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JEE Main 2025 Jan 22 Shift 2 — Physics

18 questions Ā· 17 with the official NTA answer

Q26JEE Main 2025 Jan 22 Shift 2Units and MeasurementsEasy

Which one of the following is the correct dimensional formula for the capacitance in F ? M, L, T and C stand for unit of mass, length, time and charge,

  1. A

    [F]=[CMāˆ’1Lāˆ’2T2][\mathrm{F}] = [\mathrm{C M^{-1} L^{-2} T^{2}}]

  2. B

    [F]=[CMāˆ’2Lāˆ’2Tāˆ’2][\mathrm{F}] = [\mathrm{C M^{-2} L^{-2} T^{-2}}]

  3. C

    [F]=[C2Māˆ’2L2T2][\mathrm{F}] = [\mathrm{C^{2} M^{-2} L^{2} T^{2}}]

  4. D

    [F]=[C2Māˆ’1Lāˆ’2T2][\mathrm{F}] = [\mathrm{C^{2} M^{-1} L^{-2} T^{2}}]

Show answer

Correct option: D

Q27JEE Main 2025 Jan 22 Shift 2Units and MeasurementsMedium

The maximum percentage error in the measurment of density of a wire is

[Given, mass of wire =(0.60±0.003) g= (0.60 \pm 0.003)\,\mathrm{g}

radius of wire =(0.50±0.01) cm= (0.50 \pm 0.01)\,\mathrm{cm}

length of wire =(10.00±0.05) cm= (10.00 \pm 0.05)\,\mathrm{cm}]

  1. A

    8

  2. B

    7

  3. C

    5

  4. D

    4

Show answer

Correct option: C

Q28JEE Main 2025 Jan 22 Shift 2Rotational MotionEasy

The torque due to the force (2i^+j^+2k^)\left(2\hat{i} + \hat{j} + 2\hat{k}\right) about the origin, acting on a particle whose position vector is (i^+j^+k^)\left(\hat{i} + \hat{j} + \hat{k}\right), would be

  1. A

    i^āˆ’k^\hat{i} - \hat{k}

  2. B

    j^+k^\hat{j} + \hat{k}

  3. C

    i^āˆ’j^+k^\hat{i} - \hat{j} + \hat{k}

  4. D

    i^+k^\hat{i} + \hat{k}

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Correct option: A

Q29JEE Main 2025 Jan 22 Shift 2Work, Energy and PowerEasy

A ball of mass 100 g is projected with velocity 20 m/s at 60∘60^{\circ} with horizontal. The decrease in kinetic energy of the ball during the motion from point of projection to highest point is

  1. A

    zero

  2. B

    15 J

  3. C

    20 J

  4. D

    5 J

Show answer

Correct option: B

Q30JEE Main 2025 Jan 22 Shift 2Work, Energy and PowerMedium

A body of mass 100 g is moving in circular path of radius 2 m on vertical plane as shown in figure. The velocity of the body at point A is 10 m/s. The ratio of its kinetic energies at point B and C is :

Figure — described from the original paper

a vertical circle with centre O; A is the lowest point, D the highest point; C lies above the horizontal diameter and B below it, with OB making 30∘30^{\circ} with the horizontal and angle between OC and OB equal to 90∘90^{\circ}

(Take acceleration due to gravity as 10Ā m/s210\ \mathrm{m/s^2})

  1. A

    3āˆ’22\frac{3 - \sqrt{2}}{2}

  2. B

    2+33\frac{2 + \sqrt{3}}{3}

  3. C

    3+32\frac{3 + \sqrt{3}}{2}

  4. D

    2+23\frac{2 + \sqrt{2}}{3}

Show answer

Correct option: C

Q31JEE Main 2025 Jan 22 Shift 2Work, Energy and PowerEasy

A force Fāƒ—=2i^+bj^+k^\vec{F} = 2\hat{i} + b\hat{j} + \hat{k} is applied on a particle and it undergoes a displacement i^āˆ’2j^āˆ’k^\hat{i} - 2\hat{j} - \hat{k}. What will be the value of b, if work done on the particle is zero.

