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JEE Main 2025 Apr 4 Shift 1 — Mathematics

25 questions Ā· 25 with the official NTA answer

Q1JEE Main 2025 Apr 4 Shift 1Sets, Relations and FunctionsMedium

Consider the sets A={(x,y)∈RƗR:x2+y2=25}A = \{(x, y) \in \mathbb{R} \times \mathbb{R} : x^2 + y^2 = 25\}, B={(x,y)∈RƗR:x2+9y2=144}B = \{(x, y) \in \mathbb{R} \times \mathbb{R} : x^2 + 9y^2 = 144\}, C={(x,y)∈ZƗZ:x2+y2≤4}C = \{(x, y) \in \mathbb{Z} \times \mathbb{Z} : x^2 + y^2 \le 4\} and D=A∩BD = A \cap B. The total number of one-one functions from the set DD to the set CC is:

  1. A

    15120

  2. B

    17160

  3. C

    18290

  4. D

    19320

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Correct option: B

Q2JEE Main 2025 Apr 4 Shift 1Sets, Relations and FunctionsMedium

Let f,g:(1,āˆž)→Rf, g : (1, \infty) \to \mathbb{R} be defined as f(x)=2x+35x+2f(x) = \frac{2x+3}{5x+2} and g(x)=2āˆ’3x1āˆ’xg(x) = \frac{2-3x}{1-x}. If the range of the function fog:[2,4]→Rfog : [2, 4] \to \mathbb{R} is [α,β][\alpha, \beta], then 1Ī²āˆ’Ī±\frac{1}{\beta - \alpha} is equal to

  1. A

    2

  2. B

    29

  3. C

    56

  4. D

    68

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Correct option: C

Q3JEE Main 2025 Apr 4 Shift 1Quadratic EquationsMedium

Consider the equation x2+4xāˆ’n=0x^2 + 4x - n = 0, where n∈[20,100]n \in [20, 100] is a natural number. Then the number of all distinct values of nn, for which the given equation has integral roots, is equal to

  1. A

    5

  2. B

    6

  3. C

    7

  4. D

    8

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Correct option: B

Q4JEE Main 2025 Apr 4 Shift 1Sequences and SeriesMedium

Let A={1,6,11,16,…}A = \{1, 6, 11, 16, \ldots\} and B={9,16,23,30,…}B = \{9, 16, 23, 30, \ldots\} be the sets consisting of the first 2025 terms of two arithmetic progressions. Then n(A∪B)n(A \cup B) is

  1. A

    3814

  2. B

    3761

  3. C

    4027

  4. D

    4003

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Correct option: B

Q5JEE Main 2025 Apr 4 Shift 1Sequences and SeriesMedium

1+3+52+7+92+…1 + 3 + 5^2 + 7 + 9^2 + \ldots upto 40 terms is equal to

  1. A

    33980

  2. B

    43890

  3. C

    40870

  4. D

    41880

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Correct option: D

Q6JEE Main 2025 Apr 4 Shift 1Binomial TheoremMedium

In the expansion of (23+133)n\left(\sqrt[3]{2} + \frac{1}{\sqrt[3]{3}}\right)^n, n∈Nn \in \mathbb{N}, if the ratio of 15th15^{\text{th}} term from the beginning to the 15th15^{\text{th}} term from the end is 16\frac{1}{6}, then the value of nC3^{n}\mathrm{C}_3 is

  1. A

    1040

  2. B

    2300

  3. C

    4060

  4. D

    4960

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Correct option: B

Q7JEE Main 2025 Apr 4 Shift 1Binomial TheoremMedium

For an integer n≄2n \ge 2, if the arithmetic mean of all coefficients in the binomial expansion of (x+y)2nāˆ’3(x + y)^{2n-3} is 16, then the distance of the point P(2nāˆ’1,n2āˆ’4n)\mathrm{P}(2n - 1, n^2 - 4n) from the line x+y=8x + y = 8 is

