 1Hard

Let f:R→Rf: \mathbf{R} \to \mathbf{R} be a twice differentiable function such that (sin⁔xcos⁔y)(f(2x+2y)āˆ’f(2xāˆ’2y))=(cos⁔xsin⁔y)(f(2x+2y)+f(2xāˆ’2y))(\sin x \cos y)(f(2x + 2y) - f(2x - 2y)) = (\cos x \sin y)(f(2x + 2y) + f(2x - 2y)), for all x,y∈Rx, y \in \mathbf{R}. If f′(0)=12f'(0) = \frac{1}{2}, then the value of 24f′′(5Ļ€3)24 f''\left(\frac{5\pi}{3}\right) is :

  1. A

    3

  2. B

    āˆ’3-3

  3. C

    2

  4. D

    āˆ’2-2

Show answer

Correct option: B

Q9JEE Main 2025 Apr 3 Shift 2Medium

Let f:R→Rf : \mathrm{R} \to \mathrm{R} be a function defined by f(x)=āˆ£ā€‰āˆ£x+2āˆ£āˆ’2∣xāˆ£ā€‰āˆ£f(x) = \big|\,|x + 2| - 2|x|\,\big|. If mm is the number of points of local minima and nn is the number of points of local maxima of ff, then m+nm + n is

  1. A

    5

  2. B

    2

  3. C

    3

  4. D

    4

Show answer

Correct option: C

Q10JEE Main 2025 Apr 4 Shift 2Medium

Let a>0\mathrm{a}>0. If the function f(x)=6x3āˆ’45ax2+108a2x+1f(x)=6x^3-45\mathrm{a}x^2+108\mathrm{a}^2x+1 attains its local maximum and minimum values at the points x1x_1 and x2x_2 respectively such that x1x2=54x_1x_2=54, then a+x1+x2\mathrm{a}+x_1+x_2 is equal to :

  1. A

    1313

  2. B

    1515

  3. C

    1818

  4. D

    2424

Show answer

Correct option: C

Q11JEE Main 2025 Apr 7 Shift 1Hard

Let x=āˆ’1x = -1 and x=2x = 2 be the critical points of the function f(x)=x3+ax2+blog⁔e∣x∣+1f(x) = x^3 + ax^2 + b \log_e |x| + 1, x≠0x \neq 0. Let mm and MM respectively be the absolute minimum and the absolute maximum values of ff in the interval [āˆ’2,āˆ’12]\left[-2, -\frac{1}{2}\right]. Then ∣M+m∣|M + m| is equal to (Take log⁔e2=0.7\log_e 2 = 0.7) :

  1. A

    19.8

  2. B

    20.9

  3. C

    21.1

  4. D

    22.1

Show answer

Correct option: C

Q12JEE Main 2025 Apr 7 Shift 2Medium

Let f:R→Rf : \mathbf{R} \to \mathbf{R} be a polynomial function of degree four having extreme values at x=4x = 4 and x=5x = 5. If lim⁔x→0f(x)x2=5\lim\limits_{x \to 0} \dfrac{f(x)}{x^2} = 5, then f(2)f(2) is equal to :

  1. A

    88

  2. B

    1010

  3. C

    1212

  4. D

    1414

Show answer

Correct option: B

Q13JEE Main 2025 Apr 8 Shift 2Medium

Let the function f(x)=x3+3x+3f(x) = \frac{x}{3} + \frac{3}{x} + 3, x≠0x \neq 0 be strictly increasing in (āˆ’āˆž,α1)∪(α2,āˆž)(-\infty, \alpha_1) \cup (\alpha_2, \infty) and strictly decreasing in (α3,α4)∪(α4,α5)(\alpha_3, \alpha_4) \cup (\alpha_4, \alpha_5). Then āˆ‘i=15αi2\sum\limits_{i=1}^{5} \alpha_i^2 is equal to

  1. A

    28

  2. B

    36

  3. C

    40

  4. D

    48

Show answer

Correct option: B

Q14JEE Main 2025 Jan 22 Shift 2Medium

Let f(x)=∫0x2t2āˆ’8t+15et dtf(x) = \displaystyle\int_{0}^{x^2} \dfrac{t^2 - 8t + 15}{e^t} \, dt, x∈Rx \in \mathbb{R}. Then the numbers of local maximum and local minimum points of ff, respectively, are :