  1. A

    12\frac{1}{2}

  2. B

    0

  3. C

    13\frac{1}{3}

  4. D

    2

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Correct option: A

Q32JEE Main 2025 Jan 22 Shift 2Properties of Solids and LiquidsEasy
Figure — described from the original paper

a tapering tube; water enters the wider end marked (1) and leaves the narrower end marked (2)

A tube of length L is shown in the figure. The radius of cross section at the point (1) is 2 cm and at the point (2) is 1 cm, respectively. If the velocity of water entering at point (1) is 2 m/s, then velocity of water leaving the point (2) will be

  1. A

    6 m/s

  2. B

    8 m/s

  3. C

    4 m/s

  4. D

    2 m/s

Show answer

Correct option: B

Q33JEE Main 2025 Jan 22 Shift 2Properties of Solids and LiquidsMedium

A small rigid spherical ball of mass M is dropped in a long vertical tube containing glycerine. The velocity of the ball becomes constant after some time. If the density of glycerine is half of the density of the ball, then the viscous force acting on the ball will be

(consider g as acceleration due to gravity)

  1. A

    Mg\mathrm{Mg}

  2. B

    32 Mg\frac{3}{2}\,\mathrm{Mg}

  3. C

    2 Mg2\,\mathrm{Mg}

  4. D

    Mg2\frac{\mathrm{Mg}}{2}

Show answer

Correct option: D

Q34JEE Main 2025 Jan 22 Shift 2Kinetic Theory of GasesMedium

For a diatomic gas, if γ1=(CpCv)\gamma_1 = \left(\frac{C_p}{C_v}\right) for rigid molecules and γ2=(CpCv)\gamma_2 = \left(\frac{C_p}{C_v}\right) for another diatomic molecules, but also having vibrational modes. Then, which one of the following options is correct ?

(CpC_p and CvC_v are specific heats of the gas at constant pressure and volume)

  1. A

    γ2>γ1\gamma_2 > \gamma_1

  2. B

    γ2<γ1\gamma_2 < \gamma_1

  3. C

    γ2=γ1\gamma_2 = \gamma_1

  4. D

    2γ2=γ12\gamma_2 = \gamma_1

Show answer

Correct option: B

Q35JEE Main 2025 Jan 22 Shift 2ThermodynamicsEasy

Given are statements for certain thermodynamic variables,

(A) Internal energy, volume (V) and mass (M) are extensive variables.

(B) Pressure (P), temperature (T) and density (ρ\rho) are intensive variables.

(C) Volume (V), temperature (T) and density (ρ\rho) are intensive variables.

(D) Mass (M), temperature (T) and internal energy are extensive variables.

Choose the correct answer from the options given below :

  1. A

    (A) and (B) Only

  2. B

    (B) and (C) Only

  3. C

    (C) and (D) Only

  4. D

    (D) and (A) Only

Show answer

Correct option: A

Q36JEE Main 2025 Jan 22 Shift 2OscillationsMedium

Given below are two statements. One is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A) : A simple pendulum is taken to a planet of mass and radius, 4 times and 2 times, respectively, than the Earth. The time period of the pendulum remains same on earth and the planet.

Reason (R) : The mass of the pendulum remains unchanged at Earth and the other planet.

In the light of the above statements, choose the correct answer from the options given below :

  1. A

    Both (A) and (R) are true and (R) is the correct explanation of (A)

  2. B

    Both (A) and (R) are true but (R) is NOT the correct explanation of (A)

  3. C

    (A) is true but (R) is false

  4. D

    (A) is false but (R) is true

Show answer

Correct option: B

Q37JEE Main 2025 Jan 22 Shift 2ElectrostaticsMedium

For a short dipole placed at origin O, the dipole moment P is along xx-axis, as shown in the figure. If the electric potential and electric field at A are V0V_0 and E0E_0, respectively, then the correct combination of the electric potential and electric field, respectively, at point B on the yy-axis is given by

Figure — described from the original paper

dipole P at origin O pointing along the positive xx-axis; point A on the xx-axis at distance r from O; point B on the yy-axis at distance 2r from O

