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JEE Main 2026 Apr 5 Shift 1 โ€” Chemistry

25 questions ยท 25 with the official NTA answer

Q51JEE Main 2026 Apr 5 Shift 1Some Basic Concepts in ChemistryMedium

How many grams of residue is obtained by heating 2.76 g of silver carbonate?

(Given : Molar mass of C, O and Ag are 12, 16 and 108 gย molโˆ’1\mathrm{g\ mol^{-1}} respectively)

  1. A

    1.08 g

  2. B

    2.16 g

  3. C

    3.24 g

  4. D

    4.32 g

Show answer

Correct option: B

Q52JEE Main 2026 Apr 5 Shift 1Atomic StructureEasy

Arrange the following atomic orbitals of multi electron atoms in order of increasing energy.

A. n=3,ย l=2,ย m=+1n = 3,\ l = 2,\ m = +1 B. n=4,ย l=0,ย m=0n = 4,\ l = 0,\ m = 0 C. n=6,ย l=1,ย m=0n = 6,\ l = 1,\ m = 0 D. n=5,ย l=1,ย m=+1n = 5,\ l = 1,\ m = +1 E. n=2,ย l=1,ย m=+1n = 2,\ l = 1,\ m = +1

Choose the correct answer from the options given below:

  1. A

    C < D < B < A < E

  2. B

    B < A < E < C < D

  3. C

    E < C < D < B < A

  4. D

    E < B < A < D < C

Show answer

Correct option: D

Q53JEE Main 2026 Apr 5 Shift 1Atomic StructureMedium

Identify the correct statements from the following :

A. Heisenberg uncertainty principle is applicable to electrons. B. The size of 2px\mathrm{2p_x} orbital is less than the size of 3px\mathrm{3p_x} orbital. C. The energy of 2s orbital of H atom is equal to the energy of 2s orbital of Li. D. The electronic configuration of Cr is [Ar]ย 3d5ย 4s1\mathrm{[Ar]\ 3d^5\ 4s^1}

Choose the correct answer from the options given below:

  1. A

    A, B and C Only

  2. B

    A, B and D Only

  3. C

    B, C and D Only

  4. D

    A, C and D Only

Show answer

Correct option: B

Q54JEE Main 2026 Apr 5 Shift 1SolutionsEasy

What is the mole fraction of water in 10% by weight (w/w) of aqueous urea solution?

[Given: Molar mass of H, O, C and N are 1, 16, 12 and 14 gย molโˆ’1\mathrm{g\ mol^{-1}} respectively.]

  1. A

    0.825

  2. B

    0.032

  3. C

    0.867

  4. D

    0.967

Show answer

Correct option: D

Q55JEE Main 2026 Apr 5 Shift 1EquilibriumMedium

M3A2\mathrm{M_3A_2} is a sparingly soluble salt of molar mass yy gย molโˆ’1\mathrm{g\ mol^{-1}} and solubility xx gย Lโˆ’1\mathrm{g\ L^{-1}}.

The ratio of the molar concentration of the anion (A3โˆ’\mathrm{A^{3-}}) to the solubility product of the salt is

  1. A

    154โ‹…y4x4\frac{1}{54} \cdot \frac{y^4}{x^4}

  2. B

    y5108x4\frac{y^5}{108x^4}

  3. C

    108โ‹…x5y5108 \cdot \frac{x^5}{y^5}

  4. D

    1108โ‹…y4x4\frac{1}{108} \cdot \frac{y^4}{x^4}

Show answer

Correct option: A

Q56JEE Main 2026 Apr 5 Shift 1EquilibriumMedium

Arrange the following resultant mixtures in increasing order of their pH values

A. 10 mL 0.2 M Ca(OH)2\mathrm{Ca(OH)_2} + 25 mL 0.1 M HCl B. 10 mL 0.01 M H2SO4\mathrm{H_2SO_4} + 10 mL 0.01 M Ca(OH)2\mathrm{Ca(OH)_2} C. 10 mL 0.1 M H2SO4\mathrm{H_2SO_4} + 10 mL 0.1 M KOH

Choose the correct answer from the options given below:

  1. A

    B < C < A

  2. B

    C < A < B

  3. C

    C < B < A

  4. D

    A < C < B

Show answer

Correct option: C

Q57JEE Main 2026 Apr 5 Shift 1Chemical KineticsMedium

First order gas phase reaction

Aโ†’B+C\mathrm{A \rightarrow B + C}

pip_i = initial pressure of gas A, ptp_t = total pressure of the reaction mixture at time tt

Expression of rate constant (kk) is

  1. A

    1tlnโกpi2piโˆ’pt\frac{1}{t}\ln\frac{p_i}{2p_i - p_t}

  2. B

    1tlnโก2pipiโˆ’pt\frac{1}{t}\ln\frac{2p_i}{p_i - p_t}

  3. C

    1tlnโกpi3piโˆ’2pt\frac{1}{t}\ln\frac{p_i}{3p_i - 2p_t}

  4. D

    1tlnโก3pi4piโˆ’pt\frac{1}{t}\ln\frac{3p_i}{4p_i - p_t}

Show answer

Correct option: A

Q58JEE Main 2026 Apr 5 Shift 1Classification of Elements and PeriodicityEasy

Given below are two statements:

Statement I: The correct order of electronegativity of fluorine, oxygen and nitrogen is F > O > N.

Statement II: The oxidation state of oxygen in OF2\mathrm{OF_2} is +2 and in Na2O\mathrm{Na_2O} is โˆ’2-2.

In the light of the above statements, choose the correct answer from the options given below

  1. A

    Both Statement I and Statement II are true

  2. B

    Both Statement I and Statement II are false

  3. C

    Statement I is true but Statement II is false

  4. D

    Statement I is false but Statement II is true

Show answer

Correct option: A

Q59JEE Main 2026 Apr 5 Shift 1p-Block ElementsMedium

Correct statements from the following are:

A. Nitrogen in oxidation states from +1 to +4 disproportionates in acid medium. B. Nitrogen has the ability to form dฯ€-pฯ€\mathrm{d\pi\text{-}p\pi} multiple bonds with itself and other elements with small size and high electronegativity. C. Nโ€“N single bond is stronger than Pโ€“P single bond. D. Nitrogen has highest density in its group due to small size. E. The maximum covalency of nitrogen is four since it has only four valence orbitals for bonding.

Choose the correct answer from the options given below:

  1. A

    B, C and D Only

  2. B

    C, D and E Only

  3. C

    A, C and E Only

  4. D

    A and E Only

Show answer

Correct option: D

Q60JEE Main 2026 Apr 5 Shift 1d- and f-Block ElementsEasy

Which of the following is NOT a physical or chemical characteristics of interstitial compounds?

  1. A

    They have high melting points, higher than those of pure metals.

  2. B

    They are very soft and ionic in nature.

  3. C

    They retain metallic conductivity.

  4. D

    They are chemically inert and usually non-stoichiometric.

Show answer

Correct option: B

Q61JEE Main 2026 Apr 5 Shift 1Coordination CompoundsMedium

The correct statements about metal carbonyls are

A. The metal-carbon bonds in metal carbonyls possess both ฯƒ\sigma and ฯ€\pi-character. B. Due to synergic bonding interactions between metal and CO ligand, the metal-carbon bond becomes weak. C. The metal-carbon ฯƒ\sigma bond is formed by the donation of lone pair of electrons on the carbonyl carbon into a vacant orbital of metal. D. The metal-carbon ฯ€\pi bond is formed by the donation of electrons from filled d-orbital of metal into vacant ฯ€โˆ—\pi^* orbital of CO.

Choose the correct answer from the options given below:

  1. A

    A and B Only

  2. B

    A, C and D Only

  3. C

    B and C Only

  4. D

    A and D Only

Show answer

Correct option: B

Q62JEE Main 2026 Apr 5 Shift 1Coordination CompoundsMedium

Given below are two statements:

Statement I: Each electron in eg\mathrm{e_g} orbitals destabilizes the orbitals by +0.6ย ฮ”o+0.6\ \Delta_o and each electron in the t2g\mathrm{t_{2g}} orbitals stabilizes the orbitals by โˆ’0.4ย ฮ”o-0.4\ \Delta_o in an octahedral field on the basis of crystal field theory.

Statement II: All the d-orbitals of the transition metals have the same energy in their free atomic state but when a complex is formed the ligands destroy the degeneracy of these orbitals on the basis of crystal field theory.

