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Vector Algebra — JEE Main PYQs

63 previous year questions

Q1JEE Main 2026 Apr 2 Shift 2Medium

Let the vectors aāƒ—=āˆ’i^+j^+3k^\vec{a} = -\hat{i} + \hat{j} + 3\hat{k} and bāƒ—=i^+3j^+k^\vec{b} = \hat{i} + 3\hat{j} + \hat{k}. For some Ī»,μ∈R\lambda, \mu \in \mathbb{R}, let cāƒ—=Ī»aāƒ—+μbāƒ—\vec{c} = \lambda\vec{a} + \mu\vec{b}. If cāƒ—ā‹…(3i^āˆ’6j^+2k^)=10\vec{c} \cdot \left(3\hat{i} - 6\hat{j} + 2\hat{k}\right) = 10 and cāƒ—ā‹…(i^+j^+k^)=āˆ’2\vec{c} \cdot \left(\hat{i} + \hat{j} + \hat{k}\right) = -2, then ∣cāƒ—āˆ£2|\vec{c}|^2 is equal to :

  1. A

    88

  2. B

    1212

  3. C

    1414

  4. D

    1515

Show answer

Correct option: B

Q2JEE Main 2026 Apr 2 Shift 2Hard

Two adjacent sides of a parallelogram PQRS are given by PQ→=j^+k^\overrightarrow{PQ} = \hat{j} + \hat{k} and PS→=i^āˆ’j^\overrightarrow{PS} = \hat{i} - \hat{j}. If the side PS is rotated about the point P by an acute angle α\alpha in the plane of the parallelogram so that it becomes perpendicular to the side PQ, then sin⁔2(5α2)āˆ’sin⁔2(α2)\sin^2\left(\frac{5\alpha}{2}\right) - \sin^2\left(\frac{\alpha}{2}\right) is equal to :

  1. A

    12\frac{1}{2}

  2. B

    32\frac{\sqrt{3}}{2}

  3. C

    34\frac{\sqrt{3}}{4}

  4. D

    235\frac{2\sqrt{3}}{5}

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Correct option: B

Q3JEE Main 2026 Apr 4 Shift 1HardNumerical

Let akāƒ—=(tan⁔θk) i^+j^\vec{a_k} = (\tan\theta_k)\,\hat{i} + \hat{j} and bkāƒ—=i^āˆ’(cot⁔θk) j^\vec{b_k} = \hat{i} - (\cot\theta_k)\,\hat{j}, where Īøk=2kāˆ’1Ļ€2n+1\theta_k = \frac{2^{k-1}\pi}{2^n + 1}, for some n∈Nn \in \mathbb{N}, n>5n > 5. Then the value of āˆ‘k=1n∣akāƒ—āˆ£2āˆ‘k=1n∣bkāƒ—āˆ£2\frac{\displaystyle\sum_{k=1}^{n} \left|\vec{a_k}\right|^2}{\displaystyle\sum_{k=1}^{n} \left|\vec{b_k}\right|^2} is ______.

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Answer: 3

Q4JEE Main 2026 Apr 4 Shift 2Medium

Let u^\hat{u} and v^\hat{v} be unit vectors inclined at an acute angle such that ∣u^Ɨv^∣=32|\hat{u} \times \hat{v}| = \dfrac{\sqrt{3}}{2}. If Aāƒ—=λ u^+v^+(u^Ɨv^)\vec{A} = \lambda\,\hat{u} + \hat{v} + (\hat{u} \times \hat{v}), then Ī»\lambda is equal to:

  1. A

    43(Aāƒ—ā‹…u^)āˆ’23(Aāƒ—ā‹…v^)\dfrac{4}{3}\left(\vec{A} \cdot \hat{u}\right) - \dfrac{2}{3}\left(\vec{A} \cdot \hat{v}\right)

  2. B

    23(Aāƒ—ā‹…u^)āˆ’13(Aāƒ—ā‹…v^)\dfrac{2}{3}\left(\vec{A} \cdot \hat{u}\right) - \dfrac{1}{3}\left(\vec{A} \cdot \hat{v}\right)

  3. C

    43(Aāƒ—ā‹…u^)+23(Aāƒ—ā‹…v^)\dfrac{4}{3}\left(\vec{A} \cdot \hat{u}\right) + \dfrac{2}{3}\left(\vec{A} \cdot \hat{v}\right)

  4. D

    (Aāƒ—ā‹…u^)āˆ’12(Aāƒ—ā‹…v^)\left(\vec{A} \cdot \hat{u}\right) - \dfrac{1}{2}\left(\vec{A} \cdot \hat{v}\right)

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Correct option: A

Q5JEE Main 2026 Apr 5 Shift 1Medium

Let aāƒ—=7i^+j^āˆ’k^\vec{a} = \sqrt{7}\hat{i} + \hat{j} - \hat{k} and bāƒ—=j^+2k^\vec{b} = \hat{j} + 2\hat{k}. If rāƒ—\vec{r} is a vector such that rāƒ—Ć—aāƒ—+aāƒ—Ć—bāƒ—=0āƒ—\vec{r} \times \vec{a} + \vec{a} \times \vec{b} = \vec{0} and rāƒ—ā‹…aāƒ—=0\vec{r} \cdot \vec{a} = 0, then ∣3rāƒ—āˆ£2\left| 3\vec{r} \right|^2 is equal to:

  1. A

    44

  2. B

    54

  3. C

    86

  4. D

    132

Show answer

Correct option: A

Q6JEE Main 2026 Apr 5 Shift 2Medium

Let OO be the origin, OP→=aāƒ—\overrightarrow{OP} = \vec{a} and OQ→=bāƒ—\overrightarrow{OQ} = \vec{b}. If RR is the point on OP→\overrightarrow{OP} such that OP→=5 OR→\overrightarrow{OP} = 5\,\overrightarrow{OR}, and MM is the point such that OQ→=5 RM→\overrightarrow{OQ} = 5\,\overrightarrow{RM}, then PM→\overrightarrow{PM} is equal to :

  1. A

    15(aāƒ—āˆ’4bāƒ—)\dfrac{1}{5}\left(\vec{a} - 4\vec{b}\right)

  2. B

    15(bāƒ—āˆ’4aāƒ—)\dfrac{1}{5}\left(\vec{b} - 4\vec{a}\right)

  3. C

    15(āˆ’aāƒ—+4bāƒ—)\dfrac{1}{5}\left(-\vec{a} + 4\vec{b}\right)

  4. D

    15(āˆ’bāƒ—+4aāƒ—)\dfrac{1}{5}\left(-\vec{b} + 4\vec{a}\right)

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Correct option: B

Q7JEE Main 2026 Apr 6 Shift 1MediumNumerical

If aāƒ—=i^+j^+k^\vec{a}=\hat{i}+\hat{j}+\hat{k}, bāƒ—=j^āˆ’k^\vec{b}=\hat{j}-\hat{k} and cāƒ—\vec{c} be three vectors such that aāƒ—Ć—cāƒ—=bāƒ—\vec{a}\times\vec{c}=\vec{b} and aāƒ—ā‹…cāƒ—=3\vec{a}\cdot\vec{c}=3, then cāƒ—ā‹…(aāƒ—āˆ’2bāƒ—)\vec{c}\cdot\left(\vec{a}-2\vec{b}\right) is equal to ________.