  1. A

    2\sqrt{2}

  2. B

    222\sqrt{2}

  3. C

    323\sqrt{2}

  4. D

    525\sqrt{2}

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Correct option: C

Q8JEE Main 2025 Apr 4 Shift 1ProbabilityMedium

The probability, of forming a 12 persons committee from 4 engineers, 2 doctors and 10 professors containing at least 3 engineers and at least 1 doctor, is

  1. A

    129182\frac{129}{182}

  2. B

    103182\frac{103}{182}

  3. C

    1726\frac{17}{26}

  4. D

    1926\frac{19}{26}

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Correct option: A

Q9JEE Main 2025 Apr 4 Shift 1ProbabilityMedium

A box contains 10 pens of which 3 are defective. A sample of 2 pens is drawn at random and let XX denote the number of defective pens. Then the variance of XX is

  1. A

    35\frac{3}{5}

  2. B

    1115\frac{11}{15}

  3. C

    215\frac{2}{15}

  4. D

    2875\frac{28}{75}

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Correct option: D

Q10JEE Main 2025 Apr 4 Shift 1Straight LinesMedium

Let the three sides of a triangle are on the lines 4xāˆ’7y+10=04x - 7y + 10 = 0, x+y=5x + y = 5 and 7x+4y=157x + 4y = 15. Then the distance of its orthocentre from the orthocentre of the tringle formed by the lines x=0x = 0, y=0y = 0 and x+y=1x + y = 1 is

  1. A

    20

  2. B

    5

  3. C

    5\sqrt{5}

  4. D

    20\sqrt{20}

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Correct option: C

Q11JEE Main 2025 Apr 4 Shift 1Conic SectionsMedium

The length of the latus-rectum of the ellipse, whose foci are (2,5)(2, 5) and (2,āˆ’3)(2, -3) and eccentricity is 45\frac{4}{5}, is

  1. A

    185\frac{18}{5}

  2. B

    103\frac{10}{3}

  3. C

    65\frac{6}{5}

  4. D

    503\frac{50}{3}

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Correct option: A

Q12JEE Main 2025 Apr 4 Shift 1Trigonometric Ratios and EquationsMedium

If 10sin⁔4Īø+15cos⁔4Īø=610\sin^4\theta + 15\cos^4\theta = 6, then the value of 27 cosec6Īø+8sec⁔6Īø16sec⁔8Īø\frac{27\,\mathrm{cosec}^6\theta + 8\sec^6\theta}{16\sec^8\theta} is

  1. A

    15\frac{1}{5}

  2. B

    34\frac{3}{4}

  3. C

    25\frac{2}{5}

  4. D

    35\frac{3}{5}

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Correct option: C

Q13JEE Main 2025 Apr 4 Shift 1Inverse Trigonometric FunctionsMedium

Considering the principal values of the inverse trigonometric functions, sinā”āˆ’1(32x+121āˆ’x2)\sin^{-1}\left(\frac{\sqrt{3}}{2}x + \frac{1}{2}\sqrt{1 - x^2}\right), āˆ’12<x<12-\frac{1}{2} < x < \frac{1}{\sqrt{2}}, is equal to

  1. A

    Ļ€4+sinā”āˆ’1x\frac{\pi}{4} + \sin^{-1} x

  2. B

    Ļ€6+sinā”āˆ’1x\frac{\pi}{6} + \sin^{-1} x

  3. C

    5Ļ€6āˆ’sinā”āˆ’1x\frac{5\pi}{6} - \sin^{-1} x

  4. D

    āˆ’5Ļ€6āˆ’sinā”āˆ’1x\frac{-5\pi}{6} - \sin^{-1} x

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Correct option: B

Q14JEE Main 2025 Apr 4 Shift 1Three Dimensional GeometryMedium

Let the shortest distance between the lines xāˆ’33=yāˆ’Ī±āˆ’1=zāˆ’31\frac{x-3}{3} = \frac{y-\alpha}{-1} = \frac{z-3}{1} and x+3āˆ’3=y+72=zāˆ’Ī²4\frac{x+3}{-3} = \frac{y+7}{2} = \frac{z-\beta}{4} be 3303\sqrt{30}. Then the positive value of 5α+β5\alpha + \beta is