  1. A

    3 and 2

  2. B

    2 and 3

  3. C

    2 and 2

  4. D

    1 and 3

Show answer

Correct option: B

Q15JEE Main 2025 Jan 23 Shift 2Medium

A spherical chocolate ball has a layer of ice-cream of uniform thickness around it. When the thickness of the ice-cream layer is 1 cm, the ice-cream melts at the rate of 81Ā cm3/min81\ \mathrm{cm}^3/\text{min} and the thickness of the ice-cream layer decreases at the rate of 14Ļ€\dfrac{1}{4\pi} cm/min. The surface area (in cm2\mathrm{cm}^2) of the chocolate ball (without the ice-cream layer) is :

  1. A

    196 π196\ \pi

  2. B

    128 π128\ \pi

  3. C

    256 π256\ \pi

  4. D

    225 π225\ \pi

Show answer

Correct option: C

Q16JEE Main 2025 Jan 24 Shift 1Hard

Consider the region R={(x,y):x≤y≤9āˆ’113x2,x≄0}R=\left\{(x, y): x \leq y \leq 9-\frac{11}{3}x^2, x \geq 0\right\}.

The area, of the largest rectangle of sides parallel to the coordinate axes and inscribed in R, is:

  1. A

    567121\frac{567}{121}

  2. B

    625111\frac{625}{111}

  3. C

    730119\frac{730}{119}

  4. D

    821123\frac{821}{123}

Show answer

Correct option: A

Q17JEE Main 2025 Jan 24 Shift 2Hard

Let (2,3)(2, 3) be the largest open interval in which the function f(x)=2log⁔e(xāˆ’2)āˆ’x2+ax+1f(x) = 2\log_e(x - 2) - x^2 + \mathrm{a}x + 1 is strictly increasing and (b,c)(\mathrm{b}, \mathrm{c}) be the largest open interval, in which the function g(x)=(xāˆ’1)3(x+2āˆ’a)2\mathrm{g}(x) = (x-1)^3(x + 2 - \mathrm{a})^2 is strictly decreasing. Then 100(a+bāˆ’c)100(\mathrm{a} + \mathrm{b} - \mathrm{c}) is equal to :

  1. A

    160

  2. B

    280

  3. C

    360

  4. D

    420

Show answer

Correct option: C

Q18JEE Main 2025 Jan 28 Shift 1Hard

The sum of all local minimum values of the function f(x)={1āˆ’2x,x<āˆ’113(7+2∣x∣),āˆ’1≤x≤21118(xāˆ’4)(xāˆ’5),x>2f(x) = \begin{cases} 1 - 2x, & x < -1 \\ \frac{1}{3}(7 + 2|x|), & -1 \le x \le 2 \\ \frac{11}{18}(x-4)(x-5), & x > 2 \end{cases} is

  1. A

    16772\frac{167}{72}

  2. B

    13172\frac{131}{72}

  3. C

    15772\frac{157}{72}

  4. D

    17172\frac{171}{72}

Show answer

Correct option: C

Q19JEE Main 2024 Apr 4 Shift 1Medium

Let f(x)=x5+2ex/4f(x)=x^{5}+2e^{x/4} for all x∈Rx \in \mathbf{R}. Consider a function g(x)g(x) such that (g∘f)(x)=x(g \circ f)(x)=x for all x∈Rx \in \mathbf{R}. Then the value of 8g′(2)8g'(2) is :

  1. A

    22

  2. B

    44

  3. C

    88

  4. D

    1616

Show answer

Correct option: D

Q20JEE Main 2024 Apr 4 Shift 1Medium

Let the sum of the maximum and the minimum values of the function f(x)=2x2āˆ’3x+82x2+3x+8f(x)=\frac{2x^{2}-3x+8}{2x^{2}+3x+8} be mn\frac{m}{n}, where gcd⁔(m,n)=1\gcd(m, n)=1. Then m+nm+n is equal to :

  1. A

    182182

  2. B

    195195

  3. C

    201201

  4. D

    217217

Show answer

Correct option: C

Q21JEE Main 2024 Apr 4 Shift 2Medium

Let f(x)=3xāˆ’2+4āˆ’xf(x) = 3\sqrt{x-2} + \sqrt{4-x} be a real valued function. If α\alpha and β\beta are respectively the minimum and the maximum values of ff, then α2+2β2\alpha^2 + 2\beta^2 is equal to

