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JEE Main 2025 Jan 28 Shift 2 — Question Paper

75 questions

Mathematics

Q1JEE Main 2025 Jan 28 Shift 2Sets, Relations and FunctionsMedium

[Stem missing: page 1 of the source PDF is corrupted — the stem and first three options of Question 1 could not be recovered in either English or Hindi. Only the fourth option survives.]

  1. A

    [option corrupted in source PDF]

  2. B

    [option corrupted in source PDF]

  3. C

    [option corrupted in source PDF]

  4. D

    (, 1][1, )(-\infty,\ -1] \cup [1,\ \infty)

Show answer

Correct option: A

Q2JEE Main 2025 Jan 28 Shift 2Sets, Relations and FunctionsMedium

Let f:[0, 3]Af : [0,\ 3] \to \mathrm{A} be defined by f(x)=2x315x2+36x+7f(x) = 2x^3 - 15x^2 + 36x + 7 and g:[0, )Bg : [0,\ \infty) \to \mathrm{B} be defined by g(x)=x2025x2025+1g(x) = \frac{x^{2025}}{x^{2025}+1}. If both the functions are onto and S={xZ:xA or xB}S = \{x \in \mathbf{Z} : x \in \mathrm{A} \text{ or } x \in \mathrm{B}\}, then n(S)n(S) is equal to :

  1. A

    36

  2. B

    31

  3. C

    30

  4. D

    29

Show answer

Correct option: C

Q3JEE Main 2025 Jan 28 Shift 2Quadratic EquationsMedium

Let f:R{0}(, 1)f : \mathbf{R} - \{0\} \to (-\infty,\ 1) be a polynomial of degree 2, satisfying f(x)f(1x)=f(x)+f(1x)f(x)\,f\left(\frac{1}{x}\right) = f(x) + f\left(\frac{1}{x}\right). If f(K)=2Kf(\mathrm{K}) = -2\mathrm{K}, then the sum of squares of all possible values of K\mathrm{K} is :

  1. A

    1

  2. B

    7

  3. C

    6

  4. D

    9

Show answer

Correct option: C

Q4JEE Main 2025 Jan 28 Shift 2Complex NumbersMedium

If α+iβ\alpha + i\beta and γ+iδ\gamma + i\delta are the roots of x2(32i)x(2i2)=0x^2 - (3-2i)x - (2i-2) = 0, i=1i = \sqrt{-1}, then αγ+βδ\alpha\gamma + \beta\delta is equal to :

  1. A

    2-2

  2. B

    22

  3. C

    66

  4. D

    6-6

Show answer

Correct option: B

Q5JEE Main 2025 Jan 28 Shift 2Matrices and DeterminantsHard

Let A=[12201]\mathrm{A} = \begin{bmatrix} \frac{1}{\sqrt{2}} & -2 \\ 0 & 1 \end{bmatrix} and P=[cosθsinθsinθcosθ]\mathrm{P} = \begin{bmatrix} \cos\theta & -\sin\theta \\ \sin\theta & \cos\theta \end{bmatrix}, θ>0\theta > 0. If B=PAPT\mathrm{B} = \mathrm{PAP^T}, C=PTB10P\mathrm{C} = \mathrm{P^T B^{10} P} and the sum of the diagonal elements of C\mathrm{C} is mn\frac{m}{n}, where gcd(m,n)=1\gcd(m, n) = 1, then m+nm + n is :

  1. A

    2049

  2. B

    258

  3. C

    127

  4. D

    65

Show answer

Correct option: D

Q6JEE Main 2025 Jan 28 Shift 2Sequences and SeriesMedium

For positive integers nn, if 4an=(n2+5n+6)4a_n = (n^2 + 5n + 6) and Sn=k=1n(1ak)S_n = \sum_{k=1}^{n} \left(\frac{1}{a_k}\right), then the value of 507S2025507\, S_{2025} is :

  1. A

    135

  2. B

    540

  3. C

    675

  4. D

    1350

Show answer

Correct option: C

Q7JEE Main 2025 Jan 28 Shift 2Binomial TheoremMedium

Let the coefficients of three consecutive terms Tr\mathrm{T}_r, Tr+1\mathrm{T}_{r+1} and Tr+2\mathrm{T}_{r+2} in the binomial expansion of (a+b)12(a+b)^{12} be in a G.P. and let pp be the number of all possible values of rr. Let qq be the sum of all rational terms in the binomial expansion of (34+43)12\left(\sqrt[4]{3} + \sqrt[3]{4}\right)^{12}. Then p+qp + q is equal to :

  1. A

    283

  2. B

    295

  3. C

    287

  4. D

    299

Show answer

Correct option: A

Q8JEE Main 2025 Jan 28 Shift 2ProbabilityMedium

Let S be the set of all the words that can be formed by arranging all the letters of the word GARDEN. From the set S, one word is selected at random. The probability that the select… [remainder of stem corrupted in the source PDF; the Hindi duplicate is also lost]

  1. A

    13\frac{1}{3}

  2. B

    12\frac{1}{2}

  3. C

    23\frac{2}{3}

  4. D

    14\frac{1}{4}

Show answer

Correct option: B

Q9JEE Main 2025 Jan 28 Shift 2ProbabilityEasy

Bag B1\mathrm{B}_1 contains 6 white and 4 blue balls, Bag B2\mathrm{B}_2 contains 4 white and 6 blue balls, and Bag B3\mathrm{B}_3 contains 5 white and 5 blue balls. One of the bags is selected at random and a ball is drawn from it. If the ball is white, then the probability, that the ball is drawn from Bag B2\mathrm{B}_2, is :

  1. A

    415\frac{4}{15}

  2. B

    25\frac{2}{5}

  3. C

    13\frac{1}{3}

  4. D

    23\frac{2}{3}

Show answer

Correct option: A

Q10JEE Main 2025 Jan 28 Shift 2Straight LinesMedium

Two equal sides of an isosceles triangle are along x+2y=4-x + 2y = 4 and x+y=4x + y = 4. If mm is the slope of its third side, then the sum, of all possible distinct values of mm, is :