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Answer: 3

Q8JEE Main 2026 Apr 6 Shift 2Medium

Let aāƒ—=2i^+3j^+3k^\vec{a} = 2\hat{i} + 3\hat{j} + 3\hat{k} and bāƒ—=6i^+3j^+3k^\vec{b} = 6\hat{i} + 3\hat{j} + 3\hat{k}. Then the square of the area of the triangle with adjacent sides determined by the vectors (2aāƒ—+3bāƒ—)\left(2\vec{a} + 3\vec{b}\right) and (aāƒ—āˆ’bāƒ—)\left(\vec{a} - \vec{b}\right) is :

  1. A

    450450

  2. B

    900900

  3. C

    18001800

  4. D

    24002400

Show answer

Correct option: C

Q9JEE Main 2026 Apr 8 Shift 2Medium

Let aāƒ—=4i^āˆ’j^+3k^\vec{a} = 4\hat{i} - \hat{j} + 3\hat{k}, bāƒ—=10i^+2j^āˆ’k^\vec{b} = 10\hat{i} + 2\hat{j} - \hat{k} and a vector cāƒ—\vec{c} be such that 2(aāƒ—Ć—bāƒ—)+3(bāƒ—Ć—cāƒ—)=0āƒ—2\left(\vec{a} \times \vec{b}\right) + 3\left(\vec{b} \times \vec{c}\right) = \vec{0}. If aāƒ—ā‹…cāƒ—=15\vec{a} \cdot \vec{c} = 15, then cāƒ—ā‹…(i^+j^āˆ’3k^)\vec{c} \cdot \left(\hat{i} + \hat{j} - 3\hat{k}\right) is equal to :

  1. A

    āˆ’6-6

  2. B

    āˆ’5-5

  3. C

    āˆ’4-4

  4. D

    āˆ’3-3

Show answer

Correct option: B

Q10JEE Main 2025 Apr 2 Shift 1Medium

If aāƒ—\vec{a} is a nonzero vector such that its projections on the vectors 2i^āˆ’j^+2k^2\hat{i} - \hat{j} + 2\hat{k}, i^+2j^āˆ’2k^\hat{i} + 2\hat{j} - 2\hat{k} and k^\hat{k} are equal, then a unit vector along aāƒ—\vec{a} is :

  1. A

    1155(āˆ’7i^+9j^āˆ’5k^)\frac{1}{\sqrt{155}}\left(-7\hat{i} + 9\hat{j} - 5\hat{k}\right)

  2. B

    1155(āˆ’7i^+9j^+5k^)\frac{1}{\sqrt{155}}\left(-7\hat{i} + 9\hat{j} + 5\hat{k}\right)

  3. C

    1155(7i^+9j^āˆ’5k^)\frac{1}{\sqrt{155}}\left(7\hat{i} + 9\hat{j} - 5\hat{k}\right)

  4. D

    1155(7i^+9j^+5k^)\frac{1}{\sqrt{155}}\left(7\hat{i} + 9\hat{j} + 5\hat{k}\right)

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Correct option: D

Q11JEE Main 2025 Apr 2 Shift 2Medium

Let aāƒ—=2i^āˆ’3j^+k^\vec{a}=2\hat{i}-3\hat{j}+\hat{k}, bāƒ—=3i^+2j^+5k^\vec{b}=3\hat{i}+2\hat{j}+5\hat{k} and a vector cāƒ—\vec{c} be such that (aāƒ—āˆ’cāƒ—)Ɨbāƒ—=āˆ’18i^āˆ’3j^+12k^(\vec{a}-\vec{c}) \times \vec{b}=-18\hat{i}-3\hat{j}+12\hat{k} and aāƒ—ā‹…cāƒ—=3\vec{a} \cdot \vec{c}=3. If bāƒ—Ć—cāƒ—=dāƒ—\vec{b} \times \vec{c}=\vec{d}, then ∣aāƒ—ā‹…dāƒ—āˆ£\left|\vec{a} \cdot \vec{d}\right| is equal to :

  1. A

    9

  2. B

    12

  3. C

    15

  4. D

    18

Show answer

Correct option: C

Q12JEE Main 2025 Apr 3 Shift 1HardNumerical

Let aāƒ—=i^+j^+k^\vec{a} = \hat{i} + \hat{j} + \hat{k}, bāƒ—=3i^+2j^āˆ’k^\vec{b} = 3\hat{i} + 2\hat{j} - \hat{k}, cāƒ—=Ī»j^+μk^\vec{c} = \lambda\hat{j} + \mu\hat{k} and d^\hat{d} be a unit vector such that aāƒ—Ć—d^=bāƒ—Ć—d^\vec{a} \times \hat{d} = \vec{b} \times \hat{d} and cāƒ—ā‹…d^=1\vec{c} \cdot \hat{d} = 1. If cāƒ—\vec{c} is perpendicular to aāƒ—\vec{a}, then ∣3Ī»d^+μcāƒ—āˆ£2\left|3\lambda\hat{d} + \mu\vec{c}\right|^2 is equal to __________

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Answer: 5

Q13JEE Main 2025 Apr 3 Shift 2MediumNumerical

Let aāƒ—=i^+2j^+k^\vec{a} = \hat{i} + 2\hat{j} + \hat{k}, bāƒ—=3i^āˆ’3j^+3k^\vec{b} = 3\hat{i} - 3\hat{j} + 3\hat{k}, cāƒ—=2i^āˆ’j^+2k^\vec{c} = 2\hat{i} - \hat{j} + 2\hat{k} and dāƒ—\vec{d} be a vector such that bāƒ—Ć—dāƒ—=cāƒ—Ć—dāƒ—\vec{b} \times \vec{d} = \vec{c} \times \vec{d} and aāƒ—ā‹…dāƒ—=4\vec{a} \cdot \vec{d} = 4. Then ∣(aāƒ—Ć—dāƒ—)∣2\left|\left(\vec{a} \times \vec{d}\right)\right|^2 is equal to ________.

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Answer: 128

Q14JEE Main 2025 Apr 4 Shift 1Medium

Consider two vectors uāƒ—=3i^āˆ’j^\vec{u} = 3\hat{i} - \hat{j} and vāƒ—=2i^+j^āˆ’Ī»k^\vec{v} = 2\hat{i} + \hat{j} - \lambda\hat{k}, Ī»>0\lambda > 0. The angle between them is given by cosā”āˆ’1(527)\cos^{-1}\left(\frac{\sqrt{5}}{2\sqrt{7}}\right). Let vāƒ—=v1āƒ—+v2āƒ—\vec{v} = \vec{v_1} + \vec{v_2}, where v1āƒ—\vec{v_1} is parallel to uāƒ—\vec{u} and v2āƒ—\vec{v_2} is perpendicular to uāƒ—\vec{u}. Then the value ∣v1āƒ—āˆ£2+∣v2āƒ—āˆ£2|\vec{v_1}|^2 + |\vec{v_2}|^2 is equal to

  1. A

    14

  2. B

    10

  3. C

    232\frac{23}{2}

  4. D

    252\frac{25}{2}

Show answer

Correct option: A

Q15JEE Main 2025 Apr 4 Shift 2MediumNumerical

Let the three sides of a triangle ABC be given by the vectors 2i^āˆ’j^+k^2\hat{i}-\hat{j}+\hat{k}, i^āˆ’3j^āˆ’5k^\hat{i}-3\hat{j}-5\hat{k} and 3i^āˆ’4j^āˆ’4k^3\hat{i}-4\hat{j}-4\hat{k}. Let G be the centroid of the triangle ABC. Then 6(∣AGā†’āˆ£2+∣BGā†’āˆ£2+∣CGā†’āˆ£2)6\left(|\overrightarrow{\mathrm{AG}}|^2+|\overrightarrow{\mathrm{BG}}|^2+|\overrightarrow{\mathrm{CG}}|^2\right) is equal to __________.

