Organic Compounds Containing Nitrogen — JEE Main PYQs
56 previous year questions
Q1JEE Main 2026 Apr 2 Shift 2Hard
Identify compounds A and E in the following reaction sequence.
Figure — described from the original paper
1-ethyl-4-nitrobenzene (benzene ring with C2H5 and NO2 para to each other)
Br2/AlBr3 A SnHCl B NaNO2/HCl273-278 K C C2H5OH D (i) KMnO4/KOH(ii) H3O+ E
A
Figure — described from the original paper
A = benzene ring with C2H5, with Br ortho to NO2 (meta to C2H5); E = 3-bromobenzoic acid
B
Figure — described from the original paper
A = 2-bromo-1-ethyl-4-nitrobenzene (Br ortho to C2H5); E = 2-bromobenzoic acid
C
Figure — described from the original paper
A = 1-(2-bromoethyl)-4-nitrobenzene (CH2CH2Br side chain, NO2 para); E = benzoic acid
D
Figure — described from the original paper
A = 2-bromo-1-ethyl-4-nitrobenzene (Br ortho to C2H5); E = 3-bromo-4-hydroxybenzoic acid (COOH with Br ortho and OH para)
Show answer
Correct option: B
Q2JEE Main 2026 Apr 2 Shift 2HardNumerical
Consider the following reactions sequence
Figure — described from the original paper
1-methyl-4-nitrobenzene (benzene ring with NO2 and H3C para to each other)
(i) Sn/HCl;OH−(ii) (CH3CO)2O(iii) Br2/AlBr3(iv) H3O+ Major Product (P)
When the product (P) is subjected to Carius analysis using AgNO3, 1.0 g of the product (P) will produce __________ g of the precipitate of AgBr. (Nearest Integer)
(Given : molar mass in g mol−1 C : 12, H : 1, O : 16, N : 14, Br : 80, Ag : 108)
Show answer
Answer: 1
Q3JEE Main 2026 Apr 4 Shift 1Medium
Product C of the following reaction sequence will be
Figure — described from the original paper
aniline as starting material
Aniline Br2/water A (Major Product) NaNO2/HCl273−278K B (i) HBF4(ii) NaNO2,Cu,Δ C
A
1-Bromo-4-nitrobenzene
B
1, 3, 5-Tribromo-2-nitrobenzene
C
4-Bromo-1-nitrobenzene
D
1, 3, 5-Tribromobenzene
Show answer
Correct option: B
Q4JEE Main 2026 Apr 4 Shift 2Medium
The strongest conjugate acid will result from:
A
Figure — described from the original paper
aniline — benzene ring with NH2
B
Figure — described from the original paper
4-methoxyaniline — benzene ring with NH2 and para OCH3
C
Figure — described from the original paper
4-nitroaniline — benzene ring with NH2 and para NO2
D
Figure — described from the original paper
4-methylaniline — benzene ring with NH2 and para CH3
Show answer
Correct option: C
Q5JEE Main 2026 Apr 5 Shift 1Hard
Identify the incorrect statements.
A.
Figure — described from the original paper
benzylamine
C6H5CH2NH2 is a stronger base than
Figure — described from the original paper
aniline
C6H5NH2
B.
Figure — described from the original paper
4-methoxyaniline (p-anisidine)
can be synthesized by Gabriel phthalimide synthesis.
C.
Figure — described from the original paper
2-phenylacetamide, C6H5CH2CONH2
Br2,NaOH primary aromatic amine
D.
Figure — described from the original paper
4-nitroaniline
(i) NaNO2,HCl,0∘C(ii) Δ product will dissolve in NaOH
Choose the correct answer from the options given below:
A
A and D Only
B
A and C Only
C
B and C Only
D
A and B Only
Show answer
Correct option: C
Q6JEE Main 2026 Apr 5 Shift 2Medium
Given below are two statements :
Statement I : Heating benzamide with bromine in an ethanolic solution of sodium hydroxide will give benzylamine.
