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Physics

Dual Nature of Matter and Radiation — JEE Main PYQs

38 previous year questions

Q1JEE Main 2026 Apr 4 Shift 1Medium

The graph shows variation of stopping potential V0V_0 with the frequency ν\nu of the incident radiation for three photosensitive metals X1X_1, X2X_2 and X3X_3. Which metal will give out electrons with greater kinetic energy, for the same wavelength of incident radiation?

[Figure: Graph of stopping potential V0V_0 versus frequency ν\nu showing three parallel straight lines for metals X1X_1, X2X_2, X3X_3 with threshold frequencies at 1.0, 1.5 and 2 (×1014\times 10^{14} Hz) respectively]

  1. A

    X1X_1

  2. B

    X2X_2

  3. C

    X3X_3

  4. D

    All the metals will give out photo electrons with same kinetic energies.

Show answer

Correct option: A

Q2JEE Main 2026 Apr 4 Shift 2Easy

The de Broglie wavelength associated with an electron accelerated through a potential difference VV is λe\lambda_e and the de Broglie wavelength associated with a proton accelerated through the same potential difference is λp\lambda_p. If their corresponding masses are mem_e and mpm_p, respectively, then the ratio of their de Broglie wavelengths (λeλp)\left(\frac{\lambda_e}{\lambda_p}\right) is _______.

  1. A

    mpme\sqrt{\frac{m_p}{m_e}}

  2. B

    memp\sqrt{\frac{m_e}{m_p}}

  3. C

    mpme\frac{m_p}{m_e}

  4. D

    (mpme)2\left(\frac{m_p}{m_e}\right)^2

Show answer

Correct option: A

Q3JEE Main 2026 Apr 5 Shift 1Hard

An electron of mass mm is moving in an electric field E=2E0i^\vec{E} = -2E_0\hat{i} (E0E_0 = constant >0> 0), with an initial velocity V=v0i^\vec{V} = v_0\hat{i} (v0v_0 = constant >0> 0). If λ0=h4mv0\lambda_0 = \dfrac{h}{4mv_0}, its de Broglie wavelength at time tt is ______.

(ee = charge of electron)

  1. A

    4λ0[1E0e2mtv0]\dfrac{4\lambda_0}{\left[1 - \dfrac{E_0 e}{2m}\dfrac{t}{v_0}\right]}

  2. B

    4λ0[1+E0e2mtv0]\dfrac{4\lambda_0}{\left[1 + \dfrac{E_0 e}{2m}\dfrac{t}{v_0}\right]}

  3. C

    4λ0[1+2E0emtv0]\dfrac{4\lambda_0}{\left[1 + \dfrac{2E_0 e}{m}\dfrac{t}{v_0}\right]}

  4. D

    4λ0[12E0emtv0]\dfrac{4\lambda_0}{\left[1 - \dfrac{2E_0 e}{m}\dfrac{t}{v_0}\right]}

Show answer

Correct option: C

Q4JEE Main 2026 Apr 5 Shift 1Medium

Light source having wavelength 331 nm is used to generate photo-electrons whose stopping potential is 0.2 V. The work function of the used metal in the experiment is α×1019\alpha \times 10^{-19} J. The value of α\alpha is _____.

(h=6.62×1034h = 6.62 \times 10^{-34} J s, e=1.6×1019e = 1.6 \times 10^{-19} C and c=3×108c = 3 \times 10^8 m/s)

  1. A

    3.68

  2. B

    4.68

  3. C

    5.68

  4. D

    2.68

Show answer

Correct option: C

Q5JEE Main 2026 Apr 5 Shift 2Easy

An electron is travelling with a velocity vv in free space and when it enters a medium, its velocity is reduced by 20%20\%. The de Broglie wavelength of electron in the medium is αλ0\alpha \lambda_0, where λ0\lambda_0 is its de Broglie wavelength in free space. The value of α\alpha is __________.

