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Sequences and Series — JEE Main PYQs

74 previous year questions

Q1JEE Main 2026 Apr 2 Shift 2Medium

Let a1,a2,a3,…a_1, a_2, a_3, \ldots be an A.P. and g1=a1,g2,g3,…g_1 = a_1, g_2, g_3, \ldots be an increasing G.P. If a1=a2+g2=1a_1 = a_2 + g_2 = 1 and a3+g3=4a_3 + g_3 = 4, then a10+g5a_{10} + g_5 is equal to :

  1. A

    8181

  2. B

    7676

  3. C

    6262

  4. D

    5555

Show answer

Correct option: D

Q2JEE Main 2026 Apr 2 Shift 2Easy

The sum 131+13+231+3+13+23+331+3+5+⋯\frac{1^3}{1} + \frac{1^3 + 2^3}{1 + 3} + \frac{1^3 + 2^3 + 3^3}{1 + 3 + 5} + \cdots up to 8 terms, is :

  1. A

    7070

  2. B

    7171

  3. C

    7272

  4. D

    7373

Show answer

Correct option: B

Q3JEE Main 2026 Apr 4 Shift 1Medium

The first term of an A.P. of 30 non-negative terms is 103\frac{10}{3}. If the sum of this A.P. is the cube of its last term, then its common difference is:

  1. A

    587\frac{5}{87}

  2. B

    2583\frac{25}{83}

  3. C

    1529\frac{15}{29}

  4. D

    529\frac{5}{29}

Show answer

Correct option: A

Q4JEE Main 2026 Apr 4 Shift 2Medium

Let α=14+18+116+ā€¦āˆž\alpha = \dfrac{1}{4} + \dfrac{1}{8} + \dfrac{1}{16} + \ldots\infty and β=13+19+127+ā€¦āˆž\beta = \dfrac{1}{3} + \dfrac{1}{9} + \dfrac{1}{27} + \ldots\infty. Then the value of (0.2)log⁔5(α)+(0.04)log⁔5(β)(0.2)^{\log_{\sqrt{5}}(\alpha)} + (0.04)^{\log_5(\beta)} is equal to:

  1. A

    4

  2. B

    5

  3. C

    8

  4. D

    25

Show answer

Correct option: C

Q5JEE Main 2026 Apr 5 Shift 1Medium

Let the sum of the first nn terms of an A.P. be 3n2+5n3n^2 + 5n. Then the sum of squares of the first 10 terms of the A.P. is:

  1. A

    10220

  2. B

    12860

  3. C

    15220

  4. D

    19780

Show answer

Correct option: C

Q6JEE Main 2026 Apr 5 Shift 1Easy

āˆ‘n=110(528n(n+1)(n+2))\displaystyle\sum_{n=1}^{10} \left( \frac{528}{n(n+1)(n+2)} \right) is equal to:

  1. A

    65

  2. B

    130

  3. C

    220

  4. D

    440

Show answer

Correct option: B

Q7JEE Main 2026 Apr 5 Shift 2Medium

If the sum of the first 10 terms of the series 11+14Ɨ4+21+24Ɨ4+31+34Ɨ4+41+44Ɨ4+…\dfrac{1}{1 + 1^4 \times 4} + \dfrac{2}{1 + 2^4 \times 4} + \dfrac{3}{1 + 3^4 \times 4} + \dfrac{4}{1 + 4^4 \times 4} + \ldots is mn\dfrac{m}{n}, gcd⁔(m,n)=1\gcd(m, n) = 1, then m+nm + n is equal to :

  1. A

    256

  2. B

    264

  3. C

    276

  4. D

    284

Show answer

Correct option: C

Q8JEE Main 2026 Apr 5 Shift 2Easy

Let A1,A2,A3,…,A39A_1, A_2, A_3, \ldots, A_{39} be 39 arithmetic means between the numbers 59 and 159. Then the mean of A25,A28,A31A_{25}, A_{28}, A_{31} and A36A_{36} is equal to :

  1. A

    129

  2. B

    136

  3. C

    131.50

  4. D

    134

Show answer

Correct option: D

Q9JEE Main 2026 Apr 6 Shift 1Easy

The value of 13āˆ’23+33āˆ’ā€¦+1531^3-2^3+3^3-\ldots+15^3 is:

  1. A

    17061706

  2. B

    18561856

  3. C

    19821982

  4. D

    24032403

Show answer

Correct option: B

Q10JEE Main 2026 Apr 6 Shift 1Medium

The sum of the first ten terms of an A.P. is 160 and the sum of the first two terms of a G.P. is 8. If the first term of the A.P. is equal to the common ratio of the G.P. and the first term of the G.P. is equal to common difference of the A.P., then the sum of all possible values of the first term of the G.P. is:

