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JEE Main 2024 Jan 31 Shift 2Chemistry

30 questions · 30 with the official NTA answer

Q61JEE Main 2024 Jan 31 Shift 2Some Basic Concepts in ChemistryMedium

A sample of CaCO3\mathrm{CaCO_3} and MgCO3\mathrm{MgCO_3} weighed 2.21 g2.21\ \mathrm{g} is ignited to constant weight of 1.152 g1.152\ \mathrm{g}. The composition of mixture is :

(Given molar mass in g mol1\mathrm{g\ mol^{-1}} CaCO3\mathrm{CaCO_3} : 100, MgCO3\mathrm{MgCO_3} : 84)

  1. A

    1.023 g CaCO3+1.187 g MgCO31.023\ \mathrm{g}\ \mathrm{CaCO_3} + 1.187\ \mathrm{g}\ \mathrm{MgCO_3}

  2. B

    1.187 g CaCO3+1.023 g MgCO31.187\ \mathrm{g}\ \mathrm{CaCO_3} + 1.023\ \mathrm{g}\ \mathrm{MgCO_3}

  3. C

    1.023 g CaCO3+1.023 g MgCO31.023\ \mathrm{g}\ \mathrm{CaCO_3} + 1.023\ \mathrm{g}\ \mathrm{MgCO_3}

  4. D

    1.187 g CaCO3+1.187 g MgCO31.187\ \mathrm{g}\ \mathrm{CaCO_3} + 1.187\ \mathrm{g}\ \mathrm{MgCO_3}

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Correct option: B

Q62JEE Main 2024 Jan 31 Shift 2Atomic StructureEasy

The four quantum numbers for the electron in the outer most orbital of potassium (atomic no. 19) are

  1. A

    n=2, l=0, m=0, s=+12\mathrm{n} = 2,\ l = 0,\ \mathrm{m} = 0,\ s = +\frac{1}{2}

  2. B

    n=3, l=0, m=1, s=+12\mathrm{n} = 3,\ l = 0,\ \mathrm{m} = 1,\ s = +\frac{1}{2}

  3. C

    n=4, l=0, m=0, s=+12\mathrm{n} = 4,\ l = 0,\ \mathrm{m} = 0,\ s = +\frac{1}{2}

  4. D

    n=4, l=2, m=1, s=+12\mathrm{n} = 4,\ l = 2,\ \mathrm{m} = -1,\ s = +\frac{1}{2}

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Correct option: C

Q63JEE Main 2024 Jan 31 Shift 2Chemical Bonding and Molecular StructureEasy

Which of the following is least ionic?

  1. A

    KCl\mathrm{KCl}

  2. B

    AgCl\mathrm{AgCl}

  3. C

    BaCl2\mathrm{BaCl_2}

  4. D

    CoCl2\mathrm{CoCl_2}

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Correct option: B

Q64JEE Main 2024 Jan 31 Shift 2EquilibriumMedium

A(g)B(g)+C2(g)\mathrm{A_{(g)}} \rightleftharpoons \mathrm{B_{(g)}} + \frac{\mathrm{C}}{2}_{\mathrm{(g)}} The correct relationship between KP\mathrm{K_P}, α\alpha and equilibrium pressure P\mathrm{P} is

  1. A

    KP=α3/2P1/2(2+α)1/2(1α)\mathrm{K_P} = \dfrac{\alpha^{3/2}\,\mathrm{P}^{1/2}}{(2+\alpha)^{1/2}(1-\alpha)}

  2. B

    KP=α1/2P1/2(2+α)1/2\mathrm{K_P} = \dfrac{\alpha^{1/2}\,\mathrm{P}^{1/2}}{(2+\alpha)^{1/2}}

  3. C

    KP=α1/2P1/2(2+α)3/2\mathrm{K_P} = \dfrac{\alpha^{1/2}\,\mathrm{P}^{1/2}}{(2+\alpha)^{3/2}}

  4. D

    KP=α1/2P3/2(2+α)3/2\mathrm{K_P} = \dfrac{\alpha^{1/2}\,\mathrm{P}^{3/2}}{(2+\alpha)^{3/2}}

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Correct option: A

Q65JEE Main 2024 Jan 31 Shift 2Redox Reactions and ElectrochemistryMedium

Given below are two statements :

Statement I : S8\mathrm{S_8} solid undergoes disproportionation reaction under alkaline conditions to form S2\mathrm{S^{2-}} and S2O32\mathrm{S_2O_3^{2-}}.

Statement II : ClO4\mathrm{ClO_4^-} can undergo disproportionation reaction under acidic condition.