  1. A

    12

  2. B

    6

  3. C

    6-6

  4. D

    210-2\sqrt{10}

Show answer

Correct option: B

Q11JEE Main 2025 Jan 28 Shift 2Conic SectionsMedium

If the midpoint of a chord of the ellipse x29+y24=1\frac{x^2}{9} + \frac{y^2}{4} = 1 is (2, 43)\left(\sqrt{2},\ \frac{4}{3}\right), and the length of the chord is 2α3\frac{2\sqrt{\alpha}}{3}, then α\alpha is :

  1. A

    18

  2. B

    20

  3. C

    22

  4. D

    26

Show answer

Correct option: C

Q12JEE Main 2025 Jan 28 Shift 2Conic SectionsMedium

If A and B are the points of intersection of the circle x2+y28x=0x^2 + y^2 - 8x = 0 and the hyperbola x29y24=1\frac{x^2}{9} - \frac{y^2}{4} = 1 and a point P moves on the line 2x3y+4=02x - 3y + 4 = 0, then the centroid of ΔPAB\Delta \mathrm{PAB} lies on the line :

  1. A

    4x9y=124x - 9y = 12

  2. B

    6x9y=206x - 9y = 20

  3. C

    9x9y=329x - 9y = 32

  4. D

    x+9y=36x + 9y = 36

Show answer

Correct option: B

Q13JEE Main 2025 Jan 28 Shift 2Trigonometric Ratios and EquationsMedium

If r=113{1sin(π4+(r1)π6)sin(π4+rπ6)}=a3+b\sum_{r=1}^{13} \left\{\frac{1}{\sin\left(\frac{\pi}{4} + (r-1)\frac{\pi}{6}\right) \sin\left(\frac{\pi}{4} + \frac{r\pi}{6}\right)}\right\} = a\sqrt{3} + b, a, bZa,\ b \in \mathbf{Z}, then a2+b2a^2 + b^2 is equal to :

  1. A

    2

  2. B

    4

  3. C

    10

  4. D

    8

Show answer

Correct option: D

Q14JEE Main 2025 Jan 28 Shift 2Vector AlgebraMedium

Let A, B, C be three points in xyxy-plane, whose position vector are given by 3i^+j^\sqrt{3}\hat{i} + \hat{j}, i^+3j^\hat{i} + \sqrt{3}\hat{j} and ai^+(1a)j^a\hat{i} + (1-a)\hat{j} respectively with respect to the origin O. If the distance of the point C from the line bisecting the angle between the vectors OA\overrightarrow{\mathrm{OA}} and OB\overrightarrow{\mathrm{OB}} is 92\frac{9}{\sqrt{2}}, then the sum of all the possible values of aa is :

  1. A

    92\frac{9}{2}

  2. B

    2

  3. C

    1

  4. D

    0

Show answer

Correct option: C

Q15JEE Main 2025 Jan 28 Shift 2Vector AlgebraMedium

If the components of a=αi^+βj^+γk^\vec{a} = \alpha\hat{i} + \beta\hat{j} + \gamma\hat{k} along and perpendicular to b=3i^+j^k^\vec{b} = 3\hat{i} + \hat{j} - \hat{k} respectively, are 1611(3i^+j^k^)\frac{16}{11}\left(3\hat{i} + \hat{j} - \hat{k}\right) and 111(4i^5j^17k^)\frac{1}{11}\left(-4\hat{i} - 5\hat{j} - 17\hat{k}\right), then α2+β2+γ2\alpha^2 + \beta^2 + \gamma^2 is equal to :

  1. A

    16

  2. B

    18

  3. C

    23

  4. D

    26

Show answer

Correct option: D

Q16JEE Main 2025 Jan 28 Shift 2Three Dimensional GeometryMedium

The square of the distance of the point (157, 327, 7)\left(\frac{15}{7},\ \frac{32}{7},\ 7\right) from the line x+13=y+35=z+57\frac{x+1}{3} = \frac{y+3}{5} = \frac{z+5}{7} in the direction of the vector i^+4j^+7k^\hat{i} + 4\hat{j} + 7\hat{k} is :

  1. A

    41

  2. B

    44

  3. C

    54

  4. D

    66

Show answer

Correct option: D

Q17JEE Main 2025 Jan 28 Shift 2Integral CalculusMedium

Let f:RRf : \mathbf{R} \to \mathbf{R} be a twice differentiable function such that f(2)=1f(2) = 1. If F(x)=xf(x)\mathrm{F}(x) = x f(x) for all xRx \in \mathbf{R}, 02xF(x)dx=6\int_0^2 x\, \mathrm{F}'(x)\, \mathrm{d}x = 6 and 02x2F(x)dx=40\int_0^2 x^2\, \mathrm{F}''(x)\, \mathrm{d}x = 40, then F(2)+02F(x)dx\mathrm{F}'(2) + \int_0^2 \mathrm{F}(x)\, \mathrm{d}x is equal to :

  1. A

    9

  2. B

    11

  3. C

    13

  4. D

    15

Show answer

Correct option: B

Q18JEE Main 2025 Jan 28 Shift 2Integral CalculusMedium

Let ff be a real valued continuous function defined on the positive real axis such that g(x)=0xtf(t)dtg(x) = \int_0^x \mathrm{t}\, f(\mathrm{t})\, \mathrm{dt}. If g(x3)=x6+x7g(x^3) = x^6 + x^7, then value of r=115f(r3)\sum_{r=1}^{15} f(\mathrm{r}^3) is :

  1. A

    340

  2. B

    310

  3. C

    270

  4. D

    320

Show answer

Correct option: B

Q19JEE Main 2025 Jan 28 Shift 2Integral CalculusMedium

If f(x)=1x1/4(1+x1/4)dxf(x) = \int \frac{1}{x^{1/4}\left(1 + x^{1/4}\right)} \mathrm{d}x, f(0)=6f(0) = -6, then f(1)f(1) is equal to :

  1. A

    4(loge2+2)4(\log_e 2 + 2)

  2. B

    2loge22 - \log_e 2

  3. C

    4(loge22)4(\log_e 2 - 2)

  4. D

    loge2+2\log_e 2 + 2

Show answer

Correct option: C

Q20JEE Main 2025 Jan 28 Shift 2Integral CalculusMedium

The area of the region bounded by the curves x(1+y2)=1x(1 + y^2) = 1 and y2=2xy^2 = 2x is:

  1. A

    2(π213)2\left(\frac{\pi}{2} - \frac{1}{3}\right)

  2. B

    π213\frac{\pi}{2} - \frac{1}{3}

  3. C

    12(π213)\frac{1}{2}\left(\frac{\pi}{2} - \frac{1}{3}\right)

  4. D

    π413\frac{\pi}{4} - \frac{1}{3}

Show answer

Correct option: B

Q21JEE Main 2025 Jan 28 Shift 2Sequences and SeriesEasyNumerical

The interior angles of a polygon with nn sides, are in an A.P. with common difference 6°. If the largest interior angle of the polygon is 219°219°, then nn is equal to __________.