Statement II : Nitration of aniline with HNO3/H2SO4 at 288 K produces m-nitroaniline in higher amount than o-nitroaniline (pH adjusted).
In the light of the above statements, choose the correct answer from the options given below :
A
Both Statement I and Statement II are true
B
Both Statement I and Statement II are false
C
Statement I is true but Statement II is false
D
Statement I is false but Statement II is true
Show answer
Correct option: D
Q7JEE Main 2026 Apr 6 Shift 1Easy
Arrange the following compounds according to increasing order of boiling points.
n-C4H9OH (A), n-C4H9NH2 (B), n-C4H10 (C) and C2H5NHC2H5 (D).
A
C < B < A < D
B
D < C < B < A
C
C < D < B < A
D
D < B < A < C
Show answer
Correct option: C
Q8JEE Main 2026 Apr 6 Shift 1HardNumerical
Consider the following sequence of reactions.
Figure — described from the original paper
diazoaminobenzene, C6H5−N=N−NH−C6H5
(i) HCl (ii) Aniline (in excess) (iii) Warm 40−45∘C (iv) Cool, acetic acid Yellow Product (X)
The percentage of nitrogen in the yellow product (X) formed is ________ %. (Nearest Integer)
(Given Molar mass in g mol−1 H:1, C:12, N:14)
Show answer
Answer: 21
Q9JEE Main 2026 Apr 6 Shift 2Medium
Consider the following organic reaction sequence. Choose the final product (X) from the following (consider the major product in all intermediate reactions)
Figure — described from the original paper
Propanoic acid, CH3CH2COOH, as starting material
CH3CH2COOH(i) NH3/Δ(ii) NaOH/Br2(iii) HNO2/H2O,0∘C(iv) C6H5N2Cl,0∘C (X) Major Product
A
Benzene
B
Phenol
C
Propanol
D
Chlorobenzene
Show answer
Correct option: A
Q10JEE Main 2026 Apr 6 Shift 2Medium
The number of compounds from the following which can undergo reaction with Br2/KOH (alcoholic) to give respective products and these respective products can also be obtained separately by Gabriel phthalimide reaction is :
When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid (273 K) and acidified with acetic acid, the mass (g) of 0.1 mole of product formed is :
(Given molar mass in gmol−1 H : 1, C : 12, N : 14, O : 16, S : 32)
A
330
B
33
C
66
D
343
Show answer
Correct option: B
Q15JEE Main 2025 Apr 3 Shift 1Medium
Identify [A], [B] and [C], respectively in the following reaction sequence:
The sequence from the following that would result in giving predominantly 3, 4, 5-Tribromoaniline is :
This question includes a diagram or structure that we have not reproduced yet. Refer to the official NTA paper for the figure.
A
[Figure] Aniline Br2,water
B
[Figure] Nitrobenzene (i) Br2,acetic acid; (ii) Sn,HCl
C
[Figure] 4-Nitroaniline (i) Br2(excess), acetic acid; (ii) NaNO2,HCl,CuBr; (iii) Sn,HCl
D
[Figure] Benzene (i) Br2,AlBr3; (ii) NH3
Show answer
Correct option: C
Q18JEE Main 2025 Apr 3 Shift 2MediumNumerical
X g of nitrobenzene on nitration gave 4.2 g of m-dinitrobenzene.
X = __________ g. (nearest integer)
[Given : molar mass (in gmol−1) C : 12, H : 1, O : 16, N : 14]
Show answer
Answer: 3
Q19JEE Main 2025 Apr 4 Shift 2Hard
The correct order of basicity for the following molecules is :
Figure — described from the original paper
three cyclic amide structures —*
(P) N-methylpiperidin-2-one (six-membered saturated lactam with N–Me);(Q) N-methyl-5,6-dihydropyridin-2(1H)-one (six-membered lactam with N–Me and a C=C conjugated with the C=O);
*(R) a bridged bicyclic lactam (1-azabicyclo[2.2.2
octan-2-one type) in which the nitrogen lone pair cannot conjugate with the C=O]*
A
P > Q > R
B
Q > P > R
C
R > Q > P
D
R > P > Q
Show answer
Correct option: C
Q20JEE Main 2025 Apr 7 Shift 1Easy
Which of the following amine (s) show (s) positive carbylamine test?
