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JEE Main 2024 Jan 29 Shift 1 — Mathematics

30 questions Ā· 30 with the official NTA answer

Q1JEE Main 2024 Jan 29 Shift 1Sets, Relations and FunctionsMedium

If f(x)={2+2x,āˆ’1≤x<01āˆ’x3,0≤x≤3f(x)=\begin{cases} 2+2x, & -1 \le x < 0 \\ 1-\dfrac{x}{3}, & 0 \le x \le 3 \end{cases} ; g(x)={āˆ’x,āˆ’3≤x≤0x,0<x≤1g(x)=\begin{cases} -x, & -3 \le x \le 0 \\ x, & 0 < x \le 1 \end{cases}, then range of (fog)(x)(fog)(x) is

  1. A

    [0,3)[0,3)

  2. B

    [0,1][0,1]

  3. C

    [0,1)[0,1)

  4. D

    (0,1](0,1]

Show answer

Correct option: B

Q2JEE Main 2024 Jan 29 Shift 1Sets, Relations and FunctionsEasy

Let R be a relation on ZƗZ\mathbb{Z}\times\mathbb{Z} defined by (a, b) R (c, d) if and only if adāˆ’bcad - bc is divisible by 5. Then R is

  1. A

    Reflexive and transitive but not symmetric

  2. B

    Reflexive and symmetric but not transitive

  3. C

    Reflexive, symmetric and transitive

  4. D

    Reflexive but neither symmetric nor transitive

Show answer

Correct option: B

Q3JEE Main 2024 Jan 29 Shift 1Complex NumbersMedium

If z=12āˆ’2iz=\dfrac{1}{2}-2i is such that ∣z+1∣=αz+β(1+i)|z+1| = \alpha z + \beta(1+i), i=āˆ’1i=\sqrt{-1} and α,β∈R\alpha, \beta \in \mathbb{R}, then α+β\alpha + \beta is equal to

  1. A

    āˆ’1-1

  2. B

    22

  3. C

    33

  4. D

    āˆ’4-4

Show answer

Correct option: C

Q4JEE Main 2024 Jan 29 Shift 1Matrices and DeterminantsMedium

Let A be a square matrix such that AAT=IAA^T = I. Then 12A[(A+AT)2+(Aāˆ’AT)2]\dfrac{1}{2} A\left[\left(A+A^T\right)^2 + \left(A-A^T\right)^2\right] is equal to

  1. A

    A2+ATA^2 + A^T

  2. B

    A3+ATA^3 + A^T

  3. C

    A2+IA^2 + I

  4. D

    A3+IA^3 + I

Show answer

Correct option: B

Q5JEE Main 2024 Jan 29 Shift 1Matrices and DeterminantsMedium

Let A=[1000αβ0βα]A = \begin{bmatrix} 1 & 0 & 0 \\ 0 & \alpha & \beta \\ 0 & \beta & \alpha \end{bmatrix} and ∣2A∣3=221|2A|^3 = 2^{21} where α,β∈Z\alpha, \beta \in \mathbb{Z}. Then a value of α\alpha is

  1. A

    33

  2. B

    55

  3. C

    99

  4. D

    1717

Show answer

Correct option: B

Q6JEE Main 2024 Jan 29 Shift 1Sequences and SeriesMedium

In an A.P., the sixth term a6=2a_6 = 2. If the product a1a4a5a_1 a_4 a_5 is the greatest, then the common difference of the A.P. is equal to

  1. A

    58\dfrac{5}{8}

  2. B

    85\dfrac{8}{5}

  3. C

    23\dfrac{2}{3}

  4. D

    32\dfrac{3}{2}

Show answer

Correct option: B

Q7JEE Main 2024 Jan 29 Shift 1Sequences and SeriesMedium

If in a G.P. of 64 terms, the sum of all the terms is 7 times the sum of the odd terms of the G.P, then the common ratio of the G.P. is equal to

  1. A

    44

  2. B

    55

  3. C

    66

  4. D

    77

Show answer

Correct option: C

Q8JEE Main 2024 Jan 29 Shift 1Limits, Continuity and DifferentiabilityHard

lim⁔x→π2(1(xāˆ’Ļ€2)2∫x3(Ļ€2)3cos⁔(t13)dt)\lim\limits_{x \to \frac{\pi}{2}}\left(\dfrac{1}{\left(x-\frac{\pi}{2}\right)^2}\int\limits_{x^3}^{\left(\frac{\pi}{2}\right)^3} \cos\left(t^{\frac{1}{3}}\right)dt\right) is equal to

