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Mathematics

Limits, Continuity and Differentiability β€” JEE Main PYQs

66 previous year questions

Q1JEE Main 2026 Apr 2 Shift 2HardNumerical

The number of points in the interval [2,4][2, 4], at which the function f(x)=[x2βˆ’xβˆ’12]f(x) = \left[x^2 - x - \frac{1}{2}\right], where [β‹…][\cdot] denotes the greatest integer function, is discontinuous, is __________.

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Answer: 10

Q2JEE Main 2026 Apr 4 Shift 1HardNumerical

The number of points, at which the function f(x)=max⁑{6x,2+3x2}+∣xβˆ’1∣cos⁑∣x2βˆ’14∣f(x) = \max\{6x, 2 + 3x^2\} + |x - 1|\cos\left|x^2 - \frac{1}{4}\right|, x∈(βˆ’Ο€,Ο€)x \in (-\pi, \pi), is not differentiable, is ______.

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Answer: 3

Q3JEE Main 2026 Apr 4 Shift 2HardNumerical

Let f(x)={exβˆ’1,Β x<0x2βˆ’5x+6,Β xβ‰₯0f(x) = \begin{cases} e^{x-1} & , \ x < 0 \\ x^2 - 5x + 6 & , \ x \ge 0 \end{cases} and g(x)=f(∣x∣)+∣f(x)∣g(x) = f(|x|) + |f(x)|. If the number of points where gg is not continuous and is not differentiable are Ξ±\alpha and Ξ²\beta respectively, then Ξ±+Ξ²\alpha + \beta is equal to __________

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Answer: 4

Q4JEE Main 2026 Apr 5 Shift 1Hard

The product of all possible values of Ξ±\alpha, for which

lim⁑xβ†’0(1βˆ’cos⁑(Ξ±x)cos⁑((Ξ±+1)x)cos⁑((Ξ±+2)x)sin⁑2((Ξ±+1)x))=2,Β is:\lim_{x \to 0} \left( \frac{1 - \cos(\alpha x)\cos\left( (\alpha+1)x \right)\cos\left( (\alpha+2)x \right)}{\sin^2\left( (\alpha+1)x \right)} \right) = 2, \text{ is:}

  1. A

    βˆ’2-2

  2. B

    1

  3. C

    βˆ’1-1

  4. D

    54\frac{5}{4}

Show answer

Correct option: C

Q5JEE Main 2026 Apr 5 Shift 2Medium

Let f(x)=lim⁑yβ†’0(1βˆ’cos⁑(xy))tan⁑(xy)y3f(x) = \displaystyle\lim_{y \to 0} \frac{(1 - \cos(xy))\tan(xy)}{y^3}. Then the number of solutions of the equation f(x)=sin⁑xf(x) = \sin x, x∈Rx \in \mathbf{R} is :

  1. A

    0

  2. B

    2

  3. C

    3

  4. D

    1

Show answer

Correct option: C

Q6JEE Main 2026 Apr 6 Shift 1Easy

The value of lim⁑xβ†’0(x2sin⁑2xx2βˆ’sin⁑2x)\lim\limits_{x \to 0}\left(\frac{x^2\sin^2 x}{x^2-\sin^2 x}\right) is:

  1. A

    22

  2. B

    33

  3. C

    44

  4. D

    66

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Correct option: B

Q7JEE Main 2026 Apr 6 Shift 2Hard

Let lim⁑xβ†’2(tan⁑(xβˆ’2))(rx2+(pβˆ’2)xβˆ’2p)(xβˆ’2)2=5\lim_{x \to 2} \frac{(\tan(x - 2))\left(rx^2 + (p - 2)x - 2p\right)}{(x - 2)^2} = 5 for some r,p∈Rr, p \in \mathbb{R}. If the set of all possible values of qq, such that the roots of the equation rx2βˆ’px+q=0rx^2 - px + q = 0 lie in (0,2)(0, 2), be the interval (Ξ±,Ξ²](\alpha, \beta], then 4(Ξ±+Ξ²)4(\alpha + \beta) equals :

  1. A

    1111

  2. B

    1313

  3. C

    1717

  4. D

    2121

Show answer

Correct option: C

Q8JEE Main 2026 Apr 6 Shift 2MediumNumerical

Let f(x)={x3+8Β ;x<0,x2βˆ’4Β ;xβ‰₯0,f(x) = \begin{cases} x^3 + 8\ ; & x < 0, \\ x^2 - 4\ ; & x \ge 0, \end{cases} and g(x)={(xβˆ’8)1/3Β ;x<0,(x+4)1/2Β ;xβ‰₯0.g(x) = \begin{cases} (x - 8)^{1/3}\ ; & x < 0, \\ (x + 4)^{1/2}\ ; & x \ge 0. \end{cases} Then the number of points, where the function g∘fg \circ f is discontinuous, is ________.

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Answer: 3

Q9JEE Main 2026 Apr 8 Shift 2Medium

For the function f(x)=esin⁑∣xβˆ£βˆ’βˆ£x∣f(x) = e^{\sin|x|} - |x|, x∈Rx \in \mathbb{R}, consider the following statements :

Statement I : ff is differentiable for all x∈Rx \in \mathbb{R}.

Statement II : ff is increasing in (βˆ’Ο€,βˆ’Ο€2)\left(-\pi, -\frac{\pi}{2}\right).