In the light of the above statements, choose the most appropriate answer from the options given below :

  1. A

    Both statement I and statement II are correct

  2. B

    Both statement I and statement II are incorrect

  3. C

    Statement I is correct but statement II is incorrect

  4. D

    Statement I is incorrect but statement II is correct

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Correct option: C

Q66JEE Main 2024 Jan 31 Shift 2Classification of Elements and PeriodicityMedium

Consider the following elements.

GroupABCDPeriod\text{Group} \downarrow \quad \begin{matrix} \mathrm{A'} & \mathrm{B'} \\ \mathrm{C'} & \mathrm{D'} \end{matrix} \quad \rightarrow \text{Period}

(A′ and B′ lie in the same period with B′ to the right of A′; C′ and D′ lie in the next period directly below A′ and B′ respectively.)

Which of the following is/are true about A′, B′, C′ and D′?

A. Order of atomic radii: B′ < A′ < D′ < C′ B. Order of metallic character: B′ < A′ < D′ < C′ C. Size of the element: D′ < C′ < B′ < A′ D. Order of ionic radii: B′⁺ < A′⁺ < D′⁺ < C′⁺

Choose the correct answer from the options given below :

  1. A

    A, B and D only

  2. B

    A and B only

  3. C

    B, C and D only

  4. D

    A only

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Correct option: A

Q67JEE Main 2024 Jan 31 Shift 2p-Block ElementsMedium

Given below are two statements :

Statement I : Group 13 trivalent halides get easily hydrolyzed by water due to their covalent nature.

Statement II : AlCl3\mathrm{AlCl_3} upon hydrolysis in acidified aqueous solution forms octahedral [Al(H2O)6]3+\mathrm{[Al(H_2O)_6]^{3+}} ion.

In the light of the above statements, choose the correct answer from the options given below :

  1. A

    Both statement I and statement II are true

  2. B

    Both statement I and statement II are false

  3. C

    Statement I is true but statement II is false

  4. D

    Statement I is false but statement II is true

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Correct option: A

Q68JEE Main 2024 Jan 31 Shift 2p-Block ElementsMedium

Choose the correct statements from the following

A. All group 16 elements form oxides of general formula EO2\mathrm{EO_2} and EO3\mathrm{EO_3}, where E = S, Se, Te and Po. Both the types of oxides are acidic in nature. B. TeO2\mathrm{TeO_2} is an oxidising agent while SO2\mathrm{SO_2} is reducing in nature. C. The reducing property decreases from H2S\mathrm{H_2S} to H2Te\mathrm{H_2Te} down the group. D. The ozone molecule contains five lone pairs of electrons.

Choose the correct answer from the options given below:

  1. A

    B and C only

  2. B

    A and B only

  3. C

    A and D only

  4. D

    C and D only

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Correct option: B

Q69JEE Main 2024 Jan 31 Shift 2d- and f-Block ElementsMedium

Choose the correct statements from the following

A. Mn2O7\mathrm{Mn_2O_7} is an oil at room temperature B. V2O4\mathrm{V_2O_4} reacts with acid to give VO22+\mathrm{VO_2^{2+}} C. CrO\mathrm{CrO} is a basic oxide D. V2O5\mathrm{V_2O_5} does not react with acid

Choose the correct answer from the options given below :

  1. A

    B and C only

  2. B

    A, B and C only

  3. C

    A, B and D only

  4. D

    A and C only

Show answer

Correct option: D

Q70JEE Main 2024 Jan 31 Shift 2Coordination CompoundsEasy

Select the option with correct property -

  1. A

    [NiCl4]2\mathrm{[NiCl_4]^{2-}} Diamagnetic, [Ni(CO)4]\mathrm{[Ni(CO)_4]} Paramagnetic

  2. B

    [Ni(CO)4]\mathrm{[Ni(CO)_4]} Diamagnetic, [NiCl4]2\mathrm{[NiCl_4]^{2-}} Paramagnetic

  3. C

    [Ni(CO)4]\mathrm{[Ni(CO)_4]} and [NiCl4]2\mathrm{[NiCl_4]^{2-}} both Diamagnetic

  4. D

    [Ni(CO)4]\mathrm{[Ni(CO)_4]} and [NiCl4]2\mathrm{[NiCl_4]^{2-}} both Paramagnetic