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Answer: 164

Q16JEE Main 2025 Apr 7 Shift 1Medium

Let the angle Īø\theta, 0<Īø<Ļ€20 < \theta < \frac{\pi}{2} between two unit vectors a^\hat{a} and b^\hat{b} be sinā”āˆ’1(659)\sin^{-1}\left(\frac{\sqrt{65}}{9}\right). If the vector cāƒ—=3a^+6b^+9(a^Ɨb^)\vec{c} = 3\hat{a} + 6\hat{b} + 9\left(\hat{a} \times \hat{b}\right), then the value of 9(cāƒ—ā‹…a^)āˆ’3(cāƒ—ā‹…b^)9\left(\vec{c} \cdot \hat{a}\right) - 3\left(\vec{c} \cdot \hat{b}\right) is

  1. A

    24

  2. B

    27

  3. C

    29

  4. D

    31

Show answer

Correct option: C

Q17JEE Main 2025 Apr 7 Shift 2Medium

Let aāƒ—\vec{a} and bāƒ—\vec{b} be the vectors of the same magnitude such that ∣aāƒ—+bāƒ—āˆ£+∣aāƒ—āˆ’bāƒ—āˆ£āˆ£aāƒ—+bāƒ—āˆ£āˆ’āˆ£aāƒ—āˆ’bāƒ—āˆ£=2+1\dfrac{|\vec{a} + \vec{b}| + |\vec{a} - \vec{b}|}{|\vec{a} + \vec{b}| - |\vec{a} - \vec{b}|} = \sqrt{2} + 1. Then ∣aāƒ—+bāƒ—āˆ£2∣aāƒ—āˆ£2\dfrac{|\vec{a} + \vec{b}|^2}{|\vec{a}|^2} is :

  1. A

    2+22 + \sqrt{2}

  2. B

    4+224 + 2\sqrt{2}

  3. C

    1+21 + \sqrt{2}

  4. D

    2+422 + 4\sqrt{2}

Show answer

Correct option: A

Q18JEE Main 2025 Apr 8 Shift 2Medium

Let aāƒ—=i^+2j^+k^\vec{a} = \hat{i} + 2\hat{j} + \hat{k} and bāƒ—=2i^+j^āˆ’k^\vec{b} = 2\hat{i} + \hat{j} - \hat{k}. Let c^\hat{c} be a unit vector in the plane of the vectors aāƒ—\vec{a} and bāƒ—\vec{b} and be perpendicular to aāƒ—\vec{a}. Then such a vector c^\hat{c} is :

  1. A

    13(i^āˆ’j^+k^)\frac{1}{\sqrt{3}}\left(\hat{i} - \hat{j} + \hat{k}\right)

  2. B

    13(āˆ’i^+j^āˆ’k^)\frac{1}{\sqrt{3}}\left(-\hat{i} + \hat{j} - \hat{k}\right)

  3. C

    12(āˆ’i^+k^)\frac{1}{\sqrt{2}}\left(-\hat{i} + \hat{k}\right)

  4. D

    15(j^āˆ’2k^)\frac{1}{\sqrt{5}}\left(\hat{j} - 2\hat{k}\right)

Show answer

Correct option: C

Q19JEE Main 2025 Jan 22 Shift 1MediumNumerical

Let cāƒ—\vec{c} be the projection vector of bāƒ—=Ī»i^+4k^\vec{b}=\lambda\hat{i}+4\hat{k}, Ī»>0\lambda>0, on the vector aāƒ—=i^+2j^+2k^\vec{a}=\hat{i}+2\hat{j}+2\hat{k}. If ∣aāƒ—+cāƒ—āˆ£=7|\vec{a}+\vec{c}|=7, then the area of the parallelogram formed by the vectors bāƒ—\vec{b} and cāƒ—\vec{c} is ________.

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Answer: 16

Q20JEE Main 2025 Jan 22 Shift 2Easy

Let aāƒ—\vec{a} and bāƒ—\vec{b} be two unit vectors such that the angle between them is Ļ€3\dfrac{\pi}{3}. If Ī»aāƒ—+2bāƒ—\lambda \vec{a} + 2\vec{b} and 3aāƒ—āˆ’Ī»bāƒ—3\vec{a} - \lambda \vec{b} are perpendicular to each other, then the number of values of Ī»\lambda in [āˆ’1,3][-1, 3] is :

  1. A

    0

  2. B

    1

  3. C

    2

  4. D

    3

Show answer

Correct option: A

Q21JEE Main 2025 Jan 23 Shift 1Medium

Let the arc ACAC of a circle subtend a right angle at the centre OO. If the point BB on the arc ACAC, divides the arc ACAC such that lengthĀ ofĀ arcĀ ABlengthĀ ofĀ arcĀ BC=15\frac{\text{length of arc } AB}{\text{length of arc } BC} = \frac{1}{5}, and OCāƒ—=αOAāƒ—+βOBāƒ—\vec{OC} = \alpha \vec{OA} + \beta \vec{OB}, then α+2(3āˆ’1)β\alpha + \sqrt{2}(\sqrt{3} - 1)\beta is equal to

  1. A

    232\sqrt{3}

  2. B

    2+32 + \sqrt{3}

  3. C

    2āˆ’32 - \sqrt{3}

  4. D

    535\sqrt{3}

Show answer

Correct option: C

Q22JEE Main 2025 Jan 23 Shift 1Hard

Let the position vectors of the vertices AA, BB and CC of a tetrahedron ABCDABCD be i^+2j^+k^\hat{i} + 2\hat{j} + \hat{k}, i^+3j^āˆ’2k^\hat{i} + 3\hat{j} - 2\hat{k} and 2i^+j^āˆ’k^2\hat{i} + \hat{j} - \hat{k} respectively. The altitude from the vertex DD to the opposite face ABCABC meets the median line segment through AA of the triangle ABCABC at the point EE. If the length of ADAD is 1103\frac{\sqrt{110}}{3} and the volume of the tetrahedron is 80562\frac{\sqrt{805}}{6\sqrt{2}}, then the position vector of EE is [Note: stem recovered from a low-resolution embedded thumbnail; the English and Hindi stem images were destroyed by PDF corruption — numeric values should be verified against another copy of this paper]

  1. A

    112(7i^+4j^+3k^)\frac{1}{12}(7\hat{i} + 4\hat{j} + 3\hat{k})

  2. B

    16(7i^+12j^+k^)\frac{1}{6}(7\hat{i} + 12\hat{j} + \hat{k})

  3. C

    16(12i^+12j^+k^)\frac{1}{6}(12\hat{i} + 12\hat{j} + \hat{k})

  4. D

    12(i^+4j^+7k^)\frac{1}{2}(\hat{i} + 4\hat{j} + 7\hat{k})