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Answer: 20

Q22JEE Main 2025 Jan 28 Shift 2Permutations and CombinationsMediumNumerical

The number of n… [remainder of stem corrupted in the source PDF; the Hindi duplicate is also lost]

Show answer

Answer: 64

Q23JEE Main 2025 Jan 28 Shift 2Conic SectionsHardNumerical

Let A and B be the points of intersection of the mirror image of the parabola y2=4xy^2 = 4x in the line x+y+4=0x + y + 4 = 0, and the line y+5=0y + 5 = 0. If the distance between A and B is dd and the area of ΔSAB\Delta \mathrm{SAB} is aa, where S is the focus of the parabola y2=4xy^2 = 4x, then the value of (a+d)(a + d) is __________. [English block corrupted in the source PDF; transcribed from the Hindi duplicate of the same question]

Show answer

Answer: 14

Q24JEE Main 2025 Jan 28 Shift 2Limits, Continuity and DifferentiabilityHardNumerical

Let f(x)=limnr=0n(tan(x/2r+1)+tan3(x/2r+1)1tan2(x/2r+1))f(x) = \lim_{n \to \infty} \sum_{r=0}^{n} \left(\frac{\tan\left(x/2^{r+1}\right) + \tan^3\left(x/2^{r+1}\right)}{1 - \tan^2\left(x/2^{r+1}\right)}\right). Then limx0exef(x)(xf(x))\lim_{x \to 0} \frac{\mathrm{e}^x - \mathrm{e}^{f(x)}}{(x - f(x))} is equal to __________.

Show answer

Answer: 1

Q25JEE Main 2025 Jan 28 Shift 2Differential EquationsMediumNumerical

If y=y(x)y = y(x) is the solution of the differential equation, 4x2dydx=((sin1(x2))2y)sin1(x2)\sqrt{4 - x^2}\, \frac{\mathrm{d}y}{\mathrm{d}x} = \left(\left(\sin^{-1}\left(\frac{x}{2}\right)\right)^2 - y\right) \sin^{-1}\left(\frac{x}{2}\right), 2x2-2 \le x \le 2, y(2)=π284y(2) = \frac{\pi^2 - 8}{4}, then y2(0)y^2(0) is equal to __________.

Show answer

Answer: 4

Physics

Q26JEE Main 2025 Jan 28 Shift 2Units and MeasurementsHard

[Figure: a bar magnet with poles S and N, total length 2l2l, and a field point P located on the perpendicular bisector at distance dd from the centre of the magnet]

A bar magnet has total length 2l=202l = 20 units and the field point P is at a distance d=10d = 10 units from the centre of the magnet. If the relative uncertainty of length measurement is 1%, then uncertainty of the magnetic field at point P is :

  1. A

    10%

  2. B

    3%

  3. C

    5%

  4. D

    4%

Q27JEE Main 2025 Jan 28 Shift 2Units and MeasurementsMedium

Match List - I with List - II.

List - I List - II
(A) Angular Impulse (I) [M0L2T2][\mathrm{M^0 L^2 T^{-2}}]
(B) Latent Heat (II) [ML2T3A1][\mathrm{M L^2 T^{-3} A^{-1}}]
(C) Electrical resistivity (III) [ML2T1][\mathrm{M L^2 T^{-1}}]
(D) Electromotive force (IV) [ML3T3A2][\mathrm{M L^3 T^{-3} A^{-2}}]

Choose the correct answer from the options given below :

  1. A

    (A)-(III), (B)-(I), (C)-(II), (D)-(IV)

  2. B

    (A)-(II), (B)-(I), (C)-(IV), (D)-(III)

  3. C

    (A)-(III), (B)-(I), (C)-(IV), (D)-(II)

  4. D

    (A)-(I), (B)-(III), (C)-(IV), (D)-(II)

Show answer

Correct option: C

Q28JEE Main 2025 Jan 28 Shift 2KinematicsEasy

The velocity-time graph of an object moving along a straight line is shown in figure. What is the distance covered by the object from t=0t = 0 to t=4st = 4\,\mathrm{s}?

[Figure: velocity-time graph; vv (in ms1\mathrm{ms^{-1}}) rises linearly from O at t=0t=0 to 1010 at point A (t=2st=2\,\mathrm{s}), stays constant at 1010 from A to B (t=4st=4\,\mathrm{s}), then decreases linearly to zero at t=6st=6\,\mathrm{s}]

  1. A

    10m10\,\mathrm{m}

  2. B

    11m11\,\mathrm{m}

  3. C

    13m13\,\mathrm{m}

  4. D

    30m30\,\mathrm{m}

Show answer

Correct option: D

Q29JEE Main 2025 Jan 28 Shift 2GravitationMedium

Earth has mass 8 times and radius 2 times that of a planet. If the escape velocity from the earth is 11.2km/s11.2\,\mathrm{km/s}, the escape velocity in km/s\mathrm{km/s} from the planet will be :

  1. A

    2.8

  2. B

    5.6

  3. C

    11.2

  4. D

    8.4

Show answer

Correct option: B

Q30JEE Main 2025 Jan 28 Shift 2Rotational MotionMedium

A uniform rod of mass 250 g having length 100 cm is balanced on a sharp edge at 40 cm mark. A mass of 400 g is suspended at 10 cm mark. To maintain the balance of the rod, the mass to be suspended at 90 cm mark, is

  1. A

    290 g

  2. B

    300 g

  3. C

    200 g

  4. D

    190 g

Show answer

Correct option: D

Q31JEE Main 2025 Jan 28 Shift 2Work, Energy and PowerHard

A body of mass 4 kg is placed on a plane at a point P having coordinate (3,4)(3, 4) m. Under the action of force F=(2i^+3j^)N\vec{F} = \left(2\hat{i} + 3\hat{j}\right)\,\mathrm{N}, it moves to a new point Q having coordinates (6,10)(6, 10) m in 4 sec. The average power and instantaneous power at the end of 4 sec are in the ratio of :

