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Mathematics

Inverse Trigonometric Functions — JEE Main PYQs

18 previous year questions

Q1JEE Main 2026 Apr 5 Shift 1MediumNumerical

If Ļ€4+āˆ‘p=111tanā”āˆ’1(2pāˆ’11+22pāˆ’1)=α\frac{\pi}{4} + \displaystyle\sum_{p=1}^{11} \tan^{-1}\left( \frac{2^{p-1}}{1 + 2^{2p-1}} \right) = \alpha, then tan⁔α\tan \alpha is equal to __________.

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Answer: 2048

Q2JEE Main 2026 Apr 6 Shift 1Medium

Let 0<α<10<\alpha<1, β=13α\beta=\frac{1}{3\alpha} and tanā”āˆ’1(1āˆ’Ī±)+tanā”āˆ’1(1āˆ’Ī²)=Ļ€4\tan^{-1}\left(1-\alpha\right)+\tan^{-1}\left(1-\beta\right)=\frac{\pi}{4}. Then 6(α+β)6(\alpha+\beta) is equal to:

  1. A

    66

  2. B

    77

  3. C

    88

  4. D

    99

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Correct option: B

Q3JEE Main 2026 Apr 6 Shift 2Easy

If sin⁔(tanā”āˆ’1(x2))=cot⁔(sinā”āˆ’11āˆ’x2)\sin\left(\tan^{-1}\left(x\sqrt{2}\right)\right) = \cot\left(\sin^{-1}\sqrt{1 - x^2}\right), x∈(0,1)x \in (0, 1), then the value of xx is :

  1. A

    12\frac{1}{2}

  2. B

    13\frac{1}{3}

  3. C

    23\frac{2}{3}

  4. D

    58\frac{5}{8}

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Correct option: A

Q4JEE Main 2026 Apr 8 Shift 2Medium

Let α=3sinā”āˆ’1(611)\alpha = 3\sin^{-1}\left(\frac{6}{11}\right) and β=3cosā”āˆ’1(49)\beta = 3\cos^{-1}\left(\frac{4}{9}\right), where inverse trigonometric functions take only the principal values.

Given below are two statements :

Statement I : cos⁔(α+β)>0\cos(\alpha + \beta) > 0.

Statement II : cos⁔(α)<0\cos(\alpha) < 0.

In the light of the above statements, choose the correct answer from the options given below :

  1. A

    Both Statement I and Statement II are true

  2. B

    Both Statement I and Statement II are false

  3. C

    Statement I is true but Statement II is false

  4. D

    Statement I is false but Statement II is true

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Correct option: A

Q5JEE Main 2025 Apr 2 Shift 2MediumNumerical

If y=cos⁔(Ļ€3+cosā”āˆ’1x2)y=\cos\left(\frac{\pi}{3}+\cos^{-1}\frac{x}{2}\right), then (xāˆ’y)2+3y2(x-y)^2+3y^2 is equal to _________.

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Answer: 3

Q6JEE Main 2025 Apr 4 Shift 1Medium

Considering the principal values of the inverse trigonometric functions, sinā”āˆ’1(32x+121āˆ’x2)\sin^{-1}\left(\frac{\sqrt{3}}{2}x + \frac{1}{2}\sqrt{1 - x^2}\right), āˆ’12<x<12-\frac{1}{2} < x < \frac{1}{\sqrt{2}}, is equal to

  1. A

    Ļ€4+sinā”āˆ’1x\frac{\pi}{4} + \sin^{-1} x

  2. B

    Ļ€6+sinā”āˆ’1x\frac{\pi}{6} + \sin^{-1} x

  3. C

    5Ļ€6āˆ’sinā”āˆ’1x\frac{5\pi}{6} - \sin^{-1} x

  4. D

    āˆ’5Ļ€6āˆ’sinā”āˆ’1x\frac{-5\pi}{6} - \sin^{-1} x

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Correct option: B

Q7JEE Main 2025 Apr 4 Shift 2Medium

The sum of the infinite series cotā”āˆ’1(74)+cotā”āˆ’1(194)+cotā”āˆ’1(394)+cotā”āˆ’1(674)+…\cot^{-1}\left(\dfrac{7}{4}\right)+\cot^{-1}\left(\dfrac{19}{4}\right)+\cot^{-1}\left(\dfrac{39}{4}\right)+\cot^{-1}\left(\dfrac{67}{4}\right)+\ldots is :