  1. A

    349\frac{34}{9}

  2. B

    3413\frac{34}{13}

  3. C

    329\frac{32}{9}

  4. D

    3213\frac{32}{13}

Show answer

Correct option: A

Q11JEE Main 2026 Apr 6 Shift 1MediumNumerical

For the functions f(Īø)=αtan⁔2Īø+βcot⁔2Īøf(\theta)=\alpha\tan^2\theta+\beta\cot^2\theta, and g(Īø)=αsin⁔2Īø+βcos⁔2Īøg(\theta)=\alpha\sin^2\theta+\beta\cos^2\theta, α>β>0\alpha>\beta>0, let min⁔0<Īø<Ļ€2f(Īø)=max⁔0<Īø<Ļ€g(Īø)\min\limits_{0<\theta<\frac{\pi}{2}} f(\theta)=\max\limits_{0<\theta<\pi} g(\theta). If the first term of a G.P. is (α2β)\left(\frac{\alpha}{2\beta}\right), its common ratio is (2βα)\left(\frac{2\beta}{\alpha}\right) and the sum of its first 10 terms is mn\frac{m}{n}, gcd⁔(m,n)=1\gcd(m, n)=1, then m+nm+n is equal to ________.

Show answer

Answer: 1279

Q12JEE Main 2026 Apr 6 Shift 2Easy

The sum 1+12(12+22)+13(12+22+32)+…1 + \frac{1}{2}\left(1^2 + 2^2\right) + \frac{1}{3}\left(1^2 + 2^2 + 3^2\right) + \ldots upto 10 terms is equal to :

  1. A

    130130

  2. B

    155155

  3. C

    3152\frac{315}{2}

  4. D

    3252\frac{325}{2}

Show answer

Correct option: C

Q13JEE Main 2026 Apr 8 Shift 2Medium

Let α=3+4+8+9+13+14+…\alpha = 3 + 4 + 8 + 9 + 13 + 14 + \ldots upto 40 terms. If (tan⁔β)α1020(\tan\beta)^{\frac{\alpha}{1020}} is a root of the equation x2+xāˆ’2=0x^2 + x - 2 = 0, β∈(0,Ļ€2)\beta \in \left(0, \frac{\pi}{2}\right), then sin⁔2β+3cos⁔2β\sin^2\beta + 3\cos^2\beta is equal to :

  1. A

    22

  2. B

    74\frac{7}{4}

  3. C

    52\frac{5}{2}

  4. D

    32\frac{3}{2}

Show answer

Correct option: A

Q14JEE Main 2026 Apr 8 Shift 2HardNumerical

Let ff be a polynomial function such that

log⁔2(f(x))=(log⁔2(2+23+29+ā€¦āˆž))ā‹…log⁔3(1+f(x)f(1/x)),ā€…ā€Šx>0Ā andĀ f(6)=37.\log_2(f(x)) = \left(\log_2\left(2 + \frac{2}{3} + \frac{2}{9} + \ldots \infty\right)\right) \cdot \log_3\left(1 + \frac{f(x)}{f\left(1/x\right)}\right),\; x > 0 \text{ and } f(6) = 37.

Then āˆ‘n=110f(n)\sum_{n=1}^{10} f(n) is equal to __________.

Show answer

Answer: 395

Q15JEE Main 2025 Apr 2 Shift 1Medium

Let a1,a2,a3,…\mathrm{a_1}, \mathrm{a_2}, \mathrm{a_3}, \ldots be in an A.P. such that āˆ‘k=112a2kāˆ’1=āˆ’725a1\sum_{\mathrm{k}=1}^{12} \mathrm{a_{2k-1}} = -\frac{72}{5}\mathrm{a_1}, a1≠0\mathrm{a_1} \neq 0. If āˆ‘k=1nak=0\sum_{\mathrm{k}=1}^{\mathrm{n}} \mathrm{a_k} = 0, then n is :

  1. A

    10

  2. B

    11

  3. C

    17

  4. D

    18

Show answer

Correct option: B

Q16JEE Main 2025 Apr 2 Shift 2Medium

The number of terms of an A.P. is even; the sum of all the odd terms is 24, the sum of all the even terms is 30 and the last term exceeds the first by 212\frac{21}{2}. Then the number of terms which are integers in the A.P. is :

  1. A

    4

  2. B

    6

  3. C

    8

  4. D

    10

Show answer

Correct option: A

Q17JEE Main 2025 Apr 2 Shift 2MediumNumerical

If the sum of the first 10 terms of the series 4ā‹…11+4ā‹…14+4ā‹…21+4ā‹…24+4ā‹…31+4ā‹…34+…\frac{4 \cdot 1}{1+4 \cdot 1^4}+\frac{4 \cdot 2}{1+4 \cdot 2^4}+\frac{4 \cdot 3}{1+4 \cdot 3^4}+\ldots is mn\frac{\mathrm{m}}{\mathrm{n}}, where gcd⁔(m,n)=1\gcd(\mathrm{m}, \mathrm{n})=1, then m+n\mathrm{m}+\mathrm{n} is equal to _________.