  1. A

    13:613 : 6

  2. B

    1:21 : 2

  3. C

    4:34 : 3

  4. D

    6:136 : 13

Show answer

Correct option: D

Q32JEE Main 2025 Jan 28 Shift 2Laws of MotionHard

A balloon and its content having mass M is moving up with an acceleration 'a'. The mass that must be released from the content so that the balloon starts moving up with an acceleration '3a' will be

(Take 'g' as acceleration due to gravity)

  1. A

    3Ma2a+g\dfrac{3\,Ma}{2a + g}

  2. B

    2Ma3a+g\dfrac{2\,Ma}{3a + g}

  3. C

    3Ma2ag\dfrac{3\,Ma}{2a - g}

  4. D

    2Ma3ag\dfrac{2\,Ma}{3a - g}

Show answer

Correct option: B

Q33JEE Main 2025 Jan 28 Shift 2Properties of Solids and LiquidsEasy

A 400 g solid cube having an edge of length 10 cm floats in water. How much volume of the cube is outside the water?

(Given : density of water =1000kgm3= 1000\,\mathrm{kg\,m^{-3}})

  1. A

    400cm3400\,\mathrm{cm^3}

  2. B

    600cm3600\,\mathrm{cm^3}

  3. C

    1400cm31400\,\mathrm{cm^3}

  4. D

    4000cm34000\,\mathrm{cm^3}

Show answer

Correct option: B

Q34JEE Main 2025 Jan 28 Shift 2Kinetic Theory of GasesMedium

The kinetic energy of translation of the molecules in 50 g of CO2\mathrm{CO_2} gas at 17°C is

  1. A

    4102.8J4102.8\,\mathrm{J}

  2. B

    3986.3J3986.3\,\mathrm{J}

  3. C

    4205.5J4205.5\,\mathrm{J}

  4. D

    3582.7J3582.7\,\mathrm{J}

Show answer

Correct option: A

Q35JEE Main 2025 Jan 28 Shift 2Kinetic Theory of GasesMedium

The ratio of vapour densities of two gases at the same temperature is 425\dfrac{4}{25}, then the ratio of r.m.s. velocities will be :

  1. A

    52\dfrac{5}{2}

  2. B

    25\dfrac{2}{5}

  3. C

    254\dfrac{25}{4}

  4. D

    425\dfrac{4}{25}

Show answer

Correct option: A

Q36JEE Main 2025 Jan 28 Shift 2OscillationsMedium

Given below are two statements. One is labelled as Assertion (A) and the other is labelled as Reason (R).

Assertion (A) : Knowing initial position x0x_0 and initial momentum p0p_0 is enough to determine the position and momentum at any time t for a simple harmonic motion with a given angular frequency ω\omega.

Reason (R) : The amplitude and phase can be expressed in terms of x0x_0 and p0p_0.

In the light of the above statements, choose the correct answer from the options given below :

  1. A

    Both (A) and (R) are true and (R) is the correct explanation of (A)

  2. B

    Both (A) and (R) are true but (R) is NOT the correct explanation of (A)

  3. C

    (A) is true but (R) is false

  4. D

    (A) is false but (R) is true

Show answer

Correct option: A

Q37JEE Main 2025 Jan 28 Shift 2ElectrostaticsMedium

A parallel plate capacitor of capacitance 1μF1\,\mu\mathrm{F} is charged to a potential difference of 20 V. The distance between plates is 1μm1\,\mu\mathrm{m}. The energy density between plates of capacitor is.

  1. A

    2×104J/m32 \times 10^{-4}\,\mathrm{J/m^3}

  2. B

    1.8×103J/m31.8 \times 10^{3}\,\mathrm{J/m^3}

  3. C

    1.8×105J/m31.8 \times 10^{5}\,\mathrm{J/m^3}

  4. D

    2×102J/m32 \times 10^{2}\,\mathrm{J/m^3}

Show answer

Correct option: B

Q38JEE Main 2025 Jan 28 Shift 2Magnetic Effects of Current and MagnetismHard

[Figure: an infinite straight wire carrying current I along the horizontal, which forms a circular bend (loop) of radius aa around the origin O; the arc subtends the region above and to the left of O, and the two straight portions extend to infinity on the right]

An infinite wire has a circular bend of radius aa, and carrying a current I as shown in figure. The magnitude of magnetic field at the origin O of the arc is given by :

  1. A

    μ02πIa[π2+2]\dfrac{\mu_0}{2\pi}\dfrac{I}{a}\left[\dfrac{\pi}{2} + 2\right]

  2. B

    μ04πIa[π2+1]\dfrac{\mu_0}{4\pi}\dfrac{I}{a}\left[\dfrac{\pi}{2} + 1\right]

  3. C

    μ04πIa[3π2+1]\dfrac{\mu_0}{4\pi}\dfrac{I}{a}\left[\dfrac{3\pi}{2} + 1\right]

  4. D

    μ04πIa[3π2+2]\dfrac{\mu_0}{4\pi}\dfrac{I}{a}\left[\dfrac{3\pi}{2} + 2\right]

Show answer

Correct option: C

Q39JEE Main 2025 Jan 28 Shift 2Electromagnetic Induction and Alternating CurrentsHard

A uniform magnetic field of 0.4 T acts perpendicular to a circular copper disc 20 cm in radius. The disc is having a uniform angular velocity of 10πrads110\pi\,\mathrm{rad\,s^{-1}} about an axis through its centre and perpendicular to the disc. What is the potential difference developed between the axis of the disc and the rim? (π=3.14\pi = 3.14)

  1. A

    0.2512 V

  2. B

    0.1256 V

  3. C

    0.0628 V

  4. D

    0.5024 V

Show answer

Correct option: A

Q40JEE Main 2025 Jan 28 Shift 2Electromagnetic WavesHard

The magnetic field of an E.M. wave is given by B=(32i^+12j^)30sin[ω(tzc)]\vec{B} = \left(\dfrac{\sqrt{3}}{2}\hat{i} + \dfrac{1}{2}\hat{j}\right)30\sin\left[\omega\left(t - \dfrac{z}{c}\right)\right] (S.I. Units).