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Correct option: B

Q71JEE Main 2024 Jan 31 Shift 2Coordination CompoundsMedium

Match List I with List II

LIST I (Complex ion) LIST II (Electronic Configuration)
A. [Cr(H2O)6]3+\mathrm{[Cr(H_2O)_6]^{3+}} I. t2g2eg0t_{2g}^{2}\,e_g^{0}
B. [Fe(H2O)6]3+\mathrm{[Fe(H_2O)_6]^{3+}} II. t2g3eg0t_{2g}^{3}\,e_g^{0}
C. [Ni(H2O)6]2+\mathrm{[Ni(H_2O)_6]^{2+}} III. t2g3eg2t_{2g}^{3}\,e_g^{2}
D. [V(H2O)6]3+\mathrm{[V(H_2O)_6]^{3+}} IV. t2g6eg2t_{2g}^{6}\,e_g^{2}

Choose the correct answer from the options given below:

  1. A

    A-II, B-III, C-IV, D-I

  2. B

    A-III, B-II, C-IV, D-I

  3. C

    A-IV, B-I, C-II, D-III

  4. D

    A-IV, B-III, C-I, D-II

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Correct option: A

Q72JEE Main 2024 Jan 31 Shift 2Purification and Characterisation of Organic CompoundsEasy

The fragrance of flowers is due to the presence of some steam volatile organic compounds called essential oils. These are generally insoluble in water at room temperature but are miscible with water vapour in vapour phase. A suitable method for the extraction of these oils from the flowers is -

  1. A

    distillation

  2. B

    crystallisation

  3. C

    distillation under reduced pressure

  4. D

    steam distillation

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Correct option: D

Q73JEE Main 2024 Jan 31 Shift 2HydrocarbonsEasy

The correct order of reactivity in electrophilic substitution reaction of the following compounds is :

Figure — described from the original paper

four benzene-ring structures — A: benzene, B: toluene (C6H5CH3\mathrm{C_6H_5CH_3}), C: chlorobenzene (C6H5Cl\mathrm{C_6H_5Cl}), D: nitrobenzene (C6H5NO2\mathrm{C_6H_5NO_2})

  1. A

    A > B > C > D

  2. B

    D > C > B > A

  3. C

    B > C > A > D

  4. D

    B > A > C > D

Show answer

Correct option: D

Q74JEE Main 2024 Jan 31 Shift 2Organic Compounds Containing HalogensEasy

Identify structure of 2,3–dibromo–1–phenylpentane.

  1. A
    Figure — described from the original paper

    skeletal structure

    C6H5CH2CH2CH(Br)CH(Br)CH3\mathrm{C_6H_5-CH_2-CH_2-CH(Br)-CH(Br)-CH_3}

  2. B
    Figure — described from the original paper

    skeletal structure

    C6H5CH(Br)CH(Br)CH2CH2CH3\mathrm{C_6H_5-CH(Br)-CH(Br)-CH_2-CH_2-CH_3}

  3. C
    Figure — described from the original paper

    skeletal structure

    C6H5CH2CH(Br)CH(Br)CH2CH3\mathrm{C_6H_5-CH_2-CH(Br)-CH(Br)-CH_2-CH_3}

  4. D
    Figure — described from the original paper

    skeletal structure

    C6H5CH(Br)CH2CH(Br)CH2CH3\mathrm{C_6H_5-CH(Br)-CH_2-CH(Br)-CH_2-CH_3}

Show answer

Correct option: C

Q75JEE Main 2024 Jan 31 Shift 2HydrocarbonsMedium

Major product of the following reaction is -

Figure — described from the original paper

1-methylcyclopent-1-ene treated with DCl\mathrm{D-Cl}

1-methylcyclopenteneDCl?\text{1-methylcyclopentene} \xrightarrow{\mathrm{D-Cl}} ?

  1. A
    Figure — described from the original paper

    cyclopentane ring with adjacent carbons — one bearing D (up) and H (down), the other bearing CH3\mathrm{CH_3} (up) and Cl (down); i.e. Cl and CH3\mathrm{CH_3} on the same carbon, with D and CH3\mathrm{CH_3} cis

  2. B
    Figure — described from the original paper

    cyclopentane ring with adjacent carbons — one bearing D (up) and H (down), the other bearing Cl (up) and CH3\mathrm{CH_3} (down); i.e. Cl and CH3\mathrm{CH_3} on the same carbon, with D and Cl cis

  3. C
    Figure — described from the original paper

    cyclopentane ring with adjacent carbons — one bearing H (up) and Cl (down), the other bearing D (up) and CH3\mathrm{CH_3} (down); i.e. D and CH3\mathrm{CH_3} on the same carbon, with Cl on the adjacent carbon

  4. D
    Figure — described from the original paper

    cyclopentane ring with adjacent carbons — one bearing Cl (up) and H (down), the other bearing D (up) and CH3\mathrm{CH_3} (down); i.e. D and CH3\mathrm{CH_3} on the same carbon, with Cl cis to D on the adjacent carbon

Show answer

Correct option: A

Q76JEE Main 2024 Jan 31 Shift 2Organic Compounds Containing HalogensMedium

Identify A and B in the following reaction sequence.