  1. A

    1.20

  2. B

    1.0

  3. C

    1.25

  4. D

    0.75

Show answer

Correct option: C

Q6JEE Main 2026 Apr 6 Shift 2MediumNumerical

The de Broglie wavelength for an electron accelerated through the potential difference of V1V_1 volt is λ1\lambda_1. When the potential difference is changed to V2V_2 volt, the associated de Broglie wavelength is increased by 50%. If (V1/V2)=(9/α)(V_1/V_2) = (9/\alpha), then the value of α\alpha is ________.

Show answer

Answer: 4

Q7JEE Main 2026 Apr 8 Shift 2Medium

K1K_1 and K2K_2 be the maximum kinetic energies of photoelectrons emitted from a surface of a given material for the light of wavelength λ1\lambda_1 and λ2\lambda_2, respectively. If λ1=2λ2\lambda_1 = 2\lambda_2 then the work function of material is given by :

  1. A

    K2+2K1K_2 + 2K_1

  2. B

    2K2K12K_2 - K_1

  3. C

    K12K2K_1 - 2K_2

  4. D

    K22K1K_2 - 2K_1

Show answer

Correct option: D

Q8JEE Main 2025 Apr 2 Shift 1Hard

A monochromatic light is incident on a metallic plate having work function ϕ\phi. An electron, emitted normally to the plate from a point A with maximum kinetic energy, enters a constant magnetic field, perpendicular to the initial velocity of electron. The electron passes through a curve and hits back the plate at a point B. The distance between A and B is :

(Given : The magnitude of charge of an electron is e and mass is m, h is Planck's constant and c is velocity of light. Take the magnetic field exists throughout the path of electron)

  1. A

    8m(hcλϕ)/eB\sqrt{8m\left(\dfrac{hc}{\lambda}-\phi\right)}\Big/eB

  2. B

    2m(hcλϕ)/eB\sqrt{2m\left(\dfrac{hc}{\lambda}-\phi\right)}\Big/eB

  3. C

    m(hc/λϕ)/eB\sqrt{m\left(hc/\lambda-\phi\right)}\Big/eB

  4. D

    2m(hc/λϕ)/eB2\sqrt{m\left(hc/\lambda-\phi\right)}\Big/eB

Show answer

Correct option: A

Q9JEE Main 2025 Apr 2 Shift 2Medium

An electron with mass 'm' with an initial velocity (t=0)(t=0) v=v0i^ (v0>0)\vec{v}=v_0\,\hat{i}\ (v_0>0) enters a magnetic field B=B0j^\vec{B}=B_0\,\hat{j}. If the initial de-Broglie wavelength at t=0t=0 is λ0\lambda_0 then its value after time 't' would be :

  1. A

    λ0\lambda_0

  2. B

    λ01+e2B02t2m2\lambda_0\sqrt{1+\dfrac{e^2B_0^2t^2}{m^2}}

  3. C

    λ01e2B02t2m2\dfrac{\lambda_0}{\sqrt{1-\dfrac{e^2B_0^2t^2}{m^2}}}

  4. D

    λ01+e2B02t2m2\dfrac{\lambda_0}{\sqrt{1+\dfrac{e^2B_0^2t^2}{m^2}}}

Show answer

Correct option: A

Q10JEE Main 2025 Apr 3 Shift 1Medium

The work function of a metal is 3 eV. The color of the visible light that is required to cause emission of photoelectrons is

  1. A

    Yellow

  2. B

    Green

  3. C

    Red

  4. D

    Blue

Show answer

Correct option: D

Q11JEE Main 2025 Apr 7 Shift 2Medium

A photoemissive substance is illuminated with a radiation of wavelength λi\lambda_i so that it releases electrons with de-Broglie wavelength λe\lambda_e. The longest wavelength of radiation that can emit photoelectron is λo\lambda_o. Expression for de-Broglie wavelength is given by :

(m : mass of the electron, h : Planck's constant and c : speed of light)