  1. A

    3Ļ€4\dfrac{3\pi}{4}

  2. B

    3Ļ€8\dfrac{3\pi}{8}

  3. C

    3Ļ€24\dfrac{3\pi^2}{4}

  4. D

    3Ļ€28\dfrac{3\pi^2}{8}

Show answer

Correct option: D

Q9JEE Main 2024 Jan 29 Shift 1Differentiation and Applications of DerivativesMedium

Suppose f(x)=(2x+2āˆ’x)tan⁔xtanā”āˆ’1(x2āˆ’x+1)(7x2+3x+1)3f(x)=\dfrac{\left(2^x + 2^{-x}\right)\tan x\sqrt{\tan^{-1}\left(x^2 - x + 1\right)}}{\left(7x^2 + 3x + 1\right)^3}. Then the value of f′(0)f'(0) is equal to

  1. A

    00

  2. B

    π\sqrt{\pi}

  3. C

    π\pi

  4. D

    π2\dfrac{\pi}{2}

Show answer

Correct option: B

Q10JEE Main 2024 Jan 29 Shift 1Differentiation and Applications of DerivativesMedium

Consider the function f:[12,1]→Rf:\left[\dfrac{1}{2},1\right] \to \mathbb{R} defined by f(x)=42x3āˆ’32xāˆ’1f(x)=4\sqrt{2}x^3 - 3\sqrt{2}x - 1.

Consider the statements

(I) The curve y=f(x)y=f(x) intersects the xx-axis exactly at one point.

(II) The curve y=f(x)y=f(x) intersects the xx-axis at x=cos⁔π12x=\cos\dfrac{\pi}{12}.

Then

  1. A

    Both (I) and (II) are correct.

  2. B

    Both (I) and (II) are incorrect.

  3. C

    Only (I) is correct.

  4. D

    Only (II) is correct.

Show answer

Correct option: A

Q11JEE Main 2024 Jan 29 Shift 1Integral CalculusMedium

If the value of the integral āˆ«āˆ’Ļ€2Ļ€2(x2cos⁔x1+Ļ€x+1+sin⁔2x1+esin⁔x2023)dx=Ļ€4(Ļ€+a)āˆ’2\int\limits_{-\frac{\pi}{2}}^{\frac{\pi}{2}}\left(\dfrac{x^2\cos x}{1+\pi^x} + \dfrac{1+\sin^2 x}{1+e^{\sin x^{2023}}}\right)dx = \dfrac{\pi}{4}(\pi + a) - 2, then the value of aa is

  1. A

    22

  2. B

    āˆ’32-\dfrac{3}{2}

  3. C

    32\dfrac{3}{2}

  4. D

    33

Show answer

Correct option: D

Q12JEE Main 2024 Jan 29 Shift 1Integral CalculusHard

For x∈(āˆ’Ļ€2,Ļ€2)x \in \left(-\dfrac{\pi}{2},\dfrac{\pi}{2}\right), if y(x)=∫cosec⁔x+sin⁔xcosec⁔xsec⁔x+tan⁔xsin⁔2x dxy(x)=\int \dfrac{\operatorname{cosec} x + \sin x}{\operatorname{cosec} x \sec x + \tan x \sin^2 x}\,dx, and lim⁔x→(Ļ€2)āˆ’y(x)=0\lim\limits_{x \to \left(\frac{\pi}{2}\right)^-} y(x) = 0 then y(Ļ€4)y\left(\dfrac{\pi}{4}\right) is equal to

  1. A

    tanā”āˆ’1(12)\tan^{-1}\left(\dfrac{1}{\sqrt{2}}\right)

  2. B

    12tanā”āˆ’1(āˆ’12)\dfrac{1}{\sqrt{2}}\tan^{-1}\left(-\dfrac{1}{2}\right)

  3. C

    āˆ’12tanā”āˆ’1(12)-\dfrac{1}{\sqrt{2}}\tan^{-1}\left(\dfrac{1}{\sqrt{2}}\right)

  4. D

    12tanā”āˆ’1(12)\dfrac{1}{2}\tan^{-1}\left(\dfrac{1}{\sqrt{2}}\right)

Show answer

Correct option: B

Q13JEE Main 2024 Jan 29 Shift 1Differential EquationsMedium

A function y=f(x)y=f(x) satisfies f(x)sin⁔2x+sin⁔xāˆ’(1+cos⁔2x)f′(x)=0f(x)\sin 2x + \sin x - \left(1+\cos^2 x\right)f'(x) = 0 with condition f(0)=0f(0)=0. Then, f(Ļ€2)f\left(\dfrac{\pi}{2}\right) is equal to