Show answer

Answer: 441

Q18JEE Main 2025 Apr 3 Shift 1Medium

Let a1,a2,a3,…a_1, a_2, a_3, \ldots be a G.P. of increasing positive numbers. If a3a5=729a_3 a_5 = 729 and a2+a4=1114a_2 + a_4 = \frac{111}{4}, then 24 (a1+a2+a3)24\,(a_1 + a_2 + a_3) is equal to

  1. A

    128

  2. B

    129

  3. C

    130

  4. D

    131

Show answer

Correct option: B

Q19JEE Main 2025 Apr 3 Shift 1Medium

The sum 1+3+11+25+45+71+…1 + 3 + 11 + 25 + 45 + 71 + \ldots upto 20 terms, is equal to

  1. A

    6982

  2. B

    7130

  3. C

    7240

  4. D

    8124

Show answer

Correct option: C

Q20JEE Main 2025 Apr 3 Shift 2Medium

The sum 1+1+32!+1+3+53!+1+3+5+74!+…1 + \dfrac{1+3}{2!} + \dfrac{1+3+5}{3!} + \dfrac{1+3+5+7}{4!} + \ldots upto āˆž\infty terms, is equal to

  1. A

    4e4e

  2. B

    2e2e

  3. C

    6e6e

  4. D

    3e3e

Show answer

Correct option: B

Q21JEE Main 2025 Apr 4 Shift 1Medium

Let A={1,6,11,16,…}A = \{1, 6, 11, 16, \ldots\} and B={9,16,23,30,…}B = \{9, 16, 23, 30, \ldots\} be the sets consisting of the first 2025 terms of two arithmetic progressions. Then n(A∪B)n(A \cup B) is

  1. A

    3814

  2. B

    3761

  3. C

    4027

  4. D

    4003

Show answer

Correct option: B

Q22JEE Main 2025 Apr 4 Shift 1Medium

1+3+52+7+92+…1 + 3 + 5^2 + 7 + 9^2 + \ldots upto 40 terms is equal to

  1. A

    33980

  2. B

    43890

  3. C

    40870

  4. D

    41880

Show answer

Correct option: D

Q23JEE Main 2025 Apr 4 Shift 2Medium

If the sum of the first 20 terms of the series 4ā‹…14+3ā‹…12+14+4ā‹…24+3ā‹…22+24+4ā‹…34+3ā‹…32+34+4ā‹…44+3ā‹…42+44+…\frac{4\cdot 1}{4+3\cdot 1^2+1^4}+\frac{4\cdot 2}{4+3\cdot 2^2+2^4}+\frac{4\cdot 3}{4+3\cdot 3^2+3^4}+\frac{4\cdot 4}{4+3\cdot 4^2+4^4}+\ldots is mn\dfrac{m}{n}, where mm and nn are coprime, then m+nm+n is equal to :

  1. A

    420420

  2. B

    421421

  3. C

    422422

  4. D

    423423

Show answer

Correct option: B

Q24JEE Main 2025 Apr 4 Shift 2Medium

Consider two sets A and B, each containing three numbers in A.P. Let the sum and the product of the elements of A be 36 and pp respectively and the sum and the product of the elements of B be 36 and qq respectively. Let dd and DD be the common differences of AP's in A and B respectively such that D=d+3D=d+3, d>0d>0. If p+qpāˆ’q=195\dfrac{p+q}{p-q}=\dfrac{19}{5}, then pāˆ’qp-q is equal to

  1. A

    540540

  2. B

    600600

  3. C

    630630

  4. D

    450450

Show answer

Correct option: A

Q25JEE Main 2025 Apr 7 Shift 1Medium

Let x1,x2,x3,x4x_1, x_2, x_3, x_4 be in a geometric progression. If 2, 7, 9, 5 are subtracted respectively from x1,x2,x3,x4x_1, x_2, x_3, x_4, then the resulting numbers are in an arithmetic progression. Then the value of 124(x1 x2 x3 x4)\frac{1}{24}(x_1\, x_2\, x_3\, x_4) is:

  1. A

    216

  2. B

    72

  3. C

    36

  4. D

    18

Show answer

Correct option: A

Q26JEE Main 2025 Apr 7 Shift 2Medium

Let ana_n be the nthn^{\text{th}} term of an A.P. If Sn=a1+a2+a3+…+an=700S_n = a_1 + a_2 + a_3 + \ldots + a_n = 700, a6=7a_6 = 7 and S7=7S_7 = 7, then ana_n is equal to :

  1. A

    5656

  2. B

    6464

  3. C

    6565

  4. D

    7070

Show answer

Correct option: B

Q27JEE Main 2025 Apr 7 Shift 2Medium

If the sum of the second, fourth and sixth terms of a G.P. of positive terms is 21 and the sum of its eighth, tenth and twelfth terms is 15309, then the sum of its first nine terms is :

  1. A

    750750

  2. B

    755755

  3. C

    757757

  4. D

    760760

Show answer

Correct option: C

Q28JEE Main 2025 Apr 8 Shift 2Easy

If 114+124+134+ā€¦āˆž=Ļ€490\frac{1}{1^4} + \frac{1}{2^4} + \frac{1}{3^4} + \ldots \infty = \frac{\pi^4}{90},