The corresponding electric field in S.I. units is :

  1. A

    E=(32i^12j^)30csin[ω(t+zc)]\vec{E} = \left(\dfrac{\sqrt{3}}{2}\hat{i} - \dfrac{1}{2}\hat{j}\right)30\,c\sin\left[\omega\left(t + \dfrac{z}{c}\right)\right]

  2. B

    E=(34i^+14j^)30ccos[ω(tzc)]\vec{E} = \left(\dfrac{3}{4}\hat{i} + \dfrac{1}{4}\hat{j}\right)30\,c\cos\left[\omega\left(t - \dfrac{z}{c}\right)\right]

  3. C

    E=(12i^32j^)30csin[ω(tzc)]\vec{E} = \left(\dfrac{1}{2}\hat{i} - \dfrac{\sqrt{3}}{2}\hat{j}\right)30\,c\sin\left[\omega\left(t - \dfrac{z}{c}\right)\right]

  4. D

    E=(12i^+32j^)30csin[ω(t+zc)]\vec{E} = \left(\dfrac{1}{2}\hat{i} + \dfrac{\sqrt{3}}{2}\hat{j}\right)30\,c\sin\left[\omega\left(t + \dfrac{z}{c}\right)\right]

Show answer

Correct option: C

Q41JEE Main 2025 Jan 28 Shift 2Ray OpticsHard

In a long glass tube, mixture of two liquids A and B with refractive indices 1.3 and 1.4 respectively, forms a convex refractive meniscus towards A. If an object placed at 13 cm from the vertex of the meniscus in A forms an image with a magnification of '2-2' then the radius of curvature of meniscus is :

  1. A

    13cm\dfrac{1}{3}\,\mathrm{cm}

  2. B

    23cm\dfrac{2}{3}\,\mathrm{cm}

  3. C

    1cm1\,\mathrm{cm}

  4. D

    43cm\dfrac{4}{3}\,\mathrm{cm}

Show answer

Correct option: B

Q42JEE Main 2025 Jan 28 Shift 2Ray OpticsMedium

A concave mirror produces an image of an object such that the distance between the object and image is 20 cm. If the magnification of the image is '3-3', then the magnitude of the radius of curvature of the mirror is :

  1. A

    3.75 cm

  2. B

    7.5 cm

  3. C

    15 cm

  4. D

    30 cm

Show answer

Correct option: C

Q43JEE Main 2025 Jan 28 Shift 2Atoms and NucleiMedium

The frequency of revolution of the electron in Bohr's orbit varies with n, where n is the principal quantum number, as :

  1. A

    1n3\dfrac{1}{n^3}

  2. B

    1n2\dfrac{1}{n^2}

  3. C

    1n\dfrac{1}{n}

  4. D

    1n4\dfrac{1}{n^4}

Show answer

Correct option: A

Q44JEE Main 2025 Jan 28 Shift 2Dual Nature of Matter and RadiationEasy

Which of the following phenomena can not be explained by wave theory of light?

  1. A

    Reflection of light

  2. B

    Refraction of light

  3. C

    Diffraction of light

  4. D

    Compton effect

Show answer

Correct option: D

Q45JEE Main 2025 Jan 28 Shift 2Electronic DevicesMedium

[Figure: an AC source V=V0sinωtV = V_0\sin\omega t connected in a circuit; a resistor R is in parallel between terminals A (top) and B (bottom), and a diode is in the lower branch of the loop]

In the circuit shown here, assuming threshold voltage of diode is negligibly small, then voltage VABV_{AB} is correctly represented by :

  1. A

    [Figure: VABV_{AB} vs tt graph showing a full sinusoidal wave with both positive and negative half-cycles]

  2. B

    [Figure: VABV_{AB} vs tt graph showing only positive half-cycles (upper humps), zero in between]

  3. C

    [Figure: VABV_{AB} vs tt graph showing only negative half-cycles (lower humps), zero in between]

  4. D

    VABV_{AB} would be zero at all times

Show answer

Correct option: C

Q46JEE Main 2025 Jan 28 Shift 2Properties of Solids and LiquidsMediumNumerical

The volume contraction of a solid copper cube of edge length 10 cm, when subjected to a hydraulic pressure of 7×106Pa7 \times 10^6\,\mathrm{Pa}, would be __________ mm3\mathrm{mm^3}.

(Given bulk modulus of copper =1.4×1011Nm2= 1.4 \times 10^{11}\,\mathrm{N\,m^{-2}})

Show answer

Answer: 50

Q47JEE Main 2025 Jan 28 Shift 2ElectrostaticsMediumNumerical

An electric dipole of dipole moment 6×106Cm6 \times 10^{-6}\,\mathrm{Cm} is placed in uniform electric field of magnitude 106V/m10^6\,\mathrm{V/m}. Initially, the dipole moment is parallel to electric field. The work that needs to be done on the dipole to make its dipole moment opposite to the field, will be __________ J.

Show answer

Answer: 12

Q48JEE Main 2025 Jan 28 Shift 2Current ElectricityHardNumerical

The value of current I in the electrical circuit as given below, when potential at A is equal to the potential at B, will be __________ A.

[Figure: a Wheatstone-bridge-like network. Current I enters a node splitting into two branches: the top branch has 10Ω10\,\Omega then node A then 20Ω20\,\Omega; the bottom branch has R then node B then 40Ω40\,\Omega. A 30Ω30\,\Omega resistor connects A to B (bridge arm). The two branches recombine and current I exits. The network is driven by a 40 V battery with key K.]

Show answer

Answer: 2

Q49JEE Main 2025 Jan 28 Shift 2Electromagnetic Induction and Alternating CurrentsHardNumerical

[Figure: a conducting bar moving on two conducting rails that form a V-shape (vertex at bottom); a constant magnetic field B is directed into the page (shown by × symbols)]

A conducting bar moves on two conducting rails as shown in the figure. A constant magnetic field B exists into the page. The bar starts to move from the vertex at time t=0t = 0 with a constant velocity. If the induced EMF is EtnE \propto t^n, then value of n is __________.