  1. A

    2424

  2. B

    3838

  3. C

    4444

  4. D

    4242

Q22JEE Main 2024 Apr 4 Shift 2HardNumerical

Let f:R→Rf : \mathbb{R} \to \mathbb{R} be a thrice differentiable function such that f(0)=0,f(1)=1,f(2)=āˆ’1,f(3)=2f(0) = 0, f(1) = 1, f(2) = -1, f(3) = 2 and f(4)=āˆ’2f(4) = -2. Then, the minimum number of zeros of (3f′f′′+ff′′′)(x)(3f'f'' + ff''')(x) is ___________

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Answer: 5

Q23JEE Main 2024 Apr 5 Shift 1Medium

For the function f(x)=sin⁔x+3xāˆ’2Ļ€(x2+x),Ā whereĀ x∈[0,Ļ€2],f(x) = \sin x + 3x - \frac{2}{\pi}(x^2 + x), \text{ where } x \in \left[0, \frac{\pi}{2}\right], consider the following two statements :

(I) ff is increasing in (0,Ļ€2)\left(0, \frac{\pi}{2}\right).

(II) f′f' is decreasing in (0,Ļ€2)\left(0, \frac{\pi}{2}\right).

Between the above two statements,

  1. A

    only (I) is true.

  2. B

    only (II) is true.

  3. C

    neither (I) nor (II) is true.

  4. D

    both (I) and (II) are true.

Show answer

Correct option: D

Q24JEE Main 2024 Apr 5 Shift 1Medium

Let f(x)=x5+2x3+3x+1f(x) = x^5 + 2x^3 + 3x + 1, x∈Rx \in \mathbb{R}, and g(x)g(x) be a function such that g(f(x))=xg(f(x)) = x for all x∈Rx \in \mathbb{R}. Then g(7)g′(7)\dfrac{g(7)}{g'(7)} is equal to :

  1. A

    11

  2. B

    77

  3. C

    1414

  4. D

    4242

Show answer

Correct option: C

Q25JEE Main 2024 Apr 5 Shift 1Hard

Let a rectangle ABCD of sides 2 and 4 be inscribed in another rectangle PQRS such that the vertices of the rectangle ABCD lie on the sides of the rectangle PQRS. Let a and b be the sides of the rectangle PQRS when its area is maximum. Then (a+b)2(a+b)^2 is equal to :

  1. A

    7272

  2. B

    6464

  3. C

    8080

  4. D

    6060

Show answer

Correct option: A

Q26JEE Main 2024 Apr 5 Shift 2Medium

If y(Īø)=2cos⁔θ+cos⁔2Īøcos⁔3Īø+4cos⁔2Īø+5cos⁔θ+2y(\theta) = \dfrac{2\cos\theta + \cos 2\theta}{\cos 3\theta + 4\cos 2\theta + 5\cos\theta + 2}, then at Īø=Ļ€2\theta = \dfrac{\pi}{2}, y′′+y′+yy'' + y' + y is equal to :

  1. A

    12\dfrac{1}{2}

  2. B

    1

  3. C

    32\dfrac{3}{2}

  4. D

    2

Show answer

Correct option: D

Q27JEE Main 2024 Apr 5 Shift 2HardNumerical

Let the maximum and minimum values of (8xāˆ’x2āˆ’12āˆ’4)2+(xāˆ’7)2\left(\sqrt{8x - x^2 - 12} - 4\right)^2 + (x - 7)^2, x∈Rx \in \mathbf{R} be MM and mm, respectively. Then M2āˆ’m2M^2 - m^2 is equal to ________.

Show answer

Answer: 1600

Q28JEE Main 2024 Apr 6 Shift 1Easy

The interval in which the function f(x)=xxf(x) = x^x, x>0x > 0, is strictly increasing is

  1. A

    [1e,āˆž)\left[\dfrac{1}{e}, \infty\right)

  2. B

    (0,1e]\left(0, \dfrac{1}{e}\right]

  3. C

    [1e2,1)\left[\dfrac{1}{e^2}, 1\right)

  4. D

    (0,āˆž)(0, \infty)

Show answer

Correct option: A

Q29JEE Main 2024 Apr 6 Shift 2Medium

If the function f(x)=(1x)2x;Ā x>0f(x)=\left(\frac{1}{x}\right)^{2x};\ x>0 attains the maximum value at x=1ex=\frac{1}{\mathrm{e}} then :