114+134+154+ā€¦āˆž=α\frac{1}{1^4} + \frac{1}{3^4} + \frac{1}{5^4} + \ldots \infty = \alpha,

124+144+164+ā€¦āˆž=β\frac{1}{2^4} + \frac{1}{4^4} + \frac{1}{6^4} + \ldots \infty = \beta,

then αβ\frac{\alpha}{\beta} is equal to

  1. A

    14

  2. B

    15

  3. C

    18

  4. D

    23

Show answer

Correct option: B

Q29JEE Main 2025 Jan 22 Shift 1Medium

If āˆ‘r=1nTr=(2nāˆ’1)(2n+1)(2n+3)(2n+5)64\sum_{r=1}^{n} T_r=\frac{(2n-1)(2n+1)(2n+3)(2n+5)}{64}, then lim⁔nā†’āˆžāˆ‘r=1n(1Tr)\lim_{n \to \infty} \sum_{r=1}^{n}\left(\frac{1}{T_r}\right) is equal to :

  1. A

    0

  2. B

    13\frac{1}{3}

  3. C

    23\frac{2}{3}

  4. D

    1

Show answer

Correct option: C

Q30JEE Main 2025 Jan 22 Shift 1Medium

Let a1,a2,a3,…a_1, a_2, a_3, \ldots be a G.P. of increasing positive terms. If a1a5=28a_1 a_5=28 and a2+a4=29a_2+a_4=29, then a6a_6 is equal to :

  1. A

    526

  2. B

    628

  3. C

    784

  4. D

    812

Show answer

Correct option: C

Q31JEE Main 2025 Jan 22 Shift 2Medium

Suppose that the number of terms in an A.P. is 2k2k, k∈Nk \in \mathbb{N}. If the sum of all odd terms of the A.P. is 40, the sum of all even terms is 55 and the last term of the A.P. exceeds the first term by 27, then kk is equal to :

  1. A

    4

  2. B

    5

  3. C

    6

  4. D

    8

Show answer

Correct option: B

Q32JEE Main 2025 Jan 23 Shift 1Medium

If the first term of an A.P. is 3 and the sum of its first four terms is equal to one-fifth of the sum of the next four terms, then the sum of the first 20 terms is equal to

  1. A

    āˆ’1080-1080

  2. B

    āˆ’1020-1020

  3. C

    āˆ’120-120

  4. D

    āˆ’1200-1200

Show answer

Correct option: A

Q33JEE Main 2025 Jan 23 Shift 2MediumNumerical

The roots of the quadratic equation 3x2āˆ’px+q=03x^2 - \mathrm{p}x + \mathrm{q} = 0 are 10th10^{\text{th}} and 11th11^{\text{th}} terms of an arithmetic progression with common difference 32\dfrac{3}{2}. If the sum of the first 11 terms of this arithmetic progression is 88, then qāˆ’2p\mathrm{q} - 2\mathrm{p} is equal to _________.

Show answer

Answer: 474

Q34JEE Main 2025 Jan 24 Shift 1Medium

Let Sn=12+16+112+120+…S_n = \frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\ldots upto n terms. If the sum of the first six terms of an A.P. with first term āˆ’p-p and common difference pp is 2026 S2025\sqrt{2026\, S_{2025}}, then the absolute difference between 20th20^{\text{th}} and 15th15^{\text{th}} terms of the A.P. is

  1. A

    20

  2. B

    25

  3. C

    45

  4. D

    90

Show answer

Correct option: B

Q35JEE Main 2025 Jan 24 Shift 2Medium

If 7=5+17(5+α)+172(5+2α)+173(5+3α)+ā€¦ā€¦āˆž7 = 5 + \dfrac{1}{7}(5+\alpha) + \dfrac{1}{7^2}(5 + 2\alpha) + \dfrac{1}{7^3}(5 + 3\alpha) + \ldots\ldots \infty, then the value of α\alpha is :

  1. A

    66

  2. B

    67\dfrac{6}{7}

  3. C

    11

  4. D

    17\dfrac{1}{7}

Show answer

Correct option: A

Q36JEE Main 2025 Jan 24 Shift 2Easy

In an arithmetic progression, if S40=1030\mathrm{S_{40}} = 1030 and S12=57\mathrm{S_{12}} = 57, then S30āˆ’S10\mathrm{S_{30}} - \mathrm{S_{10}} is equal to :

  1. A

    505

  2. B

    510

  3. C

    515

  4. D

    525

Show answer

Correct option: C

Q37JEE Main 2025 Jan 28 Shift 1Medium

Let <an><a_n> be a sequence such that a0=0a_0 = 0, a1=12a_1 = \frac{1}{2} and 2an+2=5an+1āˆ’3an2a_{n+2} = 5a_{n+1} - 3a_n, n=0,1,2,3,…n = 0, 1, 2, 3, \ldots. Then āˆ‘k=1100ak\sum_{k=1}^{100} a_k is equal to