In the light of the above statements, choose the correct answer from the options given below :

  1. A

    Both Statement I and Statement II are true

  2. B

    Both Statement I and Statement II are false

  3. C

    Statement I is true but Statement II is false

  4. D

    Statement I is false but Statement II is true

Show answer

Correct option: A

Q10JEE Main 2026 Apr 8 Shift 2Medium

Let f(x)={13,x≀π/2b(1βˆ’sin⁑x)(Ο€βˆ’2x)2,x>Ο€/2f(x) = \begin{cases} \frac{1}{3}, & x \le \pi/2 \\ \frac{b(1 - \sin x)}{(\pi - 2x)^2}, & x > \pi/2 \end{cases}. If ff is continuous at x=Ο€/2x = \pi/2, then the value of ∫03bβˆ’6∣x2+2xβˆ’3βˆ£β€‰dx\int_0^{3b-6} \left|x^2 + 2x - 3\right|\, dx is :

  1. A

    55

  2. B

    22

  3. C

    33

  4. D

    44

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Correct option: D

Q11JEE Main 2025 Apr 2 Shift 1Medium

For Ξ±,Ξ²,γ∈R\alpha, \beta, \gamma \in \mathbf{R}, if lim⁑xβ†’0x2sin⁑αx+(Ξ³βˆ’1)ex2sin⁑2xβˆ’Ξ²x=3\lim_{x \to 0} \frac{x^2 \sin\alpha x + (\gamma - 1)\mathrm{e}^{x^2}}{\sin 2x - \beta x} = 3, then Ξ²+Ξ³βˆ’Ξ±\beta + \gamma - \alpha is equal to :

  1. A

    βˆ’1-1

  2. B

    4

  3. C

    6

  4. D

    7

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Correct option: D

Q12JEE Main 2025 Apr 2 Shift 2Medium

If lim⁑xβ†’0cos⁑(2x)+acos⁑(4x)βˆ’bx4\displaystyle\lim_{x \to 0} \frac{\cos(2x)+a\cos(4x)-b}{x^4} is finite, then (a+b)(a+b) is equal to :

  1. A

    12\frac{1}{2}

  2. B

    0

  3. C

    34\frac{3}{4}

  4. D

    βˆ’1-1

Show answer

Correct option: A

Q13JEE Main 2025 Apr 3 Shift 1Medium

Let f(x)={(1+ax)1/x,Β x<01+b,Β x=0(x+4)1/2βˆ’2(x+c)1/3βˆ’2,Β x>0f(x) = \begin{cases} (1+ax)^{1/x} & , \ x < 0 \\ 1+b & , \ x = 0 \\ \dfrac{(x+4)^{1/2} - 2}{(x+c)^{1/3} - 2} & , \ x > 0 \end{cases}

be continuous at x=0x = 0. Then eabce^{a}bc is equal to:

  1. A

    48

  2. B

    64

  3. C

    72

  4. D

    36

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Correct option: A

Q14JEE Main 2025 Apr 3 Shift 2MediumNumerical

If lim⁑xβ†’0(tan⁑xx)1x2=p\displaystyle\lim_{x \to 0}\left(\dfrac{\tan x}{x}\right)^{\frac{1}{x^2}} = p, then 96log⁑ep96\log_e p is equal to __________

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Answer: 32

Q15JEE Main 2025 Apr 4 Shift 1Medium

If lim⁑xβ†’1+(xβˆ’1)(6+Ξ»cos⁑(xβˆ’1))+ΞΌsin⁑(1βˆ’x)(xβˆ’1)3=βˆ’1\lim\limits_{x \to 1^{+}} \frac{(x-1)(6 + \lambda\cos(x-1)) + \mu\sin(1-x)}{(x-1)^3} = -1, where Ξ»,μ∈R\lambda, \mu \in \mathbb{R}, then Ξ»+ΞΌ\lambda + \mu is equal to

  1. A

    17

  2. B

    18

  3. C

    19

  4. D

    20

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Correct option: B

Q16JEE Main 2025 Apr 4 Shift 1Medium

Let f:Rβ†’Rf : \mathbb{R} \to \mathbb{R} be a continuous function satisfying f(0)=1f(0) = 1 and f(2x)βˆ’f(x)=xf(2x) - f(x) = x for all x∈Rx \in \mathbb{R}. If lim⁑nβ†’βˆž{f(x)βˆ’f(x2n)}=G(x)\lim\limits_{n \to \infty}\left\{f(x) - f\left(\frac{x}{2^n}\right)\right\} = G(x), then βˆ‘r=110G(r2)\sum\limits_{r=1}^{10} G(r^2) is equal to

  1. A

    215

  2. B

    385

  3. C

    420

  4. D

    540

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Correct option: B

Q17JEE Main 2025 Apr 4 Shift 1MediumNumerical

Let mm and nn be the number of points at which the function f(x)=max⁑{x,x3,x5,…,x21}f(x) = \max\{x, x^3, x^5, \ldots, x^{21}\}, x∈Rx \in \mathbb{R}, is not differentiable and not continuous, respectively. Then m+nm + n is equal to ________

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Answer: 3

Q18JEE Main 2025 Apr 4 Shift 2Medium

Let ff be a differentiable function on R\mathbf{R} such that f(2)=1,fβ€²(2)=4f(2)=1, f'(2)=4. Let lim⁑xβ†’0(f(2+x))3/x=eΞ±\lim\limits_{x\to 0}\left(f(2+x)\right)^{3/x}=\mathrm{e}^{\alpha}. Then the number of times the curve y=4x3βˆ’4x2βˆ’4(Ξ±βˆ’7)xβˆ’Ξ±y=4x^3-4x^2-4(\alpha-7)x-\alpha meets xx-axis is :

  1. A

    00

  2. B

    11

  3. C

    22

  4. D

    33

Show answer

Correct option: C

Q19JEE Main 2025 Apr 7 Shift 1Medium

lim⁑xβ†’0+tan⁑(5(x)13)log⁑e(1+3x2)(tanβ‘βˆ’13x)2(e5(x)43βˆ’1)\lim_{x \to 0^+} \frac{\tan\left(5(x)^{\frac{1}{3}}\right) \log_e\left(1 + 3x^2\right)}{\left(\tan^{-1} 3\sqrt{x}\right)^2 \left(e^{5(x)^{\frac{4}{3}}} - 1\right)} is equal to