  1. A

    λe=hλi2mc\lambda_e = \sqrt{\dfrac{h\lambda_i}{2mc}}

  2. B

    λe=hλo2mc\lambda_e = \sqrt{\dfrac{h\lambda_o}{2mc}}

  3. C

    λe=h2mc(1λi1λo)\lambda_e = \dfrac{h}{\sqrt{2mc\left(\dfrac{1}{\lambda_i} - \dfrac{1}{\lambda_o}\right)}}

  4. D

    λe=h2mc(1λi1λo)\lambda_e = \sqrt{\dfrac{h}{2mc\left(\dfrac{1}{\lambda_i} - \dfrac{1}{\lambda_o}\right)}}

Show answer

Correct option: D

Q12JEE Main 2025 Apr 8 Shift 2MediumNumerical

An electron is released from rest near an infinite non-conducting sheet of uniform charge density 'σ-\sigma' .The rate of change of de-Broglie wave length associated with the electron varies inversely as nthn^{th} power of time. The numerical value of n is __________.

Show answer

Answer: 2

Q13JEE Main 2025 Jan 22 Shift 1Easy

The work functions of cesium (Cs) and lithium (Li) metals are 1.9 eV and 2.5 eV, respectively. If we incident a light of wavelength 550 nm on these two metal surfaces, then photo-electric effect is possible for the case of

  1. A

    Cs only

  2. B

    Li only

  3. C

    Both Cs and Li

  4. D

    Neither Cs nor Li

Show answer

Correct option: A

Q14JEE Main 2025 Jan 23 Shift 1Medium

A sub-atomic particle of mass 103010^{-30} kg is moving with a velocity 2.21×1062.21 \times 10^{6} m/s. Under the matter wave consideration, the particle will behave closely like _____. (h=6.63×1034h = 6.63 \times 10^{-34} J.s)

  1. A

    Infra-red radiation

  2. B

    Visible radiation

  3. C

    X-rays

  4. D

    Gamma rays

Show answer

Correct option: C

Q15JEE Main 2025 Jan 23 Shift 2Easy

In photoelectric effect an em-wave is incident on a metal surface and electrons are ejected from the surface. If the work function of the metal is 2.14 eV and stopping potential is 2V, what is the wavelength of the em-wave ?

(Given hc = 1242 eVnm where h is the Planck's constant and c is the speed of light in vaccum.)

  1. A

    200 nm

  2. B

    300 nm

  3. C

    400 nm

  4. D

    600 nm

Show answer

Correct option: B

Q16JEE Main 2025 Jan 24 Shift 1Medium

An electron of mass 'm' with an initial velocity v=v0i^(v0>0)\vec{v}=v_0\hat{i}\,(v_0>0) enters an electric field E=Eok^\vec{E}=-E_o\hat{k}. If the initial de Broglie wavelength is λ0\lambda_0, the value after time t would be

  1. A

    λ0\lambda_0

  2. B

    λo1+e2Eo2t2m2vo2\lambda_o\sqrt{1+\dfrac{e^2E_o^2t^2}{m^2v_o^2}}

  3. C

    λo1e2Eo2t2m2vo2\dfrac{\lambda_o}{\sqrt{1-\dfrac{e^2E_o^2t^2}{m^2v_o^2}}}

  4. D

    λo1+e2Eo2t2m2vo2\dfrac{\lambda_o}{\sqrt{1+\dfrac{e^2E_o^2t^2}{m^2v_o^2}}}

Show answer

Correct option: D

Q17JEE Main 2025 Jan 24 Shift 2Medium

In photoelectric effect, the stopping potential (V0)(\mathrm{V}_0) v/s frequency (ν)(\nu) curve is plotted.

(h is the Planck's constant and ϕ0\phi_0 is work function of metal)

(A) V0\mathrm{V}_0 v/s ν\nu is linear.

(B) The slope of V0\mathrm{V}_0 v/s ν\nu curve =ϕ0h= \frac{\phi_0}{h}

(C) h constant is related to the slope of V0\mathrm{V}_0 v/s ν\nu line.

