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JEE Main 2026 Apr 5 Shift 1 β€” Mathematics

25 questions Β· 25 with the official NTA answer

Q1JEE Main 2026 Apr 5 Shift 1Complex NumbersMedium

Let a,b∈Ca, b \in \mathbb{C}. Let Ξ±,Ξ²\alpha, \beta be the roots of the equation x2+ax+b=0x^2 + ax + b = 0. If Ξ²βˆ’Ξ±=11\beta - \alpha = \sqrt{11} and Ξ²2βˆ’Ξ±2=3i11\beta^2 - \alpha^2 = 3i\sqrt{11}, then (Ξ²3βˆ’Ξ±3)2(\beta^3 - \alpha^3)^2 is equal to:

  1. A

    160

  2. B

    176

  3. C

    194

  4. D

    187

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Correct option: B

Q2JEE Main 2026 Apr 5 Shift 1Sequences and SeriesMedium

Let the sum of the first nn terms of an A.P. be 3n2+5n3n^2 + 5n. Then the sum of squares of the first 10 terms of the A.P. is:

  1. A

    10220

  2. B

    12860

  3. C

    15220

  4. D

    19780

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Correct option: C

Q3JEE Main 2026 Apr 5 Shift 1Matrices and DeterminantsHard

Let AA be a 3Γ—33 \times 3 matrix such that

AT[101]=[522],β€…β€ŠAT[001]=[311],β€…β€ŠA[301]=[144]Β andΒ A[001]=[131].A^T \begin{bmatrix} 1 \\ 0 \\ 1 \end{bmatrix} = \begin{bmatrix} 5 \\ 2 \\ 2 \end{bmatrix}, \; A^T \begin{bmatrix} 0 \\ 0 \\ 1 \end{bmatrix} = \begin{bmatrix} 3 \\ 1 \\ 1 \end{bmatrix}, \; A \begin{bmatrix} 3 \\ 0 \\ 1 \end{bmatrix} = \begin{bmatrix} 1 \\ 4 \\ 4 \end{bmatrix} \text{ and } A \begin{bmatrix} 0 \\ 0 \\ 1 \end{bmatrix} = \begin{bmatrix} 1 \\ 3 \\ 1 \end{bmatrix}.

If det⁑(A)=1\det(A) = 1, then det⁑(adj⁑(A2+A))\det(\operatorname{adj}(A^2 + A)) is equal to:

  1. A

    16

  2. B

    25

  3. C

    49

  4. D

    64

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Correct option: D

Q4JEE Main 2026 Apr 5 Shift 1Matrices and DeterminantsMedium

Consider the system of linear equations in x,y,zx, y, z:

x+2y+tz=0,x + 2y + tz = 0, 6x+y+5tz=0,6x + y + 5tz = 0, 3x+t2y+f(t)z=0,3x + t^2 y + f(t)z = 0,

where f:Rβ†’Rf: \mathbb{R} \to \mathbb{R} is a differentiable function. If this system has infinitely many solutions for all t∈Rt \in \mathbb{R}, then ff

  1. A

    is a constant function

  2. B

    is strictly increasing on R\mathbb{R}

  3. C

    is strictly decreasing on R\mathbb{R}

  4. D

    has two critical points

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Correct option: B

Q5JEE Main 2026 Apr 5 Shift 1Sequences and SeriesEasy

βˆ‘n=110(528n(n+1)(n+2))\displaystyle\sum_{n=1}^{10} \left( \frac{528}{n(n+1)(n+2)} \right) is equal to:

  1. A

    65

  2. B

    130

  3. C

    220

  4. D

    440

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Correct option: B

Q6JEE Main 2026 Apr 5 Shift 1Trigonometric Ratios and EquationsMedium

Let tan⁑A,tan⁑B\tan A, \tan B, where A,B∈(βˆ’Ο€2,Ο€2)A, B \in \left( -\frac{\pi}{2}, \frac{\pi}{2} \right), be the roots of the quadratic equation x2βˆ’2xβˆ’5=0x^2 - 2x - 5 = 0. Then 20sin⁑2(A+B2)20\sin^2\left( \frac{A+B}{2} \right) is equal to:

  1. A

    10+1010 + \sqrt{10}

  2. B

    10βˆ’21010 - 2\sqrt{10}

  3. C

    10βˆ’31010 - 3\sqrt{10}

  4. D

    10βˆ’1010 - \sqrt{10}

Show answer

Correct option: C

Q7JEE Main 2026 Apr 5 Shift 1ProbabilityMedium

A letter is known to have arrived by post either from KANPUR or from ANANTPUR. On the envelope just two consecutive letters AN are visible. The probability, that the letter came from ANANTPUR, is:

  1. A

    710\frac{7}{10}

  2. B

    1017\frac{10}{17}

  3. C

    1219\frac{12}{19}

  4. D

    719\frac{7}{19}

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Correct option: B

Q8JEE Main 2026 Apr 5 Shift 1StatisticsEasy

The mean deviation about the mean for the data

xix_i 5 7 9 10 12 15
fif_i 8 6 2 2 2 6

is equal to:

  1. A

    4013\frac{40}{13}

  2. B

    4213\frac{42}{13}

  3. C

    4413\frac{44}{13}

  4. D

    4613\frac{46}{13}

Show answer

Correct option: C

Q9JEE Main 2026 Apr 5 Shift 1Conic SectionsMedium

Let a focus of the ellipse E:x2a2+y2b2=1E: \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 be S(4,0)S(4, 0) and its eccentricity be 45\frac{4}{5}. If the point P(3,Ξ±)P(3, \alpha) lies on EE and OO is the origin, then the area of β–³POS\triangle POS is equal to:

  1. A

    12/512/5

  2. B

    14/514/5

  3. C

    24/524/5

  4. D

    48/548/5

Show answer

Correct option: C

Q10JEE Main 2026 Apr 5 Shift 1CirclesMedium

Let PP be a moving point on the circle x2+y2βˆ’6xβˆ’8y+21=0x^2 + y^2 - 6x - 8y + 21 = 0. Then, the maximum distance of PP from the vertex of the parabola x2+6x+y+13=0x^2 + 6x + y + 13 = 0 is equal to:

  1. A

    8

  2. B

    10

  3. C

    12

  4. D

    9

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Correct option: C

Q11JEE Main 2026 Apr 5 Shift 1Straight LinesMedium

In an equilateral triangle PQR, let the vertex PP be at (3,5)(3, 5) and the side QR be along the line x+y=4x + y = 4. If the orthocentre of the triangle PQR is (Ξ±,Ξ²)(\alpha, \beta), then 9(Ξ±+Ξ²)9(\alpha + \beta) is equal to:

  1. A

    16

  2. B

    27

  3. C

    36

  4. D

    48

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Correct option: D

Q12JEE Main 2026 Apr 5 Shift 1Trigonometric Ratios and EquationsMedium

The sum of all the integral values of pp such that the equation 3sin⁑2x+12cos⁑xβˆ’3=p3\sin^2 x + 12\cos x - 3 = p, x∈Rx \in \mathbb{R}, has at least one solution, is:

  1. A

    βˆ’54-54

  2. B

    βˆ’60-60

  3. C

    βˆ’75-75

  4. D

    βˆ’84-84

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Correct option: C

Q13JEE Main 2026 Apr 5 Shift 1Three Dimensional GeometryEasy

The square of the distance of the point P(5,6,7)P(5, 6, 7) from the line xβˆ’22=yβˆ’53=zβˆ’24\frac{x-2}{2} = \frac{y-5}{3} = \frac{z-2}{4} is equal to:

  1. A

    3

  2. B

    5

  3. C

    6

  4. D

    8

Show answer

Correct option: C

Q14JEE Main 2026 Apr 5 Shift 1Vector AlgebraMedium

Let aβƒ—=7i^+j^βˆ’k^\vec{a} = \sqrt{7}\hat{i} + \hat{j} - \hat{k} and bβƒ—=j^+2k^\vec{b} = \hat{j} + 2\hat{k}. If rβƒ—\vec{r} is a vector such that rβƒ—Γ—aβƒ—+aβƒ—Γ—bβƒ—=0βƒ—\vec{r} \times \vec{a} + \vec{a} \times \vec{b} = \vec{0} and rβƒ—β‹…aβƒ—=0\vec{r} \cdot \vec{a} = 0, then ∣3rβƒ—βˆ£2\left| 3\vec{r} \right|^2 is equal to:

  1. A

    44

  2. B

    54

  3. C

    86

  4. D

    132

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Correct option: A

Q15JEE Main 2026 Apr 5 Shift 1Three Dimensional GeometryMedium

The square of the distance of the point of intersection of the lines rβƒ—=(i^+j^βˆ’k^)+Ξ»(ai^βˆ’j^)\vec{r} = \left( \hat{i} + \hat{j} - \hat{k} \right) + \lambda\left( a\hat{i} - \hat{j} \right), aβ‰ 0a \neq 0 and rβƒ—=(4i^βˆ’k^)+ΞΌ(2i^+ak^)\vec{r} = \left( 4\hat{i} - \hat{k} \right) + \mu\left( 2\hat{i} + a\hat{k} \right) from the origin is:

  1. A

    5

  2. B

    10

  3. C

    17

  4. D

    26

Show answer

Correct option: C

Q16JEE Main 2026 Apr 5 Shift 1Integral CalculusHard

The area of the region R={(x,y):xy≀27, 1≀y≀x2}R = \{(x, y): xy \leq 27, \, 1 \leq y \leq x^2\} is equal to:

  1. A

    78log⁑e3βˆ’52378\log_e 3 - \frac{52}{3}

  2. B

    54log⁑e3βˆ’52354\log_e 3 - \frac{52}{3}

  3. C

    54log⁑e3βˆ’26354\log_e 3 - \frac{26}{3}

  4. D

    54log⁑e3+26354\log_e 3 + \frac{26}{3}

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Correct option: B

Q17JEE Main 2026 Apr 5 Shift 1Limits, Continuity and DifferentiabilityHard

The product of all possible values of Ξ±\alpha, for which

lim⁑xβ†’0(1βˆ’cos⁑(Ξ±x)cos⁑((Ξ±+1)x)cos⁑((Ξ±+2)x)sin⁑2((Ξ±+1)x))=2,Β is:\lim_{x \to 0} \left( \frac{1 - \cos(\alpha x)\cos\left( (\alpha+1)x \right)\cos\left( (\alpha+2)x \right)}{\sin^2\left( (\alpha+1)x \right)} \right) = 2, \text{ is:}

  1. A

    βˆ’2-2

  2. B

    1

  3. C

    βˆ’1-1

  4. D

    54\frac{5}{4}

Show answer

Correct option: C

Q18JEE Main 2026 Apr 5 Shift 1Integral CalculusHard

The value of the integral ∫0∞log⁑e(x)x2+4 dx\displaystyle\int_0^{\infty} \frac{\log_e(x)}{x^2 + 4} \, dx is:

  1. A

    Ο€log⁑e(2)2\frac{\pi \log_e(2)}{2}

  2. B

    Ο€log⁑e(2)4\frac{\pi \log_e(2)}{4}

  3. C

    1+Ο€log⁑e(2)1 + \pi \log_e(2)

  4. D

    2+Ο€log⁑e(2)2 + \pi \log_e(2)

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Correct option: B

Q19JEE Main 2026 Apr 5 Shift 1Differentiation and Applications of DerivativesMedium