  1. A

    1

  2. B

    13\frac{1}{3}

  3. C

    53\frac{5}{3}

  4. D

    115\frac{1}{15}

Show answer

Correct option: B

Q20JEE Main 2025 Apr 7 Shift 1HardNumerical

The number of points of discontinuity of the function f(x)=[x22]βˆ’[x]f(x) = \left[\frac{x^2}{2}\right] - \left[\sqrt{x}\right], x∈[0,4]x \in [0, 4], where [β‹…][\cdot] denotes the greatest integer function, is __________

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Answer: 8

Q21JEE Main 2025 Apr 7 Shift 2HardNumerical

For t>βˆ’1t > -1, let Ξ±t\alpha_t and Ξ²t\beta_t be the roots of the equation ((t+2)1/7βˆ’1)x2+((t+2)1/6βˆ’1)x+((t+2)1/21βˆ’1)=0\left(\left(t + 2\right)^{1/7} - 1\right)x^2 + \left(\left(t + 2\right)^{1/6} - 1\right)x + \left(\left(t + 2\right)^{1/21} - 1\right) = 0. If lim⁑tβ†’βˆ’1+Ξ±t=a\lim\limits_{t \to -1^+} \alpha_t = a and lim⁑tβ†’βˆ’1+Ξ²t=b\lim\limits_{t \to -1^+} \beta_t = b, then 72(a+b)272(a + b)^2 is equal to _________.

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Answer: 98

Q22JEE Main 2025 Apr 7 Shift 2MediumNumerical

If the function f(x)=tan⁑(tan⁑x)βˆ’sin⁑(sin⁑x)tan⁑xβˆ’sin⁑xf(x) = \dfrac{\tan(\tan x) - \sin(\sin x)}{\tan x - \sin x} is continuous at x=0x = 0, then f(0)f(0) is equal to _________.

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Answer: 2

Q23JEE Main 2025 Apr 8 Shift 2Medium

Given below are two statements:

Statement I : lim⁑xβ†’0(tanβ‘βˆ’1x+log⁑e1+x1βˆ’xβˆ’2xx5)=25\lim\limits_{x \to 0}\left(\frac{\tan^{-1}x + \log_e\sqrt{\frac{1+x}{1-x}} - 2x}{x^5}\right) = \frac{2}{5}

Statement II : lim⁑xβ†’1(x21βˆ’x)=1e2\lim\limits_{x \to 1}\left(x^{\frac{2}{1-x}}\right) = \frac{1}{e^2}

In the light of the above statements, choose the correct answer from the options given below

  1. A

    Both Statement I and Statement II are true

  2. B

    Both Statement I and Statement II are false

  3. C

    Statement I is true but Statement II is false

  4. D

    Statement I is false but Statement II is true

Show answer

Correct option: A

Q24JEE Main 2025 Jan 22 Shift 1Hard

Let f(x)f(x) be a real differentiable function such that f(0)=1f(0)=1 and f(x+y)=f(x)fβ€²(y)+fβ€²(x)f(y)f(x+y)=f(x)f'(y)+f'(x)f(y) for all x,y∈Rx, y \in \mathbb{R}. Then βˆ‘n=1100log⁑ef(n)\sum_{n=1}^{100} \log_e f(n) is equal to :

  1. A

    2384

  2. B

    2406

  3. C

    2525

  4. D

    5220

Show answer

Correct option: C

Q25JEE Main 2025 Jan 22 Shift 2Medium

If lim⁑xβ†’βˆž((e1βˆ’e)(1eβˆ’x1+x))x=Ξ±\lim\limits_{x \to \infty} \left( \left( \dfrac{e}{1-e} \right) \left( \dfrac{1}{e} - \dfrac{x}{1+x} \right) \right)^{x} = \alpha, then the value of log⁑eΞ±1+log⁑eΞ±\dfrac{\log_e \alpha}{1 + \log_e \alpha} equals :

  1. A

    [Option unreadable: option image corrupted in source PDF]

  2. B

    [Option unreadable: option image corrupted in source PDF]

  3. C

    [Option unreadable: option image corrupted in source PDF]

  4. D

    [Option unreadable: option image corrupted in source PDF]

Show answer

Correct option: B

Q26JEE Main 2025 Jan 23 Shift 1Medium

If the function

f(x)={2x{sin⁑(k1+1)x+sin⁑(k2βˆ’1)x},x<04,x=02xlog⁑e(2+k1x2+k2x),x>0f(x) = \begin{cases} \frac{2}{x}\{\sin(k_1 + 1)x + \sin(k_2 - 1)x\}, & x < 0 \\ 4, & x = 0 \\ \frac{2}{x}\log_e\left(\frac{2 + k_1 x}{2 + k_2 x}\right), & x > 0 \end{cases}

is continuous at x=0x = 0, then k12+k22k_1^2 + k_2^2 is equal to

  1. A

    55

  2. B

    88

  3. C

    1010

  4. D

    2020

Show answer

Correct option: C

Q27JEE Main 2025 Jan 23 Shift 2Medium

lim⁑xβ†’βˆž(2x2βˆ’3x+5)(3xβˆ’1)x2(3x2+5x+4)(3x+2)x\lim\limits_{x \to \infty} \dfrac{(2x^2 - 3x + 5)(3x - 1)^{\frac{x}{2}}}{(3x^2 + 5x + 4)\sqrt{(3x + 2)^x}} is equal to :