  1. A

    eπ>πe\mathrm{e}^{\pi} > \pi^{\mathrm{e}}

  2. B

    eπ<πe\mathrm{e}^{\pi} < \pi^{\mathrm{e}}

  3. C

    e2Ļ€<(2Ļ€)e\mathrm{e}^{2\pi} < (2\pi)^{\mathrm{e}}

  4. D

    (2e)Ļ€>Ļ€(2e)(2\mathrm{e})^{\pi} > \pi^{(2\mathrm{e})}

Show answer

Correct option: A

Q30JEE Main 2024 Apr 6 Shift 2Medium

Suppose for a differentiable function hh, h(0)=0h(0)=0, h(1)=1h(1)=1 and h′(0)=h′(1)=2h'(0)=h'(1)=2. If g(x)=h(ex)eh(x)g(x)=h(\mathrm{e}^x)\mathrm{e}^{h(x)}, then g′(0)g'(0) is equal to :

  1. A

    33

  2. B

    44

  3. C

    55

  4. D

    88

Show answer

Correct option: B

Q31JEE Main 2024 Apr 8 Shift 1Medium

For the function f(x)=(cos⁔x)āˆ’x+1f(x)=(\cos x)-x+1, x∈Rx\in\mathbb{R}, between the following two statements

(S1) f(x)=0f(x)=0 for only one value of xx in [0,Ļ€][0,\pi].

(S2) f(x)f(x) is decreasing in [0,Ļ€2]\left[0,\frac{\pi}{2}\right] and increasing in [Ļ€2,Ļ€]\left[\frac{\pi}{2},\pi\right].

  1. A

    Both (S1) and (S2) are correct.

  2. B

    Only (S1) is correct.

  3. C

    Only (S2) is correct.

  4. D

    Both (S1) and (S2) are incorrect.

Show answer

Correct option: B

Q32JEE Main 2024 Apr 8 Shift 1Medium

The number of critical points of the function f(x)=(xāˆ’2)2/3(2x+1)f(x)=(x-2)^{2/3}(2x+1) is

  1. A

    0

  2. B

    1

  3. C

    2

  4. D

    3

Show answer

Correct option: C

Q33JEE Main 2024 Apr 8 Shift 1Medium

Let f(x)=4cos⁔3x+33cos⁔2xāˆ’10f(x)=4\cos^3 x+3\sqrt{3}\cos^2 x-10. The number of points of local maxima of ff in interval (0,2Ļ€)(0, 2\pi) is

  1. A

    1

  2. B

    2

  3. C

    3

  4. D

    4

Show answer

Correct option: B

Q34JEE Main 2024 Apr 8 Shift 2Medium

If the function f(x)=2x3āˆ’9ax2+12a2x+1f(x) = 2x^3 - 9ax^2 + 12a^2x + 1, a>0a > 0 has a local maximum at x=αx = \alpha and a local minimum at x=α2x = \alpha^2, then α\alpha and α2\alpha^2 are the roots of the equation :

  1. A

    8x2āˆ’6x+1=08x^2 - 6x + 1 = 0

  2. B

    8x2+6xāˆ’1=08x^2 + 6x - 1 = 0

  3. C

    x2āˆ’6x+8=0x^2 - 6x + 8 = 0

  4. D

    x2+6x+8=0x^2 + 6x + 8 = 0

Show answer

Correct option: C

Q35JEE Main 2024 Apr 8 Shift 2MediumNumerical

Let A be the region enclosed by the parabola y2=2xy^2 = 2x and the line x=24x = 24. Then the maximum area of the rectangle inscribed in the region A is ________.

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Answer: 128

Q36JEE Main 2024 Apr 9 Shift 1Easy

Let f(x)=ax3+bx2+cx+41f(x)=ax^3+bx^2+cx+41 be such that f(1)=40f(1)=40, f′(1)=2f'(1)=2 and f′′(1)=4f''(1)=4. Then a2+b2+c2a^2+b^2+c^2 is equal to :

  1. A

    5151

  2. B

    5454

  3. C

    6262

  4. D

    7373

Show answer

Correct option: A

Q37JEE Main 2024 Apr 9 Shift 1HardNumerical

Let the set of all positive values of Ī»\lambda, for which the point of local minimum of the function (1+x(Ī»2āˆ’x2))(1+x(\lambda^2-x^2)) satisfies x2+x+2x2+5x+6<0\frac{x^2+x+2}{x^2+5x+6}<0, be (α,β)(\alpha, \beta). Then α2+β2\alpha^2+\beta^2 is equal to ________.