Let f:Rβ†’Rf: \mathbb{R} \to \mathbb{R} be a differentiable function such that f(x+y3)=f(x)+f(y)3f\left( \frac{x+y}{3} \right) = \frac{f(x) + f(y)}{3} for all x,y∈Rx, y \in \mathbb{R}, and fβ€²(0)=3f'(0) = 3. Then the minimum value of the function g(x)=3+exf(x)g(x) = 3 + e^x f(x), is:

  1. A

    3(e+1e)3\left( \frac{e+1}{e} \right)

  2. B

    3(eβˆ’1e)3\left( \frac{e-1}{e} \right)

  3. C

    3βˆ’ee\frac{3-e}{e}

  4. D

    3e3e

Show answer

Correct option: B

Q20JEE Main 2026 Apr 5 Shift 1Integral CalculusMedium

The value of the integral βˆ«Ο€6Ο€3(4βˆ’cosec⁑2xcos⁑4x)dx\displaystyle\int_{\frac{\pi}{6}}^{\frac{\pi}{3}} \left( \frac{4 - \operatorname{cosec}^2 x}{\cos^4 x} \right) dx is:

  1. A

    113\frac{11}{\sqrt{3}}

  2. B

    163\frac{16}{\sqrt{3}}

  3. C

    3233\frac{32}{3\sqrt{3}}

  4. D

    6433\frac{64}{3\sqrt{3}}

Show answer

Correct option: C

Q21JEE Main 2026 Apr 5 Shift 1Permutations and CombinationsMediumNumerical

Let A={1,2,3,4,5,6}A = \{1, 2, 3, 4, 5, 6\}. The number of one-one functions f:Aβ†’Af: A \to A such that f(1)β‰₯3f(1) \geq 3, f(3)≀4f(3) \leq 4 and f(2)+f(3)=5f(2) + f(3) = 5, is __________.

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Answer: 72

Q22JEE Main 2026 Apr 5 Shift 1Permutations and CombinationsMediumNumerical

Two players A and B play a series of games of badminton. The player, who wins 5 games first, wins the series. Assuming that no game ends in a draw, the number of ways, in which player A wins the series is ________.

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Answer: 126

Q23JEE Main 2026 Apr 5 Shift 1Binomial TheoremMediumNumerical

If the sum of the coefficients of x7x^7 and x14x^{14} in the expansion of (1x3βˆ’x4)n\left( \frac{1}{x^3} - x^4 \right)^n, xβ‰ 0x \neq 0, is zero, then the value of nn is ________.

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Answer: 21

Q24JEE Main 2026 Apr 5 Shift 1Inverse Trigonometric FunctionsMediumNumerical

If Ο€4+βˆ‘p=111tanβ‘βˆ’1(2pβˆ’11+22pβˆ’1)=Ξ±\frac{\pi}{4} + \displaystyle\sum_{p=1}^{11} \tan^{-1}\left( \frac{2^{p-1}}{1 + 2^{2p-1}} \right) = \alpha, then tan⁑α\tan \alpha is equal to __________.

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Answer: 2048

Q25JEE Main 2026 Apr 5 Shift 1Differential EquationsHardNumerical

Let y=y(x)y = y(x) be the solution of the differential equation

xsin⁑(yx)dy=(ysin⁑(yx)βˆ’x)dx,y(1)=Ο€2x \sin\left( \frac{y}{x} \right) dy = \left( y \sin\left( \frac{y}{x} \right) - x \right) dx, \quad y(1) = \frac{\pi}{2}

and let Ξ±=cos⁑(y(e12)e12)\alpha = \cos\left( \frac{y\left( e^{12} \right)}{e^{12}} \right). Then the number of integral values of pp, for which the equation x2+y2βˆ’2px+2py+Ξ±+2=0x^2 + y^2 - 2px + 2py + \alpha + 2 = 0 represents a circle of radius r≀6r \leq 6, is ________.

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Dropped β€” any non-negative integer accepted