  1. A

    40

  2. B

    42

  3. C

    46

  4. D

    48

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Correct option: C

Q15JEE Main 2025 Apr 4 Shift 1Three Dimensional GeometryMedium

Let AA and BB be two distinct points on the line L:xāˆ’63=yāˆ’72=zāˆ’7āˆ’2L : \frac{x-6}{3} = \frac{y-7}{2} = \frac{z-7}{-2}. Both AA and BB are at a distance 2172\sqrt{17} from the foot of perpendicular drawn from the point (1,2,3)(1, 2, 3) on the line LL. If OO is the origin, then OA→⋅OB→\overrightarrow{OA} \cdot \overrightarrow{OB} is equal to

  1. A

    21

  2. B

    47

  3. C

    49

  4. D

    62

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Correct option: B

Q16JEE Main 2025 Apr 4 Shift 1Vector AlgebraMedium

Consider two vectors uāƒ—=3i^āˆ’j^\vec{u} = 3\hat{i} - \hat{j} and vāƒ—=2i^+j^āˆ’Ī»k^\vec{v} = 2\hat{i} + \hat{j} - \lambda\hat{k}, Ī»>0\lambda > 0. The angle between them is given by cosā”āˆ’1(527)\cos^{-1}\left(\frac{\sqrt{5}}{2\sqrt{7}}\right). Let vāƒ—=v1āƒ—+v2āƒ—\vec{v} = \vec{v_1} + \vec{v_2}, where v1āƒ—\vec{v_1} is parallel to uāƒ—\vec{u} and v2āƒ—\vec{v_2} is perpendicular to uāƒ—\vec{u}. Then the value ∣v1āƒ—āˆ£2+∣v2āƒ—āˆ£2|\vec{v_1}|^2 + |\vec{v_2}|^2 is equal to

  1. A

    14

  2. B

    10

  3. C

    232\frac{23}{2}

  4. D

    252\frac{25}{2}

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Correct option: A

Q17JEE Main 2025 Apr 4 Shift 1Limits, Continuity and DifferentiabilityMedium

If lim⁔x→1+(xāˆ’1)(6+Ī»cos⁔(xāˆ’1))+μsin⁔(1āˆ’x)(xāˆ’1)3=āˆ’1\lim\limits_{x \to 1^{+}} \frac{(x-1)(6 + \lambda\cos(x-1)) + \mu\sin(1-x)}{(x-1)^3} = -1, where Ī»,μ∈R\lambda, \mu \in \mathbb{R}, then Ī»+μ\lambda + \mu is equal to

  1. A

    17

  2. B

    18

  3. C

    19

  4. D

    20

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Correct option: B

Q18JEE Main 2025 Apr 4 Shift 1Limits, Continuity and DifferentiabilityMedium

Let f:R→Rf : \mathbb{R} \to \mathbb{R} be a continuous function satisfying f(0)=1f(0) = 1 and f(2x)āˆ’f(x)=xf(2x) - f(x) = x for all x∈Rx \in \mathbb{R}. If lim⁔nā†’āˆž{f(x)āˆ’f(x2n)}=G(x)\lim\limits_{n \to \infty}\left\{f(x) - f\left(\frac{x}{2^n}\right)\right\} = G(x), then āˆ‘r=110G(r2)\sum\limits_{r=1}^{10} G(r^2) is equal to

  1. A

    215

  2. B

    385

  3. C

    420

  4. D

    540

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Correct option: B

Q19JEE Main 2025 Apr 4 Shift 1Integral CalculusMedium

The value of āˆ«āˆ’11(1+∣xāˆ£āˆ’x)ex+(∣xāˆ£āˆ’x)eāˆ’xex+eāˆ’x dx\int\limits_{-1}^{1} \frac{\left(1 + \sqrt{|x| - x}\right)e^x + \left(\sqrt{|x| - x}\right)e^{-x}}{e^x + e^{-x}}\, dx is equal to