  1. A

    3a99+1003a_{99} + 100

  2. B

    3a99āˆ’1003a_{99} - 100

  3. C

    3a100+1003a_{100} + 100

  4. D

    3a100āˆ’1003a_{100} - 100

Show answer

Correct option: D

Q38JEE Main 2025 Jan 28 Shift 1Medium

Let TrT_r be the rthr^{\text{th}} term of an A.P. If for some mm, Tm=125T_m = \frac{1}{25}, T25=120T_{25} = \frac{1}{20}, and 20āˆ‘r=125Tr=1320\sum_{r=1}^{25} T_r = 13, then 5māˆ‘r=m2mTr5m \sum_{r=m}^{2m} T_r is equal to

  1. A

    9898

  2. B

    112112

  3. C

    126126

  4. D

    142142

Show answer

Correct option: C

Q39JEE Main 2025 Jan 28 Shift 2Medium

For positive integers nn, if 4an=(n2+5n+6)4a_n = (n^2 + 5n + 6) and Sn=āˆ‘k=1n(1ak)S_n = \sum_{k=1}^{n} \left(\frac{1}{a_k}\right), then the value of 507 S2025507\, S_{2025} is :

  1. A

    135

  2. B

    540

  3. C

    675

  4. D

    1350

Show answer

Correct option: C

Q40JEE Main 2025 Jan 28 Shift 2EasyNumerical

The interior angles of a polygon with nn sides, are in an A.P. with common difference 6°6°. If the largest interior angle of the polygon is 219°219°, then nn is equal to __________.

Show answer

Answer: 20

Q41JEE Main 2024 Apr 4 Shift 1Medium

Let the first three terms 2, pp and qq, with q≠2q \neq 2, of a G.P. be respectively the 7th7^{\text{th}}, 8th8^{\text{th}} and 13th13^{\text{th}} terms of an A.P. If the 5th5^{\text{th}} term of the G.P. is the nthn^{\text{th}} term of the A.P., then nn is equal to :

  1. A

    151151

  2. B

    163163

  3. C

    169169

  4. D

    177177

Show answer

Correct option: B

Q42JEE Main 2024 Apr 4 Shift 1HardNumerical

Let a=1+2C23!+3C24!+4C25!+…a=1+\frac{^{2}C_{2}}{3!}+\frac{^{3}C_{2}}{4!}+\frac{^{4}C_{2}}{5!}+\ldots,

b=1+1C0+1C11!+2C0+2C1+2C22!+3C0+3C1+3C2+3C33!+…b=1+\frac{^{1}C_{0}+{}^{1}C_{1}}{1!}+\frac{^{2}C_{0}+{}^{2}C_{1}+{}^{2}C_{2}}{2!}+\frac{^{3}C_{0}+{}^{3}C_{1}+{}^{3}C_{2}+{}^{3}C_{3}}{3!}+\ldots

Then 2ba2\frac{2b}{a^{2}} is equal to ________.

Show answer

Answer: 8

Q43JEE Main 2024 Apr 4 Shift 2Medium

The value of 1Ɨ22+2Ɨ32+…+100Ɨ(101)212Ɨ2+22Ɨ3+…+1002Ɨ101\frac{1 \times 2^2 + 2 \times 3^2 + \ldots + 100 \times (101)^2}{1^2 \times 2 + 2^2 \times 3 + \ldots + 100^2 \times 101} is

  1. A

    3130\frac{31}{30}

  2. B

    305301\frac{305}{301}

  3. C

    3231\frac{32}{31}

  4. D

    306305\frac{306}{305}

Show answer

Correct option: B

Q44JEE Main 2024 Apr 4 Shift 2Medium

Let three real numbers a,b,ca, b, c be in arithmetic progression and a+1,b,c+3a+1, b, c+3 be in geometric progression. If a>10a > 10 and the arithmetic mean of aa, bb and cc is 88, then the cube of the geometric mean of aa, bb and cc is

  1. A

    128128

  2. B

    312312

  3. C

    120120

  4. D

    316316

Show answer

Correct option: C

Q45JEE Main 2024 Apr 5 Shift 1Easy

If 11+2+12+3+…+199+100=m\frac{1}{\sqrt{1}+\sqrt{2}} + \frac{1}{\sqrt{2}+\sqrt{3}} + \ldots + \frac{1}{\sqrt{99}+\sqrt{100}} = \mathrm{m} and 11ā‹…2+12ā‹…3+…+199ā‹…100=n\frac{1}{1 \cdot 2} + \frac{1}{2 \cdot 3} + \ldots + \frac{1}{99 \cdot 100} = \mathrm{n}, then the point (m,n)(\mathrm{m}, \mathrm{n}) lies on the line

  1. A

    11xāˆ’100y=011x - 100y = 0

  2. B

    11(xāˆ’1)āˆ’100y=011(x-1) - 100y = 0

  3. C

    11(xāˆ’2)āˆ’100(yāˆ’1)=011(x-2) - 100(y-1) = 0

  4. D

    11(xāˆ’1)āˆ’100(yāˆ’2)=011(x-1) - 100(y-2) = 0

Show answer

Correct option: A

Q46JEE Main 2024 Apr 5 Shift 1HardNumerical

Let a1,a2,a3,…a_1, a_2, a_3, \ldots be in an arithmetic progression of positive terms.