BromobenzeneConc HNO3A(ii) HCl(i) NaOHB\text{Bromobenzene} \xrightarrow{\text{Conc } \mathrm{HNO_3}} \mathrm{A} \xrightarrow[\text{(ii) } \mathrm{HCl}]{\text{(i) } \mathrm{NaOH}} \mathrm{B}

Figure — described from the original paper

reaction scheme starting from bromobenzene

  1. A

    [Figure] A = 1-bromo-4-nitrobenzene; B = benzene ring with Br, OH ortho to Br and NO2\mathrm{NO_2} para to Br (2-bromo-4-nitrophenol skeleton)

  2. B

    [Figure] A = 1-bromo-2,4-dinitrobenzene; B = benzene ring with Br, OH ortho to Br and OH para to Br

  3. C

    [Figure] A = 2,4,6-trinitrobromobenzene (Br with NO2\mathrm{NO_2} at both ortho and para positions); B = 2,4,6-trinitrophenol (OH with NO2\mathrm{NO_2} at both ortho and para positions)

  4. D

    [Figure] A = nitrobenzene; B = 3-nitrophenol (NO2\mathrm{NO_2} meta to OH)

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Correct option: C

Q77JEE Main 2024 Jan 31 Shift 2HydrocarbonsEasy

Identify major product 'P' formed in the following reaction.

C6H6+C6H5COClAnhydrous AlCl3’P’ (Major Product)\mathrm{C_6H_6} + \mathrm{C_6H_5COCl} \xrightarrow{\text{Anhydrous } \mathrm{AlCl_3}} \text{'P' (Major Product)}

Figure — described from the original paper

benzene plus benzoyl chloride reaction scheme

  1. A

    [Figure] Benzaldehyde, C6H5CHO\mathrm{C_6H_5CHO}

  2. B

    [Figure] Benzophenone, C6H5COC6H5\mathrm{C_6H_5COC_6H_5}

  3. C

    [Figure] Phenoxy-substituted benzoyl chloride, C6H5OC6H4COCl\mathrm{C_6H_5-O-C_6H_4-COCl}

  4. D

    [Figure] Acetophenone, C6H5COCH3\mathrm{C_6H_5COCH_3}

Show answer

Correct option: B

Q78JEE Main 2024 Jan 31 Shift 2Organic Compounds Containing OxygenEasy

Identify the name reaction.

C6H6Anhyd. AlCl3/CuClCO, HClC6H5CHO\mathrm{C_6H_6} \xrightarrow[\text{Anhyd. } \mathrm{AlCl_3/CuCl}]{\mathrm{CO,\ HCl}} \mathrm{C_6H_5CHO}

  1. A

    Etard Reaction

  2. B

    Stephen Reaction

  3. C

    Gatterman - Koch Reaction

  4. D

    Rosenmund Reduction

Show answer

Correct option: C

Q79JEE Main 2024 Jan 31 Shift 2Organic Compounds Containing NitrogenMedium

Given below are two statements :

Statement I : Aniline reacts with con. H2SO4\mathrm{H_2SO_4}, followed by heating at 453 - 473 K gives p-aminobenzene sulphonic acid, which gives blood red colour in the 'Lassaigne's test'.

Statement II : In Friedel - Craft's alkylation and acylation reactions, aniline forms salt with the AlCl3\mathrm{AlCl_3} catalyst. Due to this, nitrogen of aniline aquires a positive charge and acts as deactivating group.

In the light of the above statements, choose the correct answer from the options given below :

  1. A

    Both statement I and statement II are true

  2. B

    Both statement I and statement II are false

  3. C

    Statement I is true but statement II is false

  4. D

    Statement I is false but statement II is true

Show answer

Correct option: A

Q80JEE Main 2024 Jan 31 Shift 2Organic Compounds Containing NitrogenMedium

The azo-dye (YY) formed in the following reactions is

Sulphanilic acid + NaNO2\mathrm{NaNO_2} + CH3COOH\mathrm{CH_3COOH} → X.