A.
Figure — described from the original paper
aniline — C6H5NH2
B. (CH3)2NH
C. CH3NH2
D. (CH3)3N
E.
Figure — described from the original paper
N-methylaniline — C6H5NH(CH3)
Choose the correct answer from the options given below:
A
C Only
B
B, C and D Only
C
A and C Only
D
A and E Only
Show answer
Correct option: C
Q21JEE Main 2025 Apr 7 Shift 2Medium
The descending order of basicity of following amines is :
(A) aniline (C6H5NH2)
(B) 4-methoxyaniline (4-MeO-C6H4NH2)
(C) 4-nitroaniline (4-O2N-C6H4NH2)
(D) CH3NH2
(E) (CH3)2NH
Choose the correct answer from the options given below :
A
E > D > B > A > C
B
E > D > A > B > C
C
E > A > D > C > B
D
B > E > D > A > C
Show answer
Correct option: A
Q22JEE Main 2025 Apr 8 Shift 2Medium
A(i)NaOH(ii)H3O+B(i)EtOH(ii)H2SO4,ΔC
'A' shows positive Lassaign's test for N and its molar mass is 121.
'B' gives effervescence with aq NaHCO3.
'C' gives fruity smell.
Identify A, B and C from the following.
A
Figure — described from the original paper
A = benzamide C6H5CONH2, B = benzoic acid C6H5CO2H, C = ethyl benzoate C6H5CO2Et
B
Figure — described from the original paper
A = benzene ring with CH2NHNH2 group (benzylhydrazine), B = benzoic acid C6H5CO2H, C = ethyl benzoate C6H5CO2Et
C
Figure — described from the original paper
A = 4-aminobenzaldehyde, B = benzoin-type condensation product of 4-aminobenzaldehyde (α-hydroxy ketone with two 4-aminophenyl rings), C = the corresponding diol with -OEt group (two 4-aminophenyl rings bearing OH, OH and OEt)
D
Figure — described from the original paper
A = 2-aminobenzaldehyde (NH2 ortho to CHO), B = 2-aminobenzoic acid (NH2 ortho to CO2H), C = ethyl 2-(ethylamino)benzoate (NHEt ortho to CO2Et)
Show answer
Correct option: A
Q23JEE Main 2025 Jan 22 Shift 1Medium
The products formed in the following reaction sequence are :
Choose the correct answer from the options given below :
A
(A)-(II), (B)-(IV), (C)-(III), (D)-(I)
B
(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
C
(A)-(III), (B)-(II), (C)-(IV), (D)-(I)
D
(A)-(II), (B)-(I), (C)-(III), (D)-(IV)
Show answer
Correct option: B
Q26JEE Main 2025 Jan 23 Shift 1Medium
Which among the following react with Hinsberg's reagent?
A. C6H5−NH2 (aniline)
B. C6H5−N(CH3)2 (N,N-dimethylaniline)
C. CH3−NH2
D. N(CH3)3
E. (C6H5)2NH (diphenylamine)
Choose the correct answer from the options given below:
This question includes a diagram or structure that we have not reproduced yet. Refer to the official NTA paper for the figure.
A
A, C and E Only
B
A, B and E Only
C
C and D Only
D
B and D Only
Show answer
Correct option: A
Q27JEE Main 2025 Jan 23 Shift 1MediumNumerical
Consider the following sequence of reactions to produce major product (A)
Figure — described from the original paper
3-nitrotoluene (benzene ring with CH3 group and NO2 at the meta position)
i) Br2,Feii) Sn,HCliii) NaNO2,HCl,273Kiv) H3PO2,H2O(A) Major Product
Molar mass of product (A) is _____ g mol−1.
