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JEE Main 2026 Apr 5 Shift 2 β€” Mathematics

25 questions Β· 25 with the official NTA answer

Q1JEE Main 2026 Apr 5 Shift 2Quadratic EquationsMedium

Let Ξ±,Ξ²\alpha, \beta be the roots of the equation x2βˆ’x+p=0x^2 - x + p = 0 and Ξ³,Ξ΄\gamma, \delta be the roots of the equation x2βˆ’4x+q=0x^2 - 4x + q = 0; p,q∈Zp, q \in \mathbf{Z}. If Ξ±,Ξ²,Ξ³,Ξ΄\alpha, \beta, \gamma, \delta are in G.P., then ∣p+q∣|p + q| equals :

  1. A

    16

  2. B

    32

  3. C

    34

  4. D

    38

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Correct option: C

Q2JEE Main 2026 Apr 5 Shift 2Complex NumbersMedium

Let z1,z2∈Cz_1, z_2 \in \mathbf{C} be the distinct solutions of the equation z2+4zβˆ’(1+12i)=0z^2 + 4z - (1 + 12i) = 0. Then ∣z1∣2+∣z2∣2|z_1|^2 + |z_2|^2 is equal to :

  1. A

    18

  2. B

    22

  3. C

    29

  4. D

    34

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Correct option: D

Q3JEE Main 2026 Apr 5 Shift 2Matrices and DeterminantsHard

If f:N→Zf : \mathbf{N} \to \mathbf{Z} is defined by

f(n)=∣nβˆ’1βˆ’5βˆ’2n23(2k+1)2k+1βˆ’3n33k(2k+1)3k(k+2)+1∣,β€…β€Šk∈N,f(n) = \begin{vmatrix} n & -1 & -5 \\ -2n^2 & 3(2k+1) & 2k+1 \\ -3n^3 & 3k(2k+1) & 3k(k+2)+1 \end{vmatrix}, \; k \in \mathbf{N},

and βˆ‘n=1kf(n)=98\displaystyle\sum_{n=1}^{k} f(n) = 98, then kk is equal to :

  1. A

    3

  2. B

    4

  3. C

    5

  4. D

    6

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Correct option: A

Q4JEE Main 2026 Apr 5 Shift 2Matrices and DeterminantsMedium

Let MM be a 3Γ—33 \times 3 matrix such that

M[100]=[123],β€…β€ŠM[010]=[012]Β andΒ M[001]=[βˆ’111].Β IfΒ M[xyz]=[1711],M\begin{bmatrix} 1 \\ 0 \\ 0 \end{bmatrix} = \begin{bmatrix} 1 \\ 2 \\ 3 \end{bmatrix}, \; M\begin{bmatrix} 0 \\ 1 \\ 0 \end{bmatrix} = \begin{bmatrix} 0 \\ 1 \\ 2 \end{bmatrix} \text{ and } M\begin{bmatrix} 0 \\ 0 \\ 1 \end{bmatrix} = \begin{bmatrix} -1 \\ 1 \\ 1 \end{bmatrix}. \text{ If } M\begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} 1 \\ 7 \\ 11 \end{bmatrix},

then x+y+zx + y + z equals :

  1. A

    4

  2. B

    5

  3. C

    7

  4. D

    11

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Correct option: B

Q5JEE Main 2026 Apr 5 Shift 2Sequences and SeriesMedium

If the sum of the first 10 terms of the series 11+14Γ—4+21+24Γ—4+31+34Γ—4+41+44Γ—4+…\dfrac{1}{1 + 1^4 \times 4} + \dfrac{2}{1 + 2^4 \times 4} + \dfrac{3}{1 + 3^4 \times 4} + \dfrac{4}{1 + 4^4 \times 4} + \ldots is mn\dfrac{m}{n}, gcd⁑(m,n)=1\gcd(m, n) = 1, then m+nm + n is equal to :

  1. A

    256

  2. B

    264

  3. C

    276

  4. D

    284

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Correct option: C

Q6JEE Main 2026 Apr 5 Shift 2Sequences and SeriesEasy

Let A1,A2,A3,…,A39A_1, A_2, A_3, \ldots, A_{39} be 39 arithmetic means between the numbers 59 and 159. Then the mean of A25,A28,A31A_{25}, A_{28}, A_{31} and A36A_{36} is equal to :