  1. A

    zero and E08\frac{E_0}{8}

  2. B

    V0V_0 and E04\frac{E_0}{4}

  3. C

    V02\frac{V_0}{2} and E016\frac{E_0}{16}

  4. D

    zero and E016\frac{E_0}{16}

Show answer

Correct option: D

Q38JEE Main 2025 Jan 22 Shift 2Electromagnetic Induction and Alternating CurrentsMedium

A rectangular metallic loop is moving out of a region of uniform magnetic field into a magnetic field-free region with a constant velocity. When the loop is partially inside the magnetic field, the plot of induced emf (ε\varepsilon) with time (t) is given by :

  1. A
    Figure — described from the original paper

    graph of ε\varepsilon vs t — ε\varepsilon is constant (horizontal line)

  2. B
    Figure — described from the original paper

    graph of ε\varepsilon vs t — ε\varepsilon increases linearly with t from the origin

  3. C
    Figure — described from the original paper

    graph of ε\varepsilon vs t — ε\varepsilon decays with t (exponential-like decreasing curve)

  4. D
    Figure — described from the original paper

    graph of ε\varepsilon vs t — ε\varepsilon grows with t (exponential-like increasing curve)

Show answer

Correct option: A

Q39JEE Main 2025 Jan 22 Shift 2Electromagnetic Induction and Alternating CurrentsEasy

A series LCR circuit is connected to an alternating source of emf E. The current amplitude at resonant frequency is I0I_0. If the value of resistance R becomes twice of its initial value then amplitude of current at resonance will be

  1. A

    I0I_0

  2. B

    I02\frac{I_0}{2}

  3. C

    2I02I_0

  4. D

    I02\frac{I_0}{\sqrt{2}}

Show answer

Correct option: B

Q40JEE Main 2025 Jan 22 Shift 2Wave OpticsEasy

Given below are two statements. One is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A) : In Young's double slit experiment, the fringes produced by red light are closer as compared to those produced by blue light.

Reason (R) : The fringe width is directly proportional to the wavelength of light.

In the light of the above statements, choose the correct answer from the options given below :

  1. A

    Both (A) and (R) are true and (R) is the correct explanation of (A)

  2. B

    Both (A) and (R) are true but (R) is NOT the correct explanation of (A)

  3. C

    (A) is true but (R) is false

  4. D

    (A) is false but (R) is true

Show answer

Correct option: D

Q45JEE Main 2025 Jan 22 Shift 2Electronic DevicesMedium
Figure — described from the original paper

logic circuit — inputs A and B are fed directly to one AND gate; A and B are also fed through NOT gates to a second AND gate; the outputs of both AND gates are fed to a gate G whose output is Y

A B Y
0 0 1
0 1 0
1 0 0
1 1 1

To obtain the given truth table, the following logic gate should be placed at G :

  1. A

    NOR Gate

  2. B

    NAND Gate

  3. C

    OR Gate

  4. D

    AND Gate

Q46JEE Main 2025 Jan 22 Shift 2Rotational MotionMediumNumerical

A tube of length 1m is filled completely with an ideal liquid of mass 2M, and closed at both ends. The tube is rotated uniformly in horizontal plane about one of its ends. If the force exerted by the liquid at the other end is F then angular velocity of the tube is FαM\sqrt{\dfrac{F}{\alpha M}} in SI unit. The value of α\alpha is __________.

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Answer: 1

Q49JEE Main 2025 Jan 22 Shift 2Magnetic Effects of Current and MagnetismMediumNumerical

A proton is moving undeflected in a region of crossed electric and magnetic fields at a constant speed of 2Ɨ105Ā msāˆ’12 \times 10^5\ \mathrm{ms^{-1}}. When the electric field is switched off, the proton moves along a circular path of radius 2 cm. The magnitude of electric field is xƗ104Ā N/Cx \times 10^4\ \mathrm{N/C}. The value of xx is __________. Take the mass of the proton =1.6Ɨ10āˆ’27Ā kg= 1.6 \times 10^{-27}\ \mathrm{kg}.

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Answer: 2