Show answer

Correct option: B

Q23JEE Main 2025 Jan 23 Shift 2Medium

Let the point A divide the line segment joining the points P(āˆ’1,āˆ’1,2)P(-1, -1, 2) and Q(5,5,10)Q(5, 5, 10) internally in the ratio r:1r : 1 (r>0)(r > 0). If O is the origin and (OQ→⋅OA→)āˆ’15∣OP→×OAā†’āˆ£2=10\left(\overrightarrow{\mathrm{OQ}} \cdot \overrightarrow{\mathrm{OA}}\right) - \dfrac{1}{5}\left|\overrightarrow{\mathrm{OP}} \times \overrightarrow{\mathrm{OA}}\right|^2 = 10, then the value of rr is :

  1. A

    33

  2. B

    7\sqrt{7}

  3. C

    77

  4. D

    1414

Show answer

Correct option: C

Q24JEE Main 2025 Jan 24 Shift 1Medium

Let aāƒ—=i^+2j^+3k^\vec{a}=\hat{i}+2\hat{j}+3\hat{k}, bāƒ—=3i^+j^āˆ’k^\vec{b}=3\hat{i}+\hat{j}-\hat{k} and cāƒ—\vec{c} be three vectors such that cāƒ—\vec{c} is coplanar with aāƒ—\vec{a} and bāƒ—\vec{b}. If the vector cāƒ—\vec{c} is perpendicular to bāƒ—\vec{b} and aāƒ—ā‹…cāƒ—=5\vec{a} \cdot \vec{c} = 5, then ∣cāƒ—āˆ£|\vec{c}| is equal to

  1. A

    116\sqrt{\frac{11}{6}}

  2. B

    132\frac{1}{3\sqrt{2}}

  3. C

    18

  4. D

    16

Show answer

Correct option: A

Q25JEE Main 2025 Jan 24 Shift 2Medium

Let aāƒ—=3i^āˆ’j^+2k^\vec{a} = 3\hat{i} - \hat{j} + 2\hat{k}, bāƒ—=aāƒ—Ć—(i^āˆ’2k^)\vec{b} = \vec{a} \times \left(\hat{i} - 2\hat{k}\right) and cāƒ—=bāƒ—Ć—k^\vec{c} = \vec{b} \times \hat{k}. Then the projection of cāƒ—āˆ’2j^\vec{c} - 2\hat{j} on aāƒ—\vec{a} is :

  1. A

    14\sqrt{14}

  2. B

    2142\sqrt{14}

  3. C

    272\sqrt{7}

  4. D

    373\sqrt{7}

Show answer

Correct option: B

Q26JEE Main 2025 Jan 24 Shift 2Hard

Let the position vectors of three vertices of a triangle be 4pāƒ—+qāƒ—āˆ’3rāƒ—4\vec{p} + \vec{q} - 3\vec{r}, āˆ’5pāƒ—+qāƒ—+2rāƒ—-5\vec{p} + \vec{q} + 2\vec{r} and 2pāƒ—āˆ’qāƒ—+2rāƒ—2\vec{p} - \vec{q} + 2\vec{r}. If the position vectors of the orthocenter and the circumcenter of the triangle are pāƒ—+qāƒ—+rāƒ—4\dfrac{\vec{p} + \vec{q} + \vec{r}}{4} and αpāƒ—+βqāƒ—+γrāƒ—\alpha\vec{p} + \beta\vec{q} + \gamma\vec{r} respectively, then α+2β+5γ\alpha + 2\beta + 5\gamma is equal to :

  1. A

    1

  2. B

    3

  3. C

    4

  4. D

    6

Show answer

Correct option: B

Q27JEE Main 2025 Jan 28 Shift 1HardNumerical

Let aāƒ—=i^+j^+k^\vec{a} = \hat{i} + \hat{j} + \hat{k}, bāƒ—=2i^+2j^+k^\vec{b} = 2\hat{i} + 2\hat{j} + \hat{k} and dāƒ—=aāƒ—Ć—bāƒ—\vec{d} = \vec{a} \times \vec{b}. If cāƒ—\vec{c} is a vector such that aāƒ—ā‹…cāƒ—=∣cāƒ—āˆ£\vec{a} \cdot \vec{c} = |\vec{c}|, ∣cāƒ—āˆ’2aāƒ—āˆ£2=8|\vec{c} - 2\vec{a}|^2 = 8 and the angle between dāƒ—\vec{d} and cāƒ—\vec{c} is Ļ€4\frac{\pi}{4}, then ∣10āˆ’3bāƒ—ā‹…cāƒ—āˆ£+∣dāƒ—Ć—cāƒ—āˆ£2|10 - 3\vec{b} \cdot \vec{c}| + |\vec{d} \times \vec{c}|^2 is equal to ____.

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Answer: 6

Q28JEE Main 2025 Jan 28 Shift 2Medium

Let A, B, C be three points in xyxy-plane, whose position vector are given by 3i^+j^\sqrt{3}\hat{i} + \hat{j}, i^+3j^\hat{i} + \sqrt{3}\hat{j} and ai^+(1āˆ’a)j^a\hat{i} + (1-a)\hat{j} respectively with respect to the origin O. If the distance of the point C from the line bisecting the angle between the vectors OA→\overrightarrow{\mathrm{OA}} and OB→\overrightarrow{\mathrm{OB}} is 92\frac{9}{\sqrt{2}}, then the sum of all the possible values of aa is :

  1. A

    92\frac{9}{2}

  2. B

    2

  3. C

    1

  4. D

    0

Show answer

Correct option: C

Q29JEE Main 2025 Jan 28 Shift 2Medium

If the components of aāƒ—=αi^+βj^+γk^\vec{a} = \alpha\hat{i} + \beta\hat{j} + \gamma\hat{k} along and perpendicular to bāƒ—=3i^+j^āˆ’k^\vec{b} = 3\hat{i} + \hat{j} - \hat{k} respectively, are 1611(3i^+j^āˆ’k^)\frac{16}{11}\left(3\hat{i} + \hat{j} - \hat{k}\right) and 111(āˆ’4i^āˆ’5j^āˆ’17k^)\frac{1}{11}\left(-4\hat{i} - 5\hat{j} - 17\hat{k}\right), then α2+β2+γ2\alpha^2 + \beta^2 + \gamma^2 is equal to :

  1. A

    16

  2. B

    18

  3. C

    23

  4. D

    26

Show answer

Correct option: D

Q30JEE Main 2024 Apr 4 Shift 1Hard

Let a unit vector which makes an angle of 60°60° with 2i^+2j^āˆ’k^2\hat{i}+2\hat{j}-\hat{k} and an angle of 45°45° with i^āˆ’k^\hat{i}-\hat{k} be Cāƒ—\vec{C}. Then Cāƒ—+(āˆ’12i^+132j^āˆ’23k^)\vec{C}+\left(-\frac{1}{2}\hat{i}+\frac{1}{3\sqrt{2}}\hat{j}-\frac{\sqrt{2}}{3}\hat{k}\right) is :

  1. A

    (13+12)i^+(13āˆ’132)j^+(13+23)k^\left(\frac{1}{\sqrt{3}}+\frac{1}{2}\right)\hat{i}+\left(\frac{1}{\sqrt{3}}-\frac{1}{3\sqrt{2}}\right)\hat{j}+\left(\frac{1}{\sqrt{3}}+\frac{\sqrt{2}}{3}\right)\hat{k}

  2. B

    āˆ’23i^+23j^+(12+223)k^-\frac{\sqrt{2}}{3}\hat{i}+\frac{\sqrt{2}}{3}\hat{j}+\left(\frac{1}{2}+\frac{2\sqrt{2}}{3}\right)\hat{k}

  3. C

    23i^āˆ’12k^\frac{\sqrt{2}}{3}\hat{i}-\frac{1}{2}\hat{k}

  4. D

    23i^+132j^āˆ’12k^\frac{\sqrt{2}}{3}\hat{i}+\frac{1}{3\sqrt{2}}\hat{j}-\frac{1}{2}\hat{k}

Show answer

Correct option: C

Q31JEE Main 2024 Apr 4 Shift 1HardNumerical

Let ABC be a triangle of area 15215\sqrt{2} and the vectors ABāƒ—=i^+2j^āˆ’7k^\vec{AB}=\hat{i}+2\hat{j}-7\hat{k}, BCāƒ—=ai^+bj^+ck^\vec{BC}=a\hat{i}+b\hat{j}+c\hat{k} and ACāƒ—=6i^+dj^āˆ’2k^\vec{AC}=6\hat{i}+d\hat{j}-2\hat{k}, d>0d>0. Then the square of the length of the largest side of the triangle ABC is ________.