  1. A

    129

  2. B

    136

  3. C

    131.50

  4. D

    134

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Correct option: D

Q7JEE Main 2026 Apr 5 Shift 2Binomial TheoremEasy

The coefficient of x2x^2 in the expansion of (2x2+1x)10\left(2x^2 + \dfrac{1}{x}\right)^{10}, x≠0x \neq 0, is :

  1. A

    3240

  2. B

    3360

  3. C

    3480

  4. D

    3600

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Correct option: B

Q8JEE Main 2026 Apr 5 Shift 2ProbabilityEasy

The probabilities that players A and B of a team are selected for the captaincy for a tournament are 0.6 and 0.4, respectively. If A is selected the captain, the probability that the team wins the tournament is 0.8 and if B is selected the captain, the probability that the team wins the tournament is 0.7. Then the probability, that the team wins the tournament, is :

  1. A

    0.74

  2. B

    0.76

  3. C

    0.72

  4. D

    0.78

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Correct option: B

Q9JEE Main 2026 Apr 5 Shift 2Permutations and CombinationsMedium

A box contains 5 blue, 6 yellow and 4 red balls. The number of ways, of drawing 8 balls containing at least two balls of each colour, is :

  1. A

    4100

  2. B

    4140

  3. C

    4230

  4. D

    4290

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Correct option: A

Q10JEE Main 2026 Apr 5 Shift 2StatisticsHard

A variable XX takes values 0,0,2,6,12,20,…,n(nβˆ’1)0, 0, 2, 6, 12, 20, \ldots, n(n-1) with frequencies nC0,nC1,nC2,nC3,nC4,nC5,…,nCn^{n}C_0, {}^{n}C_1, {}^{n}C_2, {}^{n}C_3, {}^{n}C_4, {}^{n}C_5, \ldots, {}^{n}C_n, respectively. If the mean of this data is 60, then its median is :

  1. A

    56

  2. B

    42

  3. C

    72

  4. D

    90

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Correct option: A

Q11JEE Main 2026 Apr 5 Shift 2CirclesMedium

Let the point PP be the vertex of the parabola y=x2βˆ’6x+12y = x^2 - 6x + 12. If a line passing through the point PP intersects the circle x2+y2βˆ’2xβˆ’4y+3=0x^2 + y^2 - 2x - 4y + 3 = 0 at the points RR and SS, then the maximum value of (PR+PS)2(PR + PS)^2 is :

  1. A

    10

  2. B

    20

  3. C

    25

  4. D

    5

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Correct option: B

Q12JEE Main 2026 Apr 5 Shift 2Conic SectionsHard

Let the directrix of the parabola P:y2=8xP : y^2 = 8x, cut xx-axis at the point AA. Let B(Ξ±,Ξ²)B(\alpha, \beta), Ξ±>1\alpha > 1, be a point on PP such that the slope of ABAB is 3/53/5. If BCBC is a focal chord of PP, then six times the area of Ξ”ABC\Delta ABC is :

  1. A

    80

  2. B

    160

  3. C

    174

  4. D

    192

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Correct option: B

Q13JEE Main 2026 Apr 5 Shift 2Conic SectionsMedium

Let the eccentricity ee of a hyperbola satisfy the equation 6e2βˆ’11e+3=06e^2 - 11e + 3 = 0. If the foci of the hyperbola are (3,5)(3, 5) and (3,βˆ’4)(3, -4), then the length of its latus rectum is :

  1. A

    113\dfrac{11}{3}

  2. B

    173\dfrac{17}{3}

  3. C

    152\dfrac{15}{2}

  4. D

    172\dfrac{17}{2}

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Correct option: C

Q14JEE Main 2026 Apr 5 Shift 2Three Dimensional GeometryMedium

Let a triangle PQRPQR be such that PP and QQ lie on the line x+38=yβˆ’42=z+12\dfrac{x+3}{8} = \dfrac{y-4}{2} = \dfrac{z+1}{2} and are at a distance of 6 units from R (1,2,3)R\,(1, 2, 3). If (Ξ±,Ξ²,Ξ³)(\alpha, \beta, \gamma) is the centroid of Ξ”PQR\Delta PQR, then Ξ±+Ξ²+Ξ³\alpha + \beta + \gamma is equal to :

