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JEE Main 2024 Apr 9 Shift 2Physics

30 questions · 30 with the official NTA answer

Q31JEE Main 2024 Apr 9 Shift 2Units and MeasurementsEasy

The de-Broglie wavelength associated with a particle of mass mm and energy EE is h/2mEh/\sqrt{2mE}. The dimensional formula for Planck's constant is :

  1. A

    [M2L2T2][\mathrm{M^2L^2T^{-2}}]

  2. B

    [ML2T1][\mathrm{ML^2T^{-1}}]

  3. C

    [ML1T2][\mathrm{ML^{-1}T^{-2}}]

  4. D

    [MLT2][\mathrm{MLT^{-2}}]

Show answer

Correct option: B

Q32JEE Main 2024 Apr 9 Shift 2KinematicsEasy

Two cars are travelling towards each other at speed of 20 m s120~\mathrm{m~s^{-1}} each. When the cars are 300 m apart, both the drivers apply brakes and the cars retard at the rate of 2 m s22~\mathrm{m~s^{-2}}. The distance between them when they come to rest is :

  1. A

    50 m

  2. B

    100 m

  3. C

    200 m

  4. D

    25 m

Show answer

Correct option: B

Q33JEE Main 2024 Apr 9 Shift 2Laws of MotionEasy

A nucleus at rest disintegrates into two smaller nuclei with their masses in the ratio of 2:1. After disintegration they will move :

  1. A

    in the same direction with same speed.

  2. B

    in opposite directions with speed in the ratio of 1:2 respectively.

  3. C

    in opposite directions with speed in the ratio of 2:1 respectively.

  4. D

    in opposite directions with the same speed.

Show answer

Correct option: B

Q34JEE Main 2024 Apr 9 Shift 2Laws of MotionMedium

A 1 kg mass is suspended from the ceiling by a rope of length 4m. A horizontal force 'FF' is applied at the mid point of the rope so that the rope makes an angle of 45°45° with respect to the vertical axis as shown in figure. The magnitude of FF is :

(Assume that the system is in equilibrium and g=10 m/s2g = 10~\mathrm{m/s^2})

Figure — described from the original paper

a rope hangs from the ceiling; at its midpoint a horizontal force F\vec{F} acts to the left, the upper segment T1T_1 makes θ=45°\theta = 45° with the vertical, and the lower segment T2T_2 carries a 1 kg block

  1. A

    10 N10~N

  2. B

    102 N\frac{10}{\sqrt{2}}~N

  3. C

    110×2 N\frac{1}{10\times\sqrt{2}}~N

  4. D

    1 N1~N

Show answer

Correct option: A

Q35JEE Main 2024 Apr 9 Shift 2Atoms and NucleiEasy

A hydrogen atom in ground state is given an energy of 10.2 eV. How many spectral lines will be emitted due to transition of electrons ?

  1. A

    1

  2. B

    3

  3. C

    6

  4. D

    10

Show answer

Correct option: A

Q36JEE Main 2024 Apr 9 Shift 2ThermodynamicsHard

A real gas within a closed chamber at 27°C27°C undergoes the cyclic process as shown in figure. The gas obeys PV3=RTPV^3 = RT equation for the path AA to BB. The net work done in the complete cycle is (assuming R=8R = 8 J/mol K) :

Figure — described from the original paper

P–V diagram with PP in N/m2\mathrm{N/m^2} and VV in m3\mathrm{m^3}; curve from A (2, 20) to B (4, 10), horizontal line from B back to C (2, 10), and vertical line from C up to A

  1. A

    20 J20~J

  2. B

    20 J-20~J

  3. C

    205 J205~J

  4. D

    225 J225~J

Show answer

Correct option: C

Q37JEE Main 2024 Apr 9 Shift 2Atoms and NucleiMedium

The energy released in the fusion of 2 kg of hydrogen deep in the sun is EHE_H and the energy released in the fission of 2 kg of 235U^{235}\mathrm{U} is EUE_U. The ratio EHEU\frac{E_H}{E_U} is approximately:

(Consider the fusion reaction as 411H+2e24He+2ν+6γ+26.74{}^{1}_{1}\mathrm{H} + 2e^- \rightarrow {}^{4}_{2}He + 2\nu + 6\gamma + 26.7 MeV, energy released in the fission reaction of 235U^{235}\mathrm{U} is 200 MeVMeV per fission nucleus and NA=6.023×1023\mathrm{N_A} = 6.023\times10^{23})

  1. A

    7.62

  2. B

    9.13

  3. C

    25.6

  4. D

    15.04

Show answer

Correct option: A

Q38JEE Main 2024 Apr 9 Shift 2GravitationMedium

A satellite of 10310^3 kg mass is revolving in circular orbit of radius 2R2R. If 104R6\frac{10^4 R}{6} J energy is supplied to the satellite, it would revolve in a new circular orbit of radius :

(use g=10 m/s2g = 10~\mathrm{m/s^2}, RR = radius of earth)

  1. A

    2.5 R2.5~R

  2. B

    3 R3~R

  3. C

    4 R4~R

  4. D

    6 R6~R

Show answer

Correct option: D

Q39JEE Main 2024 Apr 9 Shift 2Properties of Solids and LiquidsEasy

The excess pressure inside a soap bubble is thrice the excess pressure inside a second soap bubble. The ratio between the volume of the first and the second bubble is:

  1. A

    1 : 3

  2. B

    1 : 9

  3. C

    1 : 27

  4. D

    1 : 81

Show answer

Correct option: C

Q40JEE Main 2024 Apr 9 Shift 2Properties of Solids and LiquidsMedium

A spherical ball of radius 1×1041\times10^{-4} m and density 105 kg/m310^5~\mathrm{kg/m^3} falls freely under gravity through a distance hh before entering a tank of water. If after entering in water the velocity of the ball does not change, then the value of hh is approximately:

(The coefficient of viscosity of water is 9.8×106 N s/m29.8\times10^{-6}~N~s/m^2)

  1. A

    2296 m

  2. B

    2249 m

  3. C

    2396 m

  4. D

    2518 m

Show answer

Correct option: D

Q41JEE Main 2024 Apr 9 Shift 2Kinetic Theory of GasesEasy

The temperature of a gas is 78°C-78°\mathrm{C} and the average translational kinetic energy of its molecules is K. The temperature at which the average translational kinetic energy of the molecules of the same gas becomes 2K is :

  1. A

    117°C117°C

  2. B

    127°C127°C

  3. C

    78°C-78°C

  4. D

    39°C-39°C

Show answer

Correct option: A

Q42JEE Main 2024 Apr 9 Shift 2ElectrostaticsEasy

Five charges +q+q, +5q+5q, 2q-2q, +3q+3q and 4q-4q are situated as shown in the figure. The electric flux due to this configuration through the surface SS is :

Figure — described from the original paper

an irregular closed surface S enclosing charges +5q+5q, qq and 2q-2q; charges +3q+3q and 4q-4q lie outside the surface

  1. A

    4qϵ0\frac{4q}{\epsilon_0}

  2. B

    5qϵ0\frac{5q}{\epsilon_0}

  3. C

    3qϵ0\frac{3q}{\epsilon_0}

  4. D

    qϵ0\frac{q}{\epsilon_0}

Show answer

Correct option: A

Q43JEE Main 2024 Apr 9 Shift 2Current ElectricityMedium

The effective resistance between AA and BB, if resistance of each resistor is RR, will be :

Figure — described from the original paper

resistor network — from A a resistor R leads to a diamond of resistors (two R in the upper arms, two R in the lower arms) with two vertical bridge resistors R and two horizontal middle resistors R meeting at the centre, then a resistor R leads to B

  1. A

    23R\frac{2}{3}R

  2. B

    4R3\frac{4R}{3}

  3. C

    5R3\frac{5R}{3}

  4. D

    8R3\frac{8R}{3}

Show answer

Correct option: D

Q44JEE Main 2024 Apr 9 Shift 2Magnetic Effects of Current and MagnetismEasy

A proton and a deutron (q=+eq = +e, m=2.0um = 2.0\mathrm{u}) having same kinetic energies enter a region of uniform magnetic field B\vec{B}, moving perpendicular to B\vec{B}. The ratio of the radius rdr_d of deutron path to the radius rpr_p of the proton path is :