  1. A

    2e3\dfrac{2\mathrm{e}}{3}

  2. B

    23e\dfrac{2}{3\sqrt{\mathrm{e}}}

  3. C

    23e\dfrac{2}{\sqrt{3\mathrm{e}}}

  4. D

    2e3\dfrac{2\mathrm{e}}{\sqrt{3}}

Show answer

Correct option: B

Q28JEE Main 2025 Jan 24 Shift 1Medium

lim⁑xβ†’0cosec⁑x(2cos⁑2x+3cos⁑xβˆ’cos⁑2x+sin⁑x+4)\lim_{x \to 0} \operatorname{cosec} x\left(\sqrt{2\cos^2 x + 3\cos x} - \sqrt{\cos^2 x + \sin x + 4}\right) is:

  1. A

    0

  2. B

    125\frac{1}{2\sqrt{5}}

  3. C

    βˆ’125-\frac{1}{2\sqrt{5}}

  4. D

    115\frac{1}{\sqrt{15}}

Show answer

Correct option: C

Q29JEE Main 2025 Jan 24 Shift 1Medium

Let f:Rβˆ’{0}β†’Rf: \mathbb{R}-\{0\} \to \mathbb{R} be a function such that f(x)βˆ’6f(1x)=353xβˆ’52f(x)-6f\left(\frac{1}{x}\right)=\frac{35}{3x}-\frac{5}{2}. If the lim⁑xβ†’0(1Ξ±x+f(x))=Ξ²\lim_{x \to 0}\left(\frac{1}{\alpha x}+f(x)\right)=\beta ; Ξ±,β∈R\alpha, \beta \in \mathbb{R}, then Ξ±+2Ξ²\alpha + 2\beta is equal to

  1. A

    3

  2. B

    4

  3. C

    5

  4. D

    6

Show answer

Correct option: B

Q30JEE Main 2025 Jan 24 Shift 2Medium

Let [x][x] denote the greatest integer function, and let m and n respectively be the numbers of the points, where the function f(x)=[x]+∣xβˆ’2∣f(x) = [x] + |x - 2|, βˆ’2<x<3-2 < x < 3, is not continuous and not differentiable. Then m+n\mathrm{m + n} is equal to :

  1. A

    6

  2. B

    7

  3. C

    8

  4. D

    9

Show answer

Correct option: C

Q31JEE Main 2025 Jan 28 Shift 1HardNumerical

Let f(x)={3x,x<0min⁑{1+x+[x],x+2[x]},0≀x≀25,x>2,f(x) = \begin{cases} 3x, & x < 0 \\ \min\{1 + x + [x], x + 2[x]\}, & 0 \le x \le 2 \\ 5, & x > 2, \end{cases} where [.][.] denotes greatest integer function. If Ξ±\alpha and Ξ²\beta are the number of points, where ff is not continuous and is not differentiable, respectively, then Ξ±+Ξ²\alpha + \beta equals ____.

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Answer: 5

Q32JEE Main 2025 Jan 28 Shift 2HardNumerical

Let f(x)=lim⁑nβ†’βˆžβˆ‘r=0n(tan⁑(x/2r+1)+tan⁑3(x/2r+1)1βˆ’tan⁑2(x/2r+1))f(x) = \lim_{n \to \infty} \sum_{r=0}^{n} \left(\frac{\tan\left(x/2^{r+1}\right) + \tan^3\left(x/2^{r+1}\right)}{1 - \tan^2\left(x/2^{r+1}\right)}\right). Then lim⁑xβ†’0exβˆ’ef(x)(xβˆ’f(x))\lim_{x \to 0} \frac{\mathrm{e}^x - \mathrm{e}^{f(x)}}{(x - f(x))} is equal to __________.

Show answer

Answer: 1

Q33JEE Main 2024 Apr 4 Shift 1Medium

Let f:R→Rf: \mathbf{R} \to \mathbf{R} be a function given by

f(x)={1βˆ’cos⁑2xx2,x<0Ξ±,x=0,Ξ²1βˆ’cos⁑xx,x>0f(x)=\begin{cases} \frac{1-\cos 2x}{x^{2}}, & x<0 \\ \alpha, & x=0, \\ \frac{\beta\sqrt{1-\cos x}}{x}, & x>0 \end{cases}

where α,β∈R\alpha, \beta \in \mathbf{R}. If ff is continuous at x=0x=0, then α2+β2\alpha^{2}+\beta^{2} is equal to :

  1. A

    33

  2. B

    66

  3. C

    1212

  4. D

    4848

Show answer

Correct option: C

Q34JEE Main 2024 Apr 4 Shift 1MediumNumerical

If lim⁑xβ†’1(5x+1)1/3βˆ’(x+5)1/3(2x+3)1/2βˆ’(x+4)1/2=m5n(2n)2/3\lim\limits_{x \to 1} \frac{(5x+1)^{1/3}-(x+5)^{1/3}}{(2x+3)^{1/2}-(x+4)^{1/2}}=\frac{m\sqrt{5}}{n(2n)^{2/3}}, where gcd⁑(m,n)=1\gcd(m, n)=1, then 8m+12n8m+12n is equal to ________.