  1. A

    4

  2. B

    5

  3. C

    6

  4. D

    8

Show answer

Correct option: C

Q15JEE Main 2026 Apr 5 Shift 2Three Dimensional GeometryMedium

If the distance of the point (a,2,5)(a, 2, 5) from the image of the point (1,2,7)(1, 2, 7) in the line x1=yβˆ’11=zβˆ’22\dfrac{x}{1} = \dfrac{y-1}{1} = \dfrac{z-2}{2} is 4, then the sum of all possible values of aa is equal to :

  1. A

    11

  2. B

    9

  3. C

    6

  4. D

    4

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Correct option: C

Q16JEE Main 2026 Apr 5 Shift 2Vector AlgebraMedium

Let OO be the origin, OPβ†’=aβƒ—\overrightarrow{OP} = \vec{a} and OQβ†’=bβƒ—\overrightarrow{OQ} = \vec{b}. If RR is the point on OPβ†’\overrightarrow{OP} such that OPβ†’=5 ORβ†’\overrightarrow{OP} = 5\,\overrightarrow{OR}, and MM is the point such that OQβ†’=5 RMβ†’\overrightarrow{OQ} = 5\,\overrightarrow{RM}, then PMβ†’\overrightarrow{PM} is equal to :

  1. A

    15(aβƒ—βˆ’4bβƒ—)\dfrac{1}{5}\left(\vec{a} - 4\vec{b}\right)

  2. B

    15(bβƒ—βˆ’4aβƒ—)\dfrac{1}{5}\left(\vec{b} - 4\vec{a}\right)

  3. C

    15(βˆ’aβƒ—+4bβƒ—)\dfrac{1}{5}\left(-\vec{a} + 4\vec{b}\right)

  4. D

    15(βˆ’bβƒ—+4aβƒ—)\dfrac{1}{5}\left(-\vec{b} + 4\vec{a}\right)

Show answer

Correct option: B

Q17JEE Main 2026 Apr 5 Shift 2Limits, Continuity and DifferentiabilityMedium

Let f(x)=lim⁑yβ†’0(1βˆ’cos⁑(xy))tan⁑(xy)y3f(x) = \displaystyle\lim_{y \to 0} \frac{(1 - \cos(xy))\tan(xy)}{y^3}. Then the number of solutions of the equation f(x)=sin⁑xf(x) = \sin x, x∈Rx \in \mathbf{R} is :

  1. A

    0

  2. B

    2

  3. C

    3

  4. D

    1

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Correct option: C

Q18JEE Main 2026 Apr 5 Shift 2Integral CalculusHard

Let (21βˆ’a+21+a)(2^{1-a} + 2^{1+a}), f(a)f(a), (3a+3βˆ’a)(3^a + 3^{-a}) be in A.P. and Ξ±\alpha be the minimum value of f(a)f(a). Then the value of the integral ∫log⁑e(Ξ±βˆ’1)log⁑e(Ξ±)dx(e2xβˆ’eβˆ’2x)\displaystyle\int_{\log_e(\alpha - 1)}^{\log_e(\alpha)} \frac{dx}{(e^{2x} - e^{-2x})} is :

  1. A

    12log⁑e(43)\dfrac{1}{2}\log_e\left(\dfrac{4}{3}\right)

  2. B

    14log⁑e(43)\dfrac{1}{4}\log_e\left(\dfrac{4}{3}\right)

  3. C

    12log⁑e(85)\dfrac{1}{2}\log_e\left(\dfrac{8}{5}\right)

  4. D

    14log⁑e(85)\dfrac{1}{4}\log_e\left(\dfrac{8}{5}\right)

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Correct option: B

Q19JEE Main 2026 Apr 5 Shift 2Differential EquationsHard

Let f:[1,∞)β†’Rf : [1, \infty) \to \mathbf{R} be a differentiable function defined as f(x)=∫1xf(t) dt+(1βˆ’x)(log⁑exβˆ’1)+ef(x) = \displaystyle\int_1^x f(t)\,dt + (1 - x)(\log_e x - 1) + e. Then the value of f(f(1))f(f(1)) is :