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Answer: 54

Q32JEE Main 2024 Apr 4 Shift 2Medium

Let aāƒ—=i^+j^+k^\vec{a} = \hat{i} + \hat{j} + \hat{k}, bāƒ—=2i^+4j^āˆ’5k^\vec{b} = 2\hat{i} + 4\hat{j} - 5\hat{k} and cāƒ—=xi^+2j^+3k^,x∈R\vec{c} = x\hat{i} + 2\hat{j} + 3\hat{k}, x \in \mathbb{R}. If dāƒ—\vec{d} is the unit vector in the direction of bāƒ—+cāƒ—\vec{b} + \vec{c} such that aāƒ—ā‹…dāƒ—=1\vec{a} \cdot \vec{d} = 1, then (aāƒ—Ć—bāƒ—)ā‹…cāƒ—(\vec{a} \times \vec{b}) \cdot \vec{c} is equal to

  1. A

    33

  2. B

    66

  3. C

    99

  4. D

    1111

Show answer

Correct option: D

Q33JEE Main 2024 Apr 4 Shift 2Medium

For Ī»>0\lambda > 0, let Īø\theta be the angle between the vectors aāƒ—=i^+Ī»j^āˆ’3k^\vec{a} = \hat{i} + \lambda\hat{j} - 3\hat{k} and bāƒ—=3i^āˆ’j^+2k^\vec{b} = 3\hat{i} - \hat{j} + 2\hat{k}. If the vectors aāƒ—+bāƒ—\vec{a} + \vec{b} and aāƒ—āˆ’bāƒ—\vec{a} - \vec{b} are mutually perpendicular, then the value of (14cos⁔θ)2(14 \cos\theta)^2 is equal to

  1. A

    2525

  2. B

    2020

  3. C

    5050

  4. D

    4040

Show answer

Correct option: A

Q34JEE Main 2024 Apr 5 Shift 1Medium

If A(1,āˆ’1,2)A(1, -1, 2), B(5,7,āˆ’6)B(5, 7, -6), C(3,4,āˆ’10)C(3, 4, -10) and D(āˆ’1,āˆ’4,āˆ’2)D(-1, -4, -2) are the vertices of a quadrilateral ABCD, then its area is :

  1. A

    122912\sqrt{29}

  2. B

    242924\sqrt{29}

  3. C

    48748\sqrt{7}

  4. D

    24724\sqrt{7}

Show answer

Correct option: A

Q35JEE Main 2024 Apr 5 Shift 1MediumNumerical

Let aāƒ—=i^āˆ’3j^+7k^\vec{a} = \hat{i} - 3\hat{j} + 7\hat{k}, bāƒ—=2i^āˆ’j^+k^\vec{b} = 2\hat{i} - \hat{j} + \hat{k} and cāƒ—\vec{c} be a vector such that (aāƒ—+2bāƒ—)Ɨcāƒ—=3(cāƒ—Ć—aāƒ—)(\vec{a} + 2\vec{b}) \times \vec{c} = 3(\vec{c} \times \vec{a}). If aāƒ—ā‹…cāƒ—=130\vec{a} \cdot \vec{c} = 130, then bāƒ—ā‹…cāƒ—\vec{b} \cdot \vec{c} is equal to ________.

Show answer

Answer: 30

Q36JEE Main 2024 Apr 5 Shift 2Medium

Let aāƒ—=2i^+5j^āˆ’k^\vec{a} = 2\hat{i} + 5\hat{j} - \hat{k}, bāƒ—=2i^āˆ’2j^+2k^\vec{b} = 2\hat{i} - 2\hat{j} + 2\hat{k} and cāƒ—\vec{c} be three vectors such that (cāƒ—+i^)Ɨ(aāƒ—+bāƒ—+i^)=aāƒ—Ć—(cāƒ—+i^)(\vec{c} + \hat{i}) \times (\vec{a} + \vec{b} + \hat{i}) = \vec{a} \times (\vec{c} + \hat{i}). If aāƒ—ā‹…cāƒ—=āˆ’29\vec{a} \cdot \vec{c} = -29, then cāƒ—ā‹…(āˆ’2i^+j^+k^)\vec{c} \cdot (-2\hat{i} + \hat{j} + \hat{k}) is equal to :

  1. A

    15

  2. B

    12

  3. C

    10

  4. D

    5

Show answer

Correct option: D

Q37JEE Main 2024 Apr 5 Shift 2Hard

Consider three vectors aāƒ—,bāƒ—,cāƒ—\vec{a}, \vec{b}, \vec{c}. Let ∣aāƒ—āˆ£=2|\vec{a}| = 2, ∣bāƒ—āˆ£=3|\vec{b}| = 3 and aāƒ—=bāƒ—Ć—cāƒ—\vec{a} = \vec{b} \times \vec{c}. If α∈[0,Ļ€3]\alpha \in \left[0, \dfrac{\pi}{3}\right] is the angle between the vectors bāƒ—\vec{b} and cāƒ—\vec{c}, then the minimum value of 27∣cāƒ—āˆ’aāƒ—āˆ£227|\vec{c} - \vec{a}|^2 is equal to :

  1. A

    105

  2. B

    124

  3. C

    110

  4. D

    121

Show answer

Correct option: B

Q38JEE Main 2024 Apr 6 Shift 1Medium

If A(3,1,āˆ’1)A(3, 1, -1), B(53,73,13)B\left(\dfrac{5}{3}, \dfrac{7}{3}, \dfrac{1}{3}\right), C(2,2,1)C(2, 2, 1) and D(103,23,āˆ’13)D\left(\dfrac{10}{3}, \dfrac{2}{3}, \dfrac{-1}{3}\right) are the vertices of a quadrilateral ABCDABCD, then its area is

  1. A

    222\sqrt{2}

  2. B

    523\dfrac{5\sqrt{2}}{3}

  3. C

    223\dfrac{2\sqrt{2}}{3}

  4. D

    423\dfrac{4\sqrt{2}}{3}

Show answer

Correct option: D

Q39JEE Main 2024 Apr 6 Shift 1MediumNumerical

Let aāƒ—=2i^āˆ’3j^+4k^\vec{a} = 2\hat{i} - 3\hat{j} + 4\hat{k}, bāƒ—=3i^+4j^āˆ’5k^\vec{b} = 3\hat{i} + 4\hat{j} - 5\hat{k} and a vector cāƒ—\vec{c} be such that aāƒ—Ć—(bāƒ—+cāƒ—)+bāƒ—Ć—cāƒ—=i^+8j^+13k^\vec{a} \times \left(\vec{b} + \vec{c}\right) + \vec{b} \times \vec{c} = \hat{i} + 8\hat{j} + 13\hat{k}. If aāƒ—ā‹…cāƒ—=13\vec{a} \cdot \vec{c} = 13, then (24āˆ’bāƒ—ā‹…cāƒ—)\left(24 - \vec{b} \cdot \vec{c}\right) is equal to ________.