Show answer

Answer: 100

Q35JEE Main 2024 Apr 4 Shift 2Medium

If the function f(x)={72xβˆ’9xβˆ’8x+12βˆ’1+cos⁑x,Β xβ‰ 0alog⁑e2log⁑e3,Β x=0f(x) = \begin{cases} \dfrac{72^x - 9^x - 8^x + 1}{\sqrt{2} - \sqrt{1 + \cos x}} & , \ x \ne 0 \\ a \log_e 2 \log_e 3 & , \ x = 0 \end{cases} is continuous at x=0x = 0, then the value of a2a^2 is equal to

  1. A

    746746

  2. B

    968968

  3. C

    11521152

  4. D

    12501250

Show answer

Correct option: C

Q36JEE Main 2024 Apr 4 Shift 2Medium

Let f(x)=∫0x(t+sin⁑(1βˆ’et))dt,x∈Rf(x) = \int_0^x \left(t + \sin\left(1 - e^t\right)\right) dt, x \in \mathbb{R}. Then, lim⁑xβ†’0f(x)x3\lim\limits_{x \to 0} \dfrac{f(x)}{x^3} is equal to

  1. A

    23\frac{2}{3}

  2. B

    βˆ’23-\frac{2}{3}

  3. C

    16\frac{1}{6}

  4. D

    βˆ’16-\frac{1}{6}

Show answer

Correct option: D

Q37JEE Main 2024 Apr 5 Shift 1Medium

If the function f(x)=sin⁑3x+Ξ±sin⁑xβˆ’Ξ²cos⁑3xx3f(x) = \dfrac{\sin 3x + \alpha \sin x - \beta \cos 3x}{x^3}, x∈Rx \in \mathbb{R}, is continuous at x=0x = 0, then f(0)f(0) is equal to :

  1. A

    22

  2. B

    βˆ’2-2

  3. C

    44

  4. D

    βˆ’4-4

Show answer

Correct option: D

Q38JEE Main 2024 Apr 5 Shift 2Medium

Let f:[βˆ’1,2]β†’Rf : [-1, 2] \rightarrow \mathbf{R} be given by f(x)=2x2+x+[x2]βˆ’[x]f(x) = 2x^2 + x + [x^2] - [x], where [t][t] denotes the greatest integer less than or equal to tt. The number of points, where ff is not continuous, is :

  1. A

    6

  2. B

    5

  3. C

    4

  4. D

    3

Show answer

Correct option: C

Q39JEE Main 2024 Apr 5 Shift 2HardNumerical

Let a>0a > 0 be a root of the equation 2x2+xβˆ’2=02x^2 + x - 2 = 0. If lim⁑xβ†’1a16(1βˆ’cos⁑(2+xβˆ’2x2))(1βˆ’ax)2=Ξ±+Ξ²17\lim\limits_{x \to \frac{1}{a}} \dfrac{16\left(1 - \cos(2 + x - 2x^2)\right)}{(1 - ax)^2} = \alpha + \beta\sqrt{17}, where Ξ±,β∈Z\alpha, \beta \in \mathbb{Z}, then Ξ±+Ξ²\alpha + \beta is equal to ________.

Show answer

Answer: 170

Q40JEE Main 2024 Apr 6 Shift 1Hard

Let f:(βˆ’βˆž,∞)βˆ’{0}β†’Rf : (-\infty, \infty) - \{0\} \to \mathbb{R} be a differentiable function such that fβ€²(1)=lim⁑aβ†’βˆža2f(1a)f'(1) = \lim\limits_{a \to \infty} a^2 f\left(\dfrac{1}{a}\right). Then lim⁑aβ†’βˆža(a+1)2tanβ‘βˆ’1(1a)+a2βˆ’2log⁑ea\lim\limits_{a \to \infty} \dfrac{a(a+1)}{2} \tan^{-1}\left(\dfrac{1}{a}\right) + a^2 - 2\log_e a is equal to

  1. A

    52+Ο€8\dfrac{5}{2} + \dfrac{\pi}{8}

  2. B

    32+Ο€4\dfrac{3}{2} + \dfrac{\pi}{4}

  3. C

    38+Ο€4\dfrac{3}{8} + \dfrac{\pi}{4}

  4. D

    34+Ο€8\dfrac{3}{4} + \dfrac{\pi}{8}

Q41JEE Main 2024 Apr 6 Shift 1Medium

If f(x)={x3sin⁑(1x),xβ‰ 00,x=0f(x) = \begin{cases} x^3 \sin\left(\dfrac{1}{x}\right), & x \neq 0 \\ 0, & x = 0 \end{cases}, then

  1. A

    fβ€²β€²(0)=0f''(0) = 0

  2. B

    fβ€²β€²(2Ο€)=24βˆ’Ο€22Ο€f''\left(\dfrac{2}{\pi}\right) = \dfrac{24 - \pi^2}{2\pi}

  3. C

    fβ€²β€²(0)=1f''(0) = 1

  4. D

    fβ€²β€²(2Ο€)=12βˆ’Ο€22Ο€f''\left(\dfrac{2}{\pi}\right) = \dfrac{12 - \pi^2}{2\pi}

Show answer

Correct option: B

Q42JEE Main 2024 Apr 6 Shift 2Medium

lim⁑nβ†’βˆž(12βˆ’1)(nβˆ’1)+(22βˆ’2)(nβˆ’2)+β‹―+((nβˆ’1)2βˆ’(nβˆ’1))β‹…1(13+23+β‹―+n3)βˆ’(12+22+β‹―+n2)\lim\limits_{\mathrm{n}\to\infty} \dfrac{\left(1^2-1\right)(\mathrm{n}-1)+\left(2^2-2\right)(\mathrm{n}-2)+\cdots+\left((\mathrm{n}-1)^2-(\mathrm{n}-1)\right)\cdot 1}{\left(1^3+2^3+\cdots+\mathrm{n}^3\right)-\left(1^2+2^2+\cdots+\mathrm{n}^2\right)} is equal to :

  1. A

    12\frac{1}{2}

  2. B

    13\frac{1}{3}

  3. C

    23\frac{2}{3}

  4. D

    34\frac{3}{4}

Show answer

Correct option: B

Q43JEE Main 2024 Apr 6 Shift 2MediumNumerical

Let [t][t] denote the greatest integer less than or equal to tt. Let f:[0,∞)β†’Rf:[0, \infty) \to \mathbf{R} be a function defined by f(x)=[x2+3]βˆ’[x]f(x)=\left[\dfrac{x}{2}+3\right]-\left[\sqrt{x}\right]. Let SS be the set of all points in the interval [0,8][0, 8] at which ff is not continuous. Then βˆ‘a∈Sa\sum\limits_{\mathrm{a}\in S} \mathrm{a} is equal to ________.