Show answer

Answer: 1

Q50JEE Main 2025 Jan 28 Shift 2Wave OpticsHardNumerical

A thin transparent film with refractive index 1.4, is held on circular ring of radius 1.8 cm. The fluid in the film evaporates such that transmission through the film at wavelength 560 nm goes to a minimum every 12 seconds. Assuming that the film is flat on its two sides, the rate of evaporation is __________ π×1013m3/s\pi \times 10^{-13}\,\mathrm{m^3/s}.

Show answer

Answer: 54

Chemistry

Q51JEE Main 2025 Jan 28 Shift 2Atomic StructureMedium

Which of the following is/are not correct with respect to energy of atomic orbitals of hydrogen atom?

(A) 1s<2p<3d<4s1s < 2p < 3d < 4s (B) 1s<2s=2p<3s=3p1s < 2s = 2p < 3s = 3p (C) 1s<2s<2p<3s<3p1s < 2s < 2p < 3s < 3p (D) 1s<2s<4s<3d1s < 2s < 4s < 3d

Choose the correct answer from the options given below :

  1. A

    (A) and (B) only

  2. B

    (C) and (D) only

  3. C

    (A) and (C) only

  4. D

    (B) and (D) only

Show answer

Correct option: B

Q52JEE Main 2025 Jan 28 Shift 2Chemical ThermodynamicsEasy

An ideal gas undergoes a cyclic transformation starting from the point A and coming back to the same point by tracing the path ABCDAA \to B \to C \to D \to A as shown in the three cases above.

Choose the correct option regarding ΔU\Delta U :

[Figure: three VV (dm3^3) vs pp (kPa) plots — Case-I (curved loop A-B-C-D), Case-II (rectangular loop), Case-III (rhombus/diamond loop), each a closed cyclic path A→B→C→D→A]

  1. A

    ΔU(Case-I)>ΔU(Case-II)>ΔU(Case-III)\Delta U(\text{Case-I}) > \Delta U(\text{Case-II}) > \Delta U(\text{Case-III})

  2. B

    ΔU(Case-III)>ΔU(Case-II)>ΔU(Case-I)\Delta U(\text{Case-III}) > \Delta U(\text{Case-II}) > \Delta U(\text{Case-I})

  3. C

    ΔU(Case-I)>ΔU(Case-III)>ΔU(Case-II)\Delta U(\text{Case-I}) > \Delta U(\text{Case-III}) > \Delta U(\text{Case-II})

  4. D

    ΔU(Case-I)=ΔU(Case-II)=ΔU(Case-III)\Delta U(\text{Case-I}) = \Delta U(\text{Case-II}) = \Delta U(\text{Case-III})

Show answer

Correct option: D

Q53JEE Main 2025 Jan 28 Shift 2SolutionsHard

Assume a living cell with 0.9%(ω/ω)0.9\%\,(\omega/\omega) of glucose solution (aqueous). This cell is immersed in another solution having equal mole fraction of glucose and water.

(Consider the data upto first decimal place only)

The cell will :

  1. A

    shrink since solution is 0.5%(ω/ω)0.5\%\,(\omega/\omega)

  2. B

    swell up since solution is 1%(ω/ω)1\%\,(\omega/\omega)

  3. C

    show no change in volume since solution is 0.9%(ω/ω)0.9\%\,(\omega/\omega)

  4. D

    shrink since solution is 0.45%(ω/ω)0.45\%\,(\omega/\omega) as a result of association of glucose molecules (due to hydrogen bonding)

Q54JEE Main 2025 Jan 28 Shift 2Some Basic Concepts in ChemistryEasy

Concentrated nitric acid is labelled as 75% by mass. The volume in mL of the solution which contains 30 g of nitric acid is __________.

Given : Density of nitric acid solution is 1.25 g/mL1.25\ \mathrm{g/mL}.

  1. A

    40

  2. B

    45

  3. C

    32

  4. D

    55

Show answer

Correct option: C

Q55JEE Main 2025 Jan 28 Shift 2EquilibriumMedium

Arrange the following in increasing order of solubility product :

Ca(OH)2, AgBr, PbS, HgS\mathrm{Ca(OH)_2},\ \mathrm{AgBr},\ \mathrm{PbS},\ \mathrm{HgS}

  1. A

    HgS<AgBr<PbS<Ca(OH)2\mathrm{HgS} < \mathrm{AgBr} < \mathrm{PbS} < \mathrm{Ca(OH)_2}

  2. B

    HgS<PbS<AgBr<Ca(OH)2\mathrm{HgS} < \mathrm{PbS} < \mathrm{AgBr} < \mathrm{Ca(OH)_2}

  3. C

    PbS<HgS<Ca(OH)2<AgBr\mathrm{PbS} < \mathrm{HgS} < \mathrm{Ca(OH)_2} < \mathrm{AgBr}

  4. D

    Ca(OH)2<AgBr<HgS<PbS\mathrm{Ca(OH)_2} < \mathrm{AgBr} < \mathrm{HgS} < \mathrm{PbS}

Show answer

Correct option: B

Q56JEE Main 2025 Jan 28 Shift 2Chemical KineticsMedium

For bacterial growth in a cell culture, growth law is very similar to the law of radioactive decay. Which of the following graphs is most suitable to represent bacterial colony growth?

Where N - Number of Bacteria at any time, N0N_0 - Initial number of Bacteria.

  1. A

    [Figure: N/N0N/N_0 vs time — exponentially decreasing (decay) curve]

  2. B

    [Figure: N/N0N/N_0 vs time — exponentially increasing (rising) curve]

  3. C

    [Figure: N/N0N/N_0 vs time — straight line decreasing linearly]

  4. D

    [Figure: N/N0N/N_0 vs time — rising curve that levels off (saturating)]

Show answer

Correct option: B

Q57JEE Main 2025 Jan 28 Shift 2Chemical KineticsMedium

Consider an elementary reaction

A(g)+B(g)C(g)+D(g)A(g) + B(g) \to C(g) + D(g)

If the volume of reaction mixture is suddenly reduced to 13\dfrac{1}{3} of its initial volume, the reaction rate will become x'x' times of the original reaction rate. The value of xx is :

  1. A

    33

  2. B

    19\dfrac{1}{9}

  3. C

    13\dfrac{1}{3}

  4. D

    99

Show answer

Correct option: D

Q58JEE Main 2025 Jan 28 Shift 2Principles Related to Practical ChemistryMedium

Identify the inorganic sulphides that are yellow in colour :

(A) (NH4)2S\mathrm{(NH_4)_2S} (B) PbS\mathrm{PbS} (C) CuS\mathrm{CuS} (D) As2S3\mathrm{As_2S_3} (E) As2S5\mathrm{As_2S_5}

Choose the correct answer from the options given below :

  1. A

    (A), (D) and (E) only

  2. B

    (A) and (B) only

  3. C

    (A) and (C) only

  4. D

    (D) and (E) only

Show answer

Correct option: A

Q59JEE Main 2025 Jan 28 Shift 2Classification of Elements and PeriodicityMedium

Given below are two statements :

Statement (I) : According to the Law of Octaves, the elements were arranged in the increasing order of their atomic number.