(Given molar mass in g mol−1 of C : 12, H: 1, O :16, Br : 80, N : 14, P :31)
Show answer
Answer: 171
Q28JEE Main 2025 Jan 23 Shift 2HardNumerical
Consider the following sequence of reactions.
Figure — described from the original paper
reaction scheme
4-ethoxyaniline (p-ethoxyaniline) (i) NaNO2,HCl0-5∘C (A, the diazonium salt) (i) phenol, NaOH(ii) dil. HCl (B) (Molecular formula C14H14N2O2) (i) NaOH(ii) H3CCH2Br (C) (Molecular formula C16H18N2O2)
Total number of sp3 hybridised carbon atoms in the major product C formed is ________.
Show answer
Answer: 4
Q29JEE Main 2025 Jan 24 Shift 2Medium
For reaction
Figure — described from the original paper
aniline (benzene ring with −NH2) → 2-bromoaniline (benzene ring with −NH2 and an ortho −Br), labelled (Major)
The correct order of set of reagents for the above conversion is :
A
Ac2O,Br2,H2O(Δ),NaOH
B
H2SO4,Ac2O,Br2,H2O(Δ),NaOH
C
Ac2O,H2SO4,Br2,NaOH
D
Br2∣FeBr3,H2O(Δ),NaOH
Show answer
Correct option: B
Q30JEE Main 2025 Jan 28 Shift 1Medium
[Stem unrecoverable: the PDF pages carrying this question's stem are corrupted in both the English and Hindi copies. The options indicate a five-statement (A-E) multiple-select question. Option texts below are recovered from the Hindi copy.]
This question includes a diagram or structure that we have not reproduced yet. Refer to the official NTA paper for the figure.
reactant is 1-(prop-1-en-1-yl)-4-methylbenzene, i.e. p-tolyl–CH=CH–CH3
A
Figure — described from the original paper
p-tolyl–CH(NC)–CH2CH3; isocyanide (–NC) on the benzylic carbon
B
Figure — described from the original paper
p-tolyl–CH2–CH(NC)–CH3; isocyanide (–NC) on the secondary non-benzylic carbon
C
Figure — described from the original paper
p-tolyl–CH(CN)–CH3; nitrile (–CN) on the benzylic carbon
D
Figure — described from the original paper
p-tolyl–CH2–CH(NC)–CH3; isocyanide (–NC) on the secondary carbon
Show answer
Correct option: A
Q33JEE Main 2025 Jan 28 Shift 2Medium
Identify correct statements :
(A) Primary amines do not give diazonium salts when treated with NaNO2 in acidic condition.
(B) Aliphatic and aromatic primary amines on heating with CHCl3 and ethanolic KOH form carbylamines.
(C) Secondary and tertiary amines also give carbylamine test.
(D) Benzenesulfonyl chloride is known as Hinsberg's reagent.
(E) Tertiary amines reacts with benzenesulfonyl chloride very easily.
Choose the correct answer from the options given below :
A
(A) and (B) only
B
(B) and (C) only
C
(B) and (D) only
D
(D) and (E) only
Show answer
Correct option: C
Q34JEE Main 2024 Apr 4 Shift 1MediumNumerical
X g of ethylamine is subjected to reaction with NaNO2/HCl followed by water; evolved dinitrogen gas which occupied 2.24 L volume at STP. X is ________ ×10−1 g.
Show answer
Answer: 45
Q35JEE Main 2024 Apr 4 Shift 2MediumNumerical
From 6.55 g of aniline, the maximum amount of acetanilide that can be prepared will be ________ ×10−1 g.
Show answer
Answer: 95
Q36JEE Main 2024 Apr 4 Shift 2MediumNumerical
Phthalimide is made to undergo following sequence of reactions.
Phthalimide(i) KOH (ii) Benzylchloride’P’
Total number of π bonds present in product 'P' is/are ________.