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Answer: 46

Q40JEE Main 2024 Apr 6 Shift 2Medium

Let aāƒ—=2i^+j^āˆ’k^,Ā bāƒ—=((aāƒ—Ć—(i^+j^))Ɨi^)Ɨi^\vec{a}=2\hat{i}+\hat{j}-\hat{k},\ \vec{b}=\left(\left(\vec{a}\times\left(\hat{i}+\hat{j}\right)\right)\times\hat{i}\right)\times\hat{i}. Then the square of the projection of aāƒ—\vec{a} on bāƒ—\vec{b} is :

  1. A

    13\frac{1}{3}

  2. B

    22

  3. C

    23\frac{2}{3}

  4. D

    15\frac{1}{5}

Show answer

Correct option: B

Q41JEE Main 2024 Apr 6 Shift 2Hard

Let aāƒ—=6i^+j^āˆ’k^\vec{a}=6\hat{i}+\hat{j}-\hat{k} and bāƒ—=i^+j^\vec{b}=\hat{i}+\hat{j}. If cāƒ—\vec{c} is a is vector such that ∣cāƒ—āˆ£ā‰„6|\vec{c}|\ge 6, aāƒ—ā‹…cāƒ—=6∣cāƒ—āˆ£\vec{a}\cdot\vec{c}=6|\vec{c}|, ∣cāƒ—āˆ’aāƒ—āˆ£=22|\vec{c}-\vec{a}|=2\sqrt{2} and the angle between aāƒ—Ć—bāƒ—\vec{a}\times\vec{b} and cāƒ—\vec{c} is 60∘60^{\circ}, then ∣(aāƒ—Ć—bāƒ—)Ɨcāƒ—āˆ£\left|\left(\vec{a}\times\vec{b}\right)\times\vec{c}\right| is equal to :

  1. A

    323\frac{3}{2}\sqrt{3}

  2. B

    326\frac{3}{2}\sqrt{6}

  3. C

    92(6āˆ’6)\frac{9}{2}\left(6-\sqrt{6}\right)

  4. D

    92(6+6)\frac{9}{2}\left(6+\sqrt{6}\right)

Show answer

Correct option: D

Q42JEE Main 2024 Apr 8 Shift 1Medium

The set of all α\alpha, for which the vectors aāƒ—=αt i^+6j^āˆ’3k^\vec{a}=\alpha t\,\hat{i}+6\hat{j}-3\hat{k} and bāƒ—=t i^āˆ’2j^āˆ’2αt k^\vec{b}=t\,\hat{i}-2\hat{j}-2\alpha t\,\hat{k} are inclined at an obtuse angle for all t∈Rt\in\mathbb{R}, is

  1. A

    [0,1)[0, 1)

  2. B

    (āˆ’2,0](-2, 0]

  3. C

    (āˆ’43,0]\left(-\frac{4}{3}, 0\right]

  4. D

    (āˆ’43,1)\left(-\frac{4}{3}, 1\right)

Show answer

Correct option: C

Q43JEE Main 2024 Apr 8 Shift 1HardNumerical

Let aāƒ—=9i^āˆ’13j^+25k^\vec{a}=9\hat{i}-13\hat{j}+25\hat{k}, bāƒ—=3i^+7j^āˆ’13k^\vec{b}=3\hat{i}+7\hat{j}-13\hat{k} and cāƒ—=17i^āˆ’2j^+k^\vec{c}=17\hat{i}-2\hat{j}+\hat{k} be three given vectors. If rāƒ—\vec{r} is a vector such that rāƒ—Ć—aāƒ—=(bāƒ—+cāƒ—)Ɨaāƒ—\vec{r}\times\vec{a}=(\vec{b}+\vec{c})\times\vec{a} and rāƒ—ā‹…(bāƒ—āˆ’cāƒ—)=0\vec{r}\cdot(\vec{b}-\vec{c})=0, then ∣593rāƒ—+67aāƒ—āˆ£2(593)2\frac{|593\vec{r}+67\vec{a}|^2}{(593)^2} is equal to _____.

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Answer: 569

Q44JEE Main 2024 Apr 8 Shift 2Hard

Let aāƒ—=4i^āˆ’j^+k^\vec{a} = 4\hat{i} - \hat{j} + \hat{k}, bāƒ—=11i^āˆ’j^+k^\vec{b} = 11\hat{i} - \hat{j} + \hat{k} and cāƒ—\vec{c} be a vector such that (aāƒ—+bāƒ—)Ɨcāƒ—=cāƒ—Ć—(āˆ’2aāƒ—+3bāƒ—)(\vec{a} + \vec{b}) \times \vec{c} = \vec{c} \times (-2\vec{a} + 3\vec{b}). If (2aāƒ—+3bāƒ—)ā‹…cāƒ—=1670(2\vec{a} + 3\vec{b}) \cdot \vec{c} = 1670, then ∣cāƒ—āˆ£2|\vec{c}|^2 is equal to :

  1. A

    16091609

  2. B

    16001600

  3. C

    16181618

  4. D

    16271627

Show answer

Correct option: C

Q45JEE Main 2024 Apr 8 Shift 2Medium

Let aāƒ—=i^+2j^+3k^\vec{a} = \hat{i} + 2\hat{j} + 3\hat{k}, bāƒ—=2i^+3j^āˆ’5k^\vec{b} = 2\hat{i} + 3\hat{j} - 5\hat{k} and cāƒ—=3i^āˆ’j^+Ī»k^\vec{c} = 3\hat{i} - \hat{j} + \lambda\hat{k} be three vectors. Let rāƒ—\vec{r} be a unit vector along bāƒ—+cāƒ—\vec{b} + \vec{c}. If rāƒ—ā‹…aāƒ—=3\vec{r} \cdot \vec{a} = 3, then 3Ī»3\lambda is equal to :

  1. A

    2525

  2. B

    2727

  3. C

    3030

  4. D

    2121

Show answer

Correct option: A

Q46JEE Main 2024 Apr 9 Shift 1Medium

Let OAāƒ—=2aāƒ—\vec{\mathrm{OA}}=2\vec{a}, OBāƒ—=6aāƒ—+5bāƒ—\vec{\mathrm{OB}}=6\vec{a}+5\vec{b} and OCāƒ—=3bāƒ—\vec{\mathrm{OC}}=3\vec{b}, where O is the origin. If the area of the parallelogram with adjacent sides OAāƒ—\vec{\mathrm{OA}} and OCāƒ—\vec{\mathrm{OC}} is 15 sq. units, then the area (in sq. units) of the quadrilateral OABC is equal to :