Statement (II) : Meyer observed a periodically repeated pattern upon plotting physical properties of certain elements against their respective atomic numbers.

In the light of the above statements, choose the correct answer from the options given below :

  1. A

    Both Statement I and Statement II are true

  2. B

    Both Statement I and Statement II are false

  3. C

    Statement I is true but Statement II is false

  4. D

    Statement I is false but Statement II is true

Show answer

Correct option: B

Q60JEE Main 2025 Jan 28 Shift 2d- and f-Block ElementsMedium

The amphoteric oxide among V2O3\mathrm{V_2O_3}, V2O4\mathrm{V_2O_4} and V2O5\mathrm{V_2O_5}, upon reaction with alkali leads to formation of an oxide anion. The oxidation state of V in the oxide anion is :

  1. A

    +3+3

  2. B

    +4+4

  3. C

    +5+5

  4. D

    +7+7

Show answer

Correct option: C

Q61JEE Main 2025 Jan 28 Shift 2Coordination CompoundsMedium

Match List-I with List-II :

List-I (Complex) List-II (Hybridisation of central metal ion)
(A) [CoF6]3\mathrm{[CoF_6]^{3-}} (I) d2sp3d^2sp^3
(B) [NiCl4]2\mathrm{[NiCl_4]^{2-}} (II) sp3sp^3
(C) [Co(NH3)6]3+\mathrm{[Co(NH_3)_6]^{3+}} (III) sp3d2sp^3d^2
(D) [Ni(CN)4]2\mathrm{[Ni(CN)_4]^{2-}} (IV) dsp2dsp^2

Choose the correct answer from the options given below :

  1. A

    (A)-(III), (B)-(II), (C)-(I), (D)-(IV)

  2. B

    (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

  3. C

    (A)-(I), (B)-(IV), (C)-(III), (D)-(II)

  4. D

    (A)-(I), (B)-(II), (C)-(III), (D)-(IV)

Show answer

Correct option: A

Q62JEE Main 2025 Jan 28 Shift 2Purification and Characterisation of Organic CompoundsEasy

The purification method based on the following physical transformation is :

Solid(X)HeatVapour(X)CoolSolid(X)\underset{(X)}{\text{Solid}} \xrightarrow{\text{Heat}} \underset{(X)}{\text{Vapour}} \xrightarrow{\text{Cool}} \underset{(X)}{\text{Solid}}

  1. A

    Distillation

  2. B

    Sublimation

  3. C

    Crystallization

  4. D

    Extraction

Show answer

Correct option: B

Q63JEE Main 2025 Jan 28 Shift 2Some Basic Principles of Organic ChemistryMedium

Given below are two statements :

Statement (I) : [Figure: a cyclopentane ring] and [Figure: an open-chain alkene, CH3_3CH2_2CH=CHCH2_2CH3_3] are isomeric compounds.

Statement (II) : [Figure: a primary amine, CH3_3(CH2_2)4_4CH2_2NH2_2] and [Figure: a secondary amine, CH3_3CH2_2CH2_2–NH–CH2_2CH2_2CH3_3] are functional group isomers.

In the light of the above statements, choose the correct answer from the options given below :

  1. A

    Both Statement I and Statement II are true

  2. B

    Both Statement I and Statement II are false

  3. C

    Statement I is true but Statement II is false

  4. D

    Statement I is false but Statement II is true

Show answer

Correct option: A

Q64JEE Main 2025 Jan 28 Shift 2HydrocarbonsMedium

Identify product [A], [B] and [C] in the following reaction sequence.

\mathrm{CH_3 - C \equiv CH} \xrightarrow[\mathrm{H_2}]{\mathrm{Pd/C}} [A] \xrightarrow[\text{(ii) Zn, H_2O}]{\text{(i) O_3}} [B] + [C]

  1. A

    [A]:CH3CH=CH2[A]: \mathrm{CH_3-CH=CH_2}, [B]:CH3CHO[B]: \mathrm{CH_3CHO}, [C]:HCHO[C]: \mathrm{HCHO}

  2. B

    [A]:CH2=CH2[A]: \mathrm{CH_2=CH_2}, [B]:H3CCOCH3[B]: \mathrm{H_3C-CO-CH_3}, [C]:HCHO[C]: \mathrm{HCHO}

  3. C

    [A]:CH3CH=CH2[A]: \mathrm{CH_3-CH=CH_2}, [B]:CH3CHO[B]: \mathrm{CH_3CHO}, [C]:CH3CH2OH[C]: \mathrm{CH_3CH_2OH}

  4. D

    [A]:CH3CH2CH3[A]: \mathrm{CH_3CH_2CH_3}, [B]:CH3CHO[B]: \mathrm{CH_3CHO}, [C]:HCHO[C]: \mathrm{HCHO}

Show answer

Correct option: A

Q65JEE Main 2025 Jan 28 Shift 2Organic Compounds Containing HalogensHard

The major product of the following reaction is :

[Figure: a dibromide bearing a phenyl group — 4-phenyl chain with two bromine atoms on adjacent-region carbons — treated with excess KOH/EtOH, Δ\Delta (double dehydrohalogenation)]

  1. A

    6-phenylhepta-2,4-diene

  2. B

    2-phenylhepta-2,5-diene

  3. C

    6-phenylhepta-3,5-diene

  4. D

    2-phenylhepta-2,4-diene

Show answer

Correct option: D

Q66JEE Main 2025 Jan 28 Shift 2Organic Compounds Containing NitrogenHard

The product B formed in the following reaction sequence is :