Show answer
Answer: 8
Q37JEE Main 2024 Apr 5 Shift 1MediumNumerical
9.3 g of pure aniline is treated with bromine water at room temperature to give a white precipitate of the product 'P'. The mass of product 'P' obtaind is 26.4 g. The percentage yield is ________ %.
Show answer
Answer: 80
Q38JEE Main 2024 Apr 5 Shift 2MediumNumerical
X g of ethanamine was subjected to reaction with NaNO2/HCl followed by hydrolysis to liberate N2 and HCl. The HCl generated was completely neutralised by 0.2 moles of NaOH. X is ________ g.
Show answer
Answer: 9
Q39JEE Main 2024 Apr 6 Shift 1MediumNumerical
9.3 g of pure aniline upon diazotisation followed by coupling with phenol gives an orange dye. The mass of orange dye produced (assume 100% yield/conversion) is _________ g. (nearest integer)
Show answer
Answer: 20
Q40JEE Main 2024 Apr 6 Shift 2Medium
Identify the product (A) in the following reaction.
benzene ring with Cl and OH para to each other (4-chlorophenol)
B
Figure — described from the original paper
benzene ring with NH2 and Cl para to each other (4-chloroaniline)
C
Figure — described from the original paper
benzene ring with OH group (phenol)
D
Figure — described from the original paper
benzene ring with NH2 and OH para to each other (4-aminophenol)
Show answer
Correct option: C
Q41JEE Main 2024 Apr 6 Shift 2MediumNumerical
An amine (X) is prepared by ammonolysis of benzyl chloride. On adding p-toluenesulphonyl chloride to it the solution remains clear. Molar mass of the amine (X) formed is ________ gmol−1.
(Given molar mass in gmol−1 C : 12, H : 1, O : 16, N : 14)
Show answer
Answer: 287
Q42JEE Main 2024 Apr 8 Shift 1MediumNumerical
If 279 g of aniline is reacted with one equivalent of benzenediazonium chloride, the maximum amount of aniline yellow formed will be _______ g. (nearest integer)
(consider complete conversion).
Show answer
Answer: 591
Q43JEE Main 2024 Apr 8 Shift 1HardNumerical
Number of amine compounds from the following giving solids which are soluble in NaOH upon reaction with Hinsberg's reagent is ________.
Figure — described from the original paper
eleven structures — (1) aniline C6H5NH2; (2) benzamide C6H5CONH2; (3) semicarbazide H2N−NH−CO−NH2; (4) N-methylaniline C6H5−NH−CH3; (5) phenyl–NH– attached to a six-membered diene ring bearing NH2 (N-phenyl diamine structure); (6) urea H2N−CO−NH2; (7) 2-methoxyaniline (benzene ring with NH2 and OCH3 on adjacent carbons); (8) propan-1-amine CH3CH2CH2NH2; (9) triethylamine (C2H5)3N; (10) tertiary amine — N bearing ethyl, methyl and cyclohexylmethyl groups; (11) cyclohexylamine
Show answer
Answer: 5
Q44JEE Main 2024 Apr 8 Shift 2Medium
Given below are two statements :
Statement (I) : All the following compounds react with p-toluenesulfonyl chloride.
C6H5NH2(C6H5)2NH(C6H5)3N
Statement (II) : Their products in the above reaction are soluble is aqueous NaOH.
In the light of the above statements, choose the correct answer from the options given below :
A
Both Statement I and Statement II are true
B
Both Statement I and Statement II are false
C
Statement I is true but Statement II is false
D
Statement I is false but Statement II is true
Show answer
Correct option: B
Q45JEE Main 2024 Apr 9 Shift 1Easy
Correct order of basic strength of Pyrrole, Pyridine and Piperidine is :
Figure — described from the original paper
structures of pyrrole (five-membered aromatic ring with N-H), pyridine (six-membered aromatic ring with N) and piperidine (saturated six-membered ring with N-H)
A
Piperidine > Pyridine > Pyrrole
B
Pyrrole > Pyridine > Piperidine
C
Pyrrole > Piperidine > Pyridine
D
Pyridine > Piperidine > Pyrrole
Show answer
Correct option: A
Q46JEE Main 2024 Feb 1 Shift 1Easy
Given below are two statements :
Statement (I) : Aminobenzene and aniline are same organic compounds.