Show answer

Answer: 17

Q44JEE Main 2024 Apr 8 Shift 1HardNumerical

The value of lim⁑xβ†’02(1βˆ’cos⁑xcos⁑2x cos⁑3x3 ...... cos⁑10x10x2)\lim_{x\to 0} 2\left(\frac{1-\cos x\sqrt{\cos 2x}\,\sqrt[3]{\cos 3x}\,......\,\sqrt[10]{\cos 10x}}{x^2}\right) is __________.

Show answer

Answer: 55

Q45JEE Main 2024 Apr 8 Shift 2Hard

For a,b>0a, b > 0, let f(x)={tan⁑((a+1)x)+btan⁑xx,x<03,x=0ax+b2x2βˆ’axba xx,x>0f(x) = \begin{cases} \dfrac{\tan((a+1)x) + b\tan x}{x}, & x < 0 \\ 3, & x = 0 \\ \dfrac{\sqrt{ax + b^2x^2} - \sqrt{ax}}{b\sqrt{a}\, x\sqrt{x}}, & x > 0 \end{cases}

be a continous function at x=0x = 0. Then ba\dfrac{b}{a} is equal to :

  1. A

    66

  2. B

    55

  3. C

    44

  4. D

    88

Show answer

Correct option: A

Q46JEE Main 2024 Apr 8 Shift 2HardNumerical

If Ξ±=lim⁑xβ†’0+(etan⁑xβˆ’extan⁑xβˆ’x)\alpha = \displaystyle\lim_{x \to 0^+} \left( \dfrac{\mathrm{e}^{\sqrt{\tan x}} - \mathrm{e}^{\sqrt{x}}}{\sqrt{\tan x} - \sqrt{x}} \right) and Ξ²=lim⁑xβ†’0(1+sin⁑x)12cot⁑x\beta = \displaystyle\lim_{x \to 0} (1 + \sin x)^{\frac{1}{2}\cot x} are the roots of the quadratic equation ax2+bxβˆ’e=0ax^2 + bx - \sqrt{\mathrm{e}} = 0, then 12log⁑e(a+b)12\log_e(a + b) is equal to ________.

Show answer

Answer: 6

Q47JEE Main 2024 Apr 9 Shift 1MediumNumerical

Let f:(0,Ο€)β†’Rf:(0, \pi)\to\mathbf{R} be a function given by f(x)={(87)tan⁑8xtan⁑7x,0<x<Ο€2aβˆ’8,x=Ο€2(1+∣cot⁑x∣)ba∣tan⁑x∣,Ο€2<x<Ο€f(x)=\begin{cases}\left(\frac{8}{7}\right)^{\frac{\tan 8x}{\tan 7x}}, & 0<x<\frac{\pi}{2}\\ \mathrm{a}-8, & x=\frac{\pi}{2}\\ \left(1+|\cot x|\right)^{\frac{\mathrm{b}}{\mathrm{a}}|\tan x|}, & \frac{\pi}{2}<x<\pi\end{cases}

where a,b∈Z\mathrm{a}, \mathrm{b}\in\mathbf{Z}. If ff is continuous at x=Ο€2x=\frac{\pi}{2}, then a2+b2\mathrm{a}^2+\mathrm{b}^2 is equal to ________.

Show answer

Answer: 81

Q48JEE Main 2024 Apr 9 Shift 1HardNumerical

Let lim⁑nβ†’βˆž(nn4+1βˆ’2n(n2+1)n4+1+nn4+16βˆ’8n(n2+4)n4+16+…+nn4+n4βˆ’2nβ‹…n2(n2+n2)n4+n4)\lim\limits_{\mathrm{n}\to\infty}\left(\frac{\mathrm{n}}{\sqrt{\mathrm{n}^4+1}}-\frac{2\mathrm{n}}{(\mathrm{n}^2+1)\sqrt{\mathrm{n}^4+1}}+\frac{\mathrm{n}}{\sqrt{\mathrm{n}^4+16}}-\frac{8\mathrm{n}}{(\mathrm{n}^2+4)\sqrt{\mathrm{n}^4+16}}+\ldots+\frac{\mathrm{n}}{\sqrt{\mathrm{n}^4+\mathrm{n}^4}}-\frac{2\mathrm{n}\cdot\mathrm{n}^2}{(\mathrm{n}^2+\mathrm{n}^2)\sqrt{\mathrm{n}^4+\mathrm{n}^4}}\right) be Ο€k\frac{\pi}{\mathrm{k}}, using only the principal values of the inverse trigonometric functions. Then k2\mathrm{k}^2 is equal to ________.

Show answer

Answer: 32

Q49JEE Main 2024 Apr 9 Shift 2Medium

lim⁑xβ†’0eβˆ’(1+2x)12xx\lim\limits_{x \to 0} \dfrac{e-(1+2x)^{\frac{1}{2x}}}{x} is equal to

  1. A

    ee

  2. B

    00

  3. C

    eβˆ’e2e-e^2

  4. D

    βˆ’2e\frac{-2}{e}

Show answer

Correct option: A

Q50JEE Main 2024 Apr 9 Shift 2Hard

lim⁑xβ†’Ο€2(∫x3(Ο€/2)3(sin⁑(2t1/3)+cos⁑(t1/3))dt(xβˆ’Ο€2)2)\lim\limits_{x \to \frac{\pi}{2}}\left(\dfrac{\int_{x^3}^{(\pi/2)^3}\left(\sin\left(2t^{1/3}\right)+\cos\left(t^{1/3}\right)\right)dt}{\left(x-\frac{\pi}{2}\right)^2}\right) is equal to