Let Ak=a12āˆ’a22+a32āˆ’a42+…+a2kāˆ’12āˆ’a2k2A_k = a_1^2 - a_2^2 + a_3^2 - a_4^2 + \ldots + a_{2k-1}^2 - a_{2k}^2.

If A3=āˆ’153A_3 = -153, A5=āˆ’435A_5 = -435 and a12+a22+a32=66a_1^2 + a_2^2 + a_3^2 = 66, then a17āˆ’A7a_{17} - A_7 is equal to ________.

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Answer: 910

Q47JEE Main 2024 Apr 5 Shift 2Medium

For x≄0x \geq 0, the least value of KK, for which 41+x+41āˆ’x4^{1+x} + 4^{1-x}, K2\dfrac{K}{2}, 16x+16āˆ’x16^x + 16^{-x} are three consecutive terms of an A.P., is equal to :

  1. A

    10

  2. B

    8

  3. C

    4

  4. D

    16

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Correct option: A

Q48JEE Main 2024 Apr 5 Shift 2HardNumerical

If 1+3āˆ’223+5āˆ’2618+93āˆ’112363+49āˆ’206180+…uptoĀ āˆž=2+(ba+1)log⁔e(ab)1 + \dfrac{\sqrt{3} - \sqrt{2}}{2\sqrt{3}} + \dfrac{5 - 2\sqrt{6}}{18} + \dfrac{9\sqrt{3} - 11\sqrt{2}}{36\sqrt{3}} + \dfrac{49 - 20\sqrt{6}}{180} + \ldots \text{upto } \infty = 2 + \left(\sqrt{\dfrac{b}{a}} + 1\right)\log_{\mathrm{e}}\left(\dfrac{a}{b}\right), where aa and bb are integers with gcd⁔(a,b)=1\gcd(a, b) = 1, then 11a+18b11a + 18b is equal to ________.

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Answer: 76

Q49JEE Main 2024 Apr 6 Shift 1HardNumerical

Let the first term of a series be T1=6T_1 = 6 and its rthr^{\text{th}} term Tr=3Trāˆ’1+6rT_r = 3T_{r-1} + 6^r, r=2,3,......,nr = 2, 3, ......, n. If the sum of the first nn terms of this series is 15(n2āˆ’12n+39)(4ā‹…6nāˆ’5ā‹…3n+1)\dfrac{1}{5}\left(n^2 - 12n + 39\right)\left(4 \cdot 6^n - 5 \cdot 3^n + 1\right), then nn is equal to ________.

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Answer: 6

Q50JEE Main 2024 Apr 6 Shift 2Medium

A software company sets up m number of computer systems to finish an assignment in 17 days. If 4 computer systems crashed on the start of the second day, 4 more computer systems crashed on the start of the third day and so on, then it took 8 more days to finish the assignment. The value of m is equal to :

  1. A

    150150

  2. B

    125125

  3. C

    160160

  4. D

    180180

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Correct option: A

Q51JEE Main 2024 Apr 6 Shift 2Medium

Let ABCABC be an equilateral triangle. A new triangle is formed by joining the middle points of all sides of the triangle ABCABC and the same process is repeated infinitely many times. If PP is the sum of perimeters and QQ is be the sum of areas of all the triangles formed in this process, then :

  1. A

    P=363 Q2P=36\sqrt{3}\,Q^2

  2. B

    P2=63 QP^2=6\sqrt{3}\,Q

  3. C

    P2=363 QP^2=36\sqrt{3}\,Q

  4. D

    P2=723 QP^2=72\sqrt{3}\,Q

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Correct option: C

Q52JEE Main 2024 Apr 6 Shift 2HardNumerical

If S(x)=(1+x)+2(1+x)2+3(1+x)3+⋯+60(1+x)60S(x)=(1+x)+2(1+x)^2+3(1+x)^3+\cdots+60(1+x)^{60}, x≠0x \ne 0, and (60)2S(60)=a(b)b+b(60)^2 S(60)=\mathrm{a(b)^b+b}, where a,b∈N\mathrm{a, b} \in \mathbf{N}, then (a+b)(\mathrm{a+b}) equal to ________.

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Answer: 3660

Q53JEE Main 2024 Apr 8 Shift 1MediumNumerical

If the range of f(θ)=sin⁔4θ+3cos⁔2θsin⁔4θ+cos⁔2θf(\theta)=\frac{\sin^4\theta+3\cos^2\theta}{\sin^4\theta+\cos^2\theta}, θ∈R\theta\in\mathbb{R} is [α,β][\alpha, \beta], then the sum of the infinite G.P., whose first term is 64 and the common ratio is αβ\frac{\alpha}{\beta}, is equal to __________.

