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JEE Main 2025 Jan 28 Shift 2Chemistry

25 questions · 24 with the official NTA answer

Q51JEE Main 2025 Jan 28 Shift 2Atomic StructureMedium

Which of the following is/are not correct with respect to energy of atomic orbitals of hydrogen atom?

(A) 1s<2p<3d<4s1s < 2p < 3d < 4s (B) 1s<2s=2p<3s=3p1s < 2s = 2p < 3s = 3p (C) 1s<2s<2p<3s<3p1s < 2s < 2p < 3s < 3p (D) 1s<2s<4s<3d1s < 2s < 4s < 3d

Choose the correct answer from the options given below :

  1. A

    (A) and (B) only

  2. B

    (C) and (D) only

  3. C

    (A) and (C) only

  4. D

    (B) and (D) only

Show answer

Correct option: B

Q52JEE Main 2025 Jan 28 Shift 2Chemical ThermodynamicsEasy

An ideal gas undergoes a cyclic transformation starting from the point A and coming back to the same point by tracing the path ABCDAA \to B \to C \to D \to A as shown in the three cases above.

Choose the correct option regarding ΔU\Delta U :

Figure — described from the original paper

three VV (dm3^3) vs pp (kPa) plots — Case-I (curved loop A-B-C-D), Case-II (rectangular loop), Case-III (rhombus/diamond loop), each a closed cyclic path A→B→C→D→A

  1. A

    ΔU(Case-I)>ΔU(Case-II)>ΔU(Case-III)\Delta U(\text{Case-I}) > \Delta U(\text{Case-II}) > \Delta U(\text{Case-III})

  2. B

    ΔU(Case-III)>ΔU(Case-II)>ΔU(Case-I)\Delta U(\text{Case-III}) > \Delta U(\text{Case-II}) > \Delta U(\text{Case-I})

  3. C

    ΔU(Case-I)>ΔU(Case-III)>ΔU(Case-II)\Delta U(\text{Case-I}) > \Delta U(\text{Case-III}) > \Delta U(\text{Case-II})

  4. D

    ΔU(Case-I)=ΔU(Case-II)=ΔU(Case-III)\Delta U(\text{Case-I}) = \Delta U(\text{Case-II}) = \Delta U(\text{Case-III})

Show answer

Correct option: D

Q53JEE Main 2025 Jan 28 Shift 2SolutionsHard

Assume a living cell with 0.9%(ω/ω)0.9\%\,(\omega/\omega) of glucose solution (aqueous). This cell is immersed in another solution having equal mole fraction of glucose and water.

(Consider the data upto first decimal place only)

The cell will :

  1. A

    shrink since solution is 0.5%(ω/ω)0.5\%\,(\omega/\omega)

  2. B

    swell up since solution is 1%(ω/ω)1\%\,(\omega/\omega)

  3. C

    show no change in volume since solution is 0.9%(ω/ω)0.9\%\,(\omega/\omega)

  4. D

    shrink since solution is 0.45%(ω/ω)0.45\%\,(\omega/\omega) as a result of association of glucose molecules (due to hydrogen bonding)

Q54JEE Main 2025 Jan 28 Shift 2Some Basic Concepts in ChemistryEasy

Concentrated nitric acid is labelled as 75% by mass. The volume in mL of the solution which contains 30 g of nitric acid is __________.

Given : Density of nitric acid solution is 1.25 g/mL1.25\ \mathrm{g/mL}.

  1. A

    40

  2. B

    45

  3. C

    32

  4. D

    55

Show answer

Correct option: C

Q55JEE Main 2025 Jan 28 Shift 2EquilibriumMedium

Arrange the following in increasing order of solubility product :

Ca(OH)2, AgBr, PbS, HgS\mathrm{Ca(OH)_2},\ \mathrm{AgBr},\ \mathrm{PbS},\ \mathrm{HgS}

  1. A

    HgS<AgBr<PbS<Ca(OH)2\mathrm{HgS} < \mathrm{AgBr} < \mathrm{PbS} < \mathrm{Ca(OH)_2}

  2. B

    HgS<PbS<AgBr<Ca(OH)2\mathrm{HgS} < \mathrm{PbS} < \mathrm{AgBr} < \mathrm{Ca(OH)_2}

  3. C

    PbS<HgS<Ca(OH)2<AgBr\mathrm{PbS} < \mathrm{HgS} < \mathrm{Ca(OH)_2} < \mathrm{AgBr}

  4. D

    Ca(OH)2<AgBr<HgS<PbS\mathrm{Ca(OH)_2} < \mathrm{AgBr} < \mathrm{HgS} < \mathrm{PbS}

Show answer

Correct option: B

Q56JEE Main 2025 Jan 28 Shift 2Chemical KineticsMedium

For bacterial growth in a cell culture, growth law is very similar to the law of radioactive decay. Which of the following graphs is most suitable to represent bacterial colony growth?

Where N - Number of Bacteria at any time, N0N_0 - Initial number of Bacteria.

  1. A
    Figure — described from the original paper

    N/N0N/N_0 vs time — exponentially decreasing (decay) curve

  2. B
    Figure — described from the original paper

    N/N0N/N_0 vs time — exponentially increasing (rising) curve

  3. C
    Figure — described from the original paper

    N/N0N/N_0 vs time — straight line decreasing linearly

  4. D
    Figure — described from the original paper

    N/N0N/N_0 vs time — rising curve that levels off (saturating)

Show answer

Correct option: B

Q57JEE Main 2025 Jan 28 Shift 2Chemical KineticsMedium

Consider an elementary reaction

A(g)+B(g)C(g)+D(g)A(g) + B(g) \to C(g) + D(g)

If the volume of reaction mixture is suddenly reduced to 13\dfrac{1}{3} of its initial volume, the reaction rate will become x'x' times of the original reaction rate. The value of xx is :

  1. A

    33

  2. B

    19\dfrac{1}{9}

  3. C

    13\dfrac{1}{3}

  4. D

    99

Show answer

Correct option: D

Q58JEE Main 2025 Jan 28 Shift 2Principles Related to Practical ChemistryMedium

Identify the inorganic sulphides that are yellow in colour :

(A) (NH4)2S\mathrm{(NH_4)_2S} (B) PbS\mathrm{PbS} (C) CuS\mathrm{CuS} (D) As2S3\mathrm{As_2S_3} (E) As2S5\mathrm{As_2S_5}

Choose the correct answer from the options given below :

  1. A

    (A), (D) and (E) only

  2. B

    (A) and (B) only

  3. C

    (A) and (C) only

  4. D

    (D) and (E) only

Show answer

Correct option: A

Q59JEE Main 2025 Jan 28 Shift 2Classification of Elements and PeriodicityMedium

Given below are two statements :

Statement (I) : According to the Law of Octaves, the elements were arranged in the increasing order of their atomic number.

Statement (II) : Meyer observed a periodically repeated pattern upon plotting physical properties of certain elements against their respective atomic numbers.

In the light of the above statements, choose the correct answer from the options given below :

  1. A

    Both Statement I and Statement II are true

  2. B

    Both Statement I and Statement II are false

  3. C

    Statement I is true but Statement II is false

  4. D

    Statement I is false but Statement II is true

Show answer

Correct option: B

Q60JEE Main 2025 Jan 28 Shift 2d- and f-Block ElementsMedium

The amphoteric oxide among V2O3\mathrm{V_2O_3}, V2O4\mathrm{V_2O_4} and V2O5\mathrm{V_2O_5}, upon reaction with alkali leads to formation of an oxide anion. The oxidation state of V in the oxide anion is :

  1. A

    +3+3

  2. B

    +4+4

  3. C

    +5+5

  4. D

    +7+7

Show answer

Correct option: C

Q61JEE Main 2025 Jan 28 Shift 2Coordination CompoundsMedium

Match List-I with List-II :

List-I (Complex) List-II (Hybridisation of central metal ion)
(A) [CoF6]3\mathrm{[CoF_6]^{3-}} (I) d2sp3d^2sp^3
(B) [NiCl4]2\mathrm{[NiCl_4]^{2-}} (II) sp3sp^3
(C) [Co(NH3)6]3+\mathrm{[Co(NH_3)_6]^{3+}} (III) sp3d2sp^3d^2
(D) [Ni(CN)4]2\mathrm{[Ni(CN)_4]^{2-}} (IV) dsp2dsp^2

Choose the correct answer from the options given below :

  1. A

    (A)-(III), (B)-(II), (C)-(I), (D)-(IV)

  2. B

    (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

  3. C

    (A)-(I), (B)-(IV), (C)-(III), (D)-(II)

  4. D

    (A)-(I), (B)-(II), (C)-(III), (D)-(IV)

Show answer

Correct option: A

Q62JEE Main 2025 Jan 28 Shift 2Purification and Characterisation of Organic CompoundsEasy

The purification method based on the following physical transformation is :

Solid(X)HeatVapour(X)CoolSolid(X)\underset{(X)}{\text{Solid}} \xrightarrow{\text{Heat}} \underset{(X)}{\text{Vapour}} \xrightarrow{\text{Cool}} \underset{(X)}{\text{Solid}}

  1. A

    Distillation

  2. B

    Sublimation

  3. C

    Crystallization

  4. D

    Extraction

Show answer

Correct option: B

Q63JEE Main 2025 Jan 28 Shift 2Some Basic Principles of Organic ChemistryMedium

Given below are two statements :

Statement (I) :

Figure — described from the original paper

a cyclopentane ring

and

Figure — described from the original paper

an open-chain alkene, CH3_3CH2_2CH=CHCH2_2CH3_3

are isomeric compounds.

Statement (II) :

Figure — described from the original paper

a primary amine, CH3_3(CH2_2)4_4CH2_2NH2_2

and

Figure — described from the original paper

a secondary amine, CH3_3CH2_2CH2_2–NH–CH2_2CH2_2CH3_3

are functional group isomers.

In the light of the above statements, choose the correct answer from the options given below :

  1. A

    Both Statement I and Statement II are true

  2. B

    Both Statement I and Statement II are false

  3. C

    Statement I is true but Statement II is false

  4. D

    Statement I is false but Statement II is true

Show answer

Correct option: A

Q64JEE Main 2025 Jan 28 Shift 2HydrocarbonsMedium

Identify product [A], [B] and [C] in the following reaction sequence.

\mathrm{CH_3 - C \equiv CH} \xrightarrow[\mathrm{H_2}]{\mathrm{Pd/C}} [A] \xrightarrow[\text{(ii) Zn, H_2O}]{\text{(i) O_3}} [B] + [C]

  1. A

    [A]:CH3CH=CH2[A]: \mathrm{CH_3-CH=CH_2}, [B]:CH3CHO[B]: \mathrm{CH_3CHO}, [C]:HCHO[C]: \mathrm{HCHO}

  2. B

    [A]:CH2=CH2[A]: \mathrm{CH_2=CH_2}, [B]:H3CCOCH3[B]: \mathrm{H_3C-CO-CH_3}, [C]:HCHO[C]: \mathrm{HCHO}

  3. C

    [A]:CH3CH=CH2[A]: \mathrm{CH_3-CH=CH_2}, [B]:CH3CHO[B]: \mathrm{CH_3CHO}, [C]:CH3CH2OH[C]: \mathrm{CH_3CH_2OH}

  4. D

    [A]:CH3CH2CH3[A]: \mathrm{CH_3CH_2CH_3}, [B]:CH3CHO[B]: \mathrm{CH_3CHO}, [C]:HCHO[C]: \mathrm{HCHO}

Show answer

Correct option: A

Q65JEE Main 2025 Jan 28 Shift 2Organic Compounds Containing HalogensHard

The major product of the following reaction is :

Figure — described from the original paper

a dibromide bearing a phenyl group — 4-phenyl chain with two bromine atoms on adjacent-region carbons — treated with excess KOH/EtOH, Δ\Delta (double dehydrohalogenation)

  1. A

    6-phenylhepta-2,4-diene

  2. B

    2-phenylhepta-2,5-diene

  3. C

    6-phenylhepta-3,5-diene

  4. D

    2-phenylhepta-2,4-diene

Show answer

Correct option: D

Q66JEE Main 2025 Jan 28 Shift 2Organic Compounds Containing NitrogenHard

The product B formed in the following reaction sequence is :

4-methyl-(prop-1-en-1-yl)benzene(Major)HCl(A)(Major)AgCN(B)\text{4-methyl-(prop-1-en-1-yl)benzene} \xrightarrow[\text{(Major)}]{\mathrm{HCl}} (A) \xrightarrow[\text{(Major)}]{\mathrm{AgCN}} (B)

Figure — described from the original paper

reactant is 1-(prop-1-en-1-yl)-4-methylbenzene, i.e. p-tolyl–CH=CH–CH3_3

  1. A
    Figure — described from the original paper

    p-tolyl–CH(NC)–CH2_2CH3_3; isocyanide (–NC) on the benzylic carbon

  2. B
    Figure — described from the original paper

    p-tolyl–CH2_2–CH(NC)–CH3_3; isocyanide (–NC) on the secondary non-benzylic carbon

  3. C
    Figure — described from the original paper

    p-tolyl–CH(CN)–CH3_3; nitrile (–CN) on the benzylic carbon

  4. D
    Figure — described from the original paper

    p-tolyl–CH2_2–CH(NC)–CH3_3; isocyanide (–NC) on the secondary carbon

Show answer

Correct option: A

Q67JEE Main 2025 Jan 28 Shift 2HydrocarbonsHard

The total number of compounds from below when treated with hot KMnO4\mathrm{KMnO_4} giving benzoic acid is :

Figure — described from the original paper

eight compounds — toluene, ethylbenzene, isopropylbenzene (cumene), tert-butylbenzene, isobutylbenzene, 2-phenylpropan-2-ol, n-propylbenzene, 4,4'-dimethylbiphenyl

  1. A

    3

  2. B

    4

  3. C

    5

  4. D

    6

Show answer

Correct option: C

Q68JEE Main 2025 Jan 28 Shift 2Organic Compounds Containing NitrogenMedium

Identify correct statements :

(A) Primary amines do not give diazonium salts when treated with NaNO2\mathrm{NaNO_2} in acidic condition. (B) Aliphatic and aromatic primary amines on heating with CHCl3\mathrm{CHCl_3} and ethanolic KOH form carbylamines. (C) Secondary and tertiary amines also give carbylamine test. (D) Benzenesulfonyl chloride is known as Hinsberg's reagent. (E) Tertiary amines reacts with benzenesulfonyl chloride very easily.

Choose the correct answer from the options given below :

  1. A

    (A) and (B) only

  2. B

    (B) and (C) only

  3. C

    (B) and (D) only

  4. D

    (D) and (E) only

Show answer

Correct option: C

Q69JEE Main 2025 Jan 28 Shift 2BiomoleculesMedium

Match List-I with List-II :

List-I (Saccharide) List-II (Glycosidic linkage present)
(A) Sucrose (I) α14\alpha\,1-4
(B) Maltose (II) α14\alpha\,1-4 and α16\alpha\,1-6
(C) Lactose (III) α1β2\alpha\,1-\beta\,2
(D) Amylopectin (IV) β14\beta\,1-4

Choose the correct answer from the options given below :

  1. A

    (A)-(III), (B)-(I), (C)-(IV), (D)-(II)

  2. B

    (A)-(IV), (B)-(II), (C)-(I), (D)-(III)

  3. C

    (A)-(II), (B)-(IV), (C)-(III), (D)-(I)

  4. D

    (A)-(I), (B)-(II), (C)-(III), (D)-(IV)

Show answer

Correct option: A

Q70JEE Main 2025 Jan 28 Shift 2BiomoleculesMedium

Identify correct conversion during acidic hydrolysis from the following :

(A) starch gives galactose. (B) cane sugar gives equal amount of glucose and fructose. (C) milk sugar gives glucose and galactose. (D) amylopectin gives glucose and fructose. (E) amylose gives only glucose.

Choose the correct answer from the options given below :

  1. A

    (A), (B) and (C) only

  2. B

    (B), (C) and (D) only

  3. C

    (C), (D) and (E) only

  4. D

    (B), (C) and (E) only

Show answer

Correct option: D

Q71JEE Main 2025 Jan 28 Shift 2Chemical ThermodynamicsMediumNumerical

Consider the following data :

Heat of formation of CO2(g)=393.5 kJ mol1\mathrm{CO_2(g)} = -393.5\ \mathrm{kJ\ mol^{-1}} Heat of formation of H2O(l)=286.0 kJ mol1\mathrm{H_2O(l)} = -286.0\ \mathrm{kJ\ mol^{-1}} Heat of combustion of benzene =3267.0 kJ mol1= -3267.0\ \mathrm{kJ\ mol^{-1}}

The heat of formation of benzene is __________ kJ mol1\mathrm{kJ\ mol^{-1}}.

(Nearest integer)

Show answer

Answer: 48

Q72JEE Main 2025 Jan 28 Shift 2Redox Reactions and ElectrochemistryHardNumerical

Electrolysis of 600 mL aqueous solution of NaCl for 5 min changes the pH of the solution to 12. The current in Amperes used for the given electrolysis is __________. (Nearest integer).

Show answer

Answer: 2

Q73JEE Main 2025 Jan 28 Shift 2Chemical Bonding and Molecular StructureHardNumerical

Total number of molecules/species from following which will be paramagnetic is __________.

O2, O2+, O2, NO, NO2, CO, K2[NiCl4], [Co(NH3)6]Cl3, K2[Ni(CN)4]\mathrm{O_2},\ \mathrm{O_2^{+}},\ \mathrm{O_2^{-}},\ \mathrm{NO},\ \mathrm{NO_2},\ \mathrm{CO},\ \mathrm{K_2[NiCl_4]},\ \mathrm{[Co(NH_3)_6]Cl_3},\ \mathrm{K_2[Ni(CN)_4]}

Show answer

Answer: 6

Q74JEE Main 2025 Jan 28 Shift 2p-Block ElementsMediumNumerical

A group 15 element forms dπdπd\pi - d\pi bond with transition metals. It also forms hydride, which is a strongest base among the hydrides of other group members that form dπdπd\pi - d\pi bond. The atomic number of the element is __________.

Show answer

Answer: 15

Q75JEE Main 2025 Jan 28 Shift 2d- and f-Block ElementsHardNumerical

The spin only magnetic moment (μ\mu) value (B.M.) of the compound with strongest oxidising power among Mn2O3\mathrm{Mn_2O_3}, TiO\mathrm{TiO} and VO\mathrm{VO} is __________ B.M. (Nearest integer).

Show answer

Answer: 5