Show answer

Answer: 39

Q38JEE Main 2024 Apr 9 Shift 2Medium

If log⁔ey=3sinā”āˆ’1x\log_e y = 3\sin^{-1}x, then (1āˆ’x2)yā€²ā€²āˆ’xy′(1-x^2)y''-xy' at x=12x=\frac{1}{2} is equal to

  1. A

    9eπ/29e^{\pi/2}

  2. B

    9eπ/69e^{\pi/6}

  3. C

    3eπ/23e^{\pi/2}

  4. D

    3eπ/63e^{\pi/6}

Show answer

Correct option: A

Q39JEE Main 2024 Apr 9 Shift 2MediumNumerical

Let the set of all values of pp, for which f(x)=(p2āˆ’6p+8)(sin⁔22xāˆ’cos⁔22x)+2(2āˆ’p)x+7f(x)=\left(p^2-6p+8\right)\left(\sin^2 2x-\cos^2 2x\right)+2(2-p)x+7 does not have any critical point, be the interval (a,b)(a, b). Then 16ab16ab is equal to ________.

Show answer

Answer: 252

Q40JEE Main 2024 Feb 1 Shift 1Medium

If 5f(x)+4f(1x)=x2āˆ’2,āˆ€ā€‰x≠05f(x) + 4f\left(\dfrac{1}{x}\right) = x^2 - 2, \forall\, x \neq 0 and y=9x2f(x)y = 9x^2 f(x), then yy is strictly increasing in :

  1. A

    (āˆ’15, 0)∪(0, 15)\left(-\dfrac{1}{\sqrt{5}},\, 0\right) \cup \left(0,\, \dfrac{1}{\sqrt{5}}\right)

  2. B

    (āˆ’āˆž, 15)∪(0, 15)\left(-\infty,\, \dfrac{1}{\sqrt{5}}\right) \cup \left(0,\, \dfrac{1}{\sqrt{5}}\right)

  3. C

    (āˆ’15, 0)∪(15,ā€‰āˆž)\left(-\dfrac{1}{\sqrt{5}},\, 0\right) \cup \left(\dfrac{1}{\sqrt{5}},\, \infty\right)

  4. D

    (0, 15)∪(15,ā€‰āˆž)\left(0,\, \dfrac{1}{\sqrt{5}}\right) \cup \left(\dfrac{1}{\sqrt{5}},\, \infty\right)

Show answer

Correct option: C

Q41JEE Main 2024 Feb 1 Shift 2MediumNumerical

If y=(x+1)(x2āˆ’x)xx+x+x+115(3cos⁔2xāˆ’5)cos⁔3xy=\frac{(\sqrt{x}+1)(x^2-\sqrt{x})}{x\sqrt{x}+x+\sqrt{x}}+\frac{1}{15}(3\cos^2 x - 5)\cos^3 x, then 96 y′ ⁣(Ļ€6)96\, y'\!\left(\frac{\pi}{6}\right) is equal to ________.

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Answer: 105

Q42JEE Main 2024 Jan 27 Shift 1HardNumerical

Let for a differentiable function f:(0,āˆž)→Rf : (0, \infty) \to \mathbf{R}, f(x)āˆ’f(y)≄log⁔e(xy)+xāˆ’y,Ā āˆ€Ā x,y∈(0,āˆž)f(x) - f(y) \geq \log_e\left(\dfrac{x}{y}\right) + x - y,\ \forall\ x, y \in (0, \infty).

Then āˆ‘n=120f′(1n2)\sum\limits_{n=1}^{20} f'\left(\dfrac{1}{n^2}\right) is equal to ________.

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Answer: 2890

Q43JEE Main 2024 Jan 27 Shift 1MediumNumerical

Let f(x)=x3+x2f′(1)+xf′′(2)+f′′′(3)f(x) = x^3 + x^2 f'(1) + x f''(2) + f'''(3), x∈Rx \in \mathbf{R}. Then f′(10)f'(10) is equal to ________.