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Answer: 96

Q54JEE Main 2024 Apr 8 Shift 1MediumNumerical

Let the positive integers be written in the form :

[Figure: triangular arrangement of positive integers — row 1: 1; row 2: 2, 3; row 3: 4, 5, 6; row 4: 7, 8, 9, 10; and so on]

If the kthk^{\text{th}} row contains exactly kk numbers for every natural number kk, then the row in which the number 5310 will be, is __________.

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Answer: 103

Q55JEE Main 2024 Apr 8 Shift 2Medium

In an increasing geometric progression of positive terms, the sum of the second and sixth terms is 703\dfrac{70}{3} and the product of the third and fifth terms is 49. Then the sum of the 4th4^{\text{th}}, 6th6^{\text{th}} and 8th8^{\text{th}} terms is equal to :

  1. A

    7878

  2. B

    8484

  3. C

    9191

  4. D

    9696

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Correct option: C

Q56JEE Main 2024 Apr 8 Shift 2MediumNumerical

An arithmetic progression is written in the following way

25811141720232629\begin{array}{ccccccc} & & & 2 & & & \\ & & 5 & & 8 & & \\ & 11 & & 14 & & 17 & \\ 20 & & 23 & & 26 & & 29 \end{array} āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’- - - - - - - - - - - - - - āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’āˆ’- - - - - - - - - - - - - - - -

The sum of all the terms of the 10th10^{\text{th}} row is ________.

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Answer: 1505

Q57JEE Main 2024 Apr 9 Shift 1Medium

If the sum of the series 11ā‹…(1+d)+1(1+d)(1+2d)+…+1(1+9d)(1+10d)\frac{1}{1\cdot(1+\mathrm{d})}+\frac{1}{(1+\mathrm{d})(1+2\mathrm{d})}+\ldots+\frac{1}{(1+9\mathrm{d})(1+10\mathrm{d})} is equal to 5, then 50d50\mathrm{d} is equal to :

  1. A

    55

  2. B

    1010

  3. C

    1515

  4. D

    2020

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Correct option: A

Q58JEE Main 2024 Apr 9 Shift 1MediumNumerical

If a function ff satisfies f(m+n)=f(m)+f(n)f(\mathrm{m}+\mathrm{n})=f(\mathrm{m})+f(\mathrm{n}) for all m,n∈N\mathrm{m}, \mathrm{n}\in\mathbf{N} and f(1)=1f(1)=1, then the largest natural number Ī»\lambda such that āˆ‘k=12022f(Ī»+k)≤(2022)2\sum\limits_{\mathrm{k}=1}^{2022} f(\lambda+\mathrm{k})\le(2022)^2 is equal to ________.

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Answer: 1010

Q59JEE Main 2024 Apr 9 Shift 2Medium

Let a,ar,ar2,……a, ar, ar^2, \ldots\ldots be an infinite G.P. If āˆ‘n=0āˆžarn=57\sum\limits_{n=0}^{\infty} ar^n = 57 and āˆ‘n=0āˆža3r3n=9747\sum\limits_{n=0}^{\infty} a^3r^{3n} = 9747, then a+18ra+18r is equal to

  1. A

    2727

  2. B

    3131

  3. C

    3838

  4. D

    4646

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Correct option: B

Q60JEE Main 2024 Apr 9 Shift 2MediumNumerical

If (1α+1+1α+2+……+1α+1012)āˆ’(12ā‹…1+14ā‹…3+16ā‹…5+……+12024ā‹…2023)=12024\left(\dfrac{1}{\alpha+1}+\dfrac{1}{\alpha+2}+\ldots\ldots+\dfrac{1}{\alpha+1012}\right)-\left(\dfrac{1}{2\cdot 1}+\dfrac{1}{4\cdot 3}+\dfrac{1}{6\cdot 5}+\ldots\ldots+\dfrac{1}{2024\cdot 2023}\right)=\dfrac{1}{2024}, then α\alpha is equal to __________.

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Answer: 1011

Q61JEE Main 2024 Feb 1 Shift 1Medium

Let 3,a,b,c3, a, b, c be in A.P. and 3,aāˆ’1,b+1,c+93, a-1, b+1, c+9 be in G.P. Then, the arithmetic mean of a,ba, b and cc is :

  1. A

    1111

  2. B

    āˆ’1-1

  3. C

    1313

  4. D

    āˆ’4-4

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Correct option: A

Q62JEE Main 2024 Feb 1 Shift 1MediumNumerical

Let 3,7,11,15,…,4033, 7, 11, 15, \ldots, 403 and 2,5,8,11,…,4042, 5, 8, 11, \ldots, 404 be two arithmetic progressions. Then the sum, of the common terms in them, is equal to ________.