  1. A

    Ļ€2āˆ’cotā”āˆ’1(12)\dfrac{\pi}{2}-\cot^{-1}\left(\dfrac{1}{2}\right)

  2. B

    Ļ€2+tanā”āˆ’1(12)\dfrac{\pi}{2}+\tan^{-1}\left(\dfrac{1}{2}\right)

  3. C

    Ļ€2āˆ’tanā”āˆ’1(12)\dfrac{\pi}{2}-\tan^{-1}\left(\dfrac{1}{2}\right)

  4. D

    Ļ€2+cotā”āˆ’1(12)\dfrac{\pi}{2}+\cot^{-1}\left(\dfrac{1}{2}\right)

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Correct option: C

Q8JEE Main 2025 Apr 8 Shift 2Medium

The value of cotā”āˆ’1(1+tan⁔2(2)āˆ’1tan⁔(2))āˆ’cotā”āˆ’1(1+tan⁔2(12)+1tan⁔(12))\cot^{-1}\left(\frac{\sqrt{1+\tan^2(2)}-1}{\tan(2)}\right) - \cot^{-1}\left(\frac{\sqrt{1+\tan^2\left(\frac{1}{2}\right)}+1}{\tan\left(\frac{1}{2}\right)}\right) is equal to

  1. A

    Ļ€āˆ’54\pi - \frac{5}{4}

  2. B

    Ļ€āˆ’32\pi - \frac{3}{2}

  3. C

    π+52\pi + \frac{5}{2}

  4. D

    π+32\pi + \frac{3}{2}

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Correct option: A

Q9JEE Main 2025 Jan 22 Shift 1Medium

Using the principal values of the inverse trigonometric functions, the sum of the maximum and the minimum values of 16((secā”āˆ’1x)2+(cosecā”āˆ’1x)2)16\left((\sec^{-1}x)^2+(\operatorname{cosec}^{-1}x)^2\right) is :

  1. A

    18Ļ€218\pi^2

  2. B

    22Ļ€222\pi^2

  3. C

    24Ļ€224\pi^2

  4. D

    31Ļ€231\pi^2

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Correct option: B

Q10JEE Main 2025 Jan 23 Shift 1Medium

If Ļ€2≤x≤3Ļ€4\frac{\pi}{2} \le x \le \frac{3\pi}{4}, then cosā”āˆ’1(1213cos⁔x+513sin⁔x)\cos^{-1}\left(\frac{12}{13}\cos x + \frac{5}{13}\sin x\right) is equal to

  1. A

    xāˆ’tanā”āˆ’143x - \tan^{-1}\frac{4}{3}

  2. B

    x+tanā”āˆ’145x + \tan^{-1}\frac{4}{5}

  3. C

    xāˆ’tanā”āˆ’1512x - \tan^{-1}\frac{5}{12}

  4. D

    x+tanā”āˆ’1512x + \tan^{-1}\frac{5}{12}

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Correct option: C

Q11JEE Main 2025 Jan 24 Shift 1MediumNumerical

If for some α,β\alpha, \beta; α≤β\alpha \leq \beta, α+β=8\alpha + \beta = 8 and sec⁔2(tanā”āˆ’1α)+cosec⁔2(cotā”āˆ’1β)=36\sec^2(\tan^{-1}\alpha) + \operatorname{cosec}^2(\cot^{-1}\beta) = 36, then α2+β\alpha^2 + \beta is _____.