In the light of the above statements, choose the correct answer from the options given below

  1. A

    Both Statement I and Statement II are correct

  2. B

    Both Statement I and Statement II are incorrect

  3. C

    Statement I is correct but Statement II is incorrect

  4. D

    Statement I is incorrect but Statement II is correct

Show answer

Correct option: A

Q63JEE Main 2026 Apr 5 Shift 1Some Basic Principles of Organic ChemistryMedium

Given below are two statements:

Statement I: On the basis of inductive effect, the order of stability of alkyl carbanions is CH3โˆ’>CH3โˆ’CH2โˆ’>(CH3)2CHโˆ’>(CH3)3Cโˆ’\mathrm{CH_3^- > CH_3{-}CH_2^- > (CH_3)_2CH^- > (CH_3)_3C^-}.

Statement II: Allyl and benzyl carbanions are more stabilised by inductive effect and not by resonance effect.

In the light of the above statements, choose the correct answer from the options given below

  1. A

    Both Statement I and Statement II are correct

  2. B

    Both Statement I and Statement II are incorrect

  3. C

    Statement I is correct but Statement II is incorrect

  4. D

    Statement I is incorrect but Statement II is correct

Show answer

Correct option: C

Q64JEE Main 2026 Apr 5 Shift 1HydrocarbonsHard

"P" is a hydrocarbon of molecular formula:- C8H14\mathrm{C_8H_{14}}. On ozonolysis, "P" forms "Q". "Q" on treatment with alkali under reflux condition produces "R", which on treatment with I2\mathrm{I_2}/NaOH gives a yellow precipitate. Acidification of the solution gives "S". The structure of "S" is given below:-

Figure โ€” described from the original paper

cyclopentene ring with โˆ’CH3\mathrm{-CH_3} on one doubly-bonded carbon and โˆ’COOH\mathrm{-COOH} on the other, i.e. 2-methylcyclopent-1-ene-1-carboxylic acid

The correct structure of "P" is

  1. A
    Figure โ€” described from the original paper

    cyclohexene ring bearing two methyl groups on the ring carbons adjacent to the double bond, i.e. 3,6-dimethylcyclohex-1-ene

  2. B
    Figure โ€” described from the original paper

    cyclohexene ring with an ethyl (CH2โˆ’CH3\mathrm{CH_2{-}CH_3}) group on a doubly-bonded carbon, i.e. 1-ethylcyclohex-1-ene

  3. C
    Figure โ€” described from the original paper

    cyclopentene ring with โˆ’CH3\mathrm{-CH_3} on one doubly-bonded carbon and โˆ’CH2โˆ’CH3\mathrm{-CH_2{-}CH_3} on the other, i.e. 1-ethyl-2-methylcyclopent-1-ene

  4. D
    Figure โ€” described from the original paper

    cyclohexene ring with โˆ’CH3\mathrm{-CH_3} groups on both doubly-bonded carbons, i.e. 1,2-dimethylcyclohex-1-ene

Show answer

Correct option: D

Q65JEE Main 2026 Apr 5 Shift 1HydrocarbonsMedium

For the following Friedel Craft's alkylation reaction, which of the statements are correct?

Figure โ€” described from the original paper

benzene + 1-chloropropane โ†’Anhydrousย AlCl3\xrightarrow{\text{Anhydrous } \mathrm{AlCl_3}} Alkylbenzene

C6H6+CH3CH2CH2Clโ†’AnhydrousAlCl3Alkylbenzene\mathrm{C_6H_6 + CH_3CH_2CH_2Cl \xrightarrow[\text{Anhydrous}]{\mathrm{AlCl_3}} Alkylbenzene}

A. Major product is n-propyl benzene. B. iso-propyl carbocation intermediate is also generated. C. Multiple substitution is inevitable. D. Introducing electron-donating substituent on benzene will not produce any alkyl benzene.

Choose the correct answer from the options given below:

  1. A

    A and D only

  2. B

    B and C only

  3. C

    A and C only

  4. D

    B and D only

Show answer

Correct option: B

Q66JEE Main 2026 Apr 5 Shift 1Organic Compounds Containing HalogensMedium

Benzyl isocyanide can be obtained from

A.