4-methyl-(prop-1-en-1-yl)benzene(Major)HCl(A)(Major)AgCN(B)\text{4-methyl-(prop-1-en-1-yl)benzene} \xrightarrow[\text{(Major)}]{\mathrm{HCl}} (A) \xrightarrow[\text{(Major)}]{\mathrm{AgCN}} (B)

[Figure: reactant is 1-(prop-1-en-1-yl)-4-methylbenzene, i.e. p-tolyl–CH=CH–CH3_3]

  1. A

    [Figure: p-tolyl–CH(NC)–CH2_2CH3_3; isocyanide (–NC) on the benzylic carbon]

  2. B

    [Figure: p-tolyl–CH2_2–CH(NC)–CH3_3; isocyanide (–NC) on the secondary non-benzylic carbon]

  3. C

    [Figure: p-tolyl–CH(CN)–CH3_3; nitrile (–CN) on the benzylic carbon]

  4. D

    [Figure: p-tolyl–CH2_2–CH(NC)–CH3_3; isocyanide (–NC) on the secondary carbon]

Show answer

Correct option: A

Q67JEE Main 2025 Jan 28 Shift 2HydrocarbonsHard

The total number of compounds from below when treated with hot KMnO4\mathrm{KMnO_4} giving benzoic acid is :

[Figure: eight compounds — toluene, ethylbenzene, isopropylbenzene (cumene), tert-butylbenzene, isobutylbenzene, 2-phenylpropan-2-ol, n-propylbenzene, 4,4'-dimethylbiphenyl]

  1. A

    3

  2. B

    4

  3. C

    5

  4. D

    6

Show answer

Correct option: C

Q68JEE Main 2025 Jan 28 Shift 2Organic Compounds Containing NitrogenMedium

Identify correct statements :

(A) Primary amines do not give diazonium salts when treated with NaNO2\mathrm{NaNO_2} in acidic condition. (B) Aliphatic and aromatic primary amines on heating with CHCl3\mathrm{CHCl_3} and ethanolic KOH form carbylamines. (C) Secondary and tertiary amines also give carbylamine test. (D) Benzenesulfonyl chloride is known as Hinsberg's reagent. (E) Tertiary amines reacts with benzenesulfonyl chloride very easily.

Choose the correct answer from the options given below :

  1. A

    (A) and (B) only

  2. B

    (B) and (C) only

  3. C

    (B) and (D) only

  4. D

    (D) and (E) only

Show answer

Correct option: C

Q69JEE Main 2025 Jan 28 Shift 2BiomoleculesMedium

Match List-I with List-II :

List-I (Saccharide) List-II (Glycosidic linkage present)
(A) Sucrose (I) α14\alpha\,1-4
(B) Maltose (II) α14\alpha\,1-4 and α16\alpha\,1-6
(C) Lactose (III) α1β2\alpha\,1-\beta\,2
(D) Amylopectin (IV) β14\beta\,1-4

Choose the correct answer from the options given below :

  1. A

    (A)-(III), (B)-(I), (C)-(IV), (D)-(II)

  2. B

    (A)-(IV), (B)-(II), (C)-(I), (D)-(III)

  3. C

    (A)-(II), (B)-(IV), (C)-(III), (D)-(I)

  4. D

    (A)-(I), (B)-(II), (C)-(III), (D)-(IV)

Show answer

Correct option: A

Q70JEE Main 2025 Jan 28 Shift 2BiomoleculesMedium

Identify correct conversion during acidic hydrolysis from the following :

(A) starch gives galactose. (B) cane sugar gives equal amount of glucose and fructose. (C) milk sugar gives glucose and galactose. (D) amylopectin gives glucose and fructose. (E) amylose gives only glucose.

Choose the correct answer from the options given below :

  1. A

    (A), (B) and (C) only

  2. B

    (B), (C) and (D) only

  3. C

    (C), (D) and (E) only

  4. D

    (B), (C) and (E) only

Show answer

Correct option: D

Q71JEE Main 2025 Jan 28 Shift 2Chemical ThermodynamicsMediumNumerical

Consider the following data :

Heat of formation of CO2(g)=393.5 kJ mol1\mathrm{CO_2(g)} = -393.5\ \mathrm{kJ\ mol^{-1}} Heat of formation of H2O(l)=286.0 kJ mol1\mathrm{H_2O(l)} = -286.0\ \mathrm{kJ\ mol^{-1}} Heat of combustion of benzene =3267.0 kJ mol1= -3267.0\ \mathrm{kJ\ mol^{-1}}

The heat of formation of benzene is __________ kJ mol1\mathrm{kJ\ mol^{-1}}.

(Nearest integer)

Show answer

Answer: 48

Q72JEE Main 2025 Jan 28 Shift 2Redox Reactions and ElectrochemistryHardNumerical

Electrolysis of 600 mL aqueous solution of NaCl for 5 min changes the pH of the solution to 12. The current in Amperes used for the given electrolysis is __________. (Nearest integer).

Show answer

Answer: 2

Q73JEE Main 2025 Jan 28 Shift 2Chemical Bonding and Molecular StructureHardNumerical

Total number of molecules/species from following which will be paramagnetic is __________.

O2, O2+, O2, NO, NO2, CO, K2[NiCl4], [Co(NH3)6]Cl3, K2[Ni(CN)4]\mathrm{O_2},\ \mathrm{O_2^{+}},\ \mathrm{O_2^{-}},\ \mathrm{NO},\ \mathrm{NO_2},\ \mathrm{CO},\ \mathrm{K_2[NiCl_4]},\ \mathrm{[Co(NH_3)_6]Cl_3},\ \mathrm{K_2[Ni(CN)_4]}

Show answer

Answer: 6

Q74JEE Main 2025 Jan 28 Shift 2p-Block ElementsMediumNumerical

A group 15 element forms dπdπd\pi - d\pi bond with transition metals. It also forms hydride, which is a strongest base among the hydrides of other group members that form dπdπd\pi - d\pi bond. The atomic number of the element is __________.

Show answer

Answer: 15

Q75JEE Main 2025 Jan 28 Shift 2d- and f-Block ElementsHardNumerical

The spin only magnetic moment (μ\mu) value (B.M.) of the compound with strongest oxidising power among Mn2O3\mathrm{Mn_2O_3}, TiO\mathrm{TiO} and VO\mathrm{VO} is __________ B.M. (Nearest integer).

Show answer

Answer: 5