(D) The value of electric charge of electron is not required to determine h using the V0\mathrm{V}_0 v/s ν\nu curve.

(E) The work function can be estimated without knowing the value of h.

Choose the correct answer from the options given below :

  1. A

    (A), (C) and (E) only

  2. B

    (A), (B) and (C) only

  3. C

    (D) and (E) only

  4. D

    (C) and (D) only

Show answer

Correct option: A

Q18JEE Main 2025 Jan 24 Shift 2MediumNumerical

The ratio of the power of a light source S1\mathrm{S}_1 to that of the light source S2\mathrm{S}_2 is 2. S1\mathrm{S}_1 is emitting 2×10152 \times 10^{15} photons per second at 600 nm. If the wavelength of the source S2\mathrm{S}_2 is 300 nm, then the number of photons per second emitted by S2\mathrm{S}_2 is ______ ×1014\times 10^{14}.

Show answer

Answer: 5

Q19JEE Main 2025 Jan 28 Shift 1Medium

A proton of mass 'mpm_p' has same energy as that of a photon of wavelength 'λ\lambda'. If the proton is moving at non-relativistic speed, then ratio of its de Broglie wavelength to the wavelength of photon is.

  1. A

    1cEmp\frac{1}{c}\sqrt{\frac{E}{m_p}}

  2. B

    1cE2mp\frac{1}{c}\sqrt{\frac{E}{2m_p}}

  3. C

    12cEmp\frac{1}{2c}\sqrt{\frac{E}{m_p}}

  4. D

    1c2Emp\frac{1}{c}\sqrt{\frac{2E}{m_p}}

Show answer

Correct option: B

Q20JEE Main 2025 Jan 28 Shift 2Easy

Which of the following phenomena can not be explained by wave theory of light?

  1. A

    Reflection of light

  2. B

    Refraction of light

  3. C

    Diffraction of light

  4. D

    Compton effect

Show answer

Correct option: D

Q21JEE Main 2024 Apr 4 Shift 1Medium

Which figure shows the correct variation of applied potential difference (V) with photoelectric current (I) at two different intensities of light (I1<I2\mathrm{I_1} < \mathrm{I_2}) of same wavelengths :

  1. A

    [Figure: i vs V graph — curves for I1I_1 and I2I_2 cross each other; I2I_2 has the larger saturation current but its curve meets the V-axis at a less negative potential than V0-V_0 of I1I_1 (different stopping potentials)]

  2. B

    [Figure: i vs V graph — both curves start from the same stopping potential V0-V_0 and rise smoothly, with I2I_2 above I1I_1 throughout]

  3. C

    [Figure: i vs V graph — curves for I1I_1 and I2I_2 cross each other; I1I_1 saturates at a lower current while I2I_2 rises steeply, with the curves meeting the V-axis at different points near V0-V_0]

  4. D

    [Figure: i vs V graph — both curves start from the same stopping potential V0-V_0; I2I_2 saturates at a higher current than I1I_1, both showing flat saturation regions]

Show answer

Correct option: B

Q22JEE Main 2024 Apr 4 Shift 2Medium

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.

Assertion A: Number of photons increases with increase in frequency of light.

Reason R: Maximum kinetic energy of emitted electrons increases with the frequency of incident radiation.

In the light of the above statements, choose the most appropriate answer from the options given below:

  1. A

    Both A and R are correct and R is the correct explanation of A.

  2. B

    Both A and R are correct and R is NOT the correct explanation of A.

  3. C

    A is correct but R is not correct.

  4. D

    A is not correct but R is correct.

Show answer

Correct option: D

Q23JEE Main 2024 Apr 5 Shift 1Medium

Given below are two statements :

[Figure: graph of stopping potential V0V_0 versus frequency ν\nu showing two parallel straight lines for materials M1M_1 and M2M_2, with the line for M1M_1 to the left of M2M_2]

Statement I : Figure shows the variation of stopping potential with frequency (ν\nu) for the two photosensitive materials M1M_1 and M2M_2. The slope gives value of he\frac{h}{e}, where h is Planck's constant, e is the charge of electron.