  1. A

    00

  2. B

    11

  3. C

    āˆ’1-1

  4. D

    22

Show answer

Correct option: B

Q14JEE Main 2024 Jan 29 Shift 1Straight LinesMedium

Let (5,a4)\left(5,\dfrac{a}{4}\right) be the circumcenter of a triangle with vertices A(a,āˆ’2)A(a,-2), B(a,6)B(a,6) and C(a4,āˆ’2)C\left(\dfrac{a}{4},-2\right). Let α\alpha denote the circumradius, β\beta denote the area and γ\gamma denote the perimeter of the triangle. Then α+β+γ\alpha + \beta + \gamma is

  1. A

    3030

  2. B

    6060

  3. C

    6262

  4. D

    5353

Show answer

Correct option: D

Q15JEE Main 2024 Jan 29 Shift 1Straight LinesHard

In a ā–³ABC\triangle ABC, suppose y=xy=x is the equation of the bisector of the angle BB and the equation of the side ACAC is 2xāˆ’y=22x - y = 2. If 2AB=BC2AB = BC and the points AA and BB are respectively (4,6)(4, 6) and (α,β)(\alpha, \beta), then α+2β\alpha + 2\beta is equal to

  1. A

    3939

  2. B

    4242

  3. C

    4545

  4. D

    4848

Show answer

Correct option: B

Q16JEE Main 2024 Jan 29 Shift 1Three Dimensional GeometryMedium

Let PQR be a triangle with R (āˆ’1,4,2)(-1, 4, 2). Suppose M (2,1,2)(2, 1, 2) is the mid point of PQ. The distance of the centroid of ā–³PQR\triangle PQR from the point of intersection of the lines xāˆ’20=y2=z+3āˆ’1\dfrac{x-2}{0}=\dfrac{y}{2}=\dfrac{z+3}{-1} and xāˆ’11=y+3āˆ’3=z+11\dfrac{x-1}{1}=\dfrac{y+3}{-3}=\dfrac{z+1}{1} is

  1. A

    99

  2. B

    69\sqrt{69}

  3. C

    6969

  4. D

    99\sqrt{99}

Show answer

Correct option: B

Q17JEE Main 2024 Jan 29 Shift 1Vector AlgebraMedium

Let aāƒ—,bāƒ—\vec{a}, \vec{b} and cāƒ—\vec{c} be three non-zero vectors such that bāƒ—\vec{b} and cāƒ—\vec{c} are non-collinear. If aāƒ—+5bāƒ—\vec{a}+5\vec{b} is collinear with cāƒ—\vec{c}, bāƒ—+6cāƒ—\vec{b}+6\vec{c} is collinear with aāƒ—\vec{a} and aāƒ—+αbāƒ—+βcāƒ—=0āƒ—\vec{a}+\alpha\vec{b}+\beta\vec{c}=\vec{0}, then α+β\alpha + \beta is equal to

  1. A

    āˆ’25-25

  2. B

    āˆ’30-30

  3. C

    3030

  4. D

    3535

Show answer

Correct option: D

Q18JEE Main 2024 Jan 29 Shift 1Vector AlgebraMedium

Let O be the origin and the position vectors of A and B be 2i^+2j^+k^2\hat{i}+2\hat{j}+\hat{k} and 2i^+4j^+4k^2\hat{i}+4\hat{j}+4\hat{k} respectively. If the internal bisector of ∠AOB\angle AOB meets the line AB at C, then the length of OC is

  1. A

    2334\dfrac{2}{3}\sqrt{34}

  2. B

    3234\dfrac{3}{2}\sqrt{34}

  3. C

    2331\dfrac{2}{3}\sqrt{31}

  4. D

    3231\dfrac{3}{2}\sqrt{31}

Show answer

Correct option: A

Q19JEE Main 2024 Jan 29 Shift 1ProbabilityMedium

A fair die is thrown until 2 appears. Then the probability, that 2 appears in even number of throws, is

  1. A

    16\dfrac{1}{6}

  2. B

    56\dfrac{5}{6}

  3. C

    611\dfrac{6}{11}

  4. D

    511\dfrac{5}{11}

Show answer

Correct option: D

Q20JEE Main 2024 Jan 29 Shift 1Trigonometric Ratios and EquationsMedium

If α,āˆ’Ļ€2<α<Ļ€2\alpha, -\dfrac{\pi}{2} < \alpha < \dfrac{\pi}{2} is the solution of 4cos⁔θ+5sin⁔θ=14\cos\theta + 5\sin\theta = 1, then the value of tan⁔α\tan\alpha is

  1. A

    10āˆ’106\dfrac{\sqrt{10}-10}{6}

  2. B

    10āˆ’106\dfrac{10-\sqrt{10}}{6}

  3. C

    10āˆ’1012\dfrac{\sqrt{10}-10}{12}

  4. D

    10āˆ’1012\dfrac{10-\sqrt{10}}{12}

Show answer

Correct option: C

Q21JEE Main 2024 Jan 29 Shift 1Complex NumbersMediumNumerical

Let α,β\alpha, \beta be the roots of the equation x2āˆ’x+2=0x^2 - x + 2 = 0 with Im(α)>Im(β)Im(\alpha) > Im(\beta).