  1. A

    (1+ee)(1 + e^e)

  2. B

    (1+e)(1 + e)

  3. C

    (1+e+ee)(1 + e + e^e)

  4. D

    1+2e1 + 2e

Show answer

Correct option: A

Q20JEE Main 2026 Apr 5 Shift 2Differentiation and Applications of DerivativesMedium

Let f(x)f(x) and g(x)g(x) be twice differentiable functions satisfying fβ€²β€²(x)=gβ€²β€²(x)f''(x) = g''(x) for all x∈Rx \in \mathbf{R}, fβ€²(1)=2gβ€²(1)=4f'(1) = 2g'(1) = 4 and g(2)=3f(2)=9g(2) = 3f(2) = 9. Then f(25)βˆ’g(25)f(25) - g(25) is equal to :

  1. A

    20

  2. B

    40

  3. C

    βˆ’20-20

  4. D

    βˆ’40-40

Show answer

Correct option: B

Q21JEE Main 2026 Apr 5 Shift 2Sets, Relations and FunctionsMediumNumerical

Let A={1,4,7}A = \{1, 4, 7\} and B={2,3,8}B = \{2, 3, 8\}. Then the number of elements, in the relation R={((a1,b1),(a2,b2))∈((AΓ—B)Γ—(AΓ—B)):a1+b2Β dividesΒ a2+b1}R = \left\{\left((a_1, b_1), (a_2, b_2)\right) \in ((A \times B) \times (A \times B)) : a_1 + b_2 \text{ divides } a_2 + b_1\right\} is __________.

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Answer: 18

Q22JEE Main 2026 Apr 5 Shift 2Straight LinesHardNumerical

From the point (βˆ’1,βˆ’1)(-1, -1), two rays are sent making angles of 45Β°45Β° with the line x+y=0x + y = 0. These rays get reflected from the mirror x+2y=1x + 2y = 1. If the equations of the reflected rays are ax+by=9ax + by = 9 and cx+dy=7cx + dy = 7, a,b,c,d∈Za, b, c, d \in \mathbf{Z}, then the value of ad+bcad + bc is __________.

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Answer: 7

Q23JEE Main 2026 Apr 5 Shift 2Trigonometric Ratios and EquationsHardNumerical

If S={θ∈[βˆ’Ο€,Ο€]:cos⁑θcos⁑5ΞΈ2=cos⁑7ΞΈcos⁑7ΞΈ2}S = \left\{\theta \in [-\pi, \pi] : \cos\theta \cos\dfrac{5\theta}{2} = \cos 7\theta \cos\dfrac{7\theta}{2}\right\}, then n(S)n(S) is equal to __________.

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Answer: 19

Q24JEE Main 2026 Apr 5 Shift 2Integral CalculusHardNumerical

Let f:Rβ†’Rf : \mathbf{R} \to \mathbf{R} be a function such that f(x)+3f(Ο€2βˆ’x)=sin⁑xf(x) + 3f\left(\dfrac{\pi}{2} - x\right) = \sin x, x∈Rx \in \mathbf{R}. Let the maximum value of ff on R\mathbf{R} be Ξ±\alpha. If the area of the region bounded by the curves g(x)=x2g(x) = x^2 and h(x)=Ξ²x3h(x) = \beta x^3, Ξ²>0\beta > 0, is Ξ±2\alpha^2, then 30Ξ²330\beta^3 is equal to __________.

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Answer: 16

Q25JEE Main 2026 Apr 5 Shift 2Differential EquationsHardNumerical

Let y=y(x)y = y(x) be the solution of the differential equation

(tan⁑x)1/2 dy=(sec⁑3xβˆ’(tan⁑x)3/2 y)dx,β€…β€Š0<x<Ο€2,β€…β€Šy(Ο€4)=625.(\tan x)^{1/2}\,dy = \left(\sec^3 x - (\tan x)^{3/2}\,y\right)dx, \; 0 < x < \frac{\pi}{2}, \; y\left(\frac{\pi}{4}\right) = \frac{6\sqrt{2}}{5}.

If y(Ο€3)=45 αy\left(\dfrac{\pi}{3}\right) = \dfrac{4}{5}\,\alpha, then Ξ±4\alpha^4 equals __________.

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Answer: 48