  1. A

    3Ο€22\frac{3\pi^2}{2}

  2. B

    5Ο€29\frac{5\pi^2}{9}

  3. C

    9Ο€28\frac{9\pi^2}{8}

  4. D

    11Ο€210\frac{11\pi^2}{10}

Show answer

Correct option: C

Q51JEE Main 2024 Feb 1 Shift 1Medium

Let f:R→Rf: \mathbb{R} \to \mathbb{R} be defined as :

f(x)={aβˆ’bcos⁑2xx2;Β x<0x2+cx+2;Β 0≀x≀12x+1;Β x>1f(x) = \begin{cases} \dfrac{a - b\cos 2x}{x^2} & ;\ x < 0 \\ x^2 + cx + 2 & ;\ 0 \le x \le 1 \\ 2x + 1 & ;\ x > 1 \end{cases}

If ff is continuous everywhere in R\mathbb{R} and m is the number of points where ff is NOT differential then m+a+b+cm + a + b + c equals :

  1. A

    11

  2. B

    22

  3. C

    33

  4. D

    44

Show answer

Correct option: B

Q52JEE Main 2024 Feb 1 Shift 1HardNumerical

Let {x}\{x\} denote the fractional part of xx and f(x)=cosβ‘βˆ’1(1βˆ’{x}2)sinβ‘βˆ’1(1βˆ’{x}){x}βˆ’{x}3f(x) = \dfrac{\cos^{-1}\left(1 - \{x\}^2\right)\sin^{-1}(1 - \{x\})}{\{x\} - \{x\}^3}, xβ‰ 0x \neq 0. If L and R respectively denotes the left hand limit and the right hand limit of f(x)f(x) at x=0x = 0, then 32Ο€2(L2+R2)\dfrac{32}{\pi^2}\left(\mathrm{L}^2 + \mathrm{R}^2\right) is equal to ________.

Show answer

Answer: 18

Q53JEE Main 2024 Feb 1 Shift 2Medium

Let f(x)=∣2x2+5∣xβˆ£βˆ’3∣f(x)=|2x^2+5|x|-3|, x∈Rx \in \mathbf{R}. If mm and nn denote the number of points where ff is not continuous and not differentiable respectively, then m+nm+n is equal to :

  1. A

    00

  2. B

    22

  3. C

    33

  4. D

    55

Show answer

Correct option: C

Q54JEE Main 2024 Feb 1 Shift 2Medium

Let f(x)={xβˆ’1,xΒ isΒ even,2x,xΒ isΒ odd,β€…β€Šx∈Nf(x)=\begin{cases} x-1, & x \text{ is even,} \\ 2x, & x \text{ is odd,} \end{cases} \; x \in \mathbf{N}. If for some a∈Na \in \mathbf{N}, f(f(f(a)))=21f(f(f(a)))=21, then lim⁑xβ†’aβˆ’{∣x∣3aβˆ’[xa]}\lim_{x \to a^-}\left\{\frac{|x|^3}{a}-\left[\frac{x}{a}\right]\right\}, where [t][t] denotes the greatest integer less than or equal to tt, is equal to :

  1. A

    121121

  2. B

    144144

  3. C

    169169

  4. D

    225225

Show answer

Correct option: B

Q55JEE Main 2024 Jan 27 Shift 1Hard

Consider the function.

f(x)={a(7xβˆ’12βˆ’x2)b∣x2βˆ’7x+12∣,Β x<32sin⁑(xβˆ’3)xβˆ’[x],Β x>3b,Β x=3,f(x) = \begin{cases} \dfrac{a(7x - 12 - x^2)}{b|x^2 - 7x + 12|} & , \ x < 3 \\ 2^{\frac{\sin(x-3)}{x - [x]}} & , \ x > 3 \\ b & , \ x = 3 , \end{cases}

where [x][x] denotes the greatest integer less than or equal to xx. If S denotes the set of all ordered pairs (a, b) such that f(x)f(x) is continuous at x=3x = 3, then the number of elements in S is :

  1. A

    44

  2. B

    Infinitely many

  3. C

    11

  4. D

    22

Show answer

Correct option: C

Q56JEE Main 2024 Jan 27 Shift 1Medium

If a=lim⁑xβ†’01+1+x4βˆ’2x4a = \lim\limits_{x \to 0} \dfrac{\sqrt{1 + \sqrt{1 + x^4}} - \sqrt{2}}{x^4} and b=lim⁑xβ†’0sin⁑2x2βˆ’1+cos⁑xb = \lim\limits_{x \to 0} \dfrac{\sin^2 x}{\sqrt{2} - \sqrt{1 + \cos x}}, then the value of ab3ab^3 is :

  1. A

    2525

  2. B

    3030

  3. C

    3636

  4. D

    3232

Show answer

Correct option: D

Q57JEE Main 2024 Jan 29 Shift 1Hard

lim⁑xβ†’Ο€2(1(xβˆ’Ο€2)2∫x3(Ο€2)3cos⁑(t13)dt)\lim\limits_{x \to \frac{\pi}{2}}\left(\dfrac{1}{\left(x-\frac{\pi}{2}\right)^2}\int\limits_{x^3}^{\left(\frac{\pi}{2}\right)^3} \cos\left(t^{\frac{1}{3}}\right)dt\right) is equal to

  1. A

    3Ο€4\dfrac{3\pi}{4}

  2. B

    3Ο€8\dfrac{3\pi}{8}

  3. C

    3Ο€24\dfrac{3\pi^2}{4}

  4. D

    3Ο€28\dfrac{3\pi^2}{8}

Show answer

Correct option: D

Q58JEE Main 2024 Jan 30 Shift 1Medium

Let f:[βˆ’Ο€2,Ο€2]β†’Rf:\left[-\frac{\pi}{2}, \frac{\pi}{2}\right]\to \mathbf{R} be a differentiable function such that f(0)=12f(0)=\frac{1}{2}. If the lim⁑xβ†’0x∫0xf(t) dtex2βˆ’1=Ξ±\lim\limits_{x\to 0} \frac{x\int_0^x f(t)\,\mathrm{d}t}{e^{x^2}-1}=\alpha, then 8Ξ±28\alpha^2 is equal to :