  1. A

    3232

  2. B

    3535

  3. C

    3838

  4. D

    4040

Show answer

Correct option: B

Q47JEE Main 2024 Apr 9 Shift 1Medium

Let three vectors aāƒ—=αi^+4j^+2k^\vec{a}=\alpha\hat{i}+4\hat{j}+2\hat{k}, bāƒ—=5i^+3j^+4k^\vec{b}=5\hat{i}+3\hat{j}+4\hat{k}, cāƒ—=xi^+yj^+zk^\vec{c}=x\hat{i}+y\hat{j}+z\hat{k} form a triangle such that cāƒ—=aāƒ—āˆ’bāƒ—\vec{c}=\vec{a}-\vec{b} and the area of the triangle is 565\sqrt{6}. If α\alpha is a positive real number, then ∣cāƒ—āˆ£2|\vec{c}|^2 is equal to :

  1. A

    1010

  2. B

    1212

  3. C

    1414

  4. D

    1616

Show answer

Correct option: C

Q48JEE Main 2024 Apr 9 Shift 2Medium

Between the following two statements:

Statement I: Let aāƒ—=i^+2j^āˆ’3k^\vec{a}=\hat{i}+2\hat{j}-3\hat{k} and bāƒ—=2i^+j^āˆ’k^\vec{b}=2\hat{i}+\hat{j}-\hat{k}. Then the vector rāƒ—\vec{r} satisfying aāƒ—Ć—rāƒ—=aāƒ—Ć—bāƒ—\vec{a}\times\vec{r}=\vec{a}\times\vec{b} and aāƒ—ā‹…rāƒ—=0\vec{a}\cdot\vec{r}=0 is of magnitude 10\sqrt{10}.

Statement II: In a triangle ABCABC, cos⁔2A+cos⁔2B+cos⁔2Cā‰„āˆ’32\cos 2A+\cos 2B+\cos 2C \ge -\dfrac{3}{2}.

  1. A

    Both Statement I and Statement II are correct.

  2. B

    Both Statement I and Statement II are incorrect.

  3. C

    Statement I is correct but Statement II is incorrect.

  4. D

    Statement I is incorrect but Statement II is correct.

Show answer

Correct option: D

Q49JEE Main 2024 Apr 9 Shift 2Medium

Let aāƒ—=2i^+αj^+k^\vec{a}=2\hat{i}+\alpha\hat{j}+\hat{k}, bāƒ—=āˆ’i^+k^\vec{b}=-\hat{i}+\hat{k}, cāƒ—=βj^āˆ’k^\vec{c}=\beta\hat{j}-\hat{k}, where α\alpha and β\beta are integers and αβ=āˆ’6\alpha\beta=-6. Let the values of the ordered pair (α,β)(\alpha, \beta), for which the area of the parallelogram of diagonals aāƒ—+bāƒ—\vec{a}+\vec{b} and bāƒ—+cāƒ—\vec{b}+\vec{c} is 212\dfrac{\sqrt{21}}{2}, be (α1,β1)(\alpha_1, \beta_1) and (α2,β2)(\alpha_2, \beta_2). Then α12+β12āˆ’Ī±2β2\alpha_1^2+\beta_1^2-\alpha_2\beta_2 is equal to

  1. A

    1717

  2. B

    1919

  3. C

    2121

  4. D

    2424

Show answer

Correct option: B

Q50JEE Main 2024 Feb 1 Shift 1Medium

Let aāƒ—=āˆ’5i^+j^āˆ’3k^\vec{a} = -5\hat{i} + \hat{j} - 3\hat{k}, bāƒ—=i^+2j^āˆ’4k^\vec{b} = \hat{i} + 2\hat{j} - 4\hat{k} and cāƒ—=(((aāƒ—Ć—bāƒ—)Ɨi^)Ɨi^)Ɨi^\vec{c} = \left(\left(\left(\vec{a} \times \vec{b}\right) \times \hat{i}\right) \times \hat{i}\right) \times \hat{i}. Then cāƒ—ā‹…(āˆ’i^+j^+k^)\vec{c} \cdot \left(-\hat{i} + \hat{j} + \hat{k}\right) is equal to :

  1. A

    āˆ’10-10

  2. B

    āˆ’12-12

  3. C

    āˆ’13-13

  4. D

    āˆ’15-15

Show answer

Correct option: B

Q51JEE Main 2024 Feb 1 Shift 2Medium

Consider a Ī”ABC\Delta ABC where A(1,3,2)A(1, 3, 2), B(āˆ’2,8,0)B(-2, 8, 0) and C(3,6,7)C(3, 6, 7). If the angle bisector of ∠BAC\angle BAC meets the line BC at D, then the length of the projection of the vector ADāƒ—\vec{AD} on the vector ACāƒ—\vec{AC} is :

  1. A

    19\sqrt{19}

  2. B

    37238\frac{37}{2\sqrt{38}}

  3. C

    382\frac{\sqrt{38}}{2}

  4. D

    39238\frac{39}{2\sqrt{38}}

Show answer

Correct option: B

Q52JEE Main 2024 Feb 1 Shift 2MediumNumerical

Let aāƒ—=i^+j^+k^\vec{a}=\hat{i}+\hat{j}+\hat{k}, bāƒ—=āˆ’i^āˆ’8j^+2k^\vec{b}=-\hat{i}-8\hat{j}+2\hat{k} and cāƒ—=4i^+c2j^+c3k^\vec{c}=4\hat{i}+c_2\hat{j}+c_3\hat{k} be three vectors such that bāƒ—Ć—aāƒ—=cāƒ—Ć—aāƒ—\vec{b} \times \vec{a} = \vec{c} \times \vec{a}. If the angle between the vector cāƒ—\vec{c} and the vector 3i^+4j^+k^3\hat{i}+4\hat{j}+\hat{k} is Īø\theta, then the greatest integer less than or equal to tan⁔2Īø\tan^2\theta is ________.

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Answer: 38

Q53JEE Main 2024 Jan 27 Shift 1Medium

Let aāƒ—=i^+2j^+k^\vec{a} = \hat{i} + 2\hat{j} + \hat{k}, bāƒ—=3(i^āˆ’j^+k^)\vec{b} = 3(\hat{i} - \hat{j} + \hat{k}). Let cāƒ—\vec{c} be the vector such that aāƒ—Ć—cāƒ—=bāƒ—\vec{a} \times \vec{c} = \vec{b} and aāƒ—ā‹…cāƒ—=3\vec{a} \cdot \vec{c} = 3. Then aāƒ—ā‹…((cāƒ—Ć—bāƒ—)āˆ’bāƒ—āˆ’cāƒ—)\vec{a} \cdot \left( (\vec{c} \times \vec{b}) - \vec{b} - \vec{c} \right) is equal to :

  1. A

    2020

  2. B

    2424

  3. C

    3636

  4. D

    3232

Show answer

Correct option: B

Q54JEE Main 2024 Jan 27 Shift 1MediumNumerical

The least positive integral value of α\alpha, for which the angle between the vectors αi^āˆ’2j^+2k^\alpha\hat{i} - 2\hat{j} + 2\hat{k} and αi^+2αj^āˆ’2k^\alpha\hat{i} + 2\alpha\hat{j} - 2\hat{k} is acute, is ________.