Then α6+α4+β4āˆ’5α2\alpha^6 + \alpha^4 + \beta^4 - 5\alpha^2 is equal to __________.

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Answer: 13

Q22JEE Main 2024 Jan 29 Shift 1Permutations and CombinationsMediumNumerical

All the letters of the word "GTWENTY" are written in all possible ways with or without meaning and these words are written as in a dictionary. The serial number of the word "GTWENTY" is __________.

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Answer: 553

Q23JEE Main 2024 Jan 29 Shift 1Binomial TheoremMediumNumerical

If 11C12+11C23+…+11C910=nm\dfrac{{}^{11}C_1}{2} + \dfrac{{}^{11}C_2}{3} + \ldots + \dfrac{{}^{11}C_9}{10} = \dfrac{n}{m} with gcd⁔(n,m)=1\gcd(n,m)=1, then n+mn + m is equal to __________.

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Answer: 2041

Q24JEE Main 2024 Jan 29 Shift 1Differentiation and Applications of DerivativesMediumNumerical

Let f(x)=2xāˆ’x2f(x) = 2^x - x^2, x∈Rx \in \mathbb{R}. If mm and nn are respectively the number of points at which the curves y=f(x)y=f(x) and y=f′(x)y=f'(x) intersect the xx-axis, then the value of m+nm + n is __________.

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Answer: 5

Q25JEE Main 2024 Jan 29 Shift 1Integral CalculusHardNumerical

The area (in sq. units) of the part of the circle x2+y2=169x^2 + y^2 = 169 which is below the line 5xāˆ’y=135x - y = 13 is πα2Ī²āˆ’652+αβsinā”āˆ’1(1213)\dfrac{\pi\alpha}{2\beta} - \dfrac{65}{2} + \dfrac{\alpha}{\beta}\sin^{-1}\left(\dfrac{12}{13}\right), where α,β\alpha, \beta are coprime numbers. Then α+β\alpha + \beta is equal to _______

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Answer: 171

Q26JEE Main 2024 Jan 29 Shift 1Differential EquationsHardNumerical

If the solution curve y=y(x)y=y(x) of the differential equation (1+y2)(1+log⁔ex) dx+x dy=0(1+y^2)(1+\log_e x)\,dx + x\,dy = 0, x>0x > 0 passes through the point (1,1)(1,1) and y(e)=Ī±āˆ’tan⁔(32)β+tan⁔(32)y(e) = \dfrac{\alpha - \tan\left(\dfrac{3}{2}\right)}{\beta + \tan\left(\dfrac{3}{2}\right)}, then α+2β\alpha + 2\beta is __________.

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Answer: 3

Q27JEE Main 2024 Jan 29 Shift 1CirclesMediumNumerical

Equations of two diameters of a circle are 2xāˆ’3y=52x - 3y = 5 and 3xāˆ’4y=73x - 4y = 7. The line joining the points (āˆ’227,āˆ’4)\left(-\dfrac{22}{7}, -4\right) and (āˆ’17,3)\left(-\dfrac{1}{7}, 3\right) intersects the circle at only one point P(α,β)P(\alpha, \beta). Then, 17Ī²āˆ’Ī±17\beta - \alpha is equal to _______.

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Answer: 2

Q28JEE Main 2024 Jan 29 Shift 1Conic SectionsMediumNumerical

If the points of intersection of two distinct conics x2+y2=4bx^2 + y^2 = 4b and x216+y2b2=1\dfrac{x^2}{16} + \dfrac{y^2}{b^2} = 1 lie on the curve y2=3x2y^2 = 3x^2, then 333\sqrt{3} times the area of the rectangle formed by the intersection points is __________.

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Answer: 432

Q29JEE Main 2024 Jan 29 Shift 1Three Dimensional GeometryHardNumerical

A line with direction ratios 2, 1, 2 meets the lines x=y+2=zx = y + 2 = z and x+2=2y=2zx + 2 = 2y = 2z respectively at the points P and Q. If the length of the perpendicular from the point (1,2,12)(1, 2, 12) to the line PQ is ll, then l2l^2 is __________.

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Answer: 65

Q30JEE Main 2024 Jan 29 Shift 1StatisticsMediumNumerical

If the mean and variance of the data 65, 68, 58, 44, 48, 45, 60, α\alpha, β\beta, 60 where α>β\alpha > \beta, are 56 and 66.2 respectively, then α2+β2\alpha^2 + \beta^2 is equal to ________.

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Answer: 6344