  1. A

    11

  2. B

    22

  3. C

    44

  4. D

    1616

Show answer

Correct option: B

Q59JEE Main 2024 Jan 30 Shift 1Hard

Let g:Rβ†’Rg:\mathbf{R}\to\mathbf{R} be a non constant twice differentiable function such that gβ€²(12)=gβ€²(32)g'\left(\frac{1}{2}\right)=g'\left(\frac{3}{2}\right). If a real valued function ff is defined as f(x)=12[g(x)+g(2βˆ’x)]f(x)=\frac{1}{2}[g(x)+g(2-x)], then

  1. A

    fβ€²β€²(x)=0f''(x)=0 for atleast two xx in (0,2)(0, 2)

  2. B

    fβ€²β€²(x)=0f''(x)=0 for exactly one xx in (0,1)(0, 1)

  3. C

    fβ€²β€²(x)=0f''(x)=0 for no xx in (0,1)(0, 1)

  4. D

    fβ€²(32)+fβ€²(12)=1f'\left(\frac{3}{2}\right)+f'\left(\frac{1}{2}\right)=1

Show answer

Correct option: A

Q60JEE Main 2024 Jan 30 Shift 1MediumNumerical

If the function f(x)={1∣x∣,∣x∣β‰₯2ax2+2b,∣x∣<2f(x)=\begin{cases} \frac{1}{|x|}, & |x|\geq 2 \\ ax^2+2b, & |x|<2 \end{cases} is differentiable on R\mathbf{R}, then 48(a+b)48(a+b) is equal to ________.

Show answer

Answer: 15

Q61JEE Main 2024 Jan 30 Shift 2Medium

Let aa and bb be real constants such that the function ff defined by f(x)={x2+3x+a,Β x≀1bx+2,Β x>1f(x)=\begin{cases} x^2+3x+a & ,\ x \leq 1 \\ bx+2 & ,\ x > 1 \end{cases} be differentiable on R\mathbb{R}. Then, the value of βˆ«βˆ’22f(x) dx\int_{-2}^{2} f(x)\,dx equals

  1. A

    15/615/6

  2. B

    19/619/6

  3. C

    17

  4. D

    21

Show answer

Correct option: C

Q62JEE Main 2024 Jan 31 Shift 1Medium

lim⁑xβ†’0e2∣sin⁑xβˆ£βˆ’2∣sin⁑xβˆ£βˆ’1x2\lim_{x \to 0} \frac{e^{2|\sin x|}-2|\sin x|-1}{x^2}

  1. A

    is equal to 22

  2. B

    is equal to 11

  3. C

    is equal to βˆ’1-1

  4. D

    does not exist

Show answer

Correct option: A

Q63JEE Main 2024 Jan 31 Shift 1Hard

Let g(x)g(x) be a linear function and f(x)={g(x),x≀0(1+x2+x)1x,x>0f(x)=\begin{cases} g(x) & , x \leq 0 \\ \left(\frac{1+x}{2+x}\right)^{\frac{1}{x}} & , x>0 \end{cases}, is continuous at x=0x=0. If fβ€²(1)=f(βˆ’1)f'(1)=f(-1), then the value g(3)g(3) is

  1. A

    13log⁑e(49e1/3)\frac{1}{3}\log_e\left(\frac{4}{9e^{1/3}}\right)

  2. B

    log⁑e(49e1/3)\log_e\left(\frac{4}{9e^{1/3}}\right)

  3. C

    13log⁑e(49)+1\frac{1}{3}\log_e\left(\frac{4}{9}\right)+1

  4. D

    log⁑e(49)βˆ’1\log_e\left(\frac{4}{9}\right)-1

Show answer

Correct option: B

Q64JEE Main 2024 Jan 31 Shift 2Medium

Consider the function f:(0,∞)β†’Rf:(0, \infty) \rightarrow \mathbb{R} defined by f(x)=eβˆ’βˆ£log⁑ex∣f(x)=e^{-\left|\log _{e} x\right|}. If mm and nn be respectively the number of points at which ff is not continuous and ff is not differentiable, then m+nm+n is

  1. A

    0

  2. B

    1

  3. C

    2

  4. D

    3

Show answer

Correct option: B

Q65JEE Main 2024 Jan 31 Shift 2Medium

Let f:Rβ†’(0,∞)f: \mathbb{R} \rightarrow(0, \infty) be strictly increasing function such that lim⁑xβ†’βˆžf(7x)f(x)=1\lim _{x \rightarrow \infty} \frac{f(7 x)}{f(x)}=1. Then, the value of lim⁑xβ†’βˆž[f(5x)f(x)βˆ’1]\lim _{x \rightarrow \infty}\left[\frac{f(5 x)}{f(x)}-1\right] is equal to

  1. A

    1

  2. B

    7/5

  3. C

    4

  4. D

    0

Show answer

Correct option: D

Q66JEE Main 2024 Jan 31 Shift 2HardNumerical

If lim⁑xβ†’0ax2exβˆ’blog⁑e(1+x)+cxeβˆ’xx2sin⁑x=1\lim _{x \rightarrow 0} \frac{a x^{2} e^{x}-b \log _{e}(1+x)+c x e^{-x}}{x^{2} \sin x}=1, then 16(a2+b2+c2)16\left(a^{2}+b^{2}+c^{2}\right) is equal to ______.

Show answer

Answer: 81