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Answer: 6699

Q63JEE Main 2024 Feb 1 Shift 2Medium

Let SnS_n denote the sum of the first nn terms of an arithmetic progression. If S10=390S_{10}=390 and the ratio of the tenth and the fifth terms is 15:715:7, then S15āˆ’S5S_{15}-S_5 is equal to :

  1. A

    690690

  2. B

    800800

  3. C

    890890

  4. D

    790790

Show answer

Correct option: D

Q64JEE Main 2024 Feb 1 Shift 2MediumNumerical

If three successive terms of a G.P. with common ratio rr (r>1r>1) are the lengths of the sides of a triangle and [r][r] denotes the greatest integer less than or equal to rr, then 3[r]+[āˆ’r]3[r]+[-r] is equal to ________.

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Answer: 1

Q65JEE Main 2024 Jan 27 Shift 1Easy

The number of common terms in the progressions 4,9,14,19,…4, 9, 14, 19, \ldots, up to 25th25^{\text{th}} term and 3,6,9,12,…3, 6, 9, 12, \ldots, up to 37th37^{\text{th}} term is :

  1. A

    55

  2. B

    77

  3. C

    88

  4. D

    99

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Correct option: B

Q66JEE Main 2024 Jan 27 Shift 1MediumNumerical

If 8=3+14(3+p)+142(3+2p)+143(3+3p)+ā‹Æāˆž8 = 3 + \dfrac{1}{4}(3 + p) + \dfrac{1}{4^2}(3 + 2p) + \dfrac{1}{4^3}(3 + 3p) + \cdots \infty, then the value of pp is ________.

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Answer: 9

Q67JEE Main 2024 Jan 29 Shift 1Medium

In an A.P., the sixth term a6=2a_6 = 2. If the product a1a4a5a_1 a_4 a_5 is the greatest, then the common difference of the A.P. is equal to

  1. A

    58\dfrac{5}{8}

  2. B

    85\dfrac{8}{5}

  3. C

    23\dfrac{2}{3}

  4. D

    32\dfrac{3}{2}

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Correct option: B

Q68JEE Main 2024 Jan 29 Shift 1Medium

If in a G.P. of 64 terms, the sum of all the terms is 7 times the sum of the odd terms of the G.P, then the common ratio of the G.P. is equal to

  1. A

    44

  2. B

    55

  3. C

    66

  4. D

    77

Show answer

Correct option: C

Q69JEE Main 2024 Jan 30 Shift 1Easy

Let SnS_n denote the sum of first nn terms of an arithmetic progression. If S20=790S_{20}=790 and S10=145S_{10}=145, then S15āˆ’S5S_{15}-S_5 is :

  1. A

    405405

  2. B

    395395

  3. C

    390390

  4. D

    410410

Show answer

Correct option: B

Q70JEE Main 2024 Jan 30 Shift 1MediumNumerical

Let α=12+42+82+132+192+262+...\alpha=1^2+4^2+8^2+13^2+19^2+26^2+... upto 10 terms and β=āˆ‘n=110n4\beta=\sum\limits_{n=1}^{10} n^4. If 4Ī±āˆ’Ī²=55k+404\alpha-\beta=55k+40, then kk is equal to ________.

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Answer: 353

Q71JEE Main 2024 Jan 30 Shift 2Medium

Let aa and bb be be two distinct positive real numbers. Let 11th11^{\text{th}} term of a GP, whose first term is aa and third term is bb, is equal to pthp^{\text{th}} term of another GP, whose first term is aa and fifth term is bb. Then pp is equal to

  1. A

    21

  2. B

    20

  3. C

    24

  4. D

    25

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Correct option: A

Q72JEE Main 2024 Jan 30 Shift 2MediumNumerical

Let SnS_n be the sum to nn-terms of an arithmetic progression 3,7,11,…3, 7, 11, \ldots If 40<(6n(n+1)āˆ‘k=1nSk)<4240<\left(\frac{6}{n(n+1)}\sum_{k=1}^{n} S_k\right)<42, then nn equals ______.

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Answer: 9

Q73JEE Main 2024 Jan 31 Shift 1Medium

The sum of the series 11āˆ’3ā‹…12+14+21āˆ’3ā‹…22+24+31āˆ’3ā‹…32+34+…\frac{1}{1-3 \cdot 1^2+1^4}+\frac{2}{1-3 \cdot 2^2+2^4}+\frac{3}{1-3 \cdot 3^2+3^4}+\ldots up to 10-terms is

  1. A

    45109\frac{45}{109}

  2. B

    55109\frac{55}{109}

  3. C

    āˆ’55109-\frac{55}{109}

  4. D

    āˆ’45109-\frac{45}{109}

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Correct option: C

Q74JEE Main 2024 Jan 31 Shift 2Medium

Let 2ndĀ ,8thĀ 2^{\text {nd }}, 8^{\text {th }} and 44thĀ 44^{\text {th }} terms of a non-constant A. P. be respectively the 1stĀ ,2ndĀ 1^{\text {st }}, 2^{\text {nd }} and 3rdĀ 3^{\text {rd }} terms of a G. P. If the first term of the A. P. is 1, then the sum of its first 20 terms is equal to -

  1. A

    960

  2. B

    970

  3. C

    980

  4. D

    990

Show answer

Correct option: B