  1. A

    2+2232 + \frac{2\sqrt{2}}{3}

  2. B

    3āˆ’2233 - \frac{2\sqrt{2}}{3}

  3. C

    1āˆ’2231 - \frac{2\sqrt{2}}{3}

  4. D

    1+2231 + \frac{2\sqrt{2}}{3}

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Correct option: D

Q20JEE Main 2025 Apr 4 Shift 1Differential EquationsHard

Let f:[0,āˆž)→Rf : [0, \infty) \to \mathbb{R} be a differentiable function such that f(x)=1āˆ’2x+∫0xexāˆ’tf(t) dtf(x) = 1 - 2x + \int\limits_{0}^{x} e^{x-t} f(t)\, dt for all x∈[0,āˆž)x \in [0, \infty). Then the area of the region bounded by y=f(x)y = f(x) and the coordinate axes is

  1. A

    2

  2. B

    2\sqrt{2}

  3. C

    12\frac{1}{2}

  4. D

    5\sqrt{5}

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Correct option: C

Q21JEE Main 2025 Apr 4 Shift 1Complex NumbersMediumNumerical

Let A={z∈C:∣zāˆ’2āˆ’i∣=3}\mathrm{A} = \{z \in \mathbb{C} : |z - 2 - i| = 3\}, B={z∈C:Re(zāˆ’iz)=2}\mathrm{B} = \{z \in \mathbb{C} : \mathrm{Re}(z - iz) = 2\} and S=A∩B\mathrm{S} = \mathrm{A} \cap \mathrm{B}. Then āˆ‘z∈S∣z∣2\sum\limits_{z \in S} |z|^2 is equal to ________

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Answer: 22

Q22JEE Main 2025 Apr 4 Shift 1Matrices and DeterminantsMediumNumerical

Let A=[cos⁔θ0āˆ’sin⁔θ010sin⁔θ0cos⁔θ]\mathrm{A} = \begin{bmatrix} \cos\theta & 0 & -\sin\theta \\ 0 & 1 & 0 \\ \sin\theta & 0 & \cos\theta \end{bmatrix}. If for some θ∈(0,Ļ€)\theta \in (0, \pi), A2=AT\mathrm{A}^2 = \mathrm{A}^{\mathrm{T}}, then the sum of the diagonal elements of the matrix (A+I)3+(Aāˆ’I)3āˆ’6A(\mathrm{A} + \mathrm{I})^3 + (\mathrm{A} - \mathrm{I})^3 - 6\mathrm{A} is equal to ________.

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Answer: 6

Q23JEE Main 2025 Apr 4 Shift 1Conic SectionsHardNumerical

Let CC be the circle x2+(yāˆ’1)2=2x^2 + (y-1)^2 = 2, E1E_1 and E2E_2 be two ellipses whose centres lie at the origin and major axes lie on x-axis and y-axis respectively. Let the straight line x+y=3x + y = 3 touch the curves CC, E1E_1 and E2E_2 at P(x1,y1)P(x_1, y_1), Q(x2,y2)Q(x_2, y_2) and R(x3,y3)R(x_3, y_3) respectively. Given that PP is the mid point of the line segment QRQR and PQ=223PQ = \frac{2\sqrt{2}}{3}, the value of 9(x1y1+x2y2+x3y3)9(x_1 y_1 + x_2 y_2 + x_3 y_3) is equal to ________

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Answer: 46

Q24JEE Main 2025 Apr 4 Shift 1Limits, Continuity and DifferentiabilityMediumNumerical

Let mm and nn be the number of points at which the function f(x)=max⁔{x,x3,x5,…,x21}f(x) = \max\{x, x^3, x^5, \ldots, x^{21}\}, x∈Rx \in \mathbb{R}, is not differentiable and not continuous, respectively. Then m+nm + n is equal to ________

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Answer: 3

Q25JEE Main 2025 Apr 4 Shift 1Integral CalculusMediumNumerical

If the area of the region {(x,y):∣xāˆ’5āˆ£ā‰¤y≤4x}\{(x, y) : |x - 5| \le y \le 4\sqrt{x}\} is AA, then 3A3A is equal to ________

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Answer: 368