Statement II : M2M_2 will emit photoelectrons of greater kinetic energy for the incident radiation having same frequency.

In the light of the above statements, choose the most appropriate answer from the options given below.

  1. A

    Both Statement I and Statement II are correct

  2. B

    Both Statement I and Statement II are incorrect

  3. C

    Statement I is correct and Statement II is incorrect

  4. D

    Statement I is incorrect but Statement II is correct

Show answer

Correct option: C

Q24JEE Main 2024 Apr 5 Shift 2Easy

Which of the following statement is not true about stopping potential (V0)(V_0) ?

  1. A

    It depends upon frequency of the incident light.

  2. B

    It depends on the nature of emitter material.

  3. C

    It increases with increase in intensity of the incident light.

  4. D

    It is 1/e times the maximum kinetic energy of electrons emitted.

Show answer

Correct option: C

Q25JEE Main 2024 Apr 6 Shift 1Easy

In photoelectric experiment energy of 2.48 eV irradiates a photo sensitive material. The stopping potential was measured to be 0.5 V. Work function of the photo sensitive material is :

  1. A

    1.98 eV

  2. B

    1.68 eV

  3. C

    2.48 eV

  4. D

    0.5 eV

Show answer

Correct option: A

Q26JEE Main 2024 Apr 6 Shift 2Easy

When UV light of wavelength 300 nm is incident on the metal surface having work function 2.13 eV, electron emission takes place. The stopping potential is : (Given hc=1240 eVnmhc = 1240\ \mathrm{eV\,nm})

  1. A

    4.1 V4.1\ \mathrm{V}

  2. B

    1.5 V1.5\ \mathrm{V}

  3. C

    2 V2\ \mathrm{V}

  4. D

    4 V4\ \mathrm{V}

Show answer

Correct option: C

Q27JEE Main 2024 Apr 8 Shift 1Easy

A proton and an electron are associated with same de-Broglie wavelength. The ratio of their kinetic energies is:

(Assume h=6.63×1034h = 6.63 \times 10^{-34} J s, me=9.0×1031\mathrm{m_e} = 9.0 \times 10^{-31} kg and mp=1836\mathrm{m_p} = 1836 times me\mathrm{m_e})

  1. A

    1:18361 : 1836

  2. B

    1:18361 : \sqrt{1836}

  3. C

    1:118361 : \frac{1}{1836}

  4. D

    1:118361 : \frac{1}{\sqrt{1836}}

Show answer

Correct option: A

Q28JEE Main 2024 Apr 8 Shift 2Easy

A proton and an electron have the same de Broglie wavelength. If Kp\mathrm{K_p} and Ke\mathrm{K_e} be the kinetic energies of proton and electron respectively, then choose the correct relation :

  1. A

    Kp>Ke\mathrm{K_p} > \mathrm{K_e}

  2. B

    Kp<Ke\mathrm{K_p} < \mathrm{K_e}

  3. C

    Kp=Ke\mathrm{K_p} = \mathrm{K_e}

  4. D

    Kp=Ke2\mathrm{K_p} = \mathrm{K_e}^2

Show answer

Correct option: B

Q29JEE Main 2024 Apr 9 Shift 1Medium

A proton, an electron and an alpha particle have the same energies. Their de-Broglie wavelengths will be compared as :

  1. A

    λp>λe>λα\lambda_p > \lambda_e > \lambda_\alpha

  2. B

    λp<λe<λα\lambda_p < \lambda_e < \lambda_\alpha

  3. C

    λα<λp<λe\lambda_\alpha < \lambda_p < \lambda_e

  4. D

    λe>λα>λp\lambda_e > \lambda_\alpha > \lambda_p

Show answer

Correct option: C

Q30JEE Main 2024 Apr 9 Shift 2Easy

UV light of 4.13 eV is incident on a photosensitive metal surface having work function 3.13 eV. The maximum kinetic energy of ejected photoelectrons will be:

  1. A

    1 eV

  2. B

    3.13 eV

  3. C

    4.13 eV

  4. D

    7.26 eV

Show answer

Correct option: A

Q31JEE Main 2024 Feb 1 Shift 1Medium

The de Broglie wavelengths of a proton and an α\alpha particle are λ\lambda and 2λ2\lambda respectively. The ratio of the velocities of proton and α\alpha particle will be :

  1. A

    1 : 8

  2. B

    4 : 1

  3. C

    8 : 1

  4. D

    1 : 2

Show answer

Correct option: C

Q32JEE Main 2024 Feb 1 Shift 2Easy

Monochromatic light of frequency 6×10146 \times 10^{14} Hz is produced by a laser. The power emitted is 2×1032 \times 10^{-3} W. How many photons per second on an average, are emitted by the source ?

(Given h=6.63×1034h = 6.63 \times 10^{-34} Js)

  1. A

    5×10155 \times 10^{15}

  2. B

    7×10167 \times 10^{16}

  3. C

    6×10156 \times 10^{15}

  4. D

    9×10189 \times 10^{18}

Show answer

Correct option: A

Q33JEE Main 2024 Jan 27 Shift 1Medium

A convex lens of focal length 40 cm forms an image of an extended source of light on a photo-electric cell. A current I is produced. The lens is replaced by another convex lens having the same diameter but focal length 20 cm. The photoelectric current now is :

  1. A

    I2\frac{I}{2}

  2. B

    II

  3. C

    2I2I

  4. D

    4I4I

Show answer

Correct option: B

Q34JEE Main 2024 Jan 29 Shift 1Medium

The de-Broglie wavelength of an electron is the same as that of a photon. If velocity of electron is 25% of the velocity of light, then the ratio of K.E. of electron and K.E. of photon will be:

  1. A

    18\frac{1}{8}

  2. B

    81\frac{8}{1}

  3. C

    11\frac{1}{1}

  4. D

    14\frac{1}{4}

Show answer

Correct option: A

Q35JEE Main 2024 Jan 30 Shift 1Easy

The work function of a substance is 3.0 eV. The longest wavelength of light that can cause the emission of photoelectrons from this substance is approximately;

  1. A

    400 nm

  2. B

    414 nm

  3. C

    200 nm

  4. D

    215 nm

Show answer

Correct option: B

Q36JEE Main 2024 Jan 30 Shift 2Easy

For the photoelectric effect, the maximum kinetic energy (Ek)(E_k) of the photoelectrons is plotted against the frequency (ν)(\nu) of the incident photons as shown in figure. The slope of the graph gives

[Figure: straight-line graph of EkE_k (y-axis) versus ν\nu (x-axis), intersecting the ν\nu-axis at a positive intercept and making angle θ\theta with it]

  1. A

    Planck's constant

  2. B

    Charge of electron

  3. C

    Work function of the metal

  4. D

    Ratio of Planck's constant to electric charge

Show answer

Correct option: A

Q37JEE Main 2024 Jan 31 Shift 1Medium

When a metal surface is illuminated by light of wavelength λ\lambda, the stopping potential is 8V. When the same surface is illuminated by light of wavelength 3λ3\lambda, stopping potential is 2V. The threshold wavelength for this surface is:

  1. A

    4.5λ4.5\lambda

  2. B

    3λ3\lambda

  3. C

    5λ5\lambda

  4. D

    9λ9\lambda

Show answer

Correct option: D

Q38JEE Main 2024 Jan 31 Shift 2Easy

In a photoelectric effect experiment a light of frequency 1.5 times the threshold frequency is made to fall on the surface of photosensitive material. Now if the frequency is halved and intensity is doubled, the number of photo electrons emitted will be:

  1. A

    Zero

  2. B

    halved

  3. C

    doubled

  4. D

    quadrupled

Show answer

Correct option: A