Statement (II) : Aminobenzene and aniline are different organic compounds.
In the light of the above statements, choose the most appropriate answer from the options given below :
A
Both Statement I and Statement II are correct
B
Both Statement I and Statement II are incorrect
C
Statement I is correct but Statement II is incorrect
D
Statement I is incorrect but Statement II is correct
Show answer
Correct option: C
Q47JEE Main 2024 Feb 1 Shift 1Medium
Given below are two statements :
Statement (I) : The NH2 group in Aniline is ortho and para directing and a powerful activating group.
Statement (II) : Aniline does not undergo Friedel-Craft's reaction (alkylation and acylation).
In the light of the above statements, choose the most appropriate answer from the options given below :
A
Both Statement I and Statement II are correct
B
Both Statement I and Statement II are incorrect
C
Statement I is correct but Statement II is incorrect
D
Statement I is incorrect but Statement II is correct
Show answer
Correct option: A
Q48JEE Main 2024 Feb 1 Shift 2MediumNumerical
Number of compounds which give reaction with Hinsberg's reagent is ________.
A = aniline (NH2 on ring); B = a biphenyl with NH2 on one ring and OH on the other (C–C linked)
B
Figure — described from the original paper
A = 1-chloro-3-nitrobenzene (Cl and NO2 on ring); B = a biphenyl bearing HO on one ring and NO2 on the other
C
Figure — described from the original paper
A = aniline (NH2 on ring); B = p-hydroxyazobenzene, HO–C6H4–N=N–C6H5
D
Figure — described from the original paper
A = aniline (NH2 on ring); B = o-hydroxyazobenzene, ring with N=N–C6H5 and OH at the ortho position
Show answer
Correct option: C
Q54JEE Main 2024 Jan 31 Shift 2Medium
Given below are two statements :
Statement I : Aniline reacts with con. H2SO4, followed by heating at 453 - 473 K gives p-aminobenzene sulphonic acid, which gives blood red colour in the 'Lassaigne's test'.
Statement II : In Friedel - Craft's alkylation and acylation reactions, aniline forms salt with the AlCl3 catalyst. Due to this, nitrogen of aniline aquires a positive charge and acts as deactivating group.
In the light of the above statements, choose the correct answer from the options given below :
A
Both statement I and statement II are true
B
Both statement I and statement II are false
C
Statement I is true but statement II is false
D
Statement I is false but statement II is true
Show answer
Correct option: A
Q55JEE Main 2024 Jan 31 Shift 2Medium
The azo-dye (Y) formed in the following reactions is
Sulphanilic acid + NaNO2 + CH3COOH → X.
X+naphthalen-1-amine⟶Y
Figure — described from the original paper
X reacting with 1-aminonaphthalene (naphthalene with NH2 at position 1)
A
[Figure]HSO3−C6H4−N=N−naphthalene with NH2 on the same ring as the azo linkage (azo group and NH2 both on the top ring, at positions 1 and 4)
B
[Figure]HSO3−C6H4−N=N−naphthalene with NH2 on the other ring (azo group at position 1, NH2 at position 5)
C
[Figure] Bis-azo structure: two HO3S-bearing naphthalene units each linked through N=N, one unit carrying NH2
D
[Figure]HSO3−C6H4−N=N−naphthalene−N=N−C6H4−SO3H (naphthalene bearing two azo linkages, one on each ring)
Show answer
Correct option: A
Q56JEE Main 2024 Jan 31 Shift 2MediumNumerical
A compound (x) with molar mass 108gmol−1 undergoes acetylation to give product with molar mass 192gmol−1. The number of amino groups in the compund (x) is _______.