  1. A

    2:1\sqrt{2} : 1

  2. B

    1:21 : \sqrt{2}

  3. C

    1 : 2

  4. D

    1 : 1

Show answer

Correct option: A

Q45JEE Main 2024 Apr 9 Shift 2Electromagnetic Induction and Alternating CurrentsMedium

A square loop of side 15 cm being moved towards right at a constant speed of 2 cm/s as shown in figure. The front edge enters the 50 cm wide magnetic field at t=0t = 0. The value of induced emf in the loop at t=10t = 10 s will be :

Figure — described from the original paper

a 15 cm square loop moving right at 2 cm/s towards a 50 cm wide region of uniform magnetic field B=1.0 TB = 1.0~\mathrm{T} directed into the page

  1. A

    zero

  2. B

    0.3 mV0.3~mV

  3. C

    3 mV3~mV

  4. D

    4.5 mV4.5~mV

Show answer

Correct option: A

Q46JEE Main 2024 Apr 9 Shift 2Ray OpticsMedium

The following figure represents two biconvex lenses L1L_1 and L2L_2 having focal length 10 cm and 15 cm respectively. The distance between L1L_1 & L2L_2 is :

Figure — described from the original paper

parallel rays enter biconvex lens L1L_1, converge and then pass through biconvex lens L2L_2, emerging parallel to the axis

  1. A

    10 cm

  2. B

    15 cm

  3. C

    25 cm

  4. D

    35 cm

Show answer

Correct option: C

Q47JEE Main 2024 Apr 9 Shift 2Dual Nature of Matter and RadiationEasy

UV light of 4.13 eV is incident on a photosensitive metal surface having work function 3.13 eV. The maximum kinetic energy of ejected photoelectrons will be:

  1. A

    1 eV

  2. B

    3.13 eV

  3. C

    4.13 eV

  4. D

    7.26 eV

Show answer

Correct option: A

Q48JEE Main 2024 Apr 9 Shift 2Electronic DevicesMedium
Figure — described from the original paper

logic circuit — inputs A and B feed an AND gate whose output goes to one input of a NOR gate giving output E; A and B also each pass through NOT gates into a second AND gate whose output goes to the other input of the NOR gate

Truth table:

A B E
0 0 0
0 1 X
1 0 Y
1 1 0

In the truth table of the above circuit the value of X and Y are :

  1. A

    1, 0

  2. B

    0, 1

  3. C

    0, 0

  4. D

    1, 1

Show answer

Correct option: D

Q49JEE Main 2024 Apr 9 Shift 2Electronic DevicesEasy

The II-VV characteristics of an electronic device shown in the figure. The device is :

Figure — described from the original paper

I–V curve — small current for positive V rising near the origin, and for negative V a nearly constant small reverse current of 5(μA)5(\mu A) that drops sharply at a large negative (breakdown) voltage

  1. A

    a diode which can be used as a rectifier

  2. B

    a zener diode which can be used as a voltage regulator

  3. C

    a solar cell

  4. D

    a transistor which can be used as an amplifier

Show answer

Correct option: B

Q50JEE Main 2024 Apr 9 Shift 2Electromagnetic WavesMedium

The magnetic field in a plane electromagnetic wave is By=(3.5×107)sin(1.5×103x+0.5×1011t)\mathrm{B_y} = (3.5\times10^{-7})\sin(1.5\times10^3 x + 0.5\times10^{11} t) T. The corresponding electric field will be :

  1. A

    Ey=1.17sin(1.5×103x+0.5×1011t) Vm1E_y = 1.17\sin(1.5\times10^3 x + 0.5\times10^{11}t)~\mathrm{Vm^{-1}}

  2. B

    Ey=10.5sin(1.5×103x+0.5×1011t) Vm1E_y = 10.5\sin(1.5\times10^3 x + 0.5\times10^{11}t)~\mathrm{Vm^{-1}}

  3. C

    Ez=105sin(1.5×103x+0.5×1011t) Vm1E_z = 105\sin(1.5\times10^3 x + 0.5\times10^{11}t)~\mathrm{Vm^{-1}}

  4. D

    Ez=1.17sin(1.5×103x+0.5×1011t) Vm1E_z = 1.17\sin(1.5\times10^3 x + 0.5\times10^{11}t)~\mathrm{Vm^{-1}}

Show answer

Correct option: C

Q51JEE Main 2024 Apr 9 Shift 2Work, Energy and PowerEasyNumerical

A force (3x2+2x5)(3x^2 + 2x - 5) N displaces a body from x=2x = 2 m to x=4x = 4 m. Work done by this force is ________ JJ.