X+naphthalen-1-amineY\mathrm{X} + \text{naphthalen-1-amine} \longrightarrow \mathrm{Y}

Figure — described from the original paper

X reacting with 1-aminonaphthalene (naphthalene with NH2\mathrm{NH_2} at position 1)

  1. A

    [Figure] HSO3C6H4N=N\mathrm{HSO_3-C_6H_4-N{=}N-}naphthalene with NH2\mathrm{NH_2} on the same ring as the azo linkage (azo group and NH2\mathrm{NH_2} both on the top ring, at positions 1 and 4)

  2. B

    [Figure] HSO3C6H4N=N\mathrm{HSO_3-C_6H_4-N{=}N-}naphthalene with NH2\mathrm{NH_2} on the other ring (azo group at position 1, NH2\mathrm{NH_2} at position 5)

  3. C

    [Figure] Bis-azo structure: two HO3S\mathrm{HO_3S}-bearing naphthalene units each linked through N=N\mathrm{N{=}N}, one unit carrying NH2\mathrm{NH_2}

  4. D

    [Figure] HSO3C6H4N=N\mathrm{HSO_3-C_6H_4-N{=}N-}naphthaleneN=NC6H4SO3H\mathrm{-N{=}N-C_6H_4-SO_3H} (naphthalene bearing two azo linkages, one on each ring)

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Correct option: A

Q81JEE Main 2024 Jan 31 Shift 2Chemical Bonding and Molecular StructureMediumNumerical

A diatomic molecule has a dipole moment of 1.2 D. If the bond distance is 1 A˚1\ \mathrm{\AA}, then fractional charge on each atom is _______ ×101\times 10^{-1} esu.

(Given 1 D = 101810^{-18} esucm)

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Answer: 0

Q82JEE Main 2024 Jan 31 Shift 2Chemical ThermodynamicsMediumNumerical

If 5 moles of an ideal gas expands from 10 L to a volume of 100 L at 300 K under isothermal and reversible condition then work, w, is x-x J. The value of xx is _________.

(Given R=8.314 J K1 mol1\mathrm{R} = 8.314\ \mathrm{J\ K^{-1}\ mol^{-1}})

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Answer: 28721

Q83JEE Main 2024 Jan 31 Shift 2Some Basic Concepts in ChemistryMediumNumerical

The molarity of 1 L orthophosphoric acid (H3PO4\mathrm{H_3PO_4}) having 70% purity by weight (specific gravity 1.54 g cm31.54\ \mathrm{g\ cm^{-3}}) is ________ M.

(Molar mass of H3PO4\mathrm{H_3PO_4} = 98 g mol198\ \mathrm{g\ mol^{-1}})

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Answer: 11

Q84JEE Main 2024 Jan 31 Shift 2Redox Reactions and ElectrochemistryEasyNumerical

The values of conductivity of some materials at 298.15 K in S m1\mathrm{S\ m^{-1}} are 2.1×1032.1 \times 10^{3}, 1.0×10161.0 \times 10^{-16}, 1.2×101.2 \times 10, 3.913.91, 1.5×1021.5 \times 10^{-2}, 1×1071 \times 10^{-7}, 1.0×1031.0 \times 10^{3}. The number of conductors among the materials is ________.

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Answer: 4

Q85JEE Main 2024 Jan 31 Shift 2Chemical KineticsMediumNumerical

r=k[A]r = k\,[\mathrm{A}] for a reaction, 50% of A is decomposed in 120 minutes. The time taken for 90% decomposition of A is ________ minutes.

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Answer: 399

Q86JEE Main 2024 Jan 31 Shift 2Redox Reactions and ElectrochemistryMediumNumerical

Number of moles of H+\mathrm{H^+} ions required by 1 mole of MnO4\mathrm{MnO_4^-} to oxidise oxalate ion to CO2\mathrm{CO_2} is _______.

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Answer: 4

Q87JEE Main 2024 Jan 31 Shift 2Organic Compounds Containing HalogensMediumNumerical

Number of isomeric products formed by monochlorination of 2-methylbutane in presence of sunlight is ________.

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Answer: 6

Q88JEE Main 2024 Jan 31 Shift 2Organic Compounds Containing NitrogenMediumNumerical

A compound (xx) with molar mass 108 g mol1108\ \mathrm{g\ mol^{-1}} undergoes acetylation to give product with molar mass 192 g mol1192\ \mathrm{g\ mol^{-1}}. The number of amino groups in the compund (xx) is _______.

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Answer: 2

Q89JEE Main 2024 Jan 31 Shift 2BiomoleculesEasyNumerical

From the vitamins A, B1\mathrm{B_1}, B6\mathrm{B_6}, B12\mathrm{B_{12}}, C, D, E and K, the number of vitamins that can be stored in our body is________.

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Answer: 5

Q90JEE Main 2024 Jan 31 Shift 2d- and f-Block ElementsMediumNumerical

In the reaction of potassium dichromate, potassium chloride and sulfuric acid (conc.), the oxidation state of the chromium in the product is (+)________.

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Answer: 6