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Answer: 202

Q44JEE Main 2024 Jan 29 Shift 1Medium

Suppose f(x)=(2x+2āˆ’x)tan⁔xtanā”āˆ’1(x2āˆ’x+1)(7x2+3x+1)3f(x)=\dfrac{\left(2^x + 2^{-x}\right)\tan x\sqrt{\tan^{-1}\left(x^2 - x + 1\right)}}{\left(7x^2 + 3x + 1\right)^3}. Then the value of f′(0)f'(0) is equal to

  1. A

    00

  2. B

    π\sqrt{\pi}

  3. C

    π\pi

  4. D

    π2\dfrac{\pi}{2}

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Correct option: B

Q45JEE Main 2024 Jan 29 Shift 1Medium

Consider the function f:[12,1]→Rf:\left[\dfrac{1}{2},1\right] \to \mathbb{R} defined by f(x)=42x3āˆ’32xāˆ’1f(x)=4\sqrt{2}x^3 - 3\sqrt{2}x - 1.

Consider the statements

(I) The curve y=f(x)y=f(x) intersects the xx-axis exactly at one point.

(II) The curve y=f(x)y=f(x) intersects the xx-axis at x=cos⁔π12x=\cos\dfrac{\pi}{12}.

Then

  1. A

    Both (I) and (II) are correct.

  2. B

    Both (I) and (II) are incorrect.

  3. C

    Only (I) is correct.

  4. D

    Only (II) is correct.

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Correct option: A

Q46JEE Main 2024 Jan 29 Shift 1MediumNumerical

Let f(x)=2xāˆ’x2f(x) = 2^x - x^2, x∈Rx \in \mathbb{R}. If mm and nn are respectively the number of points at which the curves y=f(x)y=f(x) and y=f′(x)y=f'(x) intersect the xx-axis, then the value of m+nm + n is __________.

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Answer: 5

Q47JEE Main 2024 Jan 30 Shift 1Medium

The maximum area of a triangle whose one vertex is at (0,0)(0, 0) and the other two vertices lie on the curve y=āˆ’2x2+54y=-2x^2+54 at points (x,y)(x, y) and (āˆ’x,y)(-x, y), where y>0y > 0, is :

  1. A

    9292

  2. B

    108108

  3. C

    8888

  4. D

    122122

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Correct option: B

Q48JEE Main 2024 Jan 30 Shift 2Medium

Let f:Rāˆ’{0}→Rf: \mathbb{R}-\{0\} \to \mathbb{R} be a function satisfying f(xy)=f(x)f(y)f\left(\frac{x}{y}\right)=\frac{f(x)}{f(y)} for all x,y,Ā f(y)≠0x, y,\ f(y) \neq 0. If f′(1)=2024f'(1)=2024, then

  1. A

    xf′(x)āˆ’2024f(x)=0xf'(x)-2024f(x)=0

  2. B

    xf′(x)+2024f(x)=0xf'(x)+2024f(x)=0

  3. C

    xf′(x)āˆ’2023f(x)=0xf'(x)-2023f(x)=0

  4. D

    xf′(x)+f(x)=2024xf'(x)+f(x)=2024

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Correct option: A

Q49JEE Main 2024 Jan 30 Shift 2Medium

Let f(x)=(x+3)2(xāˆ’2)3,Ā x∈[āˆ’4,4]f(x)=(x+3)^2(x-2)^3,\ x \in [-4, 4]. If MM and mm are the maximum and minimum values of ff, respectively in [āˆ’4,4][-4, 4], then the value of Māˆ’mM-m is

  1. A

    600

  2. B

    392

  3. C

    608

  4. D

    108

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Correct option: C

Q50JEE Main 2024 Jan 31 Shift 1HardNumerical

Let S=(āˆ’1,āˆž)S=(-1, \infty) and f:S→Rf: S \rightarrow \mathbb{R} be defined as

f(x)=āˆ«āˆ’1x(etāˆ’1)11(2tāˆ’1)5(tāˆ’2)7(tāˆ’3)12(2tāˆ’10)61 dt,f(x)=\int_{-1}^{x}\left(e^t-1\right)^{11}(2t-1)^5(t-2)^7(t-3)^{12}(2t-10)^{61}\,dt,

Let p = Sum of squares of the values of xx, where f(x)f(x) attains local maxima on S, and q = Sum of the values of xx, where f(x)f(x) attains local minima on S. Then, the value of p2+2q\mathrm{p}^2+2\mathrm{q} is ________

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Answer: 27