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Answer: 5

Q55JEE Main 2024 Jan 29 Shift 1Medium

Let aāƒ—,bāƒ—\vec{a}, \vec{b} and cāƒ—\vec{c} be three non-zero vectors such that bāƒ—\vec{b} and cāƒ—\vec{c} are non-collinear. If aāƒ—+5bāƒ—\vec{a}+5\vec{b} is collinear with cāƒ—\vec{c}, bāƒ—+6cāƒ—\vec{b}+6\vec{c} is collinear with aāƒ—\vec{a} and aāƒ—+αbāƒ—+βcāƒ—=0āƒ—\vec{a}+\alpha\vec{b}+\beta\vec{c}=\vec{0}, then α+β\alpha + \beta is equal to

  1. A

    āˆ’25-25

  2. B

    āˆ’30-30

  3. C

    3030

  4. D

    3535

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Correct option: D

Q56JEE Main 2024 Jan 29 Shift 1Medium

Let O be the origin and the position vectors of A and B be 2i^+2j^+k^2\hat{i}+2\hat{j}+\hat{k} and 2i^+4j^+4k^2\hat{i}+4\hat{j}+4\hat{k} respectively. If the internal bisector of ∠AOB\angle AOB meets the line AB at C, then the length of OC is

  1. A

    2334\dfrac{2}{3}\sqrt{34}

  2. B

    3234\dfrac{3}{2}\sqrt{34}

  3. C

    2331\dfrac{2}{3}\sqrt{31}

  4. D

    3231\dfrac{3}{2}\sqrt{31}

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Correct option: A

Q57JEE Main 2024 Jan 30 Shift 1Medium

Let A(2,3,5)\mathrm{A}(2, 3, 5) and C(āˆ’3,4,āˆ’2)\mathrm{C}(-3, 4, -2) be opposite vertices of a parallelogram ABCD. If the diagonal BD→=i^+2j^+3k^\overrightarrow{\mathrm{BD}}=\hat{i}+2\hat{j}+3\hat{k}, then the area of the parallelogram is equal to :

  1. A

    12474\frac{1}{2}\sqrt{474}

  2. B

    12306\frac{1}{2}\sqrt{306}

  3. C

    12410\frac{1}{2}\sqrt{410}

  4. D

    12586\frac{1}{2}\sqrt{586}

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Correct option: A

Q58JEE Main 2024 Jan 30 Shift 1Medium

Let aāƒ—=a1i^+a2j^+a3k^\vec{a}=a_1\hat{i}+a_2\hat{j}+a_3\hat{k} and bāƒ—=b1i^+b2j^+b3k^\vec{b}=b_1\hat{i}+b_2\hat{j}+b_3\hat{k} be two vectors such that ∣aāƒ—āˆ£=1|\vec{a}|=1, aāƒ—ā‹…bāƒ—=2\vec{a}\cdot\vec{b}=2 and ∣bāƒ—āˆ£=4|\vec{b}|=4. If cāƒ—=2(aāƒ—Ć—bāƒ—)āˆ’3bāƒ—\vec{c}=2(\vec{a}\times\vec{b})-3\vec{b}, then the angle between bāƒ—\vec{b} and cāƒ—\vec{c} is equal to :

  1. A

    cosā”āˆ’1(āˆ’32)\cos^{-1}\left(-\frac{\sqrt{3}}{2}\right)

  2. B

    cosā”āˆ’1(23)\cos^{-1}\left(\frac{2}{\sqrt{3}}\right)

  3. C

    cosā”āˆ’1(23)\cos^{-1}\left(\frac{2}{3}\right)

  4. D

    cosā”āˆ’1(āˆ’13)\cos^{-1}\left(-\frac{1}{\sqrt{3}}\right)

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Correct option: A

Q59JEE Main 2024 Jan 30 Shift 2Medium

Let aāƒ—\vec{a} and bāƒ—\vec{b} be two vectors such that ∣bāƒ—āˆ£=1|\vec{b}|=1 and ∣bāƒ—Ć—aāƒ—āˆ£=2|\vec{b}\times\vec{a}|=2. Then ∣(bāƒ—Ć—aāƒ—)āˆ’bāƒ—āˆ£2\left|(\vec{b}\times\vec{a})-\vec{b}\right|^2 is equal to

  1. A

    1

  2. B

    3

  3. C

    4

  4. D

    5

Show answer

Correct option: D

Q60JEE Main 2024 Jan 30 Shift 2Medium

Let aāƒ—=i^+αj^+βk^, α,β∈R\vec{a}=\hat{i}+\alpha\hat{j}+\beta\hat{k},\ \alpha, \beta \in \mathbb{R}. Let a vector bāƒ—\vec{b} be such that the angle between aāƒ—\vec{a} and bāƒ—\vec{b} is Ļ€4\frac{\pi}{4} and ∣bāƒ—āˆ£2=6|\vec{b}|^2=6. If aāƒ—ā‹…bāƒ—=32\vec{a}\cdot\vec{b}=3\sqrt{2}, then the value of (α2+β2)∣aāƒ—Ć—bāƒ—āˆ£2(\alpha^2+\beta^2)\left|\vec{a}\times\vec{b}\right|^2 is equal to

  1. A

    75

  2. B

    90

  3. C

    85

  4. D

    95

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Correct option: B

Q61JEE Main 2024 Jan 31 Shift 1Medium

Let aāƒ—=3i^+j^āˆ’2k^\vec{a}=3\hat{i}+\hat{j}-2\hat{k}, bāƒ—=4i^+j^+7k^\vec{b}=4\hat{i}+\hat{j}+7\hat{k} and cāƒ—=i^āˆ’3j^+4k^\vec{c}=\hat{i}-3\hat{j}+4\hat{k} be three vectors. If a vectors pāƒ—\vec{p} satisfies pāƒ—Ć—bāƒ—=cāƒ—Ć—bāƒ—\vec{p} \times \vec{b}=\vec{c} \times \vec{b} and pāƒ—ā‹…aāƒ—=0\vec{p} \cdot \vec{a}=0, then pāƒ—ā‹…(i^āˆ’j^āˆ’k^)\vec{p} \cdot (\hat{i}-\hat{j}-\hat{k}) is equal to

  1. A

    2828

  2. B

    2424

  3. C

    3636

  4. D

    3232

Show answer

Correct option: D

Q62JEE Main 2024 Jan 31 Shift 1MediumNumerical

Let aāƒ—\vec{a} and bāƒ—\vec{b} be two vectors such that ∣aāƒ—āˆ£=1,∣bāƒ—āˆ£=4|\vec{a}|=1, |\vec{b}|=4, and aāƒ—ā‹…bāƒ—=2\vec{a} \cdot \vec{b}=2. If cāƒ—=(2aāƒ—Ć—bāƒ—)āˆ’3bāƒ—\vec{c}=(2\vec{a} \times \vec{b})-3\vec{b} and the angle between bāƒ—\vec{b} and cāƒ—\vec{c} is α\alpha, then 192sin⁔2α192\sin^2\alpha is equal to ______

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Answer: 48

Q63JEE Main 2024 Jan 31 Shift 2HardNumerical

Let aāƒ—=3i^+2j^+k^\vec{a}=3 \hat{i}+2 \hat{j}+\hat{k}, bāƒ—=2i^āˆ’j^+3k^\vec{b}=2 \hat{i}-\hat{j}+3 \hat{k} and cāƒ—\vec{c} be a vector such that (aāƒ—+bāƒ—)Ɨcāƒ—=2(aāƒ—Ć—bāƒ—)+24j^āˆ’6k^(\vec{a}+\vec{b}) \times \vec{c}=2(\vec{a} \times \vec{b})+24 \hat{j}-6 \hat{k} and (aāƒ—āˆ’bāƒ—+i^)ā‹…cāƒ—=āˆ’3(\vec{a}-\vec{b}+\hat{i}) \cdot \vec{c}=-3. Then ∣cāƒ—āˆ£2|\vec{c}|^{2} is equal to ______.

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Answer: 38