Figure โ€” described from the original paper

benzyl bromide

C6H5CH2Brโ†’AgCN\mathrm{C_6H_5CH_2Br \xrightarrow{AgCN}} B.

Figure โ€” described from the original paper

benzylamine

C6H5CH2NH2โ†’Aqย NaOHCHCl3\mathrm{C_6H_5CH_2NH_2 \xrightarrow[\text{Aq NaOH}]{CHCl_3}} C.

Figure โ€” described from the original paper

bromobenzene

C6H5Brโ†’AgCN\mathrm{C_6H_5Br \xrightarrow{AgCN}} D.

Figure โ€” described from the original paper

aniline

C6H5NH2โ†’Aqย NaOHCHCl3\mathrm{C_6H_5NH_2 \xrightarrow[\text{Aq NaOH}]{CHCl_3}} E.

Figure โ€” described from the original paper

(2-bromoethyl)benzene

C6H5CH2CH2Brโ†’KCN\mathrm{C_6H_5CH_2CH_2Br \xrightarrow{KCN}}

Choose the correct answer from the options given below:

  1. A

    A and B Only

  2. B

    A and C Only

  3. C

    B and D Only

  4. D

    D and E Only

Show answer

Correct option: A

Q67JEE Main 2026 Apr 5 Shift 1Organic Compounds Containing OxygenMedium

Consider compounds A, B and C with following structural formulae

A = CH3โˆ’CH2โˆ’CH2โˆ’CH2โˆ’CH2โˆ’OH\mathrm{CH_3-CH_2-CH_2-CH_2-CH_2-OH} B = CH2=CHโˆ’CH2โˆ’CH2โˆ’CH3\mathrm{CH_2{=}CH-CH_2-CH_2-CH_3} C = HOโˆ’CH2โˆ’CH2โˆ’CH(OH)โˆ’CH3\mathrm{HO-CH_2-CH_2-CH(OH)-CH_3}

For the conversion of B from A, reagent (D) required is ________ and structural formula of product (E) obtained when C undergoes same reaction using excess reagent (D) is ________.

  1. A
    D E
    Conc. H2SO4\mathrm{H_2SO_4} CH2=CHโˆ’CH(OH)CH3\mathrm{CH_2{=}CH-CH(OH)CH_3}
  2. B
    D E
    PCC HOโˆ’CH2โˆ’CH2โˆ’CH=CH2\mathrm{HO-CH_2-CH_2-CH{=}CH_2}
  3. C
    D E
    PCC CH2=CHโˆ’CH=CH2\mathrm{CH_2{=}CH-CH{=}CH_2}
  4. D
    D E
    Conc. H2SO4\mathrm{H_2SO_4} or H3PO4\mathrm{H_3PO_4} CH2=CHโˆ’CH=CH2\mathrm{CH_2{=}CH-CH{=}CH_2}
Show answer

Correct option: D

Q68JEE Main 2026 Apr 5 Shift 1Organic Compounds Containing NitrogenHard

Identify the incorrect statements.

A.

Figure โ€” described from the original paper

benzylamine

C6H5CH2NH2\mathrm{C_6H_5CH_2NH_2} is a stronger base than

Figure โ€” described from the original paper

aniline

C6H5NH2\mathrm{C_6H_5NH_2} B.

Figure โ€” described from the original paper

4-methoxyaniline (p-anisidine)

can be synthesized by Gabriel phthalimide synthesis. C.

Figure โ€” described from the original paper

2-phenylacetamide, C6H5CH2CONH2\mathrm{C_6H_5CH_2CONH_2}

โ†’Br2,ย NaOH\xrightarrow{\mathrm{Br_2},\ \mathrm{NaOH}} primary aromatic amine D.

Figure โ€” described from the original paper

4-nitroaniline

โ†’(ii)ย ฮ”(i)ย NaNO2,ย HCl,ย 0โˆ˜C\xrightarrow[\text{(ii) } \Delta]{\text{(i) } \mathrm{NaNO_2},\ \mathrm{HCl},\ 0^\circ\mathrm{C}} product will dissolve in NaOH

Choose the correct answer from the options given below:

  1. A

    A and D Only

  2. B

    A and C Only

  3. C

    B and C Only

  4. D

    A and B Only

Show answer

Correct option: C

Q69JEE Main 2026 Apr 5 Shift 1BiomoleculesMedium

Identify the correct statements.