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Answer: 14

Q12JEE Main 2025 Jan 24 Shift 2Medium

If α>β>γ>0\alpha > \beta > \gamma > 0, then the expression

cotā”āˆ’1{β+(1+β2)(Ī±āˆ’Ī²)}+cotā”āˆ’1{γ+(1+γ2)(Ī²āˆ’Ī³)}+cotā”āˆ’1{α+(1+α2)(Ī³āˆ’Ī±)}\cot^{-1}\left\{\beta + \dfrac{(1 + \beta^2)}{(\alpha - \beta)}\right\} + \cot^{-1}\left\{\gamma + \dfrac{(1 + \gamma^2)}{(\beta - \gamma)}\right\} + \cot^{-1}\left\{\alpha + \dfrac{(1 + \alpha^2)}{(\gamma - \alpha)}\right\} is equal to :

  1. A

    3Ļ€3\pi

  2. B

    00

  3. C

    Ļ€2āˆ’(α+β+γ)\dfrac{\pi}{2} - (\alpha + \beta + \gamma)

  4. D

    π\pi

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Correct option: D

Q13JEE Main 2025 Jan 28 Shift 1Medium

cos⁔(sinā”āˆ’135+sinā”āˆ’1513+sinā”āˆ’13365)\cos\left(\sin^{-1}\frac{3}{5} + \sin^{-1}\frac{5}{13} + \sin^{-1}\frac{33}{65}\right) is equal to:

  1. A

    00

  2. B

    11

  3. C

    3265\frac{32}{65}

  4. D

    3365\frac{33}{65}

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Correct option: A

Q14JEE Main 2024 Apr 4 Shift 2Hard

Given that the inverse trigonometric function assumes principal values only. Let xx, yy be any two real numbers in [āˆ’1,1][-1, 1] such that cosā”āˆ’1xāˆ’sinā”āˆ’1y=α\cos^{-1} x - \sin^{-1} y = \alpha, āˆ’Ļ€2≤α≤π\dfrac{-\pi}{2} \le \alpha \le \pi. Then, the minimum value of x2+y2+2xysin⁔αx^2 + y^2 + 2xy \sin\alpha is

  1. A

    āˆ’1-1

  2. B

    āˆ’12\frac{-1}{2}

  3. C

    00

  4. D

    12\frac{1}{2}

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Correct option: C

Q15JEE Main 2024 Apr 6 Shift 1MediumNumerical

For n∈Nn \in \mathbb{N}, if cotā”āˆ’13+cotā”āˆ’14+cotā”āˆ’15+cotā”āˆ’1n=Ļ€4\cot^{-1} 3 + \cot^{-1} 4 + \cot^{-1} 5 + \cot^{-1} n = \dfrac{\pi}{4}, then nn is equal to ________.

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Answer: 47

Q16JEE Main 2024 Apr 9 Shift 2MediumNumerical

Let the inverse trigonometric functions take principal values. The number of real solutions of the equation 2sinā”āˆ’1x+3cosā”āˆ’1x=2Ļ€52\sin^{-1}x+3\cos^{-1}x=\dfrac{2\pi}{5}, is ________.

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Answer: 0

Q17JEE Main 2024 Jan 31 Shift 1Medium

For α,β,γ≠0\alpha, \beta, \gamma \neq 0, if sinā”āˆ’1α+sinā”āˆ’1β+sinā”āˆ’1γ=Ļ€\sin^{-1}\alpha+\sin^{-1}\beta+\sin^{-1}\gamma=\pi and (α+β+γ)(Ī±āˆ’Ī³+β)=3αβ(\alpha+\beta+\gamma)(\alpha-\gamma+\beta)=3\alpha\beta, then γ\gamma equals

  1. A

    32\frac{\sqrt{3}}{2}

  2. B

    12\frac{1}{\sqrt{2}}

  3. C

    3\sqrt{3}

  4. D

    3āˆ’122\frac{\sqrt{3}-1}{2\sqrt{2}}

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Correct option: A

Q18JEE Main 2024 Jan 31 Shift 2Medium

If a=sinā”āˆ’1(sin⁔(5))a=\sin ^{-1}(\sin (5)) and b=cosā”āˆ’1(cos⁔(5))b=\cos ^{-1}(\cos (5)), then a2+b2a^{2}+b^{2} is equal to

  1. A

    25

  2. B

    4Ļ€2+254 \pi^{2}+25

  3. C

    4Ļ€2āˆ’20Ļ€+504 \pi^{2}-20 \pi+50

  4. D

    8Ļ€2āˆ’40Ļ€+508 \pi^{2}-40 \pi+50

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Correct option: D