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Answer: 58

Q52JEE Main 2024 Apr 9 Shift 2Wave OpticsMediumNumerical

Monochromatic light of wavelength 500 nm is used in Young's double slit experiment. An interference pattern is obtained on a screen. When one of the slits is covered with a very thin glass plate (refractive index = 1.5), the central maximum is shifted to a position previously occupied by the 4th4^{th} bright fringe. The thickness of the glass-plate is ________ μ\mum.

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Answer: 4

Q53JEE Main 2024 Apr 9 Shift 2Electromagnetic Induction and Alternating CurrentsMediumNumerical

A capacitor of reactance 43 Ω4\sqrt{3}~\Omega and a resistor of resistance 4 Ω4~\Omega are connected in series with an ac source of peak value 828\sqrt{2} V. The power dissipation in the circuit is ________ W.

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Answer: 4

Q54JEE Main 2024 Apr 9 Shift 2Magnetic Effects of Current and MagnetismMediumNumerical

A straight magnetic strip has a magnetic moment of 44 Am2\mathrm{Am^2}. If the strip is bent in a semicircular shape, its magnetic moment will be ________ Am2\mathrm{Am^2}.

(given π=227\pi = \frac{22}{7})

Show answer

Answer: 28

Q55JEE Main 2024 Apr 9 Shift 2Current ElectricityMediumNumerical

At room temperature (27°C27°C), the resistance of a heating element is 50 Ω50~\Omega. The temperature coefficient of the material is 2.4×104 °C12.4\times10^{-4}~°C^{-1}. The temperature of the element, when its resistance is 62 Ω62~\Omega, is ________ °C°C.

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Answer: 1027

Q56JEE Main 2024 Apr 9 Shift 2ElectrostaticsMediumNumerical

An electric field E=(2xi^)NC1\vec{E} = (2x\hat{i})\,\mathrm{NC^{-1}} exists in space. A cube of side 2m is placed in the space as per figure given below. The electric flux through the cube is ________ Nm2/C\mathrm{Nm^2/C}.

Figure — described from the original paper

a cube of side 2 m placed with one face in the y–z plane at a distance 2 m from the origin along the x-axis

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Answer: 16

Q57JEE Main 2024 Apr 9 Shift 2OscillationsMediumNumerical

A particle of mass 0.50 kgkg executes simple harmonic motion under force F=50 (Nm1)xF = -50~(\mathrm{Nm^{-1}})\,x. The time period of oscillation is x35\frac{x}{35} s. The value of xx is ________ .

(Given π=227\pi = \frac{22}{7})

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Answer: 22

Q58JEE Main 2024 Apr 9 Shift 2Rotational MotionMediumNumerical

A circular disc reaches from top to bottom of an inclined plane of length ll. When it slips down the plane, it takes tt s. When it rolls down the plane then it takes (α2)1/2t\left(\frac{\alpha}{2}\right)^{1/2} t s, where α\alpha is ________ .

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Answer: 3

Q59JEE Main 2024 Apr 9 Shift 2KinematicsMediumNumerical

The resultant of two vectors A\vec{A} and B\vec{B} is perpendicular to A\vec{A} and its magnitude is half that of B\vec{B}. The angle between vectors A\vec{A} and B\vec{B} is ________ °°.

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Answer: 150

Q60JEE Main 2024 Apr 9 Shift 2Experimental SkillsMediumNumerical

To determine the resistance (RR) of a wire, a circuit is designed below. The VV-II characteristic curve for this circuit is plotted for the voltmeter and the ammeter readings as shown in figure. The value of RR is __________ Ω\Omega.

Figure — described from the original paper

circuit — a voltmeter V of internal resistance 10 kΩ connected in parallel with resistance R, in series with a milliammeter (mA) and a variable source E; below it a graph of II(mA) versus VV(volt) showing a straight line through the origin passing through points (4, 2), (6, 3) and (8, 4)

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Answer: 2500