A. Glucose exists in two anomeric forms. B. Anomers of glucose differ in configuration at Cโ€“1 in cyclic hemiacetal structure. C. Melting point of ฮฑ\alpha-anomer of glucose is greater than ฮฒ\beta-anomer. D. Specific rotation of ฮฑ\alpha-anomer is +19โˆ˜+19^\circ while for ฮฒ\beta-anomer is +112โˆ˜+112^\circ E. ฮฑ\alpha and ฮฒ\beta-anomers of glucose are prepared by crystallization of saturated glucose solution at 303 K and 371 K respectively.

Choose the correct answer from the options given below:

  1. A

    A and B Only

  2. B

    B and C Only

  3. C

    A, B and D Only

  4. D

    A, B and E Only

Show answer

Correct option: D

Q70JEE Main 2026 Apr 5 Shift 1Principles Related to Practical ChemistryMedium

Given below are two statements:

Statement I: Sodium dichromate and potassium dichromate are classified as primary standards in titrimetric analysis.

Statement II: Phenolphthalein is a weak base, therefore it dissociates in acidic medium.

In the light of the above statements, choose the correct answer from the options given below

  1. A

    Both Statement I and Statement II are true

  2. B

    Both Statement I and Statement II are false

  3. C

    Statement I is true but Statement II is false

  4. D

    Statement I is false but Statement II is true

Show answer

Correct option: B

Q71JEE Main 2026 Apr 5 Shift 1Chemical Bonding and Molecular StructureMediumNumerical

Consider the following species:

BrF5,ย XeF5โˆ’,ย BF4โˆ’,ย ICl4โˆ’,ย XeF4,ย SF4,ย NH4+,ย ClF3,ย XeF2,ย ICl2โˆ’\mathrm{BrF_5,\ XeF_5^-,\ BF_4^-,\ ICl_4^-,\ XeF_4,\ SF_4,\ NH_4^+,\ ClF_3,\ XeF_2,\ ICl_2^-}

Number of species having sp3d\mathrm{sp^3d} hybridized central atom is ________.

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Answer: 4

Q72JEE Main 2026 Apr 5 Shift 1Purification and Characterisation of Organic CompoundsEasyNumerical

In an estimation of sulphur by Carius method 0.2 g of the substance gave 0.6 g of BaSO4\mathrm{BaSO_4}. The percentage of sulphur in the substance is ________ %.

(Given molar mass in gย molโˆ’1\mathrm{g\ mol^{-1}} S : 32, BaSO4\mathrm{BaSO_4} : 231)

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Answer: 41 or 42

Q73JEE Main 2026 Apr 5 Shift 1Organic Compounds Containing OxygenMediumNumerical

One mole of phenol is treated with dilute HNO3\mathrm{HNO_3} at 298 K to give a mixture of products. The mixture is separated by steam distillation. The steam volatile compound (X) is separated. The increase in percentage of oxygen in (X) with respect to phenol is ________ ร—10โˆ’1\times 10^{-1} %

(Given molar mass in gย molโˆ’1\mathrm{g\ mol^{-1}} H:1, C:12, N:14, O:16)

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Answer: 175

Q74JEE Main 2026 Apr 5 Shift 1Chemical ThermodynamicsMediumNumerical

The values of pressure equilibrium constant recorded at different temperatures for the following equilibrium reaction have been given below

A(g)โ‡ŒB(g)+C(g)\mathrm{A(g) \rightleftharpoons B(g) + C(g)}

1Tย (Kโˆ’1)\frac{1}{T}\ (\mathrm{K^{-1}}) logโก10Kp\log_{10} K_p
0.05 3.5
0.06 2.5
0.07 1.5

The magnitude of ฮ”Hโˆ˜R\frac{\Delta H^\circ}{R} calculated from the above data is ________. (Nearest integer)

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Answer: 230

Q75JEE Main 2026 Apr 5 Shift 1Chemical KineticsEasyNumerical

If the half life of a first order reaction is 6.93 minutes then the time required for completion of 99% of the reaction will be ________ minutes.

(Given : logโก2=0.3010\log 2